Find x with $4^{x-1} = 9cdot x^{3-x}+7$
up vote
1
down vote
favorite
How to solve this exponential functuion?
$4^{x-1} = 9cdot x^{3-x}+7$
The solution is $x=3$.
exponential-function
add a comment |
up vote
1
down vote
favorite
How to solve this exponential functuion?
$4^{x-1} = 9cdot x^{3-x}+7$
The solution is $x=3$.
exponential-function
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
How to solve this exponential functuion?
$4^{x-1} = 9cdot x^{3-x}+7$
The solution is $x=3$.
exponential-function
How to solve this exponential functuion?
$4^{x-1} = 9cdot x^{3-x}+7$
The solution is $x=3$.
exponential-function
exponential-function
edited Nov 12 at 17:15
Richard
3521110
3521110
asked Nov 12 at 16:56
ScoobyDuh
405
405
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
3
down vote
accepted
Equations such as this very rarely have closed-form solutions, and there is no general method for finding them. In this case it's easy to verify that $x=3$ works. Using the fact that for $x > 2$, the right side is decreasing while the left side is increasing, it's not hard to show this is the only positive real solution.
So this is the only way to find the solution?
– ScoobyDuh
Nov 12 at 18:56
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
Equations such as this very rarely have closed-form solutions, and there is no general method for finding them. In this case it's easy to verify that $x=3$ works. Using the fact that for $x > 2$, the right side is decreasing while the left side is increasing, it's not hard to show this is the only positive real solution.
So this is the only way to find the solution?
– ScoobyDuh
Nov 12 at 18:56
add a comment |
up vote
3
down vote
accepted
Equations such as this very rarely have closed-form solutions, and there is no general method for finding them. In this case it's easy to verify that $x=3$ works. Using the fact that for $x > 2$, the right side is decreasing while the left side is increasing, it's not hard to show this is the only positive real solution.
So this is the only way to find the solution?
– ScoobyDuh
Nov 12 at 18:56
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
Equations such as this very rarely have closed-form solutions, and there is no general method for finding them. In this case it's easy to verify that $x=3$ works. Using the fact that for $x > 2$, the right side is decreasing while the left side is increasing, it's not hard to show this is the only positive real solution.
Equations such as this very rarely have closed-form solutions, and there is no general method for finding them. In this case it's easy to verify that $x=3$ works. Using the fact that for $x > 2$, the right side is decreasing while the left side is increasing, it's not hard to show this is the only positive real solution.
answered Nov 12 at 17:32
Robert Israel
313k23206452
313k23206452
So this is the only way to find the solution?
– ScoobyDuh
Nov 12 at 18:56
add a comment |
So this is the only way to find the solution?
– ScoobyDuh
Nov 12 at 18:56
So this is the only way to find the solution?
– ScoobyDuh
Nov 12 at 18:56
So this is the only way to find the solution?
– ScoobyDuh
Nov 12 at 18:56
add a comment |
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2995558%2ffind-x-with-4x-1-9-cdot-x3-x7%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown