Prove $sum a_n b_n$ diverges if $a_n$ diverges, $a_n>0$, and $liminf_n b_n >0$












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I'm having trouble starting this proof. From the initial hypothesis, we know for some $n>N$, $b_n>0$. Since $a_n>0$ and $a_n$ diverges, for some $n>N'$, $a_ngeq varepsilon$. Then $a_n b_n>0$, so if $sum a_n b_n$ is a series of positive numbers. I'm not sure how to show it diverges however, so any help would be appreciated!










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  • $begingroup$
    @qbert isn't the answer below correct regardless?
    $endgroup$
    – clark
    Dec 3 '18 at 3:03
















1












$begingroup$


I'm having trouble starting this proof. From the initial hypothesis, we know for some $n>N$, $b_n>0$. Since $a_n>0$ and $a_n$ diverges, for some $n>N'$, $a_ngeq varepsilon$. Then $a_n b_n>0$, so if $sum a_n b_n$ is a series of positive numbers. I'm not sure how to show it diverges however, so any help would be appreciated!










share|cite|improve this question









$endgroup$












  • $begingroup$
    @qbert isn't the answer below correct regardless?
    $endgroup$
    – clark
    Dec 3 '18 at 3:03














1












1








1





$begingroup$


I'm having trouble starting this proof. From the initial hypothesis, we know for some $n>N$, $b_n>0$. Since $a_n>0$ and $a_n$ diverges, for some $n>N'$, $a_ngeq varepsilon$. Then $a_n b_n>0$, so if $sum a_n b_n$ is a series of positive numbers. I'm not sure how to show it diverges however, so any help would be appreciated!










share|cite|improve this question









$endgroup$




I'm having trouble starting this proof. From the initial hypothesis, we know for some $n>N$, $b_n>0$. Since $a_n>0$ and $a_n$ diverges, for some $n>N'$, $a_ngeq varepsilon$. Then $a_n b_n>0$, so if $sum a_n b_n$ is a series of positive numbers. I'm not sure how to show it diverges however, so any help would be appreciated!







real-analysis sequences-and-series convergence






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asked Dec 3 '18 at 2:51









t.perezt.perez

619




619












  • $begingroup$
    @qbert isn't the answer below correct regardless?
    $endgroup$
    – clark
    Dec 3 '18 at 3:03


















  • $begingroup$
    @qbert isn't the answer below correct regardless?
    $endgroup$
    – clark
    Dec 3 '18 at 3:03
















$begingroup$
@qbert isn't the answer below correct regardless?
$endgroup$
– clark
Dec 3 '18 at 3:03




$begingroup$
@qbert isn't the answer below correct regardless?
$endgroup$
– clark
Dec 3 '18 at 3:03










1 Answer
1






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$begingroup$

Let
$$
liminf_{nto infty}b_n=2delta>0
$$

Then, for large enough $N$, $b_ngeq delta$ for all $ngeq N$. Then,
$$
sum_{n=N}^infty b_na_ngeq deltasum_{n=N}^infty a_n=+infty
$$

since $lim_{nto infty}a_nne 0$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thank you! My only question is, where does the 2 go in the $2delta$ term?
    $endgroup$
    – t.perez
    Dec 5 '18 at 2:12










  • $begingroup$
    okay, that makes sense now. thank you!
    $endgroup$
    – t.perez
    Dec 5 '18 at 2:24











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4












$begingroup$

Let
$$
liminf_{nto infty}b_n=2delta>0
$$

Then, for large enough $N$, $b_ngeq delta$ for all $ngeq N$. Then,
$$
sum_{n=N}^infty b_na_ngeq deltasum_{n=N}^infty a_n=+infty
$$

since $lim_{nto infty}a_nne 0$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thank you! My only question is, where does the 2 go in the $2delta$ term?
    $endgroup$
    – t.perez
    Dec 5 '18 at 2:12










  • $begingroup$
    okay, that makes sense now. thank you!
    $endgroup$
    – t.perez
    Dec 5 '18 at 2:24
















4












$begingroup$

Let
$$
liminf_{nto infty}b_n=2delta>0
$$

Then, for large enough $N$, $b_ngeq delta$ for all $ngeq N$. Then,
$$
sum_{n=N}^infty b_na_ngeq deltasum_{n=N}^infty a_n=+infty
$$

since $lim_{nto infty}a_nne 0$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thank you! My only question is, where does the 2 go in the $2delta$ term?
    $endgroup$
    – t.perez
    Dec 5 '18 at 2:12










  • $begingroup$
    okay, that makes sense now. thank you!
    $endgroup$
    – t.perez
    Dec 5 '18 at 2:24














4












4








4





$begingroup$

Let
$$
liminf_{nto infty}b_n=2delta>0
$$

Then, for large enough $N$, $b_ngeq delta$ for all $ngeq N$. Then,
$$
sum_{n=N}^infty b_na_ngeq deltasum_{n=N}^infty a_n=+infty
$$

since $lim_{nto infty}a_nne 0$.






share|cite|improve this answer











$endgroup$



Let
$$
liminf_{nto infty}b_n=2delta>0
$$

Then, for large enough $N$, $b_ngeq delta$ for all $ngeq N$. Then,
$$
sum_{n=N}^infty b_na_ngeq deltasum_{n=N}^infty a_n=+infty
$$

since $lim_{nto infty}a_nne 0$.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Dec 3 '18 at 4:08

























answered Dec 3 '18 at 3:00









qbertqbert

22.1k32561




22.1k32561












  • $begingroup$
    Thank you! My only question is, where does the 2 go in the $2delta$ term?
    $endgroup$
    – t.perez
    Dec 5 '18 at 2:12










  • $begingroup$
    okay, that makes sense now. thank you!
    $endgroup$
    – t.perez
    Dec 5 '18 at 2:24


















  • $begingroup$
    Thank you! My only question is, where does the 2 go in the $2delta$ term?
    $endgroup$
    – t.perez
    Dec 5 '18 at 2:12










  • $begingroup$
    okay, that makes sense now. thank you!
    $endgroup$
    – t.perez
    Dec 5 '18 at 2:24
















$begingroup$
Thank you! My only question is, where does the 2 go in the $2delta$ term?
$endgroup$
– t.perez
Dec 5 '18 at 2:12




$begingroup$
Thank you! My only question is, where does the 2 go in the $2delta$ term?
$endgroup$
– t.perez
Dec 5 '18 at 2:12












$begingroup$
okay, that makes sense now. thank you!
$endgroup$
– t.perez
Dec 5 '18 at 2:24




$begingroup$
okay, that makes sense now. thank you!
$endgroup$
– t.perez
Dec 5 '18 at 2:24


















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