Cross product related question [closed]
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Prove that $langle atimes b,ctimes drangle + langle btimes c,atimes drangle +langle ctimes a, btimes drangle = 0$
where $a, b, c, d$ belong to $mathbb{R}^{3}$.
linear-algebra
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closed as off-topic by Antonios-Alexandros Robotis, Davide Giraudo, Shailesh, mrtaurho, Eevee Trainer Dec 28 '18 at 3:01
This question appears to be off-topic. The users who voted to close gave this specific reason:
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$begingroup$
Prove that $langle atimes b,ctimes drangle + langle btimes c,atimes drangle +langle ctimes a, btimes drangle = 0$
where $a, b, c, d$ belong to $mathbb{R}^{3}$.
linear-algebra
$endgroup$
closed as off-topic by Antonios-Alexandros Robotis, Davide Giraudo, Shailesh, mrtaurho, Eevee Trainer Dec 28 '18 at 3:01
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Antonios-Alexandros Robotis, Davide Giraudo, Shailesh, mrtaurho, Eevee Trainer
If this question can be reworded to fit the rules in the help center, please edit the question.
1
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Can you put any context and/or what have you tried?
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– Tito Eliatron
Dec 27 '18 at 18:27
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$begingroup$
Prove that $langle atimes b,ctimes drangle + langle btimes c,atimes drangle +langle ctimes a, btimes drangle = 0$
where $a, b, c, d$ belong to $mathbb{R}^{3}$.
linear-algebra
$endgroup$
Prove that $langle atimes b,ctimes drangle + langle btimes c,atimes drangle +langle ctimes a, btimes drangle = 0$
where $a, b, c, d$ belong to $mathbb{R}^{3}$.
linear-algebra
linear-algebra
edited Dec 27 '18 at 23:06
Eric Wofsey
193k14220352
193k14220352
asked Dec 27 '18 at 18:26
Atanu MondalAtanu Mondal
1
1
closed as off-topic by Antonios-Alexandros Robotis, Davide Giraudo, Shailesh, mrtaurho, Eevee Trainer Dec 28 '18 at 3:01
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Antonios-Alexandros Robotis, Davide Giraudo, Shailesh, mrtaurho, Eevee Trainer
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Antonios-Alexandros Robotis, Davide Giraudo, Shailesh, mrtaurho, Eevee Trainer Dec 28 '18 at 3:01
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Antonios-Alexandros Robotis, Davide Giraudo, Shailesh, mrtaurho, Eevee Trainer
If this question can be reworded to fit the rules in the help center, please edit the question.
1
$begingroup$
Can you put any context and/or what have you tried?
$endgroup$
– Tito Eliatron
Dec 27 '18 at 18:27
add a comment |
1
$begingroup$
Can you put any context and/or what have you tried?
$endgroup$
– Tito Eliatron
Dec 27 '18 at 18:27
1
1
$begingroup$
Can you put any context and/or what have you tried?
$endgroup$
– Tito Eliatron
Dec 27 '18 at 18:27
$begingroup$
Can you put any context and/or what have you tried?
$endgroup$
– Tito Eliatron
Dec 27 '18 at 18:27
add a comment |
1 Answer
1
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This is effectively a specialization of the 3-dimensional Binet-Cauchy Identity or Lagrange's Identity. First show the following (you can expand both sides to verify):
$langle atimes b,ctimes drangle = (atimes b)cdot (ctimes d)=(acdot c)(bcdot d)-(acdot d)(bcdot c).$
$langle btimes c,atimes drangle = (bcdot a)(ccdot d)-(bcdot d)(acdot c).$
$langle ctimes a,btimes drangle = (ccdot b)(acdot d)-(ccdot d)(acdot b).$
Now add them up.
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add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
This is effectively a specialization of the 3-dimensional Binet-Cauchy Identity or Lagrange's Identity. First show the following (you can expand both sides to verify):
$langle atimes b,ctimes drangle = (atimes b)cdot (ctimes d)=(acdot c)(bcdot d)-(acdot d)(bcdot c).$
$langle btimes c,atimes drangle = (bcdot a)(ccdot d)-(bcdot d)(acdot c).$
$langle ctimes a,btimes drangle = (ccdot b)(acdot d)-(ccdot d)(acdot b).$
Now add them up.
$endgroup$
add a comment |
$begingroup$
This is effectively a specialization of the 3-dimensional Binet-Cauchy Identity or Lagrange's Identity. First show the following (you can expand both sides to verify):
$langle atimes b,ctimes drangle = (atimes b)cdot (ctimes d)=(acdot c)(bcdot d)-(acdot d)(bcdot c).$
$langle btimes c,atimes drangle = (bcdot a)(ccdot d)-(bcdot d)(acdot c).$
$langle ctimes a,btimes drangle = (ccdot b)(acdot d)-(ccdot d)(acdot b).$
Now add them up.
$endgroup$
add a comment |
$begingroup$
This is effectively a specialization of the 3-dimensional Binet-Cauchy Identity or Lagrange's Identity. First show the following (you can expand both sides to verify):
$langle atimes b,ctimes drangle = (atimes b)cdot (ctimes d)=(acdot c)(bcdot d)-(acdot d)(bcdot c).$
$langle btimes c,atimes drangle = (bcdot a)(ccdot d)-(bcdot d)(acdot c).$
$langle ctimes a,btimes drangle = (ccdot b)(acdot d)-(ccdot d)(acdot b).$
Now add them up.
$endgroup$
This is effectively a specialization of the 3-dimensional Binet-Cauchy Identity or Lagrange's Identity. First show the following (you can expand both sides to verify):
$langle atimes b,ctimes drangle = (atimes b)cdot (ctimes d)=(acdot c)(bcdot d)-(acdot d)(bcdot c).$
$langle btimes c,atimes drangle = (bcdot a)(ccdot d)-(bcdot d)(acdot c).$
$langle ctimes a,btimes drangle = (ccdot b)(acdot d)-(ccdot d)(acdot b).$
Now add them up.
answered Dec 27 '18 at 18:56
Alex R.Alex R.
25.2k12452
25.2k12452
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add a comment |
1
$begingroup$
Can you put any context and/or what have you tried?
$endgroup$
– Tito Eliatron
Dec 27 '18 at 18:27