Python : Control the number of variations entered by user
0
I have a script where the user decides how many titles or images he wants to enter. The maximum is 3 titles and 3 images and my script should create unique variations of the titles and images. If the user enters 3 titles 2 images, my script should create 6 variations:
Title1 + image1
Title1 + image2
Title2 + image1
Title2 + image2
Title3 + image1
Title3 + image2
Here is my code that is working ok but I was wondering if there is a lighter way to handle this case figure:
titleNbr = 3
imageNbr = 3
if titleNbr == 1 and imageNbr == 1:
print("No variation")
if titleNbr == 1 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
if titleNbr == 1 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
if titleNbr == 2 and imageNbr == 1:
print("Variations : Title1 + image1")
print("Variations : Title2 + image1")
if titleNbr == 2 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
if titleNbr == 2 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title2 + image3")
if titleNbr == 3 and imageNbr == 1:
print("Variations : Title1 + image1")
print("Variations : Title2 + image1")
print("Variations : Title3 + image1")
if titleNbr == 3 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title3 + image1")
print("Variations : Title3 + image2")
if titleNbr == 3 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title2 + image3")
print("Variations : Title3 + image1")
print("Variations : Title3 + image2")
print("Variations : Title3 + image3")
Thank you.
python
asked Nov 22 '18 at 4:57
Creek BarbaraCreek Barbara
18610
add a comment |
0
I have a script where the user decides how many titles or images he wants to enter. The maximum is 3 titles and 3 images and my script should create unique variations of the titles and images. If the user enters 3 titles 2 images, my script should create 6 variations:
Title1 + image1
Title1 + image2
Title2 + image1
Title2 + image2
Title3 + image1
Title3 + image2
Here is my code that is working ok but I was wondering if there is a lighter way to handle this case figure:
titleNbr = 3
imageNbr = 3
if titleNbr == 1 and imageNbr == 1:
print("No variation")
if titleNbr == 1 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
if titleNbr == 1 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
if titleNbr == 2 and imageNbr == 1:
print("Variations : Title1 + image1")
print("Variations : Title2 + image1")
if titleNbr == 2 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
if titleNbr == 2 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title2 + image3")
if titleNbr == 3 and imageNbr == 1:
print("Variations : Title1 + image1")
print("Variations : Title2 + image1")
print("Variations : Title3 + image1")
if titleNbr == 3 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title3 + image1")
print("Variations : Title3 + image2")
if titleNbr == 3 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title2 + image3")
print("Variations : Title3 + image1")
print("Variations : Title3 + image2")
print("Variations : Title3 + image3")
Thank you.
python
asked Nov 22 '18 at 4:57
Creek BarbaraCreek Barbara
18610
add a comment |
0
0
0
I have a script where the user decides how many titles or images he wants to enter. The maximum is 3 titles and 3 images and my script should create unique variations of the titles and images. If the user enters 3 titles 2 images, my script should create 6 variations:
Title1 + image1
Title1 + image2
Title2 + image1
Title2 + image2
Title3 + image1
Title3 + image2
Here is my code that is working ok but I was wondering if there is a lighter way to handle this case figure:
titleNbr = 3
imageNbr = 3
if titleNbr == 1 and imageNbr == 1:
print("No variation")
if titleNbr == 1 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
if titleNbr == 1 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
if titleNbr == 2 and imageNbr == 1:
print("Variations : Title1 + image1")
print("Variations : Title2 + image1")
if titleNbr == 2 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
if titleNbr == 2 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title2 + image3")
if titleNbr == 3 and imageNbr == 1:
print("Variations : Title1 + image1")
print("Variations : Title2 + image1")
print("Variations : Title3 + image1")
if titleNbr == 3 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title3 + image1")
print("Variations : Title3 + image2")
if titleNbr == 3 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title2 + image3")
print("Variations : Title3 + image1")
print("Variations : Title3 + image2")
print("Variations : Title3 + image3")
Thank you.
python
asked Nov 22 '18 at 4:57
Creek BarbaraCreek Barbara
18610
I have a script where the user decides how many titles or images he wants to enter. The maximum is 3 titles and 3 images and my script should create unique variations of the titles and images. If the user enters 3 titles 2 images, my script should create 6 variations:
Title1 + image1
Title1 + image2
Title2 + image1
Title2 + image2
Title3 + image1
Title3 + image2
Here is my code that is working ok but I was wondering if there is a lighter way to handle this case figure:
titleNbr = 3
imageNbr = 3
if titleNbr == 1 and imageNbr == 1:
print("No variation")
if titleNbr == 1 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
if titleNbr == 1 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
if titleNbr == 2 and imageNbr == 1:
print("Variations : Title1 + image1")
print("Variations : Title2 + image1")
if titleNbr == 2 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
if titleNbr == 2 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title2 + image3")
if titleNbr == 3 and imageNbr == 1:
print("Variations : Title1 + image1")
print("Variations : Title2 + image1")
print("Variations : Title3 + image1")
if titleNbr == 3 and imageNbr == 2:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title3 + image1")
print("Variations : Title3 + image2")
if titleNbr == 3 and imageNbr == 3:
print("Variations : Title1 + image1")
print("Variations : Title1 + image2")
print("Variations : Title1 + image3")
print("Variations : Title2 + image1")
print("Variations : Title2 + image2")
print("Variations : Title2 + image3")
print("Variations : Title3 + image1")
print("Variations : Title3 + image2")
print("Variations : Title3 + image3")
Thank you.
python
python
asked Nov 22 '18 at 4:57
Creek BarbaraCreek Barbara
18610
asked Nov 22 '18 at 4:57
Creek BarbaraCreek Barbara
18610
asked Nov 22 '18 at 4:57
Creek BarbaraCreek Barbara
18610
asked Nov 22 '18 at 4:57
Creek BarbaraCreek Barbara
18610
asked Nov 22 '18 at 4:57
Creek BarbaraCreek Barbara
18610
18610
add a comment |
add a comment |
1 Answer
1
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You can do this by iterating from 1 to the title number and then from one to the image number, and just appending this number to your strings. For example:
titleNbr = 3
imageNbr = 3
if titleNbr == 1 and imageNbr == 1:
print("No variation")
else:
for i in range(1, titleNbr + 1):
for j in range(1, imageNbr + 1):
print("Variations : Title" + str(i) + " + image" + str(j))
Let me know if you need clarification on any parts of this code!
answered Nov 22 '18 at 5:27
Unsolved CypherUnsolved Cypher
510316
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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active
oldest
votes
1
You can do this by iterating from 1 to the title number and then from one to the image number, and just appending this number to your strings. For example:
titleNbr = 3
imageNbr = 3
if titleNbr == 1 and imageNbr == 1:
print("No variation")
else:
for i in range(1, titleNbr + 1):
for j in range(1, imageNbr + 1):
print("Variations : Title" + str(i) + " + image" + str(j))
Let me know if you need clarification on any parts of this code!
answered Nov 22 '18 at 5:27
Unsolved CypherUnsolved Cypher
510316
add a comment |
1
You can do this by iterating from 1 to the title number and then from one to the image number, and just appending this number to your strings. For example:
titleNbr = 3
imageNbr = 3
if titleNbr == 1 and imageNbr == 1:
print("No variation")
else:
for i in range(1, titleNbr + 1):
for j in range(1, imageNbr + 1):
print("Variations : Title" + str(i) + " + image" + str(j))
Let me know if you need clarification on any parts of this code!
answered Nov 22 '18 at 5:27
Unsolved CypherUnsolved Cypher
510316
add a comment |
1
1
1
You can do this by iterating from 1 to the title number and then from one to the image number, and just appending this number to your strings. For example:
titleNbr = 3
imageNbr = 3
if titleNbr == 1 and imageNbr == 1:
print("No variation")
else:
for i in range(1, titleNbr + 1):
for j in range(1, imageNbr + 1):
print("Variations : Title" + str(i) + " + image" + str(j))
Let me know if you need clarification on any parts of this code!
answered Nov 22 '18 at 5:27
Unsolved CypherUnsolved Cypher
510316
You can do this by iterating from 1 to the title number and then from one to the image number, and just appending this number to your strings. For example:
titleNbr = 3
imageNbr = 3
if titleNbr == 1 and imageNbr == 1:
print("No variation")
else:
for i in range(1, titleNbr + 1):
for j in range(1, imageNbr + 1):
print("Variations : Title" + str(i) + " + image" + str(j))
Let me know if you need clarification on any parts of this code!
answered Nov 22 '18 at 5:27
Unsolved CypherUnsolved Cypher
510316
answered Nov 22 '18 at 5:27
Unsolved CypherUnsolved Cypher
510316
answered Nov 22 '18 at 5:27
Unsolved CypherUnsolved Cypher
510316
answered Nov 22 '18 at 5:27
Unsolved CypherUnsolved Cypher
510316
510316
add a comment |
add a comment |
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