IndexError: tuple index out of range postgresql
I have been using the pgcrypto extension module's digest function to encode several values. I recently discovered that some of the URL values that I'm trying to encode contain '%,' which throw an
IndexError: tuple index out of range.
I have spent hours today trying to fix this issue, but so far I have not corrected this error in my code. How do I encode a URL that contains special characters?
This works in pgAdmin4, but not in my python script:
encode(digest('domainname.com/pub-cgi/retrieve.pl?doc=file%2F1999&zone_19=300%2A%20','sha256')
How do I encode a URL that contains special characters?
python python-3.x postgresql pgcrypto
add a comment |
I have been using the pgcrypto extension module's digest function to encode several values. I recently discovered that some of the URL values that I'm trying to encode contain '%,' which throw an
IndexError: tuple index out of range.
I have spent hours today trying to fix this issue, but so far I have not corrected this error in my code. How do I encode a URL that contains special characters?
This works in pgAdmin4, but not in my python script:
encode(digest('domainname.com/pub-cgi/retrieve.pl?doc=file%2F1999&zone_19=300%2A%20','sha256')
How do I encode a URL that contains special characters?
python python-3.x postgresql pgcrypto
1
Please post your code exactly how it is in your program. The snippet you have provided contains a syntax error (extra closing quote) and won't run. You will also get better answers if you post a complete traceback.
– DBrowne
Nov 21 '18 at 1:12
That extra closing quote was added by mistake when I sanitized the snippet for posting.
– Life is complex
Nov 21 '18 at 1:18
The only URLs that throw this error contain a %. If I remove this encoding piece from my code everything loads correctly including the other elements, which I encoded.
– Life is complex
Nov 21 '18 at 1:24
add a comment |
I have been using the pgcrypto extension module's digest function to encode several values. I recently discovered that some of the URL values that I'm trying to encode contain '%,' which throw an
IndexError: tuple index out of range.
I have spent hours today trying to fix this issue, but so far I have not corrected this error in my code. How do I encode a URL that contains special characters?
This works in pgAdmin4, but not in my python script:
encode(digest('domainname.com/pub-cgi/retrieve.pl?doc=file%2F1999&zone_19=300%2A%20','sha256')
How do I encode a URL that contains special characters?
python python-3.x postgresql pgcrypto
I have been using the pgcrypto extension module's digest function to encode several values. I recently discovered that some of the URL values that I'm trying to encode contain '%,' which throw an
IndexError: tuple index out of range.
I have spent hours today trying to fix this issue, but so far I have not corrected this error in my code. How do I encode a URL that contains special characters?
This works in pgAdmin4, but not in my python script:
encode(digest('domainname.com/pub-cgi/retrieve.pl?doc=file%2F1999&zone_19=300%2A%20','sha256')
How do I encode a URL that contains special characters?
python python-3.x postgresql pgcrypto
python python-3.x postgresql pgcrypto
edited Nov 21 '18 at 1:14
Life is complex
asked Nov 21 '18 at 0:42
Life is complexLife is complex
452314
452314
1
Please post your code exactly how it is in your program. The snippet you have provided contains a syntax error (extra closing quote) and won't run. You will also get better answers if you post a complete traceback.
– DBrowne
Nov 21 '18 at 1:12
That extra closing quote was added by mistake when I sanitized the snippet for posting.
– Life is complex
Nov 21 '18 at 1:18
The only URLs that throw this error contain a %. If I remove this encoding piece from my code everything loads correctly including the other elements, which I encoded.
– Life is complex
Nov 21 '18 at 1:24
add a comment |
1
Please post your code exactly how it is in your program. The snippet you have provided contains a syntax error (extra closing quote) and won't run. You will also get better answers if you post a complete traceback.
– DBrowne
Nov 21 '18 at 1:12
That extra closing quote was added by mistake when I sanitized the snippet for posting.
– Life is complex
Nov 21 '18 at 1:18
The only URLs that throw this error contain a %. If I remove this encoding piece from my code everything loads correctly including the other elements, which I encoded.
– Life is complex
Nov 21 '18 at 1:24
1
1
Please post your code exactly how it is in your program. The snippet you have provided contains a syntax error (extra closing quote) and won't run. You will also get better answers if you post a complete traceback.
– DBrowne
Nov 21 '18 at 1:12
Please post your code exactly how it is in your program. The snippet you have provided contains a syntax error (extra closing quote) and won't run. You will also get better answers if you post a complete traceback.
– DBrowne
Nov 21 '18 at 1:12
That extra closing quote was added by mistake when I sanitized the snippet for posting.
– Life is complex
Nov 21 '18 at 1:18
That extra closing quote was added by mistake when I sanitized the snippet for posting.
– Life is complex
Nov 21 '18 at 1:18
The only URLs that throw this error contain a %. If I remove this encoding piece from my code everything loads correctly including the other elements, which I encoded.
– Life is complex
Nov 21 '18 at 1:24
The only URLs that throw this error contain a %. If I remove this encoding piece from my code everything loads correctly including the other elements, which I encoded.
– Life is complex
Nov 21 '18 at 1:24
add a comment |
1 Answer
1
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After doing some more research on Stack Overflow, I found a solution that was posted years ago.
Decode escaped characters in URL
This is the code that I used to solve my encoding problem:
# This section of code reformats a href with URL encoding
def unquote(url):
return re.compile('%([0-9a-fA-F]{2})',re.M).sub(lambda m: chr(int(m.group(1),16)), url)
# URL with encoding - https://www.somedomainname.com/pubs/retrieve.pl?doc=some%2Ddocument%2Dname.pdf
print (unquote('https://www.somedomainname.com/pubs/retrieve.pl?doc=some%2Ddocument%2Dname.pdf'))
# Output - https://www.somedomainname.com/pubs/retrieve.pl?doc=some-document-name.pdf
Now that I have this URL reformatted, I can use the pgcrypto extension module's digest function to encode with a SHA-256 hash.
encode(digest('https://www.somedomainname.com/pubs/retrieve.pl?doc=some-document-name.pdf','sha256')
SPECIAL NOTE: I remove the href protocol from the URLs prior to hashing them, because it prevents duplicates, which is a concern of mine.
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
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oldest
votes
active
oldest
votes
After doing some more research on Stack Overflow, I found a solution that was posted years ago.
Decode escaped characters in URL
This is the code that I used to solve my encoding problem:
# This section of code reformats a href with URL encoding
def unquote(url):
return re.compile('%([0-9a-fA-F]{2})',re.M).sub(lambda m: chr(int(m.group(1),16)), url)
# URL with encoding - https://www.somedomainname.com/pubs/retrieve.pl?doc=some%2Ddocument%2Dname.pdf
print (unquote('https://www.somedomainname.com/pubs/retrieve.pl?doc=some%2Ddocument%2Dname.pdf'))
# Output - https://www.somedomainname.com/pubs/retrieve.pl?doc=some-document-name.pdf
Now that I have this URL reformatted, I can use the pgcrypto extension module's digest function to encode with a SHA-256 hash.
encode(digest('https://www.somedomainname.com/pubs/retrieve.pl?doc=some-document-name.pdf','sha256')
SPECIAL NOTE: I remove the href protocol from the URLs prior to hashing them, because it prevents duplicates, which is a concern of mine.
add a comment |
After doing some more research on Stack Overflow, I found a solution that was posted years ago.
Decode escaped characters in URL
This is the code that I used to solve my encoding problem:
# This section of code reformats a href with URL encoding
def unquote(url):
return re.compile('%([0-9a-fA-F]{2})',re.M).sub(lambda m: chr(int(m.group(1),16)), url)
# URL with encoding - https://www.somedomainname.com/pubs/retrieve.pl?doc=some%2Ddocument%2Dname.pdf
print (unquote('https://www.somedomainname.com/pubs/retrieve.pl?doc=some%2Ddocument%2Dname.pdf'))
# Output - https://www.somedomainname.com/pubs/retrieve.pl?doc=some-document-name.pdf
Now that I have this URL reformatted, I can use the pgcrypto extension module's digest function to encode with a SHA-256 hash.
encode(digest('https://www.somedomainname.com/pubs/retrieve.pl?doc=some-document-name.pdf','sha256')
SPECIAL NOTE: I remove the href protocol from the URLs prior to hashing them, because it prevents duplicates, which is a concern of mine.
add a comment |
After doing some more research on Stack Overflow, I found a solution that was posted years ago.
Decode escaped characters in URL
This is the code that I used to solve my encoding problem:
# This section of code reformats a href with URL encoding
def unquote(url):
return re.compile('%([0-9a-fA-F]{2})',re.M).sub(lambda m: chr(int(m.group(1),16)), url)
# URL with encoding - https://www.somedomainname.com/pubs/retrieve.pl?doc=some%2Ddocument%2Dname.pdf
print (unquote('https://www.somedomainname.com/pubs/retrieve.pl?doc=some%2Ddocument%2Dname.pdf'))
# Output - https://www.somedomainname.com/pubs/retrieve.pl?doc=some-document-name.pdf
Now that I have this URL reformatted, I can use the pgcrypto extension module's digest function to encode with a SHA-256 hash.
encode(digest('https://www.somedomainname.com/pubs/retrieve.pl?doc=some-document-name.pdf','sha256')
SPECIAL NOTE: I remove the href protocol from the URLs prior to hashing them, because it prevents duplicates, which is a concern of mine.
After doing some more research on Stack Overflow, I found a solution that was posted years ago.
Decode escaped characters in URL
This is the code that I used to solve my encoding problem:
# This section of code reformats a href with URL encoding
def unquote(url):
return re.compile('%([0-9a-fA-F]{2})',re.M).sub(lambda m: chr(int(m.group(1),16)), url)
# URL with encoding - https://www.somedomainname.com/pubs/retrieve.pl?doc=some%2Ddocument%2Dname.pdf
print (unquote('https://www.somedomainname.com/pubs/retrieve.pl?doc=some%2Ddocument%2Dname.pdf'))
# Output - https://www.somedomainname.com/pubs/retrieve.pl?doc=some-document-name.pdf
Now that I have this URL reformatted, I can use the pgcrypto extension module's digest function to encode with a SHA-256 hash.
encode(digest('https://www.somedomainname.com/pubs/retrieve.pl?doc=some-document-name.pdf','sha256')
SPECIAL NOTE: I remove the href protocol from the URLs prior to hashing them, because it prevents duplicates, which is a concern of mine.
answered Nov 21 '18 at 13:32
Life is complexLife is complex
452314
452314
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1
Please post your code exactly how it is in your program. The snippet you have provided contains a syntax error (extra closing quote) and won't run. You will also get better answers if you post a complete traceback.
– DBrowne
Nov 21 '18 at 1:12
That extra closing quote was added by mistake when I sanitized the snippet for posting.
– Life is complex
Nov 21 '18 at 1:18
The only URLs that throw this error contain a %. If I remove this encoding piece from my code everything loads correctly including the other elements, which I encoded.
– Life is complex
Nov 21 '18 at 1:24