Characteristic polynomial determines three reducible elements (line pairs) in the pencil of plane conics












0












$begingroup$


Let $eta_i,0leq ileq 4$ be 4 variables and $eta_0 x^2+4eta_1 x^3y+6eta_2 x^2y^2+4eta_3 xy^3+eta_4 y^4$ be the associated quadratic form. Consider $U=x^2,V=2xy, W=y^2$. Then the quadratic form transforms into $$eta_0 U^2+2eta_2UV+eta_2(V^2+2UW)+2eta_3VW+eta_4W^2=0quad (1)$$ and there is an additional relation $$4UW-V^2=0quad (2)$$ Denote by $Q_1$ and $Q_2$ the associated quadratic forms of $(1)$ and $(2)$.



Consider $det(Q_1+lambda Q_2)=0$ for solving $lambda$ (i.e. $(1)+lambda(2)=0$ is associated quadratic form). Then plugging $lambda$ in $(U,V,W)^T(Q_1+lambda Q_2)(U,V,W)$, one will see the polynomial splits into linear factors.



$textbf{Q:}$ Why does the polynomial splits into linear factors? I could see there is a coordinate transformation s.t. $Q_1+lambda Q_2$ is effectively (2 by 2 matrix) $oplus 0$ by $det(Q_1+lambda Q_2)=0$. That 2 by 2 is quadratic as well. Hence it reduces to quadratic of 2 variables which splits over complex number. This seems very cumbersome.



Ref. An Introduction to Invariants and Moduli, Mukai, Remark 1.26 of Chapter 1, Sec. 3(b), pg 28.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    It won't show me page 27, but it does show pages 26 and 28. I recognize the 3 by 3 image of an element of the 2 by 2 modular group. Suggest you look up W. Magnus, Noneuclidean Tessellations and their groups. The relevant material goes back to a German book by Fricke and Klein, (1897), Lectures on Automorphic Forms. F+K has recently been translated into English. (I have a cheap reprint of the 1897 original).
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:08










  • $begingroup$
    books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:09










  • $begingroup$
    books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:13










  • $begingroup$
    magnus; the material I meant is on page 23, not shown here: books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:19






  • 1




    $begingroup$
    @WillJagy I can check chpt 3 of Magnus's book. Thanks.
    $endgroup$
    – user45765
    Dec 27 '18 at 22:29
















0












$begingroup$


Let $eta_i,0leq ileq 4$ be 4 variables and $eta_0 x^2+4eta_1 x^3y+6eta_2 x^2y^2+4eta_3 xy^3+eta_4 y^4$ be the associated quadratic form. Consider $U=x^2,V=2xy, W=y^2$. Then the quadratic form transforms into $$eta_0 U^2+2eta_2UV+eta_2(V^2+2UW)+2eta_3VW+eta_4W^2=0quad (1)$$ and there is an additional relation $$4UW-V^2=0quad (2)$$ Denote by $Q_1$ and $Q_2$ the associated quadratic forms of $(1)$ and $(2)$.



Consider $det(Q_1+lambda Q_2)=0$ for solving $lambda$ (i.e. $(1)+lambda(2)=0$ is associated quadratic form). Then plugging $lambda$ in $(U,V,W)^T(Q_1+lambda Q_2)(U,V,W)$, one will see the polynomial splits into linear factors.



$textbf{Q:}$ Why does the polynomial splits into linear factors? I could see there is a coordinate transformation s.t. $Q_1+lambda Q_2$ is effectively (2 by 2 matrix) $oplus 0$ by $det(Q_1+lambda Q_2)=0$. That 2 by 2 is quadratic as well. Hence it reduces to quadratic of 2 variables which splits over complex number. This seems very cumbersome.



Ref. An Introduction to Invariants and Moduli, Mukai, Remark 1.26 of Chapter 1, Sec. 3(b), pg 28.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    It won't show me page 27, but it does show pages 26 and 28. I recognize the 3 by 3 image of an element of the 2 by 2 modular group. Suggest you look up W. Magnus, Noneuclidean Tessellations and their groups. The relevant material goes back to a German book by Fricke and Klein, (1897), Lectures on Automorphic Forms. F+K has recently been translated into English. (I have a cheap reprint of the 1897 original).
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:08










  • $begingroup$
    books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:09










  • $begingroup$
    books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:13










  • $begingroup$
    magnus; the material I meant is on page 23, not shown here: books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:19






  • 1




    $begingroup$
    @WillJagy I can check chpt 3 of Magnus's book. Thanks.
    $endgroup$
    – user45765
    Dec 27 '18 at 22:29














0












0








0





$begingroup$


Let $eta_i,0leq ileq 4$ be 4 variables and $eta_0 x^2+4eta_1 x^3y+6eta_2 x^2y^2+4eta_3 xy^3+eta_4 y^4$ be the associated quadratic form. Consider $U=x^2,V=2xy, W=y^2$. Then the quadratic form transforms into $$eta_0 U^2+2eta_2UV+eta_2(V^2+2UW)+2eta_3VW+eta_4W^2=0quad (1)$$ and there is an additional relation $$4UW-V^2=0quad (2)$$ Denote by $Q_1$ and $Q_2$ the associated quadratic forms of $(1)$ and $(2)$.



Consider $det(Q_1+lambda Q_2)=0$ for solving $lambda$ (i.e. $(1)+lambda(2)=0$ is associated quadratic form). Then plugging $lambda$ in $(U,V,W)^T(Q_1+lambda Q_2)(U,V,W)$, one will see the polynomial splits into linear factors.



$textbf{Q:}$ Why does the polynomial splits into linear factors? I could see there is a coordinate transformation s.t. $Q_1+lambda Q_2$ is effectively (2 by 2 matrix) $oplus 0$ by $det(Q_1+lambda Q_2)=0$. That 2 by 2 is quadratic as well. Hence it reduces to quadratic of 2 variables which splits over complex number. This seems very cumbersome.



Ref. An Introduction to Invariants and Moduli, Mukai, Remark 1.26 of Chapter 1, Sec. 3(b), pg 28.










share|cite|improve this question











$endgroup$




Let $eta_i,0leq ileq 4$ be 4 variables and $eta_0 x^2+4eta_1 x^3y+6eta_2 x^2y^2+4eta_3 xy^3+eta_4 y^4$ be the associated quadratic form. Consider $U=x^2,V=2xy, W=y^2$. Then the quadratic form transforms into $$eta_0 U^2+2eta_2UV+eta_2(V^2+2UW)+2eta_3VW+eta_4W^2=0quad (1)$$ and there is an additional relation $$4UW-V^2=0quad (2)$$ Denote by $Q_1$ and $Q_2$ the associated quadratic forms of $(1)$ and $(2)$.



Consider $det(Q_1+lambda Q_2)=0$ for solving $lambda$ (i.e. $(1)+lambda(2)=0$ is associated quadratic form). Then plugging $lambda$ in $(U,V,W)^T(Q_1+lambda Q_2)(U,V,W)$, one will see the polynomial splits into linear factors.



$textbf{Q:}$ Why does the polynomial splits into linear factors? I could see there is a coordinate transformation s.t. $Q_1+lambda Q_2$ is effectively (2 by 2 matrix) $oplus 0$ by $det(Q_1+lambda Q_2)=0$. That 2 by 2 is quadratic as well. Hence it reduces to quadratic of 2 variables which splits over complex number. This seems very cumbersome.



Ref. An Introduction to Invariants and Moduli, Mukai, Remark 1.26 of Chapter 1, Sec. 3(b), pg 28.







linear-algebra abstract-algebra algebraic-geometry






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 27 '18 at 22:28









user26857

39.5k124284




39.5k124284










asked Dec 27 '18 at 19:22









user45765user45765

2,7232724




2,7232724








  • 1




    $begingroup$
    It won't show me page 27, but it does show pages 26 and 28. I recognize the 3 by 3 image of an element of the 2 by 2 modular group. Suggest you look up W. Magnus, Noneuclidean Tessellations and their groups. The relevant material goes back to a German book by Fricke and Klein, (1897), Lectures on Automorphic Forms. F+K has recently been translated into English. (I have a cheap reprint of the 1897 original).
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:08










  • $begingroup$
    books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:09










  • $begingroup$
    books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:13










  • $begingroup$
    magnus; the material I meant is on page 23, not shown here: books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:19






  • 1




    $begingroup$
    @WillJagy I can check chpt 3 of Magnus's book. Thanks.
    $endgroup$
    – user45765
    Dec 27 '18 at 22:29














  • 1




    $begingroup$
    It won't show me page 27, but it does show pages 26 and 28. I recognize the 3 by 3 image of an element of the 2 by 2 modular group. Suggest you look up W. Magnus, Noneuclidean Tessellations and their groups. The relevant material goes back to a German book by Fricke and Klein, (1897), Lectures on Automorphic Forms. F+K has recently been translated into English. (I have a cheap reprint of the 1897 original).
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:08










  • $begingroup$
    books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:09










  • $begingroup$
    books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:13










  • $begingroup$
    magnus; the material I meant is on page 23, not shown here: books.google.com/…
    $endgroup$
    – Will Jagy
    Dec 27 '18 at 22:19






  • 1




    $begingroup$
    @WillJagy I can check chpt 3 of Magnus's book. Thanks.
    $endgroup$
    – user45765
    Dec 27 '18 at 22:29








1




1




$begingroup$
It won't show me page 27, but it does show pages 26 and 28. I recognize the 3 by 3 image of an element of the 2 by 2 modular group. Suggest you look up W. Magnus, Noneuclidean Tessellations and their groups. The relevant material goes back to a German book by Fricke and Klein, (1897), Lectures on Automorphic Forms. F+K has recently been translated into English. (I have a cheap reprint of the 1897 original).
$endgroup$
– Will Jagy
Dec 27 '18 at 22:08




$begingroup$
It won't show me page 27, but it does show pages 26 and 28. I recognize the 3 by 3 image of an element of the 2 by 2 modular group. Suggest you look up W. Magnus, Noneuclidean Tessellations and their groups. The relevant material goes back to a German book by Fricke and Klein, (1897), Lectures on Automorphic Forms. F+K has recently been translated into English. (I have a cheap reprint of the 1897 original).
$endgroup$
– Will Jagy
Dec 27 '18 at 22:08












$begingroup$
books.google.com/…
$endgroup$
– Will Jagy
Dec 27 '18 at 22:09




$begingroup$
books.google.com/…
$endgroup$
– Will Jagy
Dec 27 '18 at 22:09












$begingroup$
books.google.com/…
$endgroup$
– Will Jagy
Dec 27 '18 at 22:13




$begingroup$
books.google.com/…
$endgroup$
– Will Jagy
Dec 27 '18 at 22:13












$begingroup$
magnus; the material I meant is on page 23, not shown here: books.google.com/…
$endgroup$
– Will Jagy
Dec 27 '18 at 22:19




$begingroup$
magnus; the material I meant is on page 23, not shown here: books.google.com/…
$endgroup$
– Will Jagy
Dec 27 '18 at 22:19




1




1




$begingroup$
@WillJagy I can check chpt 3 of Magnus's book. Thanks.
$endgroup$
– user45765
Dec 27 '18 at 22:29




$begingroup$
@WillJagy I can check chpt 3 of Magnus's book. Thanks.
$endgroup$
– user45765
Dec 27 '18 at 22:29










0






active

oldest

votes












Your Answer








StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3054282%2fcharacteristic-polynomial-determines-three-reducible-elements-line-pairs-in-th%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3054282%2fcharacteristic-polynomial-determines-three-reducible-elements-line-pairs-in-th%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

How to change which sound is reproduced for terminal bell?

Can I use Tabulator js library in my java Spring + Thymeleaf project?

Title Spacing in Bjornstrup Chapter, Removing Chapter Number From Contents