How to make python count how many files are in a directory?
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Just by the title, you might think that this is a duplicate but it is not. I need to make my program count how many files with a specific ending such as .mp3 or .mp4 are in a directory. So if I have 10 .mp3 files in a directory I want my program to figure that out. After that, I need to list those files with numbers next to them so that the user can enter a number to launch that file. I need help with counting the files.
python directory
|
show 2 more comments
Just by the title, you might think that this is a duplicate but it is not. I need to make my program count how many files with a specific ending such as .mp3 or .mp4 are in a directory. So if I have 10 .mp3 files in a directory I want my program to figure that out. After that, I need to list those files with numbers next to them so that the user can enter a number to launch that file. I need help with counting the files.
python directory
1
Take a look at stackoverflow.com/questions/33635353/…
– KJH
Nov 23 '18 at 1:54
1
for file in glob.glob('/some/directory/*.mp3'):
– John Gordon
Nov 23 '18 at 1:57
Great for the first part but I still need help with the number part.
– Hrittik Chatterjee
Nov 23 '18 at 1:59
btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.
– Hrittik Chatterjee
Nov 23 '18 at 2:17
Split the filename on the dot; feed the extensions into collections.Counter.
– wwii
Nov 23 '18 at 2:19
|
show 2 more comments
Just by the title, you might think that this is a duplicate but it is not. I need to make my program count how many files with a specific ending such as .mp3 or .mp4 are in a directory. So if I have 10 .mp3 files in a directory I want my program to figure that out. After that, I need to list those files with numbers next to them so that the user can enter a number to launch that file. I need help with counting the files.
python directory
Just by the title, you might think that this is a duplicate but it is not. I need to make my program count how many files with a specific ending such as .mp3 or .mp4 are in a directory. So if I have 10 .mp3 files in a directory I want my program to figure that out. After that, I need to list those files with numbers next to them so that the user can enter a number to launch that file. I need help with counting the files.
python directory
python directory
edited Nov 23 '18 at 2:16
Hrittik Chatterjee
asked Nov 23 '18 at 1:51
Hrittik ChatterjeeHrittik Chatterjee
2511
2511
1
Take a look at stackoverflow.com/questions/33635353/…
– KJH
Nov 23 '18 at 1:54
1
for file in glob.glob('/some/directory/*.mp3'):
– John Gordon
Nov 23 '18 at 1:57
Great for the first part but I still need help with the number part.
– Hrittik Chatterjee
Nov 23 '18 at 1:59
btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.
– Hrittik Chatterjee
Nov 23 '18 at 2:17
Split the filename on the dot; feed the extensions into collections.Counter.
– wwii
Nov 23 '18 at 2:19
|
show 2 more comments
1
Take a look at stackoverflow.com/questions/33635353/…
– KJH
Nov 23 '18 at 1:54
1
for file in glob.glob('/some/directory/*.mp3'):
– John Gordon
Nov 23 '18 at 1:57
Great for the first part but I still need help with the number part.
– Hrittik Chatterjee
Nov 23 '18 at 1:59
btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.
– Hrittik Chatterjee
Nov 23 '18 at 2:17
Split the filename on the dot; feed the extensions into collections.Counter.
– wwii
Nov 23 '18 at 2:19
1
1
Take a look at stackoverflow.com/questions/33635353/…
– KJH
Nov 23 '18 at 1:54
Take a look at stackoverflow.com/questions/33635353/…
– KJH
Nov 23 '18 at 1:54
1
1
for file in glob.glob('/some/directory/*.mp3'):
– John Gordon
Nov 23 '18 at 1:57
for file in glob.glob('/some/directory/*.mp3'):
– John Gordon
Nov 23 '18 at 1:57
Great for the first part but I still need help with the number part.
– Hrittik Chatterjee
Nov 23 '18 at 1:59
Great for the first part but I still need help with the number part.
– Hrittik Chatterjee
Nov 23 '18 at 1:59
btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.
– Hrittik Chatterjee
Nov 23 '18 at 2:17
btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.
– Hrittik Chatterjee
Nov 23 '18 at 2:17
Split the filename on the dot; feed the extensions into collections.Counter.
– wwii
Nov 23 '18 at 2:19
Split the filename on the dot; feed the extensions into collections.Counter.
– wwii
Nov 23 '18 at 2:19
|
show 2 more comments
1 Answer
1
active
oldest
votes
import os
i=0
x=
for file in os.listdir():
if file.endswith('.mp3'):
print(file)
x.append(file)
i+=1
print('the total number of files: ' +str(i))
fileNumber=input('enter number')
os.startfile(x[int(fileNumber)])
make sure to use change directory to the folder location using os.chdir()
or enter complete path in os.listdir()
I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.
– Hrittik Chatterjee
Nov 23 '18 at 2:29
Also I cant ask any more questions apparently so if you guys could upvote this :)
– Hrittik Chatterjee
Nov 23 '18 at 2:30
you can use `os.startfile()'
– wishmaster
Nov 23 '18 at 2:34
do not worry i will edit my answer to complete your answer
– wishmaster
Nov 23 '18 at 2:35
i should note that programmers start count from 0
– wishmaster
Nov 23 '18 at 2:41
|
show 3 more comments
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
import os
i=0
x=
for file in os.listdir():
if file.endswith('.mp3'):
print(file)
x.append(file)
i+=1
print('the total number of files: ' +str(i))
fileNumber=input('enter number')
os.startfile(x[int(fileNumber)])
make sure to use change directory to the folder location using os.chdir()
or enter complete path in os.listdir()
I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.
– Hrittik Chatterjee
Nov 23 '18 at 2:29
Also I cant ask any more questions apparently so if you guys could upvote this :)
– Hrittik Chatterjee
Nov 23 '18 at 2:30
you can use `os.startfile()'
– wishmaster
Nov 23 '18 at 2:34
do not worry i will edit my answer to complete your answer
– wishmaster
Nov 23 '18 at 2:35
i should note that programmers start count from 0
– wishmaster
Nov 23 '18 at 2:41
|
show 3 more comments
import os
i=0
x=
for file in os.listdir():
if file.endswith('.mp3'):
print(file)
x.append(file)
i+=1
print('the total number of files: ' +str(i))
fileNumber=input('enter number')
os.startfile(x[int(fileNumber)])
make sure to use change directory to the folder location using os.chdir()
or enter complete path in os.listdir()
I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.
– Hrittik Chatterjee
Nov 23 '18 at 2:29
Also I cant ask any more questions apparently so if you guys could upvote this :)
– Hrittik Chatterjee
Nov 23 '18 at 2:30
you can use `os.startfile()'
– wishmaster
Nov 23 '18 at 2:34
do not worry i will edit my answer to complete your answer
– wishmaster
Nov 23 '18 at 2:35
i should note that programmers start count from 0
– wishmaster
Nov 23 '18 at 2:41
|
show 3 more comments
import os
i=0
x=
for file in os.listdir():
if file.endswith('.mp3'):
print(file)
x.append(file)
i+=1
print('the total number of files: ' +str(i))
fileNumber=input('enter number')
os.startfile(x[int(fileNumber)])
make sure to use change directory to the folder location using os.chdir()
or enter complete path in os.listdir()
import os
i=0
x=
for file in os.listdir():
if file.endswith('.mp3'):
print(file)
x.append(file)
i+=1
print('the total number of files: ' +str(i))
fileNumber=input('enter number')
os.startfile(x[int(fileNumber)])
make sure to use change directory to the folder location using os.chdir()
or enter complete path in os.listdir()
edited Nov 23 '18 at 2:45
answered Nov 23 '18 at 2:26
wishmasterwishmaster
35210
35210
I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.
– Hrittik Chatterjee
Nov 23 '18 at 2:29
Also I cant ask any more questions apparently so if you guys could upvote this :)
– Hrittik Chatterjee
Nov 23 '18 at 2:30
you can use `os.startfile()'
– wishmaster
Nov 23 '18 at 2:34
do not worry i will edit my answer to complete your answer
– wishmaster
Nov 23 '18 at 2:35
i should note that programmers start count from 0
– wishmaster
Nov 23 '18 at 2:41
|
show 3 more comments
I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.
– Hrittik Chatterjee
Nov 23 '18 at 2:29
Also I cant ask any more questions apparently so if you guys could upvote this :)
– Hrittik Chatterjee
Nov 23 '18 at 2:30
you can use `os.startfile()'
– wishmaster
Nov 23 '18 at 2:34
do not worry i will edit my answer to complete your answer
– wishmaster
Nov 23 '18 at 2:35
i should note that programmers start count from 0
– wishmaster
Nov 23 '18 at 2:41
I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.
– Hrittik Chatterjee
Nov 23 '18 at 2:29
I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.
– Hrittik Chatterjee
Nov 23 '18 at 2:29
Also I cant ask any more questions apparently so if you guys could upvote this :)
– Hrittik Chatterjee
Nov 23 '18 at 2:30
Also I cant ask any more questions apparently so if you guys could upvote this :)
– Hrittik Chatterjee
Nov 23 '18 at 2:30
you can use `os.startfile()'
– wishmaster
Nov 23 '18 at 2:34
you can use `os.startfile()'
– wishmaster
Nov 23 '18 at 2:34
do not worry i will edit my answer to complete your answer
– wishmaster
Nov 23 '18 at 2:35
do not worry i will edit my answer to complete your answer
– wishmaster
Nov 23 '18 at 2:35
i should note that programmers start count from 0
– wishmaster
Nov 23 '18 at 2:41
i should note that programmers start count from 0
– wishmaster
Nov 23 '18 at 2:41
|
show 3 more comments
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1
Take a look at stackoverflow.com/questions/33635353/…
– KJH
Nov 23 '18 at 1:54
1
for file in glob.glob('/some/directory/*.mp3'):
– John Gordon
Nov 23 '18 at 1:57
Great for the first part but I still need help with the number part.
– Hrittik Chatterjee
Nov 23 '18 at 1:59
btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.
– Hrittik Chatterjee
Nov 23 '18 at 2:17
Split the filename on the dot; feed the extensions into collections.Counter.
– wwii
Nov 23 '18 at 2:19