Create a new column based on the values of the column by ID
Please help me solve this problem. I searched online but couldn’t find the solution.
df
Id Fruit
1 Apple
1 Carrot
2 Apple
3 Carrot
list = [fruit, vegetable, both]
The question is, how to assign for each id, if id’s fruit column contains apple or carrot the list. If id contains apple then assign ID 1 fruit, if carrot only, then vegetable, if both then both.
I tried to use str.contains by row, but it doesn’t take ID column.
Result
Newdf
Id Fruit New_col
1 Apple Both
1 Carrot Both
2 Apple Fruit
3 Carrot Vegetable
Thank you a lot.
python pandas
add a comment |
Please help me solve this problem. I searched online but couldn’t find the solution.
df
Id Fruit
1 Apple
1 Carrot
2 Apple
3 Carrot
list = [fruit, vegetable, both]
The question is, how to assign for each id, if id’s fruit column contains apple or carrot the list. If id contains apple then assign ID 1 fruit, if carrot only, then vegetable, if both then both.
I tried to use str.contains by row, but it doesn’t take ID column.
Result
Newdf
Id Fruit New_col
1 Apple Both
1 Carrot Both
2 Apple Fruit
3 Carrot Vegetable
Thank you a lot.
python pandas
add a comment |
Please help me solve this problem. I searched online but couldn’t find the solution.
df
Id Fruit
1 Apple
1 Carrot
2 Apple
3 Carrot
list = [fruit, vegetable, both]
The question is, how to assign for each id, if id’s fruit column contains apple or carrot the list. If id contains apple then assign ID 1 fruit, if carrot only, then vegetable, if both then both.
I tried to use str.contains by row, but it doesn’t take ID column.
Result
Newdf
Id Fruit New_col
1 Apple Both
1 Carrot Both
2 Apple Fruit
3 Carrot Vegetable
Thank you a lot.
python pandas
Please help me solve this problem. I searched online but couldn’t find the solution.
df
Id Fruit
1 Apple
1 Carrot
2 Apple
3 Carrot
list = [fruit, vegetable, both]
The question is, how to assign for each id, if id’s fruit column contains apple or carrot the list. If id contains apple then assign ID 1 fruit, if carrot only, then vegetable, if both then both.
I tried to use str.contains by row, but it doesn’t take ID column.
Result
Newdf
Id Fruit New_col
1 Apple Both
1 Carrot Both
2 Apple Fruit
3 Carrot Vegetable
Thank you a lot.
python pandas
python pandas
asked Nov 21 '18 at 3:04
PythonistaPythonista
344
344
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Doing map
first , then we just using transform
nunqiue
finding the the position should be 'both'
s=df.Fruit.map({'Apple':'Fruit','Carrot':'Vegetable'})
mask=s.groupby(df.Id).transform('nunique').eq(2)
s[mask]='both'
df['New']=s
df
Out[190]:
Id Fruit New
0 1 Apple both
1 1 Carrot both
2 2 Apple Fruit
3 3 Carrot Vegetable
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53404704%2fcreate-a-new-column-based-on-the-values-of-the-column-by-id%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Doing map
first , then we just using transform
nunqiue
finding the the position should be 'both'
s=df.Fruit.map({'Apple':'Fruit','Carrot':'Vegetable'})
mask=s.groupby(df.Id).transform('nunique').eq(2)
s[mask]='both'
df['New']=s
df
Out[190]:
Id Fruit New
0 1 Apple both
1 1 Carrot both
2 2 Apple Fruit
3 3 Carrot Vegetable
add a comment |
Doing map
first , then we just using transform
nunqiue
finding the the position should be 'both'
s=df.Fruit.map({'Apple':'Fruit','Carrot':'Vegetable'})
mask=s.groupby(df.Id).transform('nunique').eq(2)
s[mask]='both'
df['New']=s
df
Out[190]:
Id Fruit New
0 1 Apple both
1 1 Carrot both
2 2 Apple Fruit
3 3 Carrot Vegetable
add a comment |
Doing map
first , then we just using transform
nunqiue
finding the the position should be 'both'
s=df.Fruit.map({'Apple':'Fruit','Carrot':'Vegetable'})
mask=s.groupby(df.Id).transform('nunique').eq(2)
s[mask]='both'
df['New']=s
df
Out[190]:
Id Fruit New
0 1 Apple both
1 1 Carrot both
2 2 Apple Fruit
3 3 Carrot Vegetable
Doing map
first , then we just using transform
nunqiue
finding the the position should be 'both'
s=df.Fruit.map({'Apple':'Fruit','Carrot':'Vegetable'})
mask=s.groupby(df.Id).transform('nunique').eq(2)
s[mask]='both'
df['New']=s
df
Out[190]:
Id Fruit New
0 1 Apple both
1 1 Carrot both
2 2 Apple Fruit
3 3 Carrot Vegetable
answered Nov 21 '18 at 3:11
Wen-BenWen-Ben
114k83369
114k83369
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53404704%2fcreate-a-new-column-based-on-the-values-of-the-column-by-id%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown