Can I find x and y coordinates for the vertices of an octagon with sides of unequal lengths and angles?











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Knowing only the lengths of the sides, which are: 4.283, 4.227, 4.259, 4.259, 4.226, 4.246, 4.251, 4.248, can I find the x and y points of the vertices to within three decimal places? If so, how? I have a grade 10 level understanding of math.



After reading the replies, I can see how knowing only the lengths of the sides isn't enough. What if I knew the distances across opposite vertices?










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    No. You can't determine the shape of an octagon from the lengths of its sides. You can't even determine the shape of a quadrilateral from the lengths of its sides. You need more data.
    – TonyK
    Nov 12 at 3:20















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Knowing only the lengths of the sides, which are: 4.283, 4.227, 4.259, 4.259, 4.226, 4.246, 4.251, 4.248, can I find the x and y points of the vertices to within three decimal places? If so, how? I have a grade 10 level understanding of math.



After reading the replies, I can see how knowing only the lengths of the sides isn't enough. What if I knew the distances across opposite vertices?










share|cite|improve this question









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Marciz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 1




    No. You can't determine the shape of an octagon from the lengths of its sides. You can't even determine the shape of a quadrilateral from the lengths of its sides. You need more data.
    – TonyK
    Nov 12 at 3:20













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Knowing only the lengths of the sides, which are: 4.283, 4.227, 4.259, 4.259, 4.226, 4.246, 4.251, 4.248, can I find the x and y points of the vertices to within three decimal places? If so, how? I have a grade 10 level understanding of math.



After reading the replies, I can see how knowing only the lengths of the sides isn't enough. What if I knew the distances across opposite vertices?










share|cite|improve this question









New contributor




Marciz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











Knowing only the lengths of the sides, which are: 4.283, 4.227, 4.259, 4.259, 4.226, 4.246, 4.251, 4.248, can I find the x and y points of the vertices to within three decimal places? If so, how? I have a grade 10 level understanding of math.



After reading the replies, I can see how knowing only the lengths of the sides isn't enough. What if I knew the distances across opposite vertices?







geometry






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edited Nov 12 at 16:53





















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asked Nov 12 at 3:09









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  • 1




    No. You can't determine the shape of an octagon from the lengths of its sides. You can't even determine the shape of a quadrilateral from the lengths of its sides. You need more data.
    – TonyK
    Nov 12 at 3:20














  • 1




    No. You can't determine the shape of an octagon from the lengths of its sides. You can't even determine the shape of a quadrilateral from the lengths of its sides. You need more data.
    – TonyK
    Nov 12 at 3:20








1




1




No. You can't determine the shape of an octagon from the lengths of its sides. You can't even determine the shape of a quadrilateral from the lengths of its sides. You need more data.
– TonyK
Nov 12 at 3:20




No. You can't determine the shape of an octagon from the lengths of its sides. You can't even determine the shape of a quadrilateral from the lengths of its sides. You need more data.
– TonyK
Nov 12 at 3:20










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No. Basically for any polygon with four or more sides, you can squish it and move the vertices. Triangles are rigid, as shown by side-side-side.






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  • Of course! I would need angles.
    – Marciz
    Nov 12 at 4:21











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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes








up vote
1
down vote



accepted










No. Basically for any polygon with four or more sides, you can squish it and move the vertices. Triangles are rigid, as shown by side-side-side.






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  • Of course! I would need angles.
    – Marciz
    Nov 12 at 4:21















up vote
1
down vote



accepted










No. Basically for any polygon with four or more sides, you can squish it and move the vertices. Triangles are rigid, as shown by side-side-side.






share|cite|improve this answer





















  • Of course! I would need angles.
    – Marciz
    Nov 12 at 4:21













up vote
1
down vote



accepted







up vote
1
down vote



accepted






No. Basically for any polygon with four or more sides, you can squish it and move the vertices. Triangles are rigid, as shown by side-side-side.






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No. Basically for any polygon with four or more sides, you can squish it and move the vertices. Triangles are rigid, as shown by side-side-side.







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answered Nov 12 at 3:20









Ross Millikan

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  • Of course! I would need angles.
    – Marciz
    Nov 12 at 4:21


















  • Of course! I would need angles.
    – Marciz
    Nov 12 at 4:21
















Of course! I would need angles.
– Marciz
Nov 12 at 4:21




Of course! I would need angles.
– Marciz
Nov 12 at 4:21










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