foreach loop for tikzset












2















I have the following code for drawing circles whose different radius. As seen in code there are two different pic statement (d1 and d2).



documentclass[margin=3mm]{standalone}
usepackage{tikz,pgf}
begin{document}

begin{tikzpicture}

% foreach b in {1,2}{
tikzset{
d1/.pic={
foreach r in {1,...,4}{
draw[red,thick](r,0) circle (r);
}
}
}
tikzset{
d2/.pic={
foreach r in {1,...,4}{
draw[black,thick](3*r,0) circle (r);
}
}
}
% }


pic at (0,0) {d1};
pic at (0,0) {d2};

end{tikzpicture}

end{document}


Output of the code:



enter image description here



Is it possible to one pic statement for d1 and d2 using foreach? For example:



documentclass[margin=3mm]{standalone}
usepackage{tikz,pgf}
begin{document}

begin{tikzpicture}
pgfmathsetmacro{k}{1}
foreach b in {1,2}{
tikzset{
db/.pic={

ifnumb=2 pgfmathsetmacro{k}{2} fi
foreach r in {1,...,4}{
draw[red,thick](k*r,0) circle (r);
}
}
}
}

pic at (0,0) {d1};
pic at (0,0) {d2};

end{tikzpicture}

end{document}


It seems that b counter in foreach loop does not pass into the tikzset. How can I solve this problem?










share|improve this question



























    2















    I have the following code for drawing circles whose different radius. As seen in code there are two different pic statement (d1 and d2).



    documentclass[margin=3mm]{standalone}
    usepackage{tikz,pgf}
    begin{document}

    begin{tikzpicture}

    % foreach b in {1,2}{
    tikzset{
    d1/.pic={
    foreach r in {1,...,4}{
    draw[red,thick](r,0) circle (r);
    }
    }
    }
    tikzset{
    d2/.pic={
    foreach r in {1,...,4}{
    draw[black,thick](3*r,0) circle (r);
    }
    }
    }
    % }


    pic at (0,0) {d1};
    pic at (0,0) {d2};

    end{tikzpicture}

    end{document}


    Output of the code:



    enter image description here



    Is it possible to one pic statement for d1 and d2 using foreach? For example:



    documentclass[margin=3mm]{standalone}
    usepackage{tikz,pgf}
    begin{document}

    begin{tikzpicture}
    pgfmathsetmacro{k}{1}
    foreach b in {1,2}{
    tikzset{
    db/.pic={

    ifnumb=2 pgfmathsetmacro{k}{2} fi
    foreach r in {1,...,4}{
    draw[red,thick](k*r,0) circle (r);
    }
    }
    }
    }

    pic at (0,0) {d1};
    pic at (0,0) {d2};

    end{tikzpicture}

    end{document}


    It seems that b counter in foreach loop does not pass into the tikzset. How can I solve this problem?










    share|improve this question

























      2












      2








      2








      I have the following code for drawing circles whose different radius. As seen in code there are two different pic statement (d1 and d2).



      documentclass[margin=3mm]{standalone}
      usepackage{tikz,pgf}
      begin{document}

      begin{tikzpicture}

      % foreach b in {1,2}{
      tikzset{
      d1/.pic={
      foreach r in {1,...,4}{
      draw[red,thick](r,0) circle (r);
      }
      }
      }
      tikzset{
      d2/.pic={
      foreach r in {1,...,4}{
      draw[black,thick](3*r,0) circle (r);
      }
      }
      }
      % }


      pic at (0,0) {d1};
      pic at (0,0) {d2};

      end{tikzpicture}

      end{document}


      Output of the code:



      enter image description here



      Is it possible to one pic statement for d1 and d2 using foreach? For example:



      documentclass[margin=3mm]{standalone}
      usepackage{tikz,pgf}
      begin{document}

      begin{tikzpicture}
      pgfmathsetmacro{k}{1}
      foreach b in {1,2}{
      tikzset{
      db/.pic={

      ifnumb=2 pgfmathsetmacro{k}{2} fi
      foreach r in {1,...,4}{
      draw[red,thick](k*r,0) circle (r);
      }
      }
      }
      }

      pic at (0,0) {d1};
      pic at (0,0) {d2};

      end{tikzpicture}

      end{document}


      It seems that b counter in foreach loop does not pass into the tikzset. How can I solve this problem?










      share|improve this question














      I have the following code for drawing circles whose different radius. As seen in code there are two different pic statement (d1 and d2).



      documentclass[margin=3mm]{standalone}
      usepackage{tikz,pgf}
      begin{document}

      begin{tikzpicture}

      % foreach b in {1,2}{
      tikzset{
      d1/.pic={
      foreach r in {1,...,4}{
      draw[red,thick](r,0) circle (r);
      }
      }
      }
      tikzset{
      d2/.pic={
      foreach r in {1,...,4}{
      draw[black,thick](3*r,0) circle (r);
      }
      }
      }
      % }


      pic at (0,0) {d1};
      pic at (0,0) {d2};

      end{tikzpicture}

      end{document}


      Output of the code:



      enter image description here



      Is it possible to one pic statement for d1 and d2 using foreach? For example:



      documentclass[margin=3mm]{standalone}
      usepackage{tikz,pgf}
      begin{document}

      begin{tikzpicture}
      pgfmathsetmacro{k}{1}
      foreach b in {1,2}{
      tikzset{
      db/.pic={

      ifnumb=2 pgfmathsetmacro{k}{2} fi
      foreach r in {1,...,4}{
      draw[red,thick](k*r,0) circle (r);
      }
      }
      }
      }

      pic at (0,0) {d1};
      pic at (0,0) {d2};

      end{tikzpicture}

      end{document}


      It seems that b counter in foreach loop does not pass into the tikzset. How can I solve this problem?







      tikz-pgf foreach tikzset






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Feb 12 at 17:07









      ferahfezaferahfeza

      6,08611932




      6,08611932






















          1 Answer
          1






          active

          oldest

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          3














          You could just make the pic depend on an argument that indicates the color.



          documentclass[margin=3mm]{standalone}
          usepackage{tikz}
          begin{document}

          begin{tikzpicture}
          defColorList{{"black","red","blue"}}

          tikzset{
          d/.pic={pgfmathsetmacro{mycolor}{ColorList[#1]}
          foreach r in {1,...,4}{
          draw[mycolor,thick]({r*(1+2*#1)},0) circle (r);
          }
          }
          }

          foreach b in {0,1,2}{
          pic at (0,0) {d=b};
          }
          end{tikzpicture}

          end{document}


          enter image description here






          share|improve this answer



















          • 1





            Thank you very much. An interesting approach. Actually, that's the solution that I want.

            – ferahfeza
            Feb 12 at 17:32











          Your Answer








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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3














          You could just make the pic depend on an argument that indicates the color.



          documentclass[margin=3mm]{standalone}
          usepackage{tikz}
          begin{document}

          begin{tikzpicture}
          defColorList{{"black","red","blue"}}

          tikzset{
          d/.pic={pgfmathsetmacro{mycolor}{ColorList[#1]}
          foreach r in {1,...,4}{
          draw[mycolor,thick]({r*(1+2*#1)},0) circle (r);
          }
          }
          }

          foreach b in {0,1,2}{
          pic at (0,0) {d=b};
          }
          end{tikzpicture}

          end{document}


          enter image description here






          share|improve this answer



















          • 1





            Thank you very much. An interesting approach. Actually, that's the solution that I want.

            – ferahfeza
            Feb 12 at 17:32
















          3














          You could just make the pic depend on an argument that indicates the color.



          documentclass[margin=3mm]{standalone}
          usepackage{tikz}
          begin{document}

          begin{tikzpicture}
          defColorList{{"black","red","blue"}}

          tikzset{
          d/.pic={pgfmathsetmacro{mycolor}{ColorList[#1]}
          foreach r in {1,...,4}{
          draw[mycolor,thick]({r*(1+2*#1)},0) circle (r);
          }
          }
          }

          foreach b in {0,1,2}{
          pic at (0,0) {d=b};
          }
          end{tikzpicture}

          end{document}


          enter image description here






          share|improve this answer



















          • 1





            Thank you very much. An interesting approach. Actually, that's the solution that I want.

            – ferahfeza
            Feb 12 at 17:32














          3












          3








          3







          You could just make the pic depend on an argument that indicates the color.



          documentclass[margin=3mm]{standalone}
          usepackage{tikz}
          begin{document}

          begin{tikzpicture}
          defColorList{{"black","red","blue"}}

          tikzset{
          d/.pic={pgfmathsetmacro{mycolor}{ColorList[#1]}
          foreach r in {1,...,4}{
          draw[mycolor,thick]({r*(1+2*#1)},0) circle (r);
          }
          }
          }

          foreach b in {0,1,2}{
          pic at (0,0) {d=b};
          }
          end{tikzpicture}

          end{document}


          enter image description here






          share|improve this answer













          You could just make the pic depend on an argument that indicates the color.



          documentclass[margin=3mm]{standalone}
          usepackage{tikz}
          begin{document}

          begin{tikzpicture}
          defColorList{{"black","red","blue"}}

          tikzset{
          d/.pic={pgfmathsetmacro{mycolor}{ColorList[#1]}
          foreach r in {1,...,4}{
          draw[mycolor,thick]({r*(1+2*#1)},0) circle (r);
          }
          }
          }

          foreach b in {0,1,2}{
          pic at (0,0) {d=b};
          }
          end{tikzpicture}

          end{document}


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Feb 12 at 17:17









          marmotmarmot

          101k4119228




          101k4119228








          • 1





            Thank you very much. An interesting approach. Actually, that's the solution that I want.

            – ferahfeza
            Feb 12 at 17:32














          • 1





            Thank you very much. An interesting approach. Actually, that's the solution that I want.

            – ferahfeza
            Feb 12 at 17:32








          1




          1





          Thank you very much. An interesting approach. Actually, that's the solution that I want.

          – ferahfeza
          Feb 12 at 17:32





          Thank you very much. An interesting approach. Actually, that's the solution that I want.

          – ferahfeza
          Feb 12 at 17:32


















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