Prove $sum a_n b_n$ diverges if $a_n$ diverges, $a_n>0$, and $liminf_n b_n >0$
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I'm having trouble starting this proof. From the initial hypothesis, we know for some $n>N$, $b_n>0$. Since $a_n>0$ and $a_n$ diverges, for some $n>N'$, $a_ngeq varepsilon$. Then $a_n b_n>0$, so if $sum a_n b_n$ is a series of positive numbers. I'm not sure how to show it diverges however, so any help would be appreciated!
real-analysis sequences-and-series convergence
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add a comment |
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I'm having trouble starting this proof. From the initial hypothesis, we know for some $n>N$, $b_n>0$. Since $a_n>0$ and $a_n$ diverges, for some $n>N'$, $a_ngeq varepsilon$. Then $a_n b_n>0$, so if $sum a_n b_n$ is a series of positive numbers. I'm not sure how to show it diverges however, so any help would be appreciated!
real-analysis sequences-and-series convergence
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@qbert isn't the answer below correct regardless?
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– clark
Dec 3 '18 at 3:03
add a comment |
$begingroup$
I'm having trouble starting this proof. From the initial hypothesis, we know for some $n>N$, $b_n>0$. Since $a_n>0$ and $a_n$ diverges, for some $n>N'$, $a_ngeq varepsilon$. Then $a_n b_n>0$, so if $sum a_n b_n$ is a series of positive numbers. I'm not sure how to show it diverges however, so any help would be appreciated!
real-analysis sequences-and-series convergence
$endgroup$
I'm having trouble starting this proof. From the initial hypothesis, we know for some $n>N$, $b_n>0$. Since $a_n>0$ and $a_n$ diverges, for some $n>N'$, $a_ngeq varepsilon$. Then $a_n b_n>0$, so if $sum a_n b_n$ is a series of positive numbers. I'm not sure how to show it diverges however, so any help would be appreciated!
real-analysis sequences-and-series convergence
real-analysis sequences-and-series convergence
asked Dec 3 '18 at 2:51
t.perezt.perez
619
619
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@qbert isn't the answer below correct regardless?
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– clark
Dec 3 '18 at 3:03
add a comment |
$begingroup$
@qbert isn't the answer below correct regardless?
$endgroup$
– clark
Dec 3 '18 at 3:03
$begingroup$
@qbert isn't the answer below correct regardless?
$endgroup$
– clark
Dec 3 '18 at 3:03
$begingroup$
@qbert isn't the answer below correct regardless?
$endgroup$
– clark
Dec 3 '18 at 3:03
add a comment |
1 Answer
1
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oldest
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Let
$$
liminf_{nto infty}b_n=2delta>0
$$
Then, for large enough $N$, $b_ngeq delta$ for all $ngeq N$. Then,
$$
sum_{n=N}^infty b_na_ngeq deltasum_{n=N}^infty a_n=+infty
$$
since $lim_{nto infty}a_nne 0$.
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$begingroup$
Thank you! My only question is, where does the 2 go in the $2delta$ term?
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– t.perez
Dec 5 '18 at 2:12
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okay, that makes sense now. thank you!
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– t.perez
Dec 5 '18 at 2:24
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Let
$$
liminf_{nto infty}b_n=2delta>0
$$
Then, for large enough $N$, $b_ngeq delta$ for all $ngeq N$. Then,
$$
sum_{n=N}^infty b_na_ngeq deltasum_{n=N}^infty a_n=+infty
$$
since $lim_{nto infty}a_nne 0$.
$endgroup$
$begingroup$
Thank you! My only question is, where does the 2 go in the $2delta$ term?
$endgroup$
– t.perez
Dec 5 '18 at 2:12
$begingroup$
okay, that makes sense now. thank you!
$endgroup$
– t.perez
Dec 5 '18 at 2:24
add a comment |
$begingroup$
Let
$$
liminf_{nto infty}b_n=2delta>0
$$
Then, for large enough $N$, $b_ngeq delta$ for all $ngeq N$. Then,
$$
sum_{n=N}^infty b_na_ngeq deltasum_{n=N}^infty a_n=+infty
$$
since $lim_{nto infty}a_nne 0$.
$endgroup$
$begingroup$
Thank you! My only question is, where does the 2 go in the $2delta$ term?
$endgroup$
– t.perez
Dec 5 '18 at 2:12
$begingroup$
okay, that makes sense now. thank you!
$endgroup$
– t.perez
Dec 5 '18 at 2:24
add a comment |
$begingroup$
Let
$$
liminf_{nto infty}b_n=2delta>0
$$
Then, for large enough $N$, $b_ngeq delta$ for all $ngeq N$. Then,
$$
sum_{n=N}^infty b_na_ngeq deltasum_{n=N}^infty a_n=+infty
$$
since $lim_{nto infty}a_nne 0$.
$endgroup$
Let
$$
liminf_{nto infty}b_n=2delta>0
$$
Then, for large enough $N$, $b_ngeq delta$ for all $ngeq N$. Then,
$$
sum_{n=N}^infty b_na_ngeq deltasum_{n=N}^infty a_n=+infty
$$
since $lim_{nto infty}a_nne 0$.
edited Dec 3 '18 at 4:08
answered Dec 3 '18 at 3:00
qbertqbert
22.1k32561
22.1k32561
$begingroup$
Thank you! My only question is, where does the 2 go in the $2delta$ term?
$endgroup$
– t.perez
Dec 5 '18 at 2:12
$begingroup$
okay, that makes sense now. thank you!
$endgroup$
– t.perez
Dec 5 '18 at 2:24
add a comment |
$begingroup$
Thank you! My only question is, where does the 2 go in the $2delta$ term?
$endgroup$
– t.perez
Dec 5 '18 at 2:12
$begingroup$
okay, that makes sense now. thank you!
$endgroup$
– t.perez
Dec 5 '18 at 2:24
$begingroup$
Thank you! My only question is, where does the 2 go in the $2delta$ term?
$endgroup$
– t.perez
Dec 5 '18 at 2:12
$begingroup$
Thank you! My only question is, where does the 2 go in the $2delta$ term?
$endgroup$
– t.perez
Dec 5 '18 at 2:12
$begingroup$
okay, that makes sense now. thank you!
$endgroup$
– t.perez
Dec 5 '18 at 2:24
$begingroup$
okay, that makes sense now. thank you!
$endgroup$
– t.perez
Dec 5 '18 at 2:24
add a comment |
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$begingroup$
@qbert isn't the answer below correct regardless?
$endgroup$
– clark
Dec 3 '18 at 3:03