Affine $mathfrak{su}(2)_k$ characters and Jacobi triple product











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In this post, the Kac character formula for affine $mathfrak{su}(2)_k$
$$chi_{ell}^{(k)}(tau,z) = frac{Theta_{ell+1,k+2}(tau,z)-Theta_{-ell-1,k+2}(tau,z)}{Theta_{1,2}(tau,z)-Theta_{-1,2}(tau,z)}$$
with
$$Theta_{ell,k}(tau,z)=sum_{nin mathbb{Z}+frac{ell}{2k}} q^{kn^2}y^{kn}, ,qquad (q=e^{2pi itau},,:y=e^{2pi iz})$$
is put in a nice form:
$$chi_{ell}^{(k)}(tau,z)=q^{m_{ell}}frac{sum_{ninmathbb{Z}}frac{sinleft[(ell+1+2n(k+2))pi zright]}{sin(pi z)}q^{n(ell+1)+n^2(k+2)}}{prod_{n>0}(1-q^n)(1-q^n y)(1-q^n y^{-1})}, .$$



I'm running into some trouble getting this expression. I'm guessing the Jacobi triple product identity is used for the denominator, but when I try to compute it I get
begin{align*} Theta_{1,2}(tau,z)-Theta_{-1,2}(tau,z)&=&sum_{ngeqslant 0}q^{2(n+1/4)^2}y^{2(n+1/4)}-sum_{ngeqslant 0}q^{2(n-1/4)^2}y^{2(n-1/4)}\&=& prod_{n>0}(1+q^n y^2)(1+q^n y^{-2})(1-q^{n+2}),.end{align*}
I'm running into the same kind of trouble for the numerator, so I suspect I'm not using the $Theta$ functions right... Some more details on this derivation would be much appreciated, or references where things are done a bit more explicitly!










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    up vote
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    In this post, the Kac character formula for affine $mathfrak{su}(2)_k$
    $$chi_{ell}^{(k)}(tau,z) = frac{Theta_{ell+1,k+2}(tau,z)-Theta_{-ell-1,k+2}(tau,z)}{Theta_{1,2}(tau,z)-Theta_{-1,2}(tau,z)}$$
    with
    $$Theta_{ell,k}(tau,z)=sum_{nin mathbb{Z}+frac{ell}{2k}} q^{kn^2}y^{kn}, ,qquad (q=e^{2pi itau},,:y=e^{2pi iz})$$
    is put in a nice form:
    $$chi_{ell}^{(k)}(tau,z)=q^{m_{ell}}frac{sum_{ninmathbb{Z}}frac{sinleft[(ell+1+2n(k+2))pi zright]}{sin(pi z)}q^{n(ell+1)+n^2(k+2)}}{prod_{n>0}(1-q^n)(1-q^n y)(1-q^n y^{-1})}, .$$



    I'm running into some trouble getting this expression. I'm guessing the Jacobi triple product identity is used for the denominator, but when I try to compute it I get
    begin{align*} Theta_{1,2}(tau,z)-Theta_{-1,2}(tau,z)&=&sum_{ngeqslant 0}q^{2(n+1/4)^2}y^{2(n+1/4)}-sum_{ngeqslant 0}q^{2(n-1/4)^2}y^{2(n-1/4)}\&=& prod_{n>0}(1+q^n y^2)(1+q^n y^{-2})(1-q^{n+2}),.end{align*}
    I'm running into the same kind of trouble for the numerator, so I suspect I'm not using the $Theta$ functions right... Some more details on this derivation would be much appreciated, or references where things are done a bit more explicitly!










    share|cite|improve this question









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    Ella is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      up vote
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      down vote

      favorite
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      up vote
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      In this post, the Kac character formula for affine $mathfrak{su}(2)_k$
      $$chi_{ell}^{(k)}(tau,z) = frac{Theta_{ell+1,k+2}(tau,z)-Theta_{-ell-1,k+2}(tau,z)}{Theta_{1,2}(tau,z)-Theta_{-1,2}(tau,z)}$$
      with
      $$Theta_{ell,k}(tau,z)=sum_{nin mathbb{Z}+frac{ell}{2k}} q^{kn^2}y^{kn}, ,qquad (q=e^{2pi itau},,:y=e^{2pi iz})$$
      is put in a nice form:
      $$chi_{ell}^{(k)}(tau,z)=q^{m_{ell}}frac{sum_{ninmathbb{Z}}frac{sinleft[(ell+1+2n(k+2))pi zright]}{sin(pi z)}q^{n(ell+1)+n^2(k+2)}}{prod_{n>0}(1-q^n)(1-q^n y)(1-q^n y^{-1})}, .$$



      I'm running into some trouble getting this expression. I'm guessing the Jacobi triple product identity is used for the denominator, but when I try to compute it I get
      begin{align*} Theta_{1,2}(tau,z)-Theta_{-1,2}(tau,z)&=&sum_{ngeqslant 0}q^{2(n+1/4)^2}y^{2(n+1/4)}-sum_{ngeqslant 0}q^{2(n-1/4)^2}y^{2(n-1/4)}\&=& prod_{n>0}(1+q^n y^2)(1+q^n y^{-2})(1-q^{n+2}),.end{align*}
      I'm running into the same kind of trouble for the numerator, so I suspect I'm not using the $Theta$ functions right... Some more details on this derivation would be much appreciated, or references where things are done a bit more explicitly!










      share|cite|improve this question









      New contributor




      Ella is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      In this post, the Kac character formula for affine $mathfrak{su}(2)_k$
      $$chi_{ell}^{(k)}(tau,z) = frac{Theta_{ell+1,k+2}(tau,z)-Theta_{-ell-1,k+2}(tau,z)}{Theta_{1,2}(tau,z)-Theta_{-1,2}(tau,z)}$$
      with
      $$Theta_{ell,k}(tau,z)=sum_{nin mathbb{Z}+frac{ell}{2k}} q^{kn^2}y^{kn}, ,qquad (q=e^{2pi itau},,:y=e^{2pi iz})$$
      is put in a nice form:
      $$chi_{ell}^{(k)}(tau,z)=q^{m_{ell}}frac{sum_{ninmathbb{Z}}frac{sinleft[(ell+1+2n(k+2))pi zright]}{sin(pi z)}q^{n(ell+1)+n^2(k+2)}}{prod_{n>0}(1-q^n)(1-q^n y)(1-q^n y^{-1})}, .$$



      I'm running into some trouble getting this expression. I'm guessing the Jacobi triple product identity is used for the denominator, but when I try to compute it I get
      begin{align*} Theta_{1,2}(tau,z)-Theta_{-1,2}(tau,z)&=&sum_{ngeqslant 0}q^{2(n+1/4)^2}y^{2(n+1/4)}-sum_{ngeqslant 0}q^{2(n-1/4)^2}y^{2(n-1/4)}\&=& prod_{n>0}(1+q^n y^2)(1+q^n y^{-2})(1-q^{n+2}),.end{align*}
      I'm running into the same kind of trouble for the numerator, so I suspect I'm not using the $Theta$ functions right... Some more details on this derivation would be much appreciated, or references where things are done a bit more explicitly!







      representation-theory lie-algebras characters






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      edited Nov 12 at 16:53





















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      asked Nov 10 at 17:12









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