SQL Server CTE Bottom to Top Recursive with Where clause












3















I have an Employee Table with an EmployeeId, ManagerId and a Name field.



The goal is to make a recursive With fetching all the rows from an employee to the top manager (ManagerId is null).



I found this link which helped to get the base of the code but I do not manage to make it work for my case



DECLARE @EmployeeTable table ([EmployeeId] int, [name] varchar(10), [managerId] int)
INSERT @EmployeeTable VALUES (1,'Jerome', NULL ) -- tree is as follows:
INSERT @EmployeeTable VALUES (2,'Joe' ,1) -- 1-Jerome
INSERT @EmployeeTable VALUES (3,'Paul' ,2) -- /
INSERT @EmployeeTable VALUES (4,'Jack' ,3) -- 2-Joe 9-Bill
INSERT @EmployeeTable VALUES (5,'Daniel',3) -- /
INSERT @EmployeeTable VALUES (6,'David' ,2) -- 3-Paul 6-David 10-Sam
INSERT @EmployeeTable VALUES (7,'Ian' ,6) -- / /
INSERT @EmployeeTable VALUES (8,'Helen' ,6) -- 4-Jack 5-Daniel 7-Ian 8-Helen
INSERT @EmployeeTable VALUES (9,'Bill ' ,1) --
INSERT @EmployeeTable VALUES (10,'Sam' ,9) --

DECLARE @employeeId int = 3

;WITH StaffTree AS
(
SELECT
c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]
FROM @EmployeeTable c
LEFT OUTER JOIN @EmployeeTable cc ON c.managerId=cc.EmployeeId
WHERE c.EmployeeId=@employeeId OR (@employeeId IS NULL AND c.managerId IS NULL)
UNION ALL
SELECT
s.[EmployeeId], s.[name], s.managerId, t.[Level]+1
FROM StaffTree t
INNER JOIN @EmployeeTable s ON t.[EmployeeId]=s.managerId
WHERE s.managerId=@employeeId OR @employeeId IS NULL OR t.Level>1
)
SELECT * FROM StaffTree


In case you select the employee 3 hierarchy, the result should be:



EmployeeId | Name    | ManagerId 
1 | Jerome | NULL
2 | Joe | 1
3 | Paul | 2









share|improve this question



























    3















    I have an Employee Table with an EmployeeId, ManagerId and a Name field.



    The goal is to make a recursive With fetching all the rows from an employee to the top manager (ManagerId is null).



    I found this link which helped to get the base of the code but I do not manage to make it work for my case



    DECLARE @EmployeeTable table ([EmployeeId] int, [name] varchar(10), [managerId] int)
    INSERT @EmployeeTable VALUES (1,'Jerome', NULL ) -- tree is as follows:
    INSERT @EmployeeTable VALUES (2,'Joe' ,1) -- 1-Jerome
    INSERT @EmployeeTable VALUES (3,'Paul' ,2) -- /
    INSERT @EmployeeTable VALUES (4,'Jack' ,3) -- 2-Joe 9-Bill
    INSERT @EmployeeTable VALUES (5,'Daniel',3) -- /
    INSERT @EmployeeTable VALUES (6,'David' ,2) -- 3-Paul 6-David 10-Sam
    INSERT @EmployeeTable VALUES (7,'Ian' ,6) -- / /
    INSERT @EmployeeTable VALUES (8,'Helen' ,6) -- 4-Jack 5-Daniel 7-Ian 8-Helen
    INSERT @EmployeeTable VALUES (9,'Bill ' ,1) --
    INSERT @EmployeeTable VALUES (10,'Sam' ,9) --

    DECLARE @employeeId int = 3

    ;WITH StaffTree AS
    (
    SELECT
    c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]
    FROM @EmployeeTable c
    LEFT OUTER JOIN @EmployeeTable cc ON c.managerId=cc.EmployeeId
    WHERE c.EmployeeId=@employeeId OR (@employeeId IS NULL AND c.managerId IS NULL)
    UNION ALL
    SELECT
    s.[EmployeeId], s.[name], s.managerId, t.[Level]+1
    FROM StaffTree t
    INNER JOIN @EmployeeTable s ON t.[EmployeeId]=s.managerId
    WHERE s.managerId=@employeeId OR @employeeId IS NULL OR t.Level>1
    )
    SELECT * FROM StaffTree


    In case you select the employee 3 hierarchy, the result should be:



    EmployeeId | Name    | ManagerId 
    1 | Jerome | NULL
    2 | Joe | 1
    3 | Paul | 2









    share|improve this question

























      3












      3








      3


      1






      I have an Employee Table with an EmployeeId, ManagerId and a Name field.



      The goal is to make a recursive With fetching all the rows from an employee to the top manager (ManagerId is null).



      I found this link which helped to get the base of the code but I do not manage to make it work for my case



      DECLARE @EmployeeTable table ([EmployeeId] int, [name] varchar(10), [managerId] int)
      INSERT @EmployeeTable VALUES (1,'Jerome', NULL ) -- tree is as follows:
      INSERT @EmployeeTable VALUES (2,'Joe' ,1) -- 1-Jerome
      INSERT @EmployeeTable VALUES (3,'Paul' ,2) -- /
      INSERT @EmployeeTable VALUES (4,'Jack' ,3) -- 2-Joe 9-Bill
      INSERT @EmployeeTable VALUES (5,'Daniel',3) -- /
      INSERT @EmployeeTable VALUES (6,'David' ,2) -- 3-Paul 6-David 10-Sam
      INSERT @EmployeeTable VALUES (7,'Ian' ,6) -- / /
      INSERT @EmployeeTable VALUES (8,'Helen' ,6) -- 4-Jack 5-Daniel 7-Ian 8-Helen
      INSERT @EmployeeTable VALUES (9,'Bill ' ,1) --
      INSERT @EmployeeTable VALUES (10,'Sam' ,9) --

      DECLARE @employeeId int = 3

      ;WITH StaffTree AS
      (
      SELECT
      c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]
      FROM @EmployeeTable c
      LEFT OUTER JOIN @EmployeeTable cc ON c.managerId=cc.EmployeeId
      WHERE c.EmployeeId=@employeeId OR (@employeeId IS NULL AND c.managerId IS NULL)
      UNION ALL
      SELECT
      s.[EmployeeId], s.[name], s.managerId, t.[Level]+1
      FROM StaffTree t
      INNER JOIN @EmployeeTable s ON t.[EmployeeId]=s.managerId
      WHERE s.managerId=@employeeId OR @employeeId IS NULL OR t.Level>1
      )
      SELECT * FROM StaffTree


      In case you select the employee 3 hierarchy, the result should be:



      EmployeeId | Name    | ManagerId 
      1 | Jerome | NULL
      2 | Joe | 1
      3 | Paul | 2









      share|improve this question














      I have an Employee Table with an EmployeeId, ManagerId and a Name field.



      The goal is to make a recursive With fetching all the rows from an employee to the top manager (ManagerId is null).



      I found this link which helped to get the base of the code but I do not manage to make it work for my case



      DECLARE @EmployeeTable table ([EmployeeId] int, [name] varchar(10), [managerId] int)
      INSERT @EmployeeTable VALUES (1,'Jerome', NULL ) -- tree is as follows:
      INSERT @EmployeeTable VALUES (2,'Joe' ,1) -- 1-Jerome
      INSERT @EmployeeTable VALUES (3,'Paul' ,2) -- /
      INSERT @EmployeeTable VALUES (4,'Jack' ,3) -- 2-Joe 9-Bill
      INSERT @EmployeeTable VALUES (5,'Daniel',3) -- /
      INSERT @EmployeeTable VALUES (6,'David' ,2) -- 3-Paul 6-David 10-Sam
      INSERT @EmployeeTable VALUES (7,'Ian' ,6) -- / /
      INSERT @EmployeeTable VALUES (8,'Helen' ,6) -- 4-Jack 5-Daniel 7-Ian 8-Helen
      INSERT @EmployeeTable VALUES (9,'Bill ' ,1) --
      INSERT @EmployeeTable VALUES (10,'Sam' ,9) --

      DECLARE @employeeId int = 3

      ;WITH StaffTree AS
      (
      SELECT
      c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]
      FROM @EmployeeTable c
      LEFT OUTER JOIN @EmployeeTable cc ON c.managerId=cc.EmployeeId
      WHERE c.EmployeeId=@employeeId OR (@employeeId IS NULL AND c.managerId IS NULL)
      UNION ALL
      SELECT
      s.[EmployeeId], s.[name], s.managerId, t.[Level]+1
      FROM StaffTree t
      INNER JOIN @EmployeeTable s ON t.[EmployeeId]=s.managerId
      WHERE s.managerId=@employeeId OR @employeeId IS NULL OR t.Level>1
      )
      SELECT * FROM StaffTree


      In case you select the employee 3 hierarchy, the result should be:



      EmployeeId | Name    | ManagerId 
      1 | Jerome | NULL
      2 | Joe | 1
      3 | Paul | 2






      sql-server cte hierarchy recursive






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Feb 12 at 15:04









      Lenny32Lenny32

      1184




      1184






















          3 Answers
          3






          active

          oldest

          votes


















          2














          Swapping the columns in the inner join in the recursive part is a way to go about this.



          Join columns changed from t.[EmployeeId]=s.managerId to s.[EmployeeId]=t.managerId



          I deleted some parts that did not seem like they were needed.



          DECLARE @employeeId int = 3

          ;WITH StaffTree AS
          (
          SELECT
          c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]
          FROM @EmployeeTable c
          WHERE c.EmployeeId=@employeeId OR (@employeeId IS NULL AND c.managerId IS NULL)
          UNION ALL
          SELECT
          s.[EmployeeId], s.[name], s.managerId, t.[Level]+1
          FROM StaffTree t
          INNER JOIN @EmployeeTable s ON s.[EmployeeId]=t.managerId
          )
          SELECT EmployeeId,
          name,
          managerId
          FROM StaffTree
          ORDER BY managerId asc;


          Result



          EmployeeId  name    managerId
          1 Jerome NULL
          2 Joe 1
          3 Paul 2





          share|improve this answer

































            0














            It looks like you had a tiny error when copying the example that you linked to -



            c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]


            should be



            c.[EmployeeId], c.[name], c.managerId, 1 AS [Level]


            Once I make that change, your code functions the same way as the example.






            share|improve this answer































              0














              This Link will help you a lot in learning Recursive CTEs with excellent and useful examples : https://www.codeproject.com/Articles/818694/SQL-queries-to-manage-hierarchical-or-parent-child.






              share|improve this answer








              New contributor




              Pantea Tourang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.




















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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                2














                Swapping the columns in the inner join in the recursive part is a way to go about this.



                Join columns changed from t.[EmployeeId]=s.managerId to s.[EmployeeId]=t.managerId



                I deleted some parts that did not seem like they were needed.



                DECLARE @employeeId int = 3

                ;WITH StaffTree AS
                (
                SELECT
                c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]
                FROM @EmployeeTable c
                WHERE c.EmployeeId=@employeeId OR (@employeeId IS NULL AND c.managerId IS NULL)
                UNION ALL
                SELECT
                s.[EmployeeId], s.[name], s.managerId, t.[Level]+1
                FROM StaffTree t
                INNER JOIN @EmployeeTable s ON s.[EmployeeId]=t.managerId
                )
                SELECT EmployeeId,
                name,
                managerId
                FROM StaffTree
                ORDER BY managerId asc;


                Result



                EmployeeId  name    managerId
                1 Jerome NULL
                2 Joe 1
                3 Paul 2





                share|improve this answer






























                  2














                  Swapping the columns in the inner join in the recursive part is a way to go about this.



                  Join columns changed from t.[EmployeeId]=s.managerId to s.[EmployeeId]=t.managerId



                  I deleted some parts that did not seem like they were needed.



                  DECLARE @employeeId int = 3

                  ;WITH StaffTree AS
                  (
                  SELECT
                  c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]
                  FROM @EmployeeTable c
                  WHERE c.EmployeeId=@employeeId OR (@employeeId IS NULL AND c.managerId IS NULL)
                  UNION ALL
                  SELECT
                  s.[EmployeeId], s.[name], s.managerId, t.[Level]+1
                  FROM StaffTree t
                  INNER JOIN @EmployeeTable s ON s.[EmployeeId]=t.managerId
                  )
                  SELECT EmployeeId,
                  name,
                  managerId
                  FROM StaffTree
                  ORDER BY managerId asc;


                  Result



                  EmployeeId  name    managerId
                  1 Jerome NULL
                  2 Joe 1
                  3 Paul 2





                  share|improve this answer




























                    2












                    2








                    2







                    Swapping the columns in the inner join in the recursive part is a way to go about this.



                    Join columns changed from t.[EmployeeId]=s.managerId to s.[EmployeeId]=t.managerId



                    I deleted some parts that did not seem like they were needed.



                    DECLARE @employeeId int = 3

                    ;WITH StaffTree AS
                    (
                    SELECT
                    c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]
                    FROM @EmployeeTable c
                    WHERE c.EmployeeId=@employeeId OR (@employeeId IS NULL AND c.managerId IS NULL)
                    UNION ALL
                    SELECT
                    s.[EmployeeId], s.[name], s.managerId, t.[Level]+1
                    FROM StaffTree t
                    INNER JOIN @EmployeeTable s ON s.[EmployeeId]=t.managerId
                    )
                    SELECT EmployeeId,
                    name,
                    managerId
                    FROM StaffTree
                    ORDER BY managerId asc;


                    Result



                    EmployeeId  name    managerId
                    1 Jerome NULL
                    2 Joe 1
                    3 Paul 2





                    share|improve this answer















                    Swapping the columns in the inner join in the recursive part is a way to go about this.



                    Join columns changed from t.[EmployeeId]=s.managerId to s.[EmployeeId]=t.managerId



                    I deleted some parts that did not seem like they were needed.



                    DECLARE @employeeId int = 3

                    ;WITH StaffTree AS
                    (
                    SELECT
                    c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]
                    FROM @EmployeeTable c
                    WHERE c.EmployeeId=@employeeId OR (@employeeId IS NULL AND c.managerId IS NULL)
                    UNION ALL
                    SELECT
                    s.[EmployeeId], s.[name], s.managerId, t.[Level]+1
                    FROM StaffTree t
                    INNER JOIN @EmployeeTable s ON s.[EmployeeId]=t.managerId
                    )
                    SELECT EmployeeId,
                    name,
                    managerId
                    FROM StaffTree
                    ORDER BY managerId asc;


                    Result



                    EmployeeId  name    managerId
                    1 Jerome NULL
                    2 Joe 1
                    3 Paul 2






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Feb 12 at 16:18









                    jadarnel27

                    5,29811836




                    5,29811836










                    answered Feb 12 at 15:41









                    Randi VertongenRandi Vertongen

                    2,776721




                    2,776721

























                        0














                        It looks like you had a tiny error when copying the example that you linked to -



                        c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]


                        should be



                        c.[EmployeeId], c.[name], c.managerId, 1 AS [Level]


                        Once I make that change, your code functions the same way as the example.






                        share|improve this answer




























                          0














                          It looks like you had a tiny error when copying the example that you linked to -



                          c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]


                          should be



                          c.[EmployeeId], c.[name], c.managerId, 1 AS [Level]


                          Once I make that change, your code functions the same way as the example.






                          share|improve this answer


























                            0












                            0








                            0







                            It looks like you had a tiny error when copying the example that you linked to -



                            c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]


                            should be



                            c.[EmployeeId], c.[name], c.managerId, 1 AS [Level]


                            Once I make that change, your code functions the same way as the example.






                            share|improve this answer













                            It looks like you had a tiny error when copying the example that you linked to -



                            c.[EmployeeId], c.[name], c.managerId, 0 AS [Level]


                            should be



                            c.[EmployeeId], c.[name], c.managerId, 1 AS [Level]


                            Once I make that change, your code functions the same way as the example.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Feb 12 at 15:57









                            Darren GDarren G

                            1




                            1























                                0














                                This Link will help you a lot in learning Recursive CTEs with excellent and useful examples : https://www.codeproject.com/Articles/818694/SQL-queries-to-manage-hierarchical-or-parent-child.






                                share|improve this answer








                                New contributor




                                Pantea Tourang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                Check out our Code of Conduct.

























                                  0














                                  This Link will help you a lot in learning Recursive CTEs with excellent and useful examples : https://www.codeproject.com/Articles/818694/SQL-queries-to-manage-hierarchical-or-parent-child.






                                  share|improve this answer








                                  New contributor




                                  Pantea Tourang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                  Check out our Code of Conduct.























                                    0












                                    0








                                    0







                                    This Link will help you a lot in learning Recursive CTEs with excellent and useful examples : https://www.codeproject.com/Articles/818694/SQL-queries-to-manage-hierarchical-or-parent-child.






                                    share|improve this answer








                                    New contributor




                                    Pantea Tourang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                    Check out our Code of Conduct.










                                    This Link will help you a lot in learning Recursive CTEs with excellent and useful examples : https://www.codeproject.com/Articles/818694/SQL-queries-to-manage-hierarchical-or-parent-child.







                                    share|improve this answer








                                    New contributor




                                    Pantea Tourang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                    Check out our Code of Conduct.









                                    share|improve this answer



                                    share|improve this answer






                                    New contributor




                                    Pantea Tourang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                    Check out our Code of Conduct.









                                    answered Feb 13 at 11:27









                                    Pantea TourangPantea Tourang

                                    11




                                    11




                                    New contributor




                                    Pantea Tourang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                    Check out our Code of Conduct.





                                    New contributor





                                    Pantea Tourang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                    Check out our Code of Conduct.






                                    Pantea Tourang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                    Check out our Code of Conduct.






























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