A problem with benzene ring and chemfig
I want to create a Benzene ring with carbon atoms placed at the six nodes of the ring. I am using chemfig package to achieve this. But it so happens that the bond is actually going into the carbon atom at one of the sites.
MWE and output is appended below.
documentclass{article}
usepackage{chemfig}
begin{document}
chemfig{*6(C(-H)=C(-H)-C(-H)=C(-H)-C(-H)=C(-H)-)}
end{document}
Ideally all the bond lengths should be the same, but somehow only on the atom seems to be a problem. Any ideas how to resolve this?
chemfig
edited Mar 22 at 21:16
Sebastiano
11.5k42164
asked Feb 26 '18 at 5:41
DamitrDamitr
709413
add a comment |
I want to create a Benzene ring with carbon atoms placed at the six nodes of the ring. I am using chemfig package to achieve this. But it so happens that the bond is actually going into the carbon atom at one of the sites.
MWE and output is appended below.
documentclass{article}
usepackage{chemfig}
begin{document}
chemfig{*6(C(-H)=C(-H)-C(-H)=C(-H)-C(-H)=C(-H)-)}
end{document}
Ideally all the bond lengths should be the same, but somehow only on the atom seems to be a problem. Any ideas how to resolve this?
chemfig
edited Mar 22 at 21:16
Sebastiano
11.5k42164
asked Feb 26 '18 at 5:41
DamitrDamitr
709413
add a comment |
I want to create a Benzene ring with carbon atoms placed at the six nodes of the ring. I am using chemfig package to achieve this. But it so happens that the bond is actually going into the carbon atom at one of the sites.
MWE and output is appended below.
documentclass{article}
usepackage{chemfig}
begin{document}
chemfig{*6(C(-H)=C(-H)-C(-H)=C(-H)-C(-H)=C(-H)-)}
end{document}
Ideally all the bond lengths should be the same, but somehow only on the atom seems to be a problem. Any ideas how to resolve this?
chemfig
edited Mar 22 at 21:16
Sebastiano
11.5k42164
asked Feb 26 '18 at 5:41
DamitrDamitr
709413
I want to create a Benzene ring with carbon atoms placed at the six nodes of the ring. I am using chemfig package to achieve this. But it so happens that the bond is actually going into the carbon atom at one of the sites.
MWE and output is appended below.
documentclass{article}
usepackage{chemfig}
begin{document}
chemfig{*6(C(-H)=C(-H)-C(-H)=C(-H)-C(-H)=C(-H)-)}
end{document}
Ideally all the bond lengths should be the same, but somehow only on the atom seems to be a problem. Any ideas how to resolve this?
chemfig
chemfig
edited Mar 22 at 21:16
Sebastiano
11.5k42164
asked Feb 26 '18 at 5:41
DamitrDamitr
709413
edited Mar 22 at 21:16
Sebastiano
11.5k42164
asked Feb 26 '18 at 5:41
DamitrDamitr
709413
edited Mar 22 at 21:16
Sebastiano
11.5k42164
edited Mar 22 at 21:16
Sebastiano
11.5k42164
edited Mar 22 at 21:16
Sebastiano
11.5k42164
11.5k42164
asked Feb 26 '18 at 5:41
DamitrDamitr
709413
asked Feb 26 '18 at 5:41
DamitrDamitr
709413
asked Feb 26 '18 at 5:41
DamitrDamitr
709413
709413
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Ok, got the correct configuration by moving the first Carbon atom outside the ring.
chemfig{C*6((-H)=C(-H)-C(-H)=C(-H)-C(-H)=C(-H)-)}
answered Feb 26 '18 at 6:37
DamitrDamitr
709413
More information on this topic can be found in chapter 10 of thechemfigmanual: 'chemfigcan easily draw regular polygons. The idea is to attach a ring to an<atom>outside the ring with this syntax:<atom>*<n>(<code>)<n>is the number of sides of the polygon and the<code>describes the bonds and groups of atoms which makeup its edges and vertices. This code mustbegin with a bond because the atom is outside the ring.'
– leandriis
Mar 22 at 21:23
add a comment |
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Ok, got the correct configuration by moving the first Carbon atom outside the ring.
chemfig{C*6((-H)=C(-H)-C(-H)=C(-H)-C(-H)=C(-H)-)}
answered Feb 26 '18 at 6:37
DamitrDamitr
709413
More information on this topic can be found in chapter 10 of thechemfigmanual: 'chemfigcan easily draw regular polygons. The idea is to attach a ring to an<atom>outside the ring with this syntax:<atom>*<n>(<code>)<n>is the number of sides of the polygon and the<code>describes the bonds and groups of atoms which makeup its edges and vertices. This code mustbegin with a bond because the atom is outside the ring.'
– leandriis
Mar 22 at 21:23
add a comment |
Ok, got the correct configuration by moving the first Carbon atom outside the ring.
chemfig{C*6((-H)=C(-H)-C(-H)=C(-H)-C(-H)=C(-H)-)}
answered Feb 26 '18 at 6:37
DamitrDamitr
709413
More information on this topic can be found in chapter 10 of thechemfigmanual: 'chemfigcan easily draw regular polygons. The idea is to attach a ring to an<atom>outside the ring with this syntax:<atom>*<n>(<code>)<n>is the number of sides of the polygon and the<code>describes the bonds and groups of atoms which makeup its edges and vertices. This code mustbegin with a bond because the atom is outside the ring.'
– leandriis
Mar 22 at 21:23
add a comment |
Ok, got the correct configuration by moving the first Carbon atom outside the ring.
chemfig{C*6((-H)=C(-H)-C(-H)=C(-H)-C(-H)=C(-H)-)}
answered Feb 26 '18 at 6:37
DamitrDamitr
709413
Ok, got the correct configuration by moving the first Carbon atom outside the ring.
chemfig{C*6((-H)=C(-H)-C(-H)=C(-H)-C(-H)=C(-H)-)}
answered Feb 26 '18 at 6:37
DamitrDamitr
709413
answered Feb 26 '18 at 6:37
DamitrDamitr
709413
answered Feb 26 '18 at 6:37
DamitrDamitr
709413
answered Feb 26 '18 at 6:37
DamitrDamitr
709413
709413
More information on this topic can be found in chapter 10 of thechemfigmanual: 'chemfigcan easily draw regular polygons. The idea is to attach a ring to an<atom>outside the ring with this syntax:<atom>*<n>(<code>)<n>is the number of sides of the polygon and the<code>describes the bonds and groups of atoms which makeup its edges and vertices. This code mustbegin with a bond because the atom is outside the ring.'
– leandriis
Mar 22 at 21:23
add a comment |
More information on this topic can be found in chapter 10 of thechemfigmanual: 'chemfigcan easily draw regular polygons. The idea is to attach a ring to an<atom>outside the ring with this syntax:<atom>*<n>(<code>)<n>is the number of sides of the polygon and the<code>describes the bonds and groups of atoms which makeup its edges and vertices. This code mustbegin with a bond because the atom is outside the ring.'
– leandriis
Mar 22 at 21:23
More information on this topic can be found in chapter 10 of the
chemfig manual: 'chemfig can easily draw regular polygons. The idea is to attach a ring to an <atom> outside the ring with this syntax: <atom>*<n>(<code>)<n>is the number of sides of the polygon and the <code> describes the bonds and groups of atoms which makeup its edges and vertices. This code mustbegin with a bond because the atom is outside the ring.'– leandriis
Mar 22 at 21:23
More information on this topic can be found in chapter 10 of the
chemfig manual: 'chemfig can easily draw regular polygons. The idea is to attach a ring to an <atom> outside the ring with this syntax: <atom>*<n>(<code>)<n>is the number of sides of the polygon and the <code> describes the bonds and groups of atoms which makeup its edges and vertices. This code mustbegin with a bond because the atom is outside the ring.'– leandriis
Mar 22 at 21:23
add a comment |
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