How to get the memory usage by bytes using script











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I have a script and I need to modify this so it can print the memory usage into the file with bytes.



#!/bin/bash    
echo "$HOSTNAME, timestamp=$( date +%s ), free -b" >> "system_monitor.csv"









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    up vote
    0
    down vote

    favorite












    I have a script and I need to modify this so it can print the memory usage into the file with bytes.



    #!/bin/bash    
    echo "$HOSTNAME, timestamp=$( date +%s ), free -b" >> "system_monitor.csv"









    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have a script and I need to modify this so it can print the memory usage into the file with bytes.



      #!/bin/bash    
      echo "$HOSTNAME, timestamp=$( date +%s ), free -b" >> "system_monitor.csv"









      share|improve this question















      I have a script and I need to modify this so it can print the memory usage into the file with bytes.



      #!/bin/bash    
      echo "$HOSTNAME, timestamp=$( date +%s ), free -b" >> "system_monitor.csv"






      command-line bash scripts






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      share|improve this question













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      share|improve this question








      edited Nov 20 at 9:54

























      asked Nov 20 at 9:47









      Onyic

      335




      335






















          1 Answer
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          What your script should look like is this:



          #!/usr/bin/env bash

          echo -e "$HOSTNAME, $(date +%s), \n $(free -b)" >> "system_monitor.csv"


          The timestamp variable is unnecessary in this case. And I would suggest adding two news line or one to make the output readable. So a better command would be:



          #! /usr/bin/env bash

          echo -e "$HOSTNAME, $(date +%s), \n $(free -b) \n \n" >> "system_monitor.csv"





          share|improve this answer























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            1 Answer
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            active

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            0
            down vote



            accepted










            What your script should look like is this:



            #!/usr/bin/env bash

            echo -e "$HOSTNAME, $(date +%s), \n $(free -b)" >> "system_monitor.csv"


            The timestamp variable is unnecessary in this case. And I would suggest adding two news line or one to make the output readable. So a better command would be:



            #! /usr/bin/env bash

            echo -e "$HOSTNAME, $(date +%s), \n $(free -b) \n \n" >> "system_monitor.csv"





            share|improve this answer



























              up vote
              0
              down vote



              accepted










              What your script should look like is this:



              #!/usr/bin/env bash

              echo -e "$HOSTNAME, $(date +%s), \n $(free -b)" >> "system_monitor.csv"


              The timestamp variable is unnecessary in this case. And I would suggest adding two news line or one to make the output readable. So a better command would be:



              #! /usr/bin/env bash

              echo -e "$HOSTNAME, $(date +%s), \n $(free -b) \n \n" >> "system_monitor.csv"





              share|improve this answer

























                up vote
                0
                down vote



                accepted







                up vote
                0
                down vote



                accepted






                What your script should look like is this:



                #!/usr/bin/env bash

                echo -e "$HOSTNAME, $(date +%s), \n $(free -b)" >> "system_monitor.csv"


                The timestamp variable is unnecessary in this case. And I would suggest adding two news line or one to make the output readable. So a better command would be:



                #! /usr/bin/env bash

                echo -e "$HOSTNAME, $(date +%s), \n $(free -b) \n \n" >> "system_monitor.csv"





                share|improve this answer














                What your script should look like is this:



                #!/usr/bin/env bash

                echo -e "$HOSTNAME, $(date +%s), \n $(free -b)" >> "system_monitor.csv"


                The timestamp variable is unnecessary in this case. And I would suggest adding two news line or one to make the output readable. So a better command would be:



                #! /usr/bin/env bash

                echo -e "$HOSTNAME, $(date +%s), \n $(free -b) \n \n" >> "system_monitor.csv"






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 20 at 16:21

























                answered Nov 20 at 10:06









                George Udosen

                18.5k94265




                18.5k94265






























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