SQL Column Value Within string
I Have a string below
100Pipers22WoodfieldRoadBlackpoolFY16AX
I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.
I cant seem to get a match.
sql function matching
add a comment |
I Have a string below
100Pipers22WoodfieldRoadBlackpoolFY16AX
I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.
I cant seem to get a match.
sql function matching
2
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 '18 at 12:08
add a comment |
I Have a string below
100Pipers22WoodfieldRoadBlackpoolFY16AX
I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.
I cant seem to get a match.
sql function matching
I Have a string below
100Pipers22WoodfieldRoadBlackpoolFY16AX
I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.
I cant seem to get a match.
sql function matching
sql function matching
asked Nov 20 '18 at 12:08
Sam ParkySam Parky
196
196
2
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 '18 at 12:08
add a comment |
2
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 '18 at 12:08
2
2
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 '18 at 12:08
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 '18 at 12:08
add a comment |
2 Answers
2
active
oldest
votes
If I understand correctly, you can use like
. In standard SQL, this would look like:
where string like '%' || postcode
The ||
is the string concatenation operator. Some databases have their own operators or functions for this functionality.
Might want to consider case too - e.g.UPPER
orLOWER
on both your string and search-term (in this casepostcode
)
– doublesidedstickytape
Nov 20 '18 at 12:15
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 '18 at 13:25
add a comment |
Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'
Select Count(*) From tbl_Address Where Zip = right(@vString,6)
If the select statement returns a value greater than zero, you have a match.
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If I understand correctly, you can use like
. In standard SQL, this would look like:
where string like '%' || postcode
The ||
is the string concatenation operator. Some databases have their own operators or functions for this functionality.
Might want to consider case too - e.g.UPPER
orLOWER
on both your string and search-term (in this casepostcode
)
– doublesidedstickytape
Nov 20 '18 at 12:15
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 '18 at 13:25
add a comment |
If I understand correctly, you can use like
. In standard SQL, this would look like:
where string like '%' || postcode
The ||
is the string concatenation operator. Some databases have their own operators or functions for this functionality.
Might want to consider case too - e.g.UPPER
orLOWER
on both your string and search-term (in this casepostcode
)
– doublesidedstickytape
Nov 20 '18 at 12:15
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 '18 at 13:25
add a comment |
If I understand correctly, you can use like
. In standard SQL, this would look like:
where string like '%' || postcode
The ||
is the string concatenation operator. Some databases have their own operators or functions for this functionality.
If I understand correctly, you can use like
. In standard SQL, this would look like:
where string like '%' || postcode
The ||
is the string concatenation operator. Some databases have their own operators or functions for this functionality.
answered Nov 20 '18 at 12:09
Gordon LinoffGordon Linoff
776k35306409
776k35306409
Might want to consider case too - e.g.UPPER
orLOWER
on both your string and search-term (in this casepostcode
)
– doublesidedstickytape
Nov 20 '18 at 12:15
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 '18 at 13:25
add a comment |
Might want to consider case too - e.g.UPPER
orLOWER
on both your string and search-term (in this casepostcode
)
– doublesidedstickytape
Nov 20 '18 at 12:15
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 '18 at 13:25
Might want to consider case too - e.g.
UPPER
or LOWER
on both your string and search-term (in this case postcode
)– doublesidedstickytape
Nov 20 '18 at 12:15
Might want to consider case too - e.g.
UPPER
or LOWER
on both your string and search-term (in this case postcode
)– doublesidedstickytape
Nov 20 '18 at 12:15
1
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 '18 at 13:25
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 '18 at 13:25
add a comment |
Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'
Select Count(*) From tbl_Address Where Zip = right(@vString,6)
If the select statement returns a value greater than zero, you have a match.
add a comment |
Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'
Select Count(*) From tbl_Address Where Zip = right(@vString,6)
If the select statement returns a value greater than zero, you have a match.
add a comment |
Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'
Select Count(*) From tbl_Address Where Zip = right(@vString,6)
If the select statement returns a value greater than zero, you have a match.
Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'
Select Count(*) From tbl_Address Where Zip = right(@vString,6)
If the select statement returns a value greater than zero, you have a match.
answered Nov 20 '18 at 15:35
level3looperlevel3looper
59126
59126
add a comment |
add a comment |
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2
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 '18 at 12:08