C Checking for EOF
I developed a C program that does addition of integers but the problem I am having with this is that it needs to take input from stdin via input text (not interactive). However after testing I can only get it to work for a single line of input when it should work for multiple, assume this sample input are all in a single input file ((Line 1) 123+456= (Line 2) 999999999+1= ).
I think it has to do with EOF and it should go through and repeat until finished. I tried putting an EOF in the first while loop but the output is very different than what it should be. The input format has to stay the same and cannot be changed. Is there anyway I can get it to do operations until the end of input file?
#include<stdio.h>
#include<stdbool.h>
int main() {
char c;
char a[100], b[100], array[101];
int n = 0;
//It should scan through everyrthing then exit and it think start arround HERE
while ((c = (char) getchar()) != '=') {
array[n] = c;
putchar(c);
n++;
}
printf("=n");
array[n] = '';
int n1 = 0, n2 = -1;
while (n1 + n2 < n) { //Splits the array into two separate char arrays
if (array[n1] == '+') {
n2 = 0;
n1 += 1;
}
if (n2 == -1) {
a[n1] = array[n1];
n1++;
} else {
b[n2] = array[n1 + n2];
n2++;
}
}
n1--;
a[n1] = b[n2] = '';
int i = 0, z = 0, p = 0;
char array2[101];
bool val = false;
while (n1 > 0 || n2 > 0) { //Addition Calculation
int x = 0, y = 0;
if (n1 > 0)
x = a[n1 - 1] - '0';
if (n2 > 0)
y = b[n2 - 1] - '0';
z = x + y;
if (val)
z = z + p;
if (z > 9) {
p = z % 10;
array2[i++] = (char) (p + '0');
p = z / 10;
val = true;
} else {
array2[i++] = (char) (z + '0');
val = false;
}
n1--;
n2--;
}
if (val) {
array2[i++] = (char) (p + '0');
array2[i] = '';
}
for (n = i - 1; n >= 0; n--) { //Print Result
printf("%c", array2[n]);
}
printf("n");
return 0;
}
c
add a comment |
I developed a C program that does addition of integers but the problem I am having with this is that it needs to take input from stdin via input text (not interactive). However after testing I can only get it to work for a single line of input when it should work for multiple, assume this sample input are all in a single input file ((Line 1) 123+456= (Line 2) 999999999+1= ).
I think it has to do with EOF and it should go through and repeat until finished. I tried putting an EOF in the first while loop but the output is very different than what it should be. The input format has to stay the same and cannot be changed. Is there anyway I can get it to do operations until the end of input file?
#include<stdio.h>
#include<stdbool.h>
int main() {
char c;
char a[100], b[100], array[101];
int n = 0;
//It should scan through everyrthing then exit and it think start arround HERE
while ((c = (char) getchar()) != '=') {
array[n] = c;
putchar(c);
n++;
}
printf("=n");
array[n] = '';
int n1 = 0, n2 = -1;
while (n1 + n2 < n) { //Splits the array into two separate char arrays
if (array[n1] == '+') {
n2 = 0;
n1 += 1;
}
if (n2 == -1) {
a[n1] = array[n1];
n1++;
} else {
b[n2] = array[n1 + n2];
n2++;
}
}
n1--;
a[n1] = b[n2] = '';
int i = 0, z = 0, p = 0;
char array2[101];
bool val = false;
while (n1 > 0 || n2 > 0) { //Addition Calculation
int x = 0, y = 0;
if (n1 > 0)
x = a[n1 - 1] - '0';
if (n2 > 0)
y = b[n2 - 1] - '0';
z = x + y;
if (val)
z = z + p;
if (z > 9) {
p = z % 10;
array2[i++] = (char) (p + '0');
p = z / 10;
val = true;
} else {
array2[i++] = (char) (z + '0');
val = false;
}
n1--;
n2--;
}
if (val) {
array2[i++] = (char) (p + '0');
array2[i] = '';
}
for (n = i - 1; n >= 0; n--) { //Print Result
printf("%c", array2[n]);
}
printf("n");
return 0;
}
c
1
Why don't you readint
s usingscanf()
when you wantint
s?while ((c = (char) getchar()) != '=')
is why your code only processes the first line.
– Swordfish
Nov 21 '18 at 3:31
I needed to find a way to split the characters between input and exit once it reaches = unless it can be done with scanf and still work the same. getchar just seemed easier since it reads character by character.
– GameCoder
Nov 21 '18 at 3:41
You have to get rid of the misconception that you need to read single chars in the first place. You want numbers? Read numbers.
– Swordfish
Nov 21 '18 at 3:58
add a comment |
I developed a C program that does addition of integers but the problem I am having with this is that it needs to take input from stdin via input text (not interactive). However after testing I can only get it to work for a single line of input when it should work for multiple, assume this sample input are all in a single input file ((Line 1) 123+456= (Line 2) 999999999+1= ).
I think it has to do with EOF and it should go through and repeat until finished. I tried putting an EOF in the first while loop but the output is very different than what it should be. The input format has to stay the same and cannot be changed. Is there anyway I can get it to do operations until the end of input file?
#include<stdio.h>
#include<stdbool.h>
int main() {
char c;
char a[100], b[100], array[101];
int n = 0;
//It should scan through everyrthing then exit and it think start arround HERE
while ((c = (char) getchar()) != '=') {
array[n] = c;
putchar(c);
n++;
}
printf("=n");
array[n] = '';
int n1 = 0, n2 = -1;
while (n1 + n2 < n) { //Splits the array into two separate char arrays
if (array[n1] == '+') {
n2 = 0;
n1 += 1;
}
if (n2 == -1) {
a[n1] = array[n1];
n1++;
} else {
b[n2] = array[n1 + n2];
n2++;
}
}
n1--;
a[n1] = b[n2] = '';
int i = 0, z = 0, p = 0;
char array2[101];
bool val = false;
while (n1 > 0 || n2 > 0) { //Addition Calculation
int x = 0, y = 0;
if (n1 > 0)
x = a[n1 - 1] - '0';
if (n2 > 0)
y = b[n2 - 1] - '0';
z = x + y;
if (val)
z = z + p;
if (z > 9) {
p = z % 10;
array2[i++] = (char) (p + '0');
p = z / 10;
val = true;
} else {
array2[i++] = (char) (z + '0');
val = false;
}
n1--;
n2--;
}
if (val) {
array2[i++] = (char) (p + '0');
array2[i] = '';
}
for (n = i - 1; n >= 0; n--) { //Print Result
printf("%c", array2[n]);
}
printf("n");
return 0;
}
c
I developed a C program that does addition of integers but the problem I am having with this is that it needs to take input from stdin via input text (not interactive). However after testing I can only get it to work for a single line of input when it should work for multiple, assume this sample input are all in a single input file ((Line 1) 123+456= (Line 2) 999999999+1= ).
I think it has to do with EOF and it should go through and repeat until finished. I tried putting an EOF in the first while loop but the output is very different than what it should be. The input format has to stay the same and cannot be changed. Is there anyway I can get it to do operations until the end of input file?
#include<stdio.h>
#include<stdbool.h>
int main() {
char c;
char a[100], b[100], array[101];
int n = 0;
//It should scan through everyrthing then exit and it think start arround HERE
while ((c = (char) getchar()) != '=') {
array[n] = c;
putchar(c);
n++;
}
printf("=n");
array[n] = '';
int n1 = 0, n2 = -1;
while (n1 + n2 < n) { //Splits the array into two separate char arrays
if (array[n1] == '+') {
n2 = 0;
n1 += 1;
}
if (n2 == -1) {
a[n1] = array[n1];
n1++;
} else {
b[n2] = array[n1 + n2];
n2++;
}
}
n1--;
a[n1] = b[n2] = '';
int i = 0, z = 0, p = 0;
char array2[101];
bool val = false;
while (n1 > 0 || n2 > 0) { //Addition Calculation
int x = 0, y = 0;
if (n1 > 0)
x = a[n1 - 1] - '0';
if (n2 > 0)
y = b[n2 - 1] - '0';
z = x + y;
if (val)
z = z + p;
if (z > 9) {
p = z % 10;
array2[i++] = (char) (p + '0');
p = z / 10;
val = true;
} else {
array2[i++] = (char) (z + '0');
val = false;
}
n1--;
n2--;
}
if (val) {
array2[i++] = (char) (p + '0');
array2[i] = '';
}
for (n = i - 1; n >= 0; n--) { //Print Result
printf("%c", array2[n]);
}
printf("n");
return 0;
}
c
c
asked Nov 21 '18 at 3:25
GameCoderGameCoder
102
102
1
Why don't you readint
s usingscanf()
when you wantint
s?while ((c = (char) getchar()) != '=')
is why your code only processes the first line.
– Swordfish
Nov 21 '18 at 3:31
I needed to find a way to split the characters between input and exit once it reaches = unless it can be done with scanf and still work the same. getchar just seemed easier since it reads character by character.
– GameCoder
Nov 21 '18 at 3:41
You have to get rid of the misconception that you need to read single chars in the first place. You want numbers? Read numbers.
– Swordfish
Nov 21 '18 at 3:58
add a comment |
1
Why don't you readint
s usingscanf()
when you wantint
s?while ((c = (char) getchar()) != '=')
is why your code only processes the first line.
– Swordfish
Nov 21 '18 at 3:31
I needed to find a way to split the characters between input and exit once it reaches = unless it can be done with scanf and still work the same. getchar just seemed easier since it reads character by character.
– GameCoder
Nov 21 '18 at 3:41
You have to get rid of the misconception that you need to read single chars in the first place. You want numbers? Read numbers.
– Swordfish
Nov 21 '18 at 3:58
1
1
Why don't you read
int
s using scanf()
when you want int
s? while ((c = (char) getchar()) != '=')
is why your code only processes the first line.– Swordfish
Nov 21 '18 at 3:31
Why don't you read
int
s using scanf()
when you want int
s? while ((c = (char) getchar()) != '=')
is why your code only processes the first line.– Swordfish
Nov 21 '18 at 3:31
I needed to find a way to split the characters between input and exit once it reaches = unless it can be done with scanf and still work the same. getchar just seemed easier since it reads character by character.
– GameCoder
Nov 21 '18 at 3:41
I needed to find a way to split the characters between input and exit once it reaches = unless it can be done with scanf and still work the same. getchar just seemed easier since it reads character by character.
– GameCoder
Nov 21 '18 at 3:41
You have to get rid of the misconception that you need to read single chars in the first place. You want numbers? Read numbers.
– Swordfish
Nov 21 '18 at 3:58
You have to get rid of the misconception that you need to read single chars in the first place. You want numbers? Read numbers.
– Swordfish
Nov 21 '18 at 3:58
add a comment |
1 Answer
1
active
oldest
votes
Using scanf()
what you want is a 4-liner:
#include <stdio.h>
int main(void)
{
int a, b;
char op, ch;
while (scanf(" %d %c %d %c", &a, &op, &b, &ch) == 4 && op == '+' && ch == '=')
printf("%d+%d=%dn", a, b, a + b);
}
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Using scanf()
what you want is a 4-liner:
#include <stdio.h>
int main(void)
{
int a, b;
char op, ch;
while (scanf(" %d %c %d %c", &a, &op, &b, &ch) == 4 && op == '+' && ch == '=')
printf("%d+%d=%dn", a, b, a + b);
}
add a comment |
Using scanf()
what you want is a 4-liner:
#include <stdio.h>
int main(void)
{
int a, b;
char op, ch;
while (scanf(" %d %c %d %c", &a, &op, &b, &ch) == 4 && op == '+' && ch == '=')
printf("%d+%d=%dn", a, b, a + b);
}
add a comment |
Using scanf()
what you want is a 4-liner:
#include <stdio.h>
int main(void)
{
int a, b;
char op, ch;
while (scanf(" %d %c %d %c", &a, &op, &b, &ch) == 4 && op == '+' && ch == '=')
printf("%d+%d=%dn", a, b, a + b);
}
Using scanf()
what you want is a 4-liner:
#include <stdio.h>
int main(void)
{
int a, b;
char op, ch;
while (scanf(" %d %c %d %c", &a, &op, &b, &ch) == 4 && op == '+' && ch == '=')
printf("%d+%d=%dn", a, b, a + b);
}
answered Nov 21 '18 at 3:54
SwordfishSwordfish
10.2k11437
10.2k11437
add a comment |
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1
Why don't you read
int
s usingscanf()
when you wantint
s?while ((c = (char) getchar()) != '=')
is why your code only processes the first line.– Swordfish
Nov 21 '18 at 3:31
I needed to find a way to split the characters between input and exit once it reaches = unless it can be done with scanf and still work the same. getchar just seemed easier since it reads character by character.
– GameCoder
Nov 21 '18 at 3:41
You have to get rid of the misconception that you need to read single chars in the first place. You want numbers? Read numbers.
– Swordfish
Nov 21 '18 at 3:58