Topological Properties closed sets











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I'm slightly confused with the idea of 'topological properties'
Is closed-ness of a subset of a metric space X a topological property?
I think it is because if a subset is closed under 1 metric then it should be closed under another?










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    up vote
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    down vote

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    I'm slightly confused with the idea of 'topological properties'
    Is closed-ness of a subset of a metric space X a topological property?
    I think it is because if a subset is closed under 1 metric then it should be closed under another?










    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I'm slightly confused with the idea of 'topological properties'
      Is closed-ness of a subset of a metric space X a topological property?
      I think it is because if a subset is closed under 1 metric then it should be closed under another?










      share|cite|improve this question













      I'm slightly confused with the idea of 'topological properties'
      Is closed-ness of a subset of a metric space X a topological property?
      I think it is because if a subset is closed under 1 metric then it should be closed under another?







      general-topology metric-spaces






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      asked Nov 15 at 12:13









      MathematicianP

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      3315






















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          You are right, but for the wrong reason. Being closed is a topological property because it depends only upon the topology induced by the metric, not by the metric itself. For instance, being bounded is not a topological property, because a set may be bounded with respect to a metric and unbounded with respect to another equivalent metric.



          On the other hand, it is false that if a set is closed with respect to a metric then it will automatically be closed with respect to any other metric. For instance, in $mathbb R$, $[0,1)$ is closed with respect to the discrete metric, but not with respect to the usual one.






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          • 1




            but why does it depend only on the topology induced by the metric?
            – MathematicianP
            Nov 15 at 12:24










          • Because being closed means that its complement is open and the set of open subsets is the topology.
            – José Carlos Santos
            Nov 15 at 12:27










          • Thank you for your clarity!!
            – MathematicianP
            Nov 15 at 12:37










          • I'm glad I could help.
            – José Carlos Santos
            Nov 15 at 12:38










          • Is it therefore true that being closed and bounded is not a topological property?
            – MathematicianP
            Nov 15 at 12:43











          Your Answer





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          down vote



          accepted










          You are right, but for the wrong reason. Being closed is a topological property because it depends only upon the topology induced by the metric, not by the metric itself. For instance, being bounded is not a topological property, because a set may be bounded with respect to a metric and unbounded with respect to another equivalent metric.



          On the other hand, it is false that if a set is closed with respect to a metric then it will automatically be closed with respect to any other metric. For instance, in $mathbb R$, $[0,1)$ is closed with respect to the discrete metric, but not with respect to the usual one.






          share|cite|improve this answer

















          • 1




            but why does it depend only on the topology induced by the metric?
            – MathematicianP
            Nov 15 at 12:24










          • Because being closed means that its complement is open and the set of open subsets is the topology.
            – José Carlos Santos
            Nov 15 at 12:27










          • Thank you for your clarity!!
            – MathematicianP
            Nov 15 at 12:37










          • I'm glad I could help.
            – José Carlos Santos
            Nov 15 at 12:38










          • Is it therefore true that being closed and bounded is not a topological property?
            – MathematicianP
            Nov 15 at 12:43















          up vote
          1
          down vote



          accepted










          You are right, but for the wrong reason. Being closed is a topological property because it depends only upon the topology induced by the metric, not by the metric itself. For instance, being bounded is not a topological property, because a set may be bounded with respect to a metric and unbounded with respect to another equivalent metric.



          On the other hand, it is false that if a set is closed with respect to a metric then it will automatically be closed with respect to any other metric. For instance, in $mathbb R$, $[0,1)$ is closed with respect to the discrete metric, but not with respect to the usual one.






          share|cite|improve this answer

















          • 1




            but why does it depend only on the topology induced by the metric?
            – MathematicianP
            Nov 15 at 12:24










          • Because being closed means that its complement is open and the set of open subsets is the topology.
            – José Carlos Santos
            Nov 15 at 12:27










          • Thank you for your clarity!!
            – MathematicianP
            Nov 15 at 12:37










          • I'm glad I could help.
            – José Carlos Santos
            Nov 15 at 12:38










          • Is it therefore true that being closed and bounded is not a topological property?
            – MathematicianP
            Nov 15 at 12:43













          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          You are right, but for the wrong reason. Being closed is a topological property because it depends only upon the topology induced by the metric, not by the metric itself. For instance, being bounded is not a topological property, because a set may be bounded with respect to a metric and unbounded with respect to another equivalent metric.



          On the other hand, it is false that if a set is closed with respect to a metric then it will automatically be closed with respect to any other metric. For instance, in $mathbb R$, $[0,1)$ is closed with respect to the discrete metric, but not with respect to the usual one.






          share|cite|improve this answer












          You are right, but for the wrong reason. Being closed is a topological property because it depends only upon the topology induced by the metric, not by the metric itself. For instance, being bounded is not a topological property, because a set may be bounded with respect to a metric and unbounded with respect to another equivalent metric.



          On the other hand, it is false that if a set is closed with respect to a metric then it will automatically be closed with respect to any other metric. For instance, in $mathbb R$, $[0,1)$ is closed with respect to the discrete metric, but not with respect to the usual one.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 15 at 12:17









          José Carlos Santos

          142k20111207




          142k20111207








          • 1




            but why does it depend only on the topology induced by the metric?
            – MathematicianP
            Nov 15 at 12:24










          • Because being closed means that its complement is open and the set of open subsets is the topology.
            – José Carlos Santos
            Nov 15 at 12:27










          • Thank you for your clarity!!
            – MathematicianP
            Nov 15 at 12:37










          • I'm glad I could help.
            – José Carlos Santos
            Nov 15 at 12:38










          • Is it therefore true that being closed and bounded is not a topological property?
            – MathematicianP
            Nov 15 at 12:43














          • 1




            but why does it depend only on the topology induced by the metric?
            – MathematicianP
            Nov 15 at 12:24










          • Because being closed means that its complement is open and the set of open subsets is the topology.
            – José Carlos Santos
            Nov 15 at 12:27










          • Thank you for your clarity!!
            – MathematicianP
            Nov 15 at 12:37










          • I'm glad I could help.
            – José Carlos Santos
            Nov 15 at 12:38










          • Is it therefore true that being closed and bounded is not a topological property?
            – MathematicianP
            Nov 15 at 12:43








          1




          1




          but why does it depend only on the topology induced by the metric?
          – MathematicianP
          Nov 15 at 12:24




          but why does it depend only on the topology induced by the metric?
          – MathematicianP
          Nov 15 at 12:24












          Because being closed means that its complement is open and the set of open subsets is the topology.
          – José Carlos Santos
          Nov 15 at 12:27




          Because being closed means that its complement is open and the set of open subsets is the topology.
          – José Carlos Santos
          Nov 15 at 12:27












          Thank you for your clarity!!
          – MathematicianP
          Nov 15 at 12:37




          Thank you for your clarity!!
          – MathematicianP
          Nov 15 at 12:37












          I'm glad I could help.
          – José Carlos Santos
          Nov 15 at 12:38




          I'm glad I could help.
          – José Carlos Santos
          Nov 15 at 12:38












          Is it therefore true that being closed and bounded is not a topological property?
          – MathematicianP
          Nov 15 at 12:43




          Is it therefore true that being closed and bounded is not a topological property?
          – MathematicianP
          Nov 15 at 12:43


















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