Bell number generating function











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I'm finding in various questions/textbooks that for Bell number $B_n$, defined as $$B_n = sum_{kgeq 0}left( begin{array}{rl}n \ k end{array} right) B_k$$ the exponential generating function is known to be $$B(t) = e^{e^t - 1}$$



I can check that this holds by, i.e., expanding it to Taylor series, but how is this expression derived?










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  • See page 22 in math.upenn.edu/~wilf/gfologyLinked2.pdf
    – Robert Z
    Nov 13 at 13:09










  • @RobertZ very useful reference, thanks! Found some more questions answered there :)
    – Nutle
    Nov 13 at 13:26

















up vote
1
down vote

favorite












I'm finding in various questions/textbooks that for Bell number $B_n$, defined as $$B_n = sum_{kgeq 0}left( begin{array}{rl}n \ k end{array} right) B_k$$ the exponential generating function is known to be $$B(t) = e^{e^t - 1}$$



I can check that this holds by, i.e., expanding it to Taylor series, but how is this expression derived?










share|cite|improve this question






















  • See page 22 in math.upenn.edu/~wilf/gfologyLinked2.pdf
    – Robert Z
    Nov 13 at 13:09










  • @RobertZ very useful reference, thanks! Found some more questions answered there :)
    – Nutle
    Nov 13 at 13:26















up vote
1
down vote

favorite









up vote
1
down vote

favorite











I'm finding in various questions/textbooks that for Bell number $B_n$, defined as $$B_n = sum_{kgeq 0}left( begin{array}{rl}n \ k end{array} right) B_k$$ the exponential generating function is known to be $$B(t) = e^{e^t - 1}$$



I can check that this holds by, i.e., expanding it to Taylor series, but how is this expression derived?










share|cite|improve this question













I'm finding in various questions/textbooks that for Bell number $B_n$, defined as $$B_n = sum_{kgeq 0}left( begin{array}{rl}n \ k end{array} right) B_k$$ the exponential generating function is known to be $$B(t) = e^{e^t - 1}$$



I can check that this holds by, i.e., expanding it to Taylor series, but how is this expression derived?







combinatorics






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asked Nov 13 at 13:05









Nutle

16010




16010












  • See page 22 in math.upenn.edu/~wilf/gfologyLinked2.pdf
    – Robert Z
    Nov 13 at 13:09










  • @RobertZ very useful reference, thanks! Found some more questions answered there :)
    – Nutle
    Nov 13 at 13:26




















  • See page 22 in math.upenn.edu/~wilf/gfologyLinked2.pdf
    – Robert Z
    Nov 13 at 13:09










  • @RobertZ very useful reference, thanks! Found some more questions answered there :)
    – Nutle
    Nov 13 at 13:26


















See page 22 in math.upenn.edu/~wilf/gfologyLinked2.pdf
– Robert Z
Nov 13 at 13:09




See page 22 in math.upenn.edu/~wilf/gfologyLinked2.pdf
– Robert Z
Nov 13 at 13:09












@RobertZ very useful reference, thanks! Found some more questions answered there :)
– Nutle
Nov 13 at 13:26






@RobertZ very useful reference, thanks! Found some more questions answered there :)
– Nutle
Nov 13 at 13:26

















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