Vanishing of the Nijenhuis tensor












2












$begingroup$


The Nijenhuis tensor is defined to be:



$$(1):quad
N_J(X,Y)equiv[X,Y]+J[JX,Y]+J[X,JY]-[JX,JY],
$$



for vector fields $X$ and $Y$ on the manifold $M$, equipped with Almost Complex Structure $J$:



$$(2):quad
J:TMrightarrow TMquad|quad J^2=-I_{TM}.
$$



The requirement is to show that given $J$ is integrable, $N_J$ is vanishing. I am having an issue with the following computation which gives a vanishing $N_J$, regardless of whether $J$ is integrable or not:



$$
N_J(X,Y)equiv[X,Y]+J[JX,Y]+J[X,JY]-[JX,JY]
$$

$$
=[X,Y]+J^2XY-JYJX+JXJY-J^2YX-[JX,JY]
$$

$$
=[X,Y]+J^2[X,Y]
$$

$$
=[X,Y]-[X,Y]=0quadtext{(by (2) alone)}.
$$

I find this very strange because this makes absolutely no reference at all to $J$ being integrable or not, rather this follows solely from the definition of $J$ in $(2)$. Suggesting that if $J$ is an almost complex structure, then $N_J$ is always vanishing. Is it that I can write $(2)$ only for integrable $J$ ? If someone could please explain what is it that I am not doing right or do not understand correctly ?...










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    The condition $J^2 = - I$ is definitely not true just for integrable $J$. For example, $S^6$ has an almost complex structure $J$ coming from thinking of it as the unit octonians, but this almost complex structure is not integrable. In your computation, it's not clear to me that $J[JX,Y] = J^2XY - JYJX$, and similarly for the third term. I agree that $J(V+W) = JV + JW$ for any vectors $V$ and $W$, but when you write $[JX,Y] = JXY - YJX$, you have to remember that the terms $JXY$ and $YJX$ are not actually vector fields themselves, so there is no reason for $J$ to distribute over them....
    $endgroup$
    – Jason DeVito
    Nov 30 '18 at 19:28










  • $begingroup$
    Perfect ... that answers it! you got me spot on :)
    $endgroup$
    – Kong
    Nov 30 '18 at 19:32










  • $begingroup$
    Well, I wish I knew how to actually do the computation!
    $endgroup$
    – Jason DeVito
    Nov 30 '18 at 19:35






  • 1




    $begingroup$
    Hint: If $X$ is any tangent vector, then $X-iJX$ is an $i$-eigenvector of $J$, and $X+iJX$ is a $(-i)$-eigenvector.
    $endgroup$
    – Jack Lee
    Nov 30 '18 at 22:56
















2












$begingroup$


The Nijenhuis tensor is defined to be:



$$(1):quad
N_J(X,Y)equiv[X,Y]+J[JX,Y]+J[X,JY]-[JX,JY],
$$



for vector fields $X$ and $Y$ on the manifold $M$, equipped with Almost Complex Structure $J$:



$$(2):quad
J:TMrightarrow TMquad|quad J^2=-I_{TM}.
$$



The requirement is to show that given $J$ is integrable, $N_J$ is vanishing. I am having an issue with the following computation which gives a vanishing $N_J$, regardless of whether $J$ is integrable or not:



$$
N_J(X,Y)equiv[X,Y]+J[JX,Y]+J[X,JY]-[JX,JY]
$$

$$
=[X,Y]+J^2XY-JYJX+JXJY-J^2YX-[JX,JY]
$$

$$
=[X,Y]+J^2[X,Y]
$$

$$
=[X,Y]-[X,Y]=0quadtext{(by (2) alone)}.
$$

I find this very strange because this makes absolutely no reference at all to $J$ being integrable or not, rather this follows solely from the definition of $J$ in $(2)$. Suggesting that if $J$ is an almost complex structure, then $N_J$ is always vanishing. Is it that I can write $(2)$ only for integrable $J$ ? If someone could please explain what is it that I am not doing right or do not understand correctly ?...










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    The condition $J^2 = - I$ is definitely not true just for integrable $J$. For example, $S^6$ has an almost complex structure $J$ coming from thinking of it as the unit octonians, but this almost complex structure is not integrable. In your computation, it's not clear to me that $J[JX,Y] = J^2XY - JYJX$, and similarly for the third term. I agree that $J(V+W) = JV + JW$ for any vectors $V$ and $W$, but when you write $[JX,Y] = JXY - YJX$, you have to remember that the terms $JXY$ and $YJX$ are not actually vector fields themselves, so there is no reason for $J$ to distribute over them....
    $endgroup$
    – Jason DeVito
    Nov 30 '18 at 19:28










  • $begingroup$
    Perfect ... that answers it! you got me spot on :)
    $endgroup$
    – Kong
    Nov 30 '18 at 19:32










  • $begingroup$
    Well, I wish I knew how to actually do the computation!
    $endgroup$
    – Jason DeVito
    Nov 30 '18 at 19:35






  • 1




    $begingroup$
    Hint: If $X$ is any tangent vector, then $X-iJX$ is an $i$-eigenvector of $J$, and $X+iJX$ is a $(-i)$-eigenvector.
    $endgroup$
    – Jack Lee
    Nov 30 '18 at 22:56














2












2








2


1



$begingroup$


The Nijenhuis tensor is defined to be:



$$(1):quad
N_J(X,Y)equiv[X,Y]+J[JX,Y]+J[X,JY]-[JX,JY],
$$



for vector fields $X$ and $Y$ on the manifold $M$, equipped with Almost Complex Structure $J$:



$$(2):quad
J:TMrightarrow TMquad|quad J^2=-I_{TM}.
$$



The requirement is to show that given $J$ is integrable, $N_J$ is vanishing. I am having an issue with the following computation which gives a vanishing $N_J$, regardless of whether $J$ is integrable or not:



$$
N_J(X,Y)equiv[X,Y]+J[JX,Y]+J[X,JY]-[JX,JY]
$$

$$
=[X,Y]+J^2XY-JYJX+JXJY-J^2YX-[JX,JY]
$$

$$
=[X,Y]+J^2[X,Y]
$$

$$
=[X,Y]-[X,Y]=0quadtext{(by (2) alone)}.
$$

I find this very strange because this makes absolutely no reference at all to $J$ being integrable or not, rather this follows solely from the definition of $J$ in $(2)$. Suggesting that if $J$ is an almost complex structure, then $N_J$ is always vanishing. Is it that I can write $(2)$ only for integrable $J$ ? If someone could please explain what is it that I am not doing right or do not understand correctly ?...










share|cite|improve this question











$endgroup$




The Nijenhuis tensor is defined to be:



$$(1):quad
N_J(X,Y)equiv[X,Y]+J[JX,Y]+J[X,JY]-[JX,JY],
$$



for vector fields $X$ and $Y$ on the manifold $M$, equipped with Almost Complex Structure $J$:



$$(2):quad
J:TMrightarrow TMquad|quad J^2=-I_{TM}.
$$



The requirement is to show that given $J$ is integrable, $N_J$ is vanishing. I am having an issue with the following computation which gives a vanishing $N_J$, regardless of whether $J$ is integrable or not:



$$
N_J(X,Y)equiv[X,Y]+J[JX,Y]+J[X,JY]-[JX,JY]
$$

$$
=[X,Y]+J^2XY-JYJX+JXJY-J^2YX-[JX,JY]
$$

$$
=[X,Y]+J^2[X,Y]
$$

$$
=[X,Y]-[X,Y]=0quadtext{(by (2) alone)}.
$$

I find this very strange because this makes absolutely no reference at all to $J$ being integrable or not, rather this follows solely from the definition of $J$ in $(2)$. Suggesting that if $J$ is an almost complex structure, then $N_J$ is always vanishing. Is it that I can write $(2)$ only for integrable $J$ ? If someone could please explain what is it that I am not doing right or do not understand correctly ?...







differential-geometry complex-manifolds almost-complex






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 30 '18 at 17:11







Kong

















asked Nov 30 '18 at 17:06









KongKong

315




315








  • 1




    $begingroup$
    The condition $J^2 = - I$ is definitely not true just for integrable $J$. For example, $S^6$ has an almost complex structure $J$ coming from thinking of it as the unit octonians, but this almost complex structure is not integrable. In your computation, it's not clear to me that $J[JX,Y] = J^2XY - JYJX$, and similarly for the third term. I agree that $J(V+W) = JV + JW$ for any vectors $V$ and $W$, but when you write $[JX,Y] = JXY - YJX$, you have to remember that the terms $JXY$ and $YJX$ are not actually vector fields themselves, so there is no reason for $J$ to distribute over them....
    $endgroup$
    – Jason DeVito
    Nov 30 '18 at 19:28










  • $begingroup$
    Perfect ... that answers it! you got me spot on :)
    $endgroup$
    – Kong
    Nov 30 '18 at 19:32










  • $begingroup$
    Well, I wish I knew how to actually do the computation!
    $endgroup$
    – Jason DeVito
    Nov 30 '18 at 19:35






  • 1




    $begingroup$
    Hint: If $X$ is any tangent vector, then $X-iJX$ is an $i$-eigenvector of $J$, and $X+iJX$ is a $(-i)$-eigenvector.
    $endgroup$
    – Jack Lee
    Nov 30 '18 at 22:56














  • 1




    $begingroup$
    The condition $J^2 = - I$ is definitely not true just for integrable $J$. For example, $S^6$ has an almost complex structure $J$ coming from thinking of it as the unit octonians, but this almost complex structure is not integrable. In your computation, it's not clear to me that $J[JX,Y] = J^2XY - JYJX$, and similarly for the third term. I agree that $J(V+W) = JV + JW$ for any vectors $V$ and $W$, but when you write $[JX,Y] = JXY - YJX$, you have to remember that the terms $JXY$ and $YJX$ are not actually vector fields themselves, so there is no reason for $J$ to distribute over them....
    $endgroup$
    – Jason DeVito
    Nov 30 '18 at 19:28










  • $begingroup$
    Perfect ... that answers it! you got me spot on :)
    $endgroup$
    – Kong
    Nov 30 '18 at 19:32










  • $begingroup$
    Well, I wish I knew how to actually do the computation!
    $endgroup$
    – Jason DeVito
    Nov 30 '18 at 19:35






  • 1




    $begingroup$
    Hint: If $X$ is any tangent vector, then $X-iJX$ is an $i$-eigenvector of $J$, and $X+iJX$ is a $(-i)$-eigenvector.
    $endgroup$
    – Jack Lee
    Nov 30 '18 at 22:56








1




1




$begingroup$
The condition $J^2 = - I$ is definitely not true just for integrable $J$. For example, $S^6$ has an almost complex structure $J$ coming from thinking of it as the unit octonians, but this almost complex structure is not integrable. In your computation, it's not clear to me that $J[JX,Y] = J^2XY - JYJX$, and similarly for the third term. I agree that $J(V+W) = JV + JW$ for any vectors $V$ and $W$, but when you write $[JX,Y] = JXY - YJX$, you have to remember that the terms $JXY$ and $YJX$ are not actually vector fields themselves, so there is no reason for $J$ to distribute over them....
$endgroup$
– Jason DeVito
Nov 30 '18 at 19:28




$begingroup$
The condition $J^2 = - I$ is definitely not true just for integrable $J$. For example, $S^6$ has an almost complex structure $J$ coming from thinking of it as the unit octonians, but this almost complex structure is not integrable. In your computation, it's not clear to me that $J[JX,Y] = J^2XY - JYJX$, and similarly for the third term. I agree that $J(V+W) = JV + JW$ for any vectors $V$ and $W$, but when you write $[JX,Y] = JXY - YJX$, you have to remember that the terms $JXY$ and $YJX$ are not actually vector fields themselves, so there is no reason for $J$ to distribute over them....
$endgroup$
– Jason DeVito
Nov 30 '18 at 19:28












$begingroup$
Perfect ... that answers it! you got me spot on :)
$endgroup$
– Kong
Nov 30 '18 at 19:32




$begingroup$
Perfect ... that answers it! you got me spot on :)
$endgroup$
– Kong
Nov 30 '18 at 19:32












$begingroup$
Well, I wish I knew how to actually do the computation!
$endgroup$
– Jason DeVito
Nov 30 '18 at 19:35




$begingroup$
Well, I wish I knew how to actually do the computation!
$endgroup$
– Jason DeVito
Nov 30 '18 at 19:35




1




1




$begingroup$
Hint: If $X$ is any tangent vector, then $X-iJX$ is an $i$-eigenvector of $J$, and $X+iJX$ is a $(-i)$-eigenvector.
$endgroup$
– Jack Lee
Nov 30 '18 at 22:56




$begingroup$
Hint: If $X$ is any tangent vector, then $X-iJX$ is an $i$-eigenvector of $J$, and $X+iJX$ is a $(-i)$-eigenvector.
$endgroup$
– Jack Lee
Nov 30 '18 at 22:56










0






active

oldest

votes











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3020336%2fvanishing-of-the-nijenhuis-tensor%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3020336%2fvanishing-of-the-nijenhuis-tensor%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

mysqli_query(): Empty query in /home/lucindabrummitt/public_html/blog/wp-includes/wp-db.php on line 1924

How to change which sound is reproduced for terminal bell?

Can I use Tabulator js library in my java Spring + Thymeleaf project?