How to draw the diamond structure using `chains`?












2















I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
2nd-iso-wiki



The code and the resulting figure is shown as follows.



How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



2nd-iso



documentclass[tikz]{standalone}
usetikzlibrary{chains, scopes}

begin{document}
begin{tikzpicture}[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
{
[start chain = G going below] % G chain
node (g) [on chain] {$G$};
node (hn) [on chain, below = 0.50cm of g] {$HN$};
{ [start branch = H going below left] % H branch
node (h) [on chain] {$H$};
}
{ [start branch = N going below right] % N branch
node [on chain] {$N$};
}
node [on chain] {}; % dummy node % continue G chain
node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] {$H cap N$};
node (e) [on chain, below = 0.50cm of hcapn] {${ e }$};
}
end{tikzpicture}
end{document}









share|improve this question



























    2















    I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
    2nd-iso-wiki



    The code and the resulting figure is shown as follows.



    How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



    2nd-iso



    documentclass[tikz]{standalone}
    usetikzlibrary{chains, scopes}

    begin{document}
    begin{tikzpicture}[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
    {
    [start chain = G going below] % G chain
    node (g) [on chain] {$G$};
    node (hn) [on chain, below = 0.50cm of g] {$HN$};
    { [start branch = H going below left] % H branch
    node (h) [on chain] {$H$};
    }
    { [start branch = N going below right] % N branch
    node [on chain] {$N$};
    }
    node [on chain] {}; % dummy node % continue G chain
    node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] {$H cap N$};
    node (e) [on chain, below = 0.50cm of hcapn] {${ e }$};
    }
    end{tikzpicture}
    end{document}









    share|improve this question

























      2












      2








      2








      I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
      2nd-iso-wiki



      The code and the resulting figure is shown as follows.



      How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



      2nd-iso



      documentclass[tikz]{standalone}
      usetikzlibrary{chains, scopes}

      begin{document}
      begin{tikzpicture}[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
      {
      [start chain = G going below] % G chain
      node (g) [on chain] {$G$};
      node (hn) [on chain, below = 0.50cm of g] {$HN$};
      { [start branch = H going below left] % H branch
      node (h) [on chain] {$H$};
      }
      { [start branch = N going below right] % N branch
      node [on chain] {$N$};
      }
      node [on chain] {}; % dummy node % continue G chain
      node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] {$H cap N$};
      node (e) [on chain, below = 0.50cm of hcapn] {${ e }$};
      }
      end{tikzpicture}
      end{document}









      share|improve this question














      I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
      2nd-iso-wiki



      The code and the resulting figure is shown as follows.



      How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



      2nd-iso



      documentclass[tikz]{standalone}
      usetikzlibrary{chains, scopes}

      begin{document}
      begin{tikzpicture}[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
      {
      [start chain = G going below] % G chain
      node (g) [on chain] {$G$};
      node (hn) [on chain, below = 0.50cm of g] {$HN$};
      { [start branch = H going below left] % H branch
      node (h) [on chain] {$H$};
      }
      { [start branch = N going below right] % N branch
      node [on chain] {$N$};
      }
      node [on chain] {}; % dummy node % continue G chain
      node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] {$H cap N$};
      node (e) [on chain, below = 0.50cm of hcapn] {${ e }$};
      }
      end{tikzpicture}
      end{document}






      tikz-pgf tikz-chains






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 31 at 7:00









      hengxinhengxin

      1,04021026




      1,04021026






















          2 Answers
          2






          active

          oldest

          votes


















          3














          with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



          documentclass[tikz, margin=3mm]{standalone}
          usetikzlibrary{chains, positioning, shapes.geometric}
          makeatletter
          tikzset{suspend join/.code={deftikz@after@path{}}}
          makeatother

          begin{document}
          begin{tikzpicture}[
          node distance = 8mm and 10 mm,
          start chain = going below,
          N/.style = {ellipse, draw, inner sep=2pt, on chain, join=by -}]
          node (g) [N] {$G$};
          node (hn) [N] {$HN$};
          node (h) [N, below left=of hn] {$H$};
          node (hcapn) [N, below=of h -| hn] {$H cap N$};
          node (e) [N] {${ e }$};
          %
          node (n) [N,suspend join,
          below right=of hn] {$N$};
          node [below=of hn] {$cong$};
          draw (hn) -- (n) (n) -- (hcapn);
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer


























          • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

            – marmot
            Mar 31 at 13:49













          • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

            – Zarko
            Mar 31 at 19:00











          • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

            – marmot
            Mar 31 at 21:51











          • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

            – Zarko
            Mar 31 at 22:04



















          5














          If you want to replicate the linked picture, I propose this



          documentclass[tikz]{standalone}
          usetikzlibrary{shapes,fit}
          usepackage{mathptmx}
          begin{document}
          begin{tikzpicture}[x=1.75cm,y=1.75cm]
          begin{scope}[every node/.style={draw,circle,minimum size=1cm}]
          node (g) at (0,2) {$G$};
          node (sn) at (0,1) {$SN$};
          node (n) at (-1,0) {$N$};
          node (s) at (1,0) {$S$};
          node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) {$Scap N$};
          node (e) at (0,-2) {${e}$};
          end{scope}
          draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
          node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] {};
          node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] {};
          node {$cong$};
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer
























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3














            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]{standalone}
            usetikzlibrary{chains, positioning, shapes.geometric}
            makeatletter
            tikzset{suspend join/.code={deftikz@after@path{}}}
            makeatother

            begin{document}
            begin{tikzpicture}[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = {ellipse, draw, inner sep=2pt, on chain, join=by -}]
            node (g) [N] {$G$};
            node (hn) [N] {$HN$};
            node (h) [N, below left=of hn] {$H$};
            node (hcapn) [N, below=of h -| hn] {$H cap N$};
            node (e) [N] {${ e }$};
            %
            node (n) [N,suspend join,
            below right=of hn] {$N$};
            node [below=of hn] {$cong$};
            draw (hn) -- (n) (n) -- (hcapn);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer


























            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              Mar 31 at 13:49













            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              Mar 31 at 19:00











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              Mar 31 at 21:51











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              Mar 31 at 22:04
















            3














            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]{standalone}
            usetikzlibrary{chains, positioning, shapes.geometric}
            makeatletter
            tikzset{suspend join/.code={deftikz@after@path{}}}
            makeatother

            begin{document}
            begin{tikzpicture}[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = {ellipse, draw, inner sep=2pt, on chain, join=by -}]
            node (g) [N] {$G$};
            node (hn) [N] {$HN$};
            node (h) [N, below left=of hn] {$H$};
            node (hcapn) [N, below=of h -| hn] {$H cap N$};
            node (e) [N] {${ e }$};
            %
            node (n) [N,suspend join,
            below right=of hn] {$N$};
            node [below=of hn] {$cong$};
            draw (hn) -- (n) (n) -- (hcapn);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer


























            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              Mar 31 at 13:49













            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              Mar 31 at 19:00











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              Mar 31 at 21:51











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              Mar 31 at 22:04














            3












            3








            3







            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]{standalone}
            usetikzlibrary{chains, positioning, shapes.geometric}
            makeatletter
            tikzset{suspend join/.code={deftikz@after@path{}}}
            makeatother

            begin{document}
            begin{tikzpicture}[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = {ellipse, draw, inner sep=2pt, on chain, join=by -}]
            node (g) [N] {$G$};
            node (hn) [N] {$HN$};
            node (h) [N, below left=of hn] {$H$};
            node (hcapn) [N, below=of h -| hn] {$H cap N$};
            node (e) [N] {${ e }$};
            %
            node (n) [N,suspend join,
            below right=of hn] {$N$};
            node [below=of hn] {$cong$};
            draw (hn) -- (n) (n) -- (hcapn);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer















            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]{standalone}
            usetikzlibrary{chains, positioning, shapes.geometric}
            makeatletter
            tikzset{suspend join/.code={deftikz@after@path{}}}
            makeatother

            begin{document}
            begin{tikzpicture}[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = {ellipse, draw, inner sep=2pt, on chain, join=by -}]
            node (g) [N] {$G$};
            node (hn) [N] {$HN$};
            node (h) [N, below left=of hn] {$H$};
            node (hcapn) [N, below=of h -| hn] {$H cap N$};
            node (e) [N] {${ e }$};
            %
            node (n) [N,suspend join,
            below right=of hn] {$N$};
            node [below=of hn] {$cong$};
            draw (hn) -- (n) (n) -- (hcapn);
            end{tikzpicture}
            end{document}


            enter image description here







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Mar 31 at 8:10

























            answered Mar 31 at 7:48









            ZarkoZarko

            129k868169




            129k868169













            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              Mar 31 at 13:49













            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              Mar 31 at 19:00











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              Mar 31 at 21:51











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              Mar 31 at 22:04



















            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              Mar 31 at 13:49













            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              Mar 31 at 19:00











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              Mar 31 at 21:51











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              Mar 31 at 22:04

















            Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

            – marmot
            Mar 31 at 13:49







            Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

            – marmot
            Mar 31 at 13:49















            i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

            – Zarko
            Mar 31 at 19:00





            i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

            – Zarko
            Mar 31 at 19:00













            What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

            – marmot
            Mar 31 at 21:51





            What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

            – marmot
            Mar 31 at 21:51













            @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

            – Zarko
            Mar 31 at 22:04





            @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

            – Zarko
            Mar 31 at 22:04











            5














            If you want to replicate the linked picture, I propose this



            documentclass[tikz]{standalone}
            usetikzlibrary{shapes,fit}
            usepackage{mathptmx}
            begin{document}
            begin{tikzpicture}[x=1.75cm,y=1.75cm]
            begin{scope}[every node/.style={draw,circle,minimum size=1cm}]
            node (g) at (0,2) {$G$};
            node (sn) at (0,1) {$SN$};
            node (n) at (-1,0) {$N$};
            node (s) at (1,0) {$S$};
            node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) {$Scap N$};
            node (e) at (0,-2) {${e}$};
            end{scope}
            draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
            node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] {};
            node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] {};
            node {$cong$};
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer




























              5














              If you want to replicate the linked picture, I propose this



              documentclass[tikz]{standalone}
              usetikzlibrary{shapes,fit}
              usepackage{mathptmx}
              begin{document}
              begin{tikzpicture}[x=1.75cm,y=1.75cm]
              begin{scope}[every node/.style={draw,circle,minimum size=1cm}]
              node (g) at (0,2) {$G$};
              node (sn) at (0,1) {$SN$};
              node (n) at (-1,0) {$N$};
              node (s) at (1,0) {$S$};
              node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) {$Scap N$};
              node (e) at (0,-2) {${e}$};
              end{scope}
              draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
              node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] {};
              node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] {};
              node {$cong$};
              end{tikzpicture}
              end{document}


              enter image description here






              share|improve this answer


























                5












                5








                5







                If you want to replicate the linked picture, I propose this



                documentclass[tikz]{standalone}
                usetikzlibrary{shapes,fit}
                usepackage{mathptmx}
                begin{document}
                begin{tikzpicture}[x=1.75cm,y=1.75cm]
                begin{scope}[every node/.style={draw,circle,minimum size=1cm}]
                node (g) at (0,2) {$G$};
                node (sn) at (0,1) {$SN$};
                node (n) at (-1,0) {$N$};
                node (s) at (1,0) {$S$};
                node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) {$Scap N$};
                node (e) at (0,-2) {${e}$};
                end{scope}
                draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] {};
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] {};
                node {$cong$};
                end{tikzpicture}
                end{document}


                enter image description here






                share|improve this answer













                If you want to replicate the linked picture, I propose this



                documentclass[tikz]{standalone}
                usetikzlibrary{shapes,fit}
                usepackage{mathptmx}
                begin{document}
                begin{tikzpicture}[x=1.75cm,y=1.75cm]
                begin{scope}[every node/.style={draw,circle,minimum size=1cm}]
                node (g) at (0,2) {$G$};
                node (sn) at (0,1) {$SN$};
                node (n) at (-1,0) {$N$};
                node (s) at (1,0) {$S$};
                node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) {$Scap N$};
                node (e) at (0,-2) {${e}$};
                end{scope}
                draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] {};
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] {};
                node {$cong$};
                end{tikzpicture}
                end{document}


                enter image description here







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                answered Mar 31 at 7:17









                JouleVJouleV

                12k22662




                12k22662






























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