Cfrgtkky

I would like to run ls and exclude certain files in the output.

When I run the following command, I get all files with each on one line:

$ ls -1

file1

file2

file3

temp

I would like to run this command in a way so it shows

$ ls -1 <insert magic here> temp

file1

file2

file3

ls -I <filename>

-I = Ignore the filename, i.e., don't list the specified file.

To ignore more than one file add an -I before each filename.

ls -I file1 -I file2

To ignore files by their name extensions do the following, for example.

ls -I "*.jpg" -I "*.svg"

For me if I use -I once, it works but if I use twice it doesn't.
e.g:
ls -I *.csv works.

But
ls -I *.csv -I *.txt doesn't work and returns txt files instead.

--ignore did the trick for me. This is what I needed and worked.

ls -lhrt --ignore="*.gz" --ignore="*.1"

That will list me files from log folder where it exclude old backup logs.

ls --ignore={"*.jpg","*.png","*.svg"}

I think that this produces the output you're looking for:

ls -1 !(temp)

Apparently, you need shopt -s extglob for that to work

(I have it enabled, so I guess some time in the distant past I found it useful and enabled it).

I guess you could also use grep to filter the output:

ls -1 | grep -v '^temp$'

Using a pipe and filters provides a lot more flexibility, and skills that are transferable to other commands/situations, though you might not be interested in that for this specific case.