Perfect forwarding in constructors (C++17)











up vote
13
down vote

favorite
2












Consider the following code



struct A {
A(int id) : id_ { id } {}

A(const A& rhs) { std::cout << "cctor from " +
std::to_string(rhs.id_) << std::endl; }
A(A&& rhs) { std::cout << "mctor from " +
std::to_string(rhs.id_) << std::endl; }

int id_;
};

template<typename T>
struct B1 {
constexpr B1(T&& x) noexcept : x_ { std::forward<T>(x) } {}

T x_;
};

template<typename T>
struct B2 {
constexpr B2(T&& x) noexcept;

T x_;
};

template<typename T>
constexpr
B2<T>::B2(
T&& x
) noexcept :
x_ { std::forward<T>(x) } {
}

int
main(
) {
A a { 1 };

//B1 b11 { a }; // Not compiling
B1 b12 { A { 2 } };

B2 b21 { a };
B2 b22 { A { 3 } };

return 0;
}


which yields



mctor from 2
mctor from 3


So it basically looks as if the externally defined constructor perfectly forwards the value category of its argument while the inline-defined constructor does not.



Is it that an externally defined constructor is handled like a function template (which perfectly forwards its arguments) or what's going on here?



Links to the appropriate section of the standard would be welcome.



I am using GCC 7.2.0.










share|improve this question




















  • 2




    Clang won't compile this B2 b21 { a };
    – AndyG
    Nov 28 at 12:46






  • 4




    I think that you have an imperfect understanding of what perfect forwarding means. Because your template argument is on the class, not the constructor, you are accepting r-value references, no forwarding references.
    – AndyG
    Nov 28 at 12:51






  • 1




    @AndyG: I think OP uses the wrong term, as there is the Template Argument Deduction with T&& (with T from class).
    – Jarod42
    Nov 28 at 12:56






  • 1




    To clarify OP's question: should b21 be B2<A&>, or should it not compile ?
    – Jarod42
    Nov 28 at 12:58








  • 1




    B1 and B2 should behave the same.
    – Jarod42
    Nov 28 at 13:00















up vote
13
down vote

favorite
2












Consider the following code



struct A {
A(int id) : id_ { id } {}

A(const A& rhs) { std::cout << "cctor from " +
std::to_string(rhs.id_) << std::endl; }
A(A&& rhs) { std::cout << "mctor from " +
std::to_string(rhs.id_) << std::endl; }

int id_;
};

template<typename T>
struct B1 {
constexpr B1(T&& x) noexcept : x_ { std::forward<T>(x) } {}

T x_;
};

template<typename T>
struct B2 {
constexpr B2(T&& x) noexcept;

T x_;
};

template<typename T>
constexpr
B2<T>::B2(
T&& x
) noexcept :
x_ { std::forward<T>(x) } {
}

int
main(
) {
A a { 1 };

//B1 b11 { a }; // Not compiling
B1 b12 { A { 2 } };

B2 b21 { a };
B2 b22 { A { 3 } };

return 0;
}


which yields



mctor from 2
mctor from 3


So it basically looks as if the externally defined constructor perfectly forwards the value category of its argument while the inline-defined constructor does not.



Is it that an externally defined constructor is handled like a function template (which perfectly forwards its arguments) or what's going on here?



Links to the appropriate section of the standard would be welcome.



I am using GCC 7.2.0.










share|improve this question




















  • 2




    Clang won't compile this B2 b21 { a };
    – AndyG
    Nov 28 at 12:46






  • 4




    I think that you have an imperfect understanding of what perfect forwarding means. Because your template argument is on the class, not the constructor, you are accepting r-value references, no forwarding references.
    – AndyG
    Nov 28 at 12:51






  • 1




    @AndyG: I think OP uses the wrong term, as there is the Template Argument Deduction with T&& (with T from class).
    – Jarod42
    Nov 28 at 12:56






  • 1




    To clarify OP's question: should b21 be B2<A&>, or should it not compile ?
    – Jarod42
    Nov 28 at 12:58








  • 1




    B1 and B2 should behave the same.
    – Jarod42
    Nov 28 at 13:00













up vote
13
down vote

favorite
2









up vote
13
down vote

favorite
2






2





Consider the following code



struct A {
A(int id) : id_ { id } {}

A(const A& rhs) { std::cout << "cctor from " +
std::to_string(rhs.id_) << std::endl; }
A(A&& rhs) { std::cout << "mctor from " +
std::to_string(rhs.id_) << std::endl; }

int id_;
};

template<typename T>
struct B1 {
constexpr B1(T&& x) noexcept : x_ { std::forward<T>(x) } {}

T x_;
};

template<typename T>
struct B2 {
constexpr B2(T&& x) noexcept;

T x_;
};

template<typename T>
constexpr
B2<T>::B2(
T&& x
) noexcept :
x_ { std::forward<T>(x) } {
}

int
main(
) {
A a { 1 };

//B1 b11 { a }; // Not compiling
B1 b12 { A { 2 } };

B2 b21 { a };
B2 b22 { A { 3 } };

return 0;
}


which yields



mctor from 2
mctor from 3


So it basically looks as if the externally defined constructor perfectly forwards the value category of its argument while the inline-defined constructor does not.



Is it that an externally defined constructor is handled like a function template (which perfectly forwards its arguments) or what's going on here?



Links to the appropriate section of the standard would be welcome.



I am using GCC 7.2.0.










share|improve this question















Consider the following code



struct A {
A(int id) : id_ { id } {}

A(const A& rhs) { std::cout << "cctor from " +
std::to_string(rhs.id_) << std::endl; }
A(A&& rhs) { std::cout << "mctor from " +
std::to_string(rhs.id_) << std::endl; }

int id_;
};

template<typename T>
struct B1 {
constexpr B1(T&& x) noexcept : x_ { std::forward<T>(x) } {}

T x_;
};

template<typename T>
struct B2 {
constexpr B2(T&& x) noexcept;

T x_;
};

template<typename T>
constexpr
B2<T>::B2(
T&& x
) noexcept :
x_ { std::forward<T>(x) } {
}

int
main(
) {
A a { 1 };

//B1 b11 { a }; // Not compiling
B1 b12 { A { 2 } };

B2 b21 { a };
B2 b22 { A { 3 } };

return 0;
}


which yields



mctor from 2
mctor from 3


So it basically looks as if the externally defined constructor perfectly forwards the value category of its argument while the inline-defined constructor does not.



Is it that an externally defined constructor is handled like a function template (which perfectly forwards its arguments) or what's going on here?



Links to the appropriate section of the standard would be welcome.



I am using GCC 7.2.0.







c++ gcc language-lawyer c++17 template-deduction






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 28 at 17:59









Peter Mortensen

13.4k1983111




13.4k1983111










asked Nov 28 at 12:39









plexando

9011




9011








  • 2




    Clang won't compile this B2 b21 { a };
    – AndyG
    Nov 28 at 12:46






  • 4




    I think that you have an imperfect understanding of what perfect forwarding means. Because your template argument is on the class, not the constructor, you are accepting r-value references, no forwarding references.
    – AndyG
    Nov 28 at 12:51






  • 1




    @AndyG: I think OP uses the wrong term, as there is the Template Argument Deduction with T&& (with T from class).
    – Jarod42
    Nov 28 at 12:56






  • 1




    To clarify OP's question: should b21 be B2<A&>, or should it not compile ?
    – Jarod42
    Nov 28 at 12:58








  • 1




    B1 and B2 should behave the same.
    – Jarod42
    Nov 28 at 13:00














  • 2




    Clang won't compile this B2 b21 { a };
    – AndyG
    Nov 28 at 12:46






  • 4




    I think that you have an imperfect understanding of what perfect forwarding means. Because your template argument is on the class, not the constructor, you are accepting r-value references, no forwarding references.
    – AndyG
    Nov 28 at 12:51






  • 1




    @AndyG: I think OP uses the wrong term, as there is the Template Argument Deduction with T&& (with T from class).
    – Jarod42
    Nov 28 at 12:56






  • 1




    To clarify OP's question: should b21 be B2<A&>, or should it not compile ?
    – Jarod42
    Nov 28 at 12:58








  • 1




    B1 and B2 should behave the same.
    – Jarod42
    Nov 28 at 13:00








2




2




Clang won't compile this B2 b21 { a };
– AndyG
Nov 28 at 12:46




Clang won't compile this B2 b21 { a };
– AndyG
Nov 28 at 12:46




4




4




I think that you have an imperfect understanding of what perfect forwarding means. Because your template argument is on the class, not the constructor, you are accepting r-value references, no forwarding references.
– AndyG
Nov 28 at 12:51




I think that you have an imperfect understanding of what perfect forwarding means. Because your template argument is on the class, not the constructor, you are accepting r-value references, no forwarding references.
– AndyG
Nov 28 at 12:51




1




1




@AndyG: I think OP uses the wrong term, as there is the Template Argument Deduction with T&& (with T from class).
– Jarod42
Nov 28 at 12:56




@AndyG: I think OP uses the wrong term, as there is the Template Argument Deduction with T&& (with T from class).
– Jarod42
Nov 28 at 12:56




1




1




To clarify OP's question: should b21 be B2<A&>, or should it not compile ?
– Jarod42
Nov 28 at 12:58






To clarify OP's question: should b21 be B2<A&>, or should it not compile ?
– Jarod42
Nov 28 at 12:58






1




1




B1 and B2 should behave the same.
– Jarod42
Nov 28 at 13:00




B1 and B2 should behave the same.
– Jarod42
Nov 28 at 13:00












2 Answers
2






active

oldest

votes

















up vote
9
down vote



accepted










It's a GCC bug. Forwarding references have a very clear cut definition:




[temp.deduct.call] (emphasis mine)



3 A forwarding reference is an rvalue reference to a
cv-unqualified template parameter that does not represent a template
parameter of a class template
(during class template argument
deduction ([over.match.class.deduct])). If P is a forwarding reference
and the argument is an lvalue, the type “lvalue reference to A” is
used in place of A for type deduction.




In both cases T names a template parameter of the enclosing class during CTAD, so it should not produce a forwarding reference either way. The c'tor being defined inline or outside the class definition has no bearing on this.






share|improve this answer





















  • You wouldn't happen to have any idea if this has been reported to the project?
    – jaked122
    Nov 28 at 18:11






  • 1




    @jaked122 - I gave the GCC bugzilla a quick search in an effort to complete the answer. And tried on the tip of the trunk that several online IDE's host (where it was reproduced). I'd guess it isn't a known bug, but I can't confirm
    – StoryTeller
    Nov 28 at 18:14










  • Bug report done #88252
    – Oliv
    Nov 28 at 20:01










  • Bug still present in latest snapshot (9.0.0 20181125 (experimental)).
    – plexando
    Nov 29 at 11:21










  • @plexando - The snapshot is from 2018 11 25 (I.e. Nov 25). The report in the comment above is from yesterday.
    – StoryTeller
    Nov 29 at 11:25


















up vote
6
down vote













It looks that GCC incorrectly treats T&& in an auto-generated deduction guide as a forwarding reference:



template <typename T>
B2(T&& x) -> B2<T>;


In this case T&& is a non-forwarding r-value reference, because it's a class parameter. Instead, GCC incorrectly deduces T=A& parameter type and B2<T>=B2<A&> class type, which collapses the reference type in the constructor, allowing the code to compile with an lvalue constructor argument:



constexpr B2(A& x) noexcept;


Class template argument deduction makes no distinction between inline and and out-of-line definitions. In this particular case, B2 b21 { a }; should fail.






share|improve this answer





















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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    9
    down vote



    accepted










    It's a GCC bug. Forwarding references have a very clear cut definition:




    [temp.deduct.call] (emphasis mine)



    3 A forwarding reference is an rvalue reference to a
    cv-unqualified template parameter that does not represent a template
    parameter of a class template
    (during class template argument
    deduction ([over.match.class.deduct])). If P is a forwarding reference
    and the argument is an lvalue, the type “lvalue reference to A” is
    used in place of A for type deduction.




    In both cases T names a template parameter of the enclosing class during CTAD, so it should not produce a forwarding reference either way. The c'tor being defined inline or outside the class definition has no bearing on this.






    share|improve this answer





















    • You wouldn't happen to have any idea if this has been reported to the project?
      – jaked122
      Nov 28 at 18:11






    • 1




      @jaked122 - I gave the GCC bugzilla a quick search in an effort to complete the answer. And tried on the tip of the trunk that several online IDE's host (where it was reproduced). I'd guess it isn't a known bug, but I can't confirm
      – StoryTeller
      Nov 28 at 18:14










    • Bug report done #88252
      – Oliv
      Nov 28 at 20:01










    • Bug still present in latest snapshot (9.0.0 20181125 (experimental)).
      – plexando
      Nov 29 at 11:21










    • @plexando - The snapshot is from 2018 11 25 (I.e. Nov 25). The report in the comment above is from yesterday.
      – StoryTeller
      Nov 29 at 11:25















    up vote
    9
    down vote



    accepted










    It's a GCC bug. Forwarding references have a very clear cut definition:




    [temp.deduct.call] (emphasis mine)



    3 A forwarding reference is an rvalue reference to a
    cv-unqualified template parameter that does not represent a template
    parameter of a class template
    (during class template argument
    deduction ([over.match.class.deduct])). If P is a forwarding reference
    and the argument is an lvalue, the type “lvalue reference to A” is
    used in place of A for type deduction.




    In both cases T names a template parameter of the enclosing class during CTAD, so it should not produce a forwarding reference either way. The c'tor being defined inline or outside the class definition has no bearing on this.






    share|improve this answer





















    • You wouldn't happen to have any idea if this has been reported to the project?
      – jaked122
      Nov 28 at 18:11






    • 1




      @jaked122 - I gave the GCC bugzilla a quick search in an effort to complete the answer. And tried on the tip of the trunk that several online IDE's host (where it was reproduced). I'd guess it isn't a known bug, but I can't confirm
      – StoryTeller
      Nov 28 at 18:14










    • Bug report done #88252
      – Oliv
      Nov 28 at 20:01










    • Bug still present in latest snapshot (9.0.0 20181125 (experimental)).
      – plexando
      Nov 29 at 11:21










    • @plexando - The snapshot is from 2018 11 25 (I.e. Nov 25). The report in the comment above is from yesterday.
      – StoryTeller
      Nov 29 at 11:25













    up vote
    9
    down vote



    accepted







    up vote
    9
    down vote



    accepted






    It's a GCC bug. Forwarding references have a very clear cut definition:




    [temp.deduct.call] (emphasis mine)



    3 A forwarding reference is an rvalue reference to a
    cv-unqualified template parameter that does not represent a template
    parameter of a class template
    (during class template argument
    deduction ([over.match.class.deduct])). If P is a forwarding reference
    and the argument is an lvalue, the type “lvalue reference to A” is
    used in place of A for type deduction.




    In both cases T names a template parameter of the enclosing class during CTAD, so it should not produce a forwarding reference either way. The c'tor being defined inline or outside the class definition has no bearing on this.






    share|improve this answer












    It's a GCC bug. Forwarding references have a very clear cut definition:




    [temp.deduct.call] (emphasis mine)



    3 A forwarding reference is an rvalue reference to a
    cv-unqualified template parameter that does not represent a template
    parameter of a class template
    (during class template argument
    deduction ([over.match.class.deduct])). If P is a forwarding reference
    and the argument is an lvalue, the type “lvalue reference to A” is
    used in place of A for type deduction.




    In both cases T names a template parameter of the enclosing class during CTAD, so it should not produce a forwarding reference either way. The c'tor being defined inline or outside the class definition has no bearing on this.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 28 at 12:53









    StoryTeller

    92.3k12183249




    92.3k12183249












    • You wouldn't happen to have any idea if this has been reported to the project?
      – jaked122
      Nov 28 at 18:11






    • 1




      @jaked122 - I gave the GCC bugzilla a quick search in an effort to complete the answer. And tried on the tip of the trunk that several online IDE's host (where it was reproduced). I'd guess it isn't a known bug, but I can't confirm
      – StoryTeller
      Nov 28 at 18:14










    • Bug report done #88252
      – Oliv
      Nov 28 at 20:01










    • Bug still present in latest snapshot (9.0.0 20181125 (experimental)).
      – plexando
      Nov 29 at 11:21










    • @plexando - The snapshot is from 2018 11 25 (I.e. Nov 25). The report in the comment above is from yesterday.
      – StoryTeller
      Nov 29 at 11:25


















    • You wouldn't happen to have any idea if this has been reported to the project?
      – jaked122
      Nov 28 at 18:11






    • 1




      @jaked122 - I gave the GCC bugzilla a quick search in an effort to complete the answer. And tried on the tip of the trunk that several online IDE's host (where it was reproduced). I'd guess it isn't a known bug, but I can't confirm
      – StoryTeller
      Nov 28 at 18:14










    • Bug report done #88252
      – Oliv
      Nov 28 at 20:01










    • Bug still present in latest snapshot (9.0.0 20181125 (experimental)).
      – plexando
      Nov 29 at 11:21










    • @plexando - The snapshot is from 2018 11 25 (I.e. Nov 25). The report in the comment above is from yesterday.
      – StoryTeller
      Nov 29 at 11:25
















    You wouldn't happen to have any idea if this has been reported to the project?
    – jaked122
    Nov 28 at 18:11




    You wouldn't happen to have any idea if this has been reported to the project?
    – jaked122
    Nov 28 at 18:11




    1




    1




    @jaked122 - I gave the GCC bugzilla a quick search in an effort to complete the answer. And tried on the tip of the trunk that several online IDE's host (where it was reproduced). I'd guess it isn't a known bug, but I can't confirm
    – StoryTeller
    Nov 28 at 18:14




    @jaked122 - I gave the GCC bugzilla a quick search in an effort to complete the answer. And tried on the tip of the trunk that several online IDE's host (where it was reproduced). I'd guess it isn't a known bug, but I can't confirm
    – StoryTeller
    Nov 28 at 18:14












    Bug report done #88252
    – Oliv
    Nov 28 at 20:01




    Bug report done #88252
    – Oliv
    Nov 28 at 20:01












    Bug still present in latest snapshot (9.0.0 20181125 (experimental)).
    – plexando
    Nov 29 at 11:21




    Bug still present in latest snapshot (9.0.0 20181125 (experimental)).
    – plexando
    Nov 29 at 11:21












    @plexando - The snapshot is from 2018 11 25 (I.e. Nov 25). The report in the comment above is from yesterday.
    – StoryTeller
    Nov 29 at 11:25




    @plexando - The snapshot is from 2018 11 25 (I.e. Nov 25). The report in the comment above is from yesterday.
    – StoryTeller
    Nov 29 at 11:25












    up vote
    6
    down vote













    It looks that GCC incorrectly treats T&& in an auto-generated deduction guide as a forwarding reference:



    template <typename T>
    B2(T&& x) -> B2<T>;


    In this case T&& is a non-forwarding r-value reference, because it's a class parameter. Instead, GCC incorrectly deduces T=A& parameter type and B2<T>=B2<A&> class type, which collapses the reference type in the constructor, allowing the code to compile with an lvalue constructor argument:



    constexpr B2(A& x) noexcept;


    Class template argument deduction makes no distinction between inline and and out-of-line definitions. In this particular case, B2 b21 { a }; should fail.






    share|improve this answer

























      up vote
      6
      down vote













      It looks that GCC incorrectly treats T&& in an auto-generated deduction guide as a forwarding reference:



      template <typename T>
      B2(T&& x) -> B2<T>;


      In this case T&& is a non-forwarding r-value reference, because it's a class parameter. Instead, GCC incorrectly deduces T=A& parameter type and B2<T>=B2<A&> class type, which collapses the reference type in the constructor, allowing the code to compile with an lvalue constructor argument:



      constexpr B2(A& x) noexcept;


      Class template argument deduction makes no distinction between inline and and out-of-line definitions. In this particular case, B2 b21 { a }; should fail.






      share|improve this answer























        up vote
        6
        down vote










        up vote
        6
        down vote









        It looks that GCC incorrectly treats T&& in an auto-generated deduction guide as a forwarding reference:



        template <typename T>
        B2(T&& x) -> B2<T>;


        In this case T&& is a non-forwarding r-value reference, because it's a class parameter. Instead, GCC incorrectly deduces T=A& parameter type and B2<T>=B2<A&> class type, which collapses the reference type in the constructor, allowing the code to compile with an lvalue constructor argument:



        constexpr B2(A& x) noexcept;


        Class template argument deduction makes no distinction between inline and and out-of-line definitions. In this particular case, B2 b21 { a }; should fail.






        share|improve this answer












        It looks that GCC incorrectly treats T&& in an auto-generated deduction guide as a forwarding reference:



        template <typename T>
        B2(T&& x) -> B2<T>;


        In this case T&& is a non-forwarding r-value reference, because it's a class parameter. Instead, GCC incorrectly deduces T=A& parameter type and B2<T>=B2<A&> class type, which collapses the reference type in the constructor, allowing the code to compile with an lvalue constructor argument:



        constexpr B2(A& x) noexcept;


        Class template argument deduction makes no distinction between inline and and out-of-line definitions. In this particular case, B2 b21 { a }; should fail.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 28 at 13:11









        Piotr Skotnicki

        34.4k470117




        34.4k470117






























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