SQL Column Value Within string












0















I Have a string below



100Pipers22WoodfieldRoadBlackpoolFY16AX


I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.



I cant seem to get a match.










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  • 2





    Tag your question with the database you are using. Also, provide the code you have.

    – Gordon Linoff
    Nov 20 '18 at 12:08
















0















I Have a string below



100Pipers22WoodfieldRoadBlackpoolFY16AX


I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.



I cant seem to get a match.










share|improve this question


















  • 2





    Tag your question with the database you are using. Also, provide the code you have.

    – Gordon Linoff
    Nov 20 '18 at 12:08














0












0








0








I Have a string below



100Pipers22WoodfieldRoadBlackpoolFY16AX


I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.



I cant seem to get a match.










share|improve this question














I Have a string below



100Pipers22WoodfieldRoadBlackpoolFY16AX


I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.



I cant seem to get a match.







sql function matching






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share|improve this question










asked Nov 20 '18 at 12:08









Sam ParkySam Parky

196




196








  • 2





    Tag your question with the database you are using. Also, provide the code you have.

    – Gordon Linoff
    Nov 20 '18 at 12:08














  • 2





    Tag your question with the database you are using. Also, provide the code you have.

    – Gordon Linoff
    Nov 20 '18 at 12:08








2




2





Tag your question with the database you are using. Also, provide the code you have.

– Gordon Linoff
Nov 20 '18 at 12:08





Tag your question with the database you are using. Also, provide the code you have.

– Gordon Linoff
Nov 20 '18 at 12:08












2 Answers
2






active

oldest

votes


















1














If I understand correctly, you can use like. In standard SQL, this would look like:



where string like '%' || postcode


The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.






share|improve this answer
























  • Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)

    – doublesidedstickytape
    Nov 20 '18 at 12:15






  • 1





    @doublesidedstickytape, better to use a case insensitive collation.

    – jarlh
    Nov 20 '18 at 13:25





















0














Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'

Select Count(*) From tbl_Address Where Zip = right(@vString,6)


If the select statement returns a value greater than zero, you have a match.






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    2 Answers
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    2 Answers
    2






    active

    oldest

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    active

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    active

    oldest

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    1














    If I understand correctly, you can use like. In standard SQL, this would look like:



    where string like '%' || postcode


    The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.






    share|improve this answer
























    • Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)

      – doublesidedstickytape
      Nov 20 '18 at 12:15






    • 1





      @doublesidedstickytape, better to use a case insensitive collation.

      – jarlh
      Nov 20 '18 at 13:25


















    1














    If I understand correctly, you can use like. In standard SQL, this would look like:



    where string like '%' || postcode


    The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.






    share|improve this answer
























    • Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)

      – doublesidedstickytape
      Nov 20 '18 at 12:15






    • 1





      @doublesidedstickytape, better to use a case insensitive collation.

      – jarlh
      Nov 20 '18 at 13:25
















    1












    1








    1







    If I understand correctly, you can use like. In standard SQL, this would look like:



    where string like '%' || postcode


    The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.






    share|improve this answer













    If I understand correctly, you can use like. In standard SQL, this would look like:



    where string like '%' || postcode


    The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 20 '18 at 12:09









    Gordon LinoffGordon Linoff

    776k35306409




    776k35306409













    • Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)

      – doublesidedstickytape
      Nov 20 '18 at 12:15






    • 1





      @doublesidedstickytape, better to use a case insensitive collation.

      – jarlh
      Nov 20 '18 at 13:25





















    • Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)

      – doublesidedstickytape
      Nov 20 '18 at 12:15






    • 1





      @doublesidedstickytape, better to use a case insensitive collation.

      – jarlh
      Nov 20 '18 at 13:25



















    Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)

    – doublesidedstickytape
    Nov 20 '18 at 12:15





    Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)

    – doublesidedstickytape
    Nov 20 '18 at 12:15




    1




    1





    @doublesidedstickytape, better to use a case insensitive collation.

    – jarlh
    Nov 20 '18 at 13:25







    @doublesidedstickytape, better to use a case insensitive collation.

    – jarlh
    Nov 20 '18 at 13:25















    0














    Declare @vString nvarchar(50)
    Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'

    Select Count(*) From tbl_Address Where Zip = right(@vString,6)


    If the select statement returns a value greater than zero, you have a match.






    share|improve this answer




























      0














      Declare @vString nvarchar(50)
      Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'

      Select Count(*) From tbl_Address Where Zip = right(@vString,6)


      If the select statement returns a value greater than zero, you have a match.






      share|improve this answer


























        0












        0








        0







        Declare @vString nvarchar(50)
        Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'

        Select Count(*) From tbl_Address Where Zip = right(@vString,6)


        If the select statement returns a value greater than zero, you have a match.






        share|improve this answer













        Declare @vString nvarchar(50)
        Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'

        Select Count(*) From tbl_Address Where Zip = right(@vString,6)


        If the select statement returns a value greater than zero, you have a match.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 20 '18 at 15:35









        level3looperlevel3looper

        59126




        59126






























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