How do I get perl to replace strtolower($value) with strtolower(substr($value, 0, 2))





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I have several hundred PHP scripts that expect a language field to contain an ISO 639-1 2-character identifier. for example "en", which I now want to modify to support language codes qualified by country code, for example "fr-CA". In each of these scripts there is the following code:



    case 'lang':
{ // language code
if (strlen($value) == 2)
$lang = strtolower($value);
break;
} // language code


which I want to modify to:



    case 'lang':
{ // language code
if (strlen($value) >= 2)
$lang = strtolower(substr($value,0,2));
break;
} // language code


So I wrote a perl script to run over the entire directory tree and modify all of the matching scripts. For testing I have set the script up to create all of the modified scripts in a new directory structure:



use strict;
use warnings;
use 5.010;

use File::Find;
use File::Slurp;

my @content;
find( &wanted, '/home/jcobban/public_html/');

exit;

sub wanted {
if (-f)
{
print "wanted: ", $File::Find::name, "n";
my $odir = '/home/jcobban/testlang' . substr($File::Find::dir, 25);
if ((substr $odir, -1) ne "/"){
$odir = "$odir/";
}
if (! -d $odir){
mkdir $odir;
}
print "odir '$odir'n";
my @lines = read_file($File::Find::name);
my $caselang = 0;
my $updated = 0;
foreach my $line (@lines){
if ($line =~ /bcaseb/)
{
$caselang = $line =~ /blangb/i;
}

if ($line =~ /bbreakb/)
{
$caselang = 0;
}

if ($caselang)
{
print "old $linen";
$line =~ s/ == 2/ >= 2/;
$line =~ s/strtolower(.value)/strtolower(substr($value,0,2))/;
$updated = 1;
print "new $linen";
}
}

if ($updated)
{
# my $newfile = $File::Find::dir . "/" . $_;
my $newfile = $odir . $_;
print "alter $lang to support ll-CC $newfilen";
write_file($newfile, @lines);
}
else
{
print "did not find lang support in $_n";
}

}
return;
}


The first match replace works, to change the == to >=, but the second match replace does not modify any lines and I do not understand well. I thought maybe there was a problem with matching to "$" so I replaced it with "." but still no lines are changed. I applied the same command to other regex engines and they all worked. The output for a typical file is:



wanted: /home/jcobban/public_html/videoTutorials.php
odir '/home/jcobban/testlang/'
old case 'lang':
new case 'lang':
old {
new {
old if (strlen($value) == 2)
new if (strlen($value) >= 2)
old $lang = strtolower($value);
new $lang = strtolower($value);
alter $lang to support ll-CC /home/jcobban/testlang/videoTutorials.php









share|improve this question





























    1















    I have several hundred PHP scripts that expect a language field to contain an ISO 639-1 2-character identifier. for example "en", which I now want to modify to support language codes qualified by country code, for example "fr-CA". In each of these scripts there is the following code:



        case 'lang':
    { // language code
    if (strlen($value) == 2)
    $lang = strtolower($value);
    break;
    } // language code


    which I want to modify to:



        case 'lang':
    { // language code
    if (strlen($value) >= 2)
    $lang = strtolower(substr($value,0,2));
    break;
    } // language code


    So I wrote a perl script to run over the entire directory tree and modify all of the matching scripts. For testing I have set the script up to create all of the modified scripts in a new directory structure:



    use strict;
    use warnings;
    use 5.010;

    use File::Find;
    use File::Slurp;

    my @content;
    find( &wanted, '/home/jcobban/public_html/');

    exit;

    sub wanted {
    if (-f)
    {
    print "wanted: ", $File::Find::name, "n";
    my $odir = '/home/jcobban/testlang' . substr($File::Find::dir, 25);
    if ((substr $odir, -1) ne "/"){
    $odir = "$odir/";
    }
    if (! -d $odir){
    mkdir $odir;
    }
    print "odir '$odir'n";
    my @lines = read_file($File::Find::name);
    my $caselang = 0;
    my $updated = 0;
    foreach my $line (@lines){
    if ($line =~ /bcaseb/)
    {
    $caselang = $line =~ /blangb/i;
    }

    if ($line =~ /bbreakb/)
    {
    $caselang = 0;
    }

    if ($caselang)
    {
    print "old $linen";
    $line =~ s/ == 2/ >= 2/;
    $line =~ s/strtolower(.value)/strtolower(substr($value,0,2))/;
    $updated = 1;
    print "new $linen";
    }
    }

    if ($updated)
    {
    # my $newfile = $File::Find::dir . "/" . $_;
    my $newfile = $odir . $_;
    print "alter $lang to support ll-CC $newfilen";
    write_file($newfile, @lines);
    }
    else
    {
    print "did not find lang support in $_n";
    }

    }
    return;
    }


    The first match replace works, to change the == to >=, but the second match replace does not modify any lines and I do not understand well. I thought maybe there was a problem with matching to "$" so I replaced it with "." but still no lines are changed. I applied the same command to other regex engines and they all worked. The output for a typical file is:



    wanted: /home/jcobban/public_html/videoTutorials.php
    odir '/home/jcobban/testlang/'
    old case 'lang':
    new case 'lang':
    old {
    new {
    old if (strlen($value) == 2)
    new if (strlen($value) >= 2)
    old $lang = strtolower($value);
    new $lang = strtolower($value);
    alter $lang to support ll-CC /home/jcobban/testlang/videoTutorials.php









    share|improve this question

























      1












      1








      1








      I have several hundred PHP scripts that expect a language field to contain an ISO 639-1 2-character identifier. for example "en", which I now want to modify to support language codes qualified by country code, for example "fr-CA". In each of these scripts there is the following code:



          case 'lang':
      { // language code
      if (strlen($value) == 2)
      $lang = strtolower($value);
      break;
      } // language code


      which I want to modify to:



          case 'lang':
      { // language code
      if (strlen($value) >= 2)
      $lang = strtolower(substr($value,0,2));
      break;
      } // language code


      So I wrote a perl script to run over the entire directory tree and modify all of the matching scripts. For testing I have set the script up to create all of the modified scripts in a new directory structure:



      use strict;
      use warnings;
      use 5.010;

      use File::Find;
      use File::Slurp;

      my @content;
      find( &wanted, '/home/jcobban/public_html/');

      exit;

      sub wanted {
      if (-f)
      {
      print "wanted: ", $File::Find::name, "n";
      my $odir = '/home/jcobban/testlang' . substr($File::Find::dir, 25);
      if ((substr $odir, -1) ne "/"){
      $odir = "$odir/";
      }
      if (! -d $odir){
      mkdir $odir;
      }
      print "odir '$odir'n";
      my @lines = read_file($File::Find::name);
      my $caselang = 0;
      my $updated = 0;
      foreach my $line (@lines){
      if ($line =~ /bcaseb/)
      {
      $caselang = $line =~ /blangb/i;
      }

      if ($line =~ /bbreakb/)
      {
      $caselang = 0;
      }

      if ($caselang)
      {
      print "old $linen";
      $line =~ s/ == 2/ >= 2/;
      $line =~ s/strtolower(.value)/strtolower(substr($value,0,2))/;
      $updated = 1;
      print "new $linen";
      }
      }

      if ($updated)
      {
      # my $newfile = $File::Find::dir . "/" . $_;
      my $newfile = $odir . $_;
      print "alter $lang to support ll-CC $newfilen";
      write_file($newfile, @lines);
      }
      else
      {
      print "did not find lang support in $_n";
      }

      }
      return;
      }


      The first match replace works, to change the == to >=, but the second match replace does not modify any lines and I do not understand well. I thought maybe there was a problem with matching to "$" so I replaced it with "." but still no lines are changed. I applied the same command to other regex engines and they all worked. The output for a typical file is:



      wanted: /home/jcobban/public_html/videoTutorials.php
      odir '/home/jcobban/testlang/'
      old case 'lang':
      new case 'lang':
      old {
      new {
      old if (strlen($value) == 2)
      new if (strlen($value) >= 2)
      old $lang = strtolower($value);
      new $lang = strtolower($value);
      alter $lang to support ll-CC /home/jcobban/testlang/videoTutorials.php









      share|improve this question














      I have several hundred PHP scripts that expect a language field to contain an ISO 639-1 2-character identifier. for example "en", which I now want to modify to support language codes qualified by country code, for example "fr-CA". In each of these scripts there is the following code:



          case 'lang':
      { // language code
      if (strlen($value) == 2)
      $lang = strtolower($value);
      break;
      } // language code


      which I want to modify to:



          case 'lang':
      { // language code
      if (strlen($value) >= 2)
      $lang = strtolower(substr($value,0,2));
      break;
      } // language code


      So I wrote a perl script to run over the entire directory tree and modify all of the matching scripts. For testing I have set the script up to create all of the modified scripts in a new directory structure:



      use strict;
      use warnings;
      use 5.010;

      use File::Find;
      use File::Slurp;

      my @content;
      find( &wanted, '/home/jcobban/public_html/');

      exit;

      sub wanted {
      if (-f)
      {
      print "wanted: ", $File::Find::name, "n";
      my $odir = '/home/jcobban/testlang' . substr($File::Find::dir, 25);
      if ((substr $odir, -1) ne "/"){
      $odir = "$odir/";
      }
      if (! -d $odir){
      mkdir $odir;
      }
      print "odir '$odir'n";
      my @lines = read_file($File::Find::name);
      my $caselang = 0;
      my $updated = 0;
      foreach my $line (@lines){
      if ($line =~ /bcaseb/)
      {
      $caselang = $line =~ /blangb/i;
      }

      if ($line =~ /bbreakb/)
      {
      $caselang = 0;
      }

      if ($caselang)
      {
      print "old $linen";
      $line =~ s/ == 2/ >= 2/;
      $line =~ s/strtolower(.value)/strtolower(substr($value,0,2))/;
      $updated = 1;
      print "new $linen";
      }
      }

      if ($updated)
      {
      # my $newfile = $File::Find::dir . "/" . $_;
      my $newfile = $odir . $_;
      print "alter $lang to support ll-CC $newfilen";
      write_file($newfile, @lines);
      }
      else
      {
      print "did not find lang support in $_n";
      }

      }
      return;
      }


      The first match replace works, to change the == to >=, but the second match replace does not modify any lines and I do not understand well. I thought maybe there was a problem with matching to "$" so I replaced it with "." but still no lines are changed. I applied the same command to other regex engines and they all worked. The output for a typical file is:



      wanted: /home/jcobban/public_html/videoTutorials.php
      odir '/home/jcobban/testlang/'
      old case 'lang':
      new case 'lang':
      old {
      new {
      old if (strlen($value) == 2)
      new if (strlen($value) >= 2)
      old $lang = strtolower($value);
      new $lang = strtolower($value);
      alter $lang to support ll-CC /home/jcobban/testlang/videoTutorials.php






      regex perl






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 23 '18 at 2:09









      James CobbanJames Cobban

      654




      654
























          2 Answers
          2






          active

          oldest

          votes


















          2














          I have obviously been spending too much time using VIM. The problem with my code was that I needed to escape the round brackets so they were not interpreted as a subpattern.



              $line       =~ s/strtolower(.value)/strtolower(substr($value,0,2))/;





          share|improve this answer































            0














            Just want to show some hacks, maybe it will be interesting for you:



            s'strtolower(K$value'substr($value,0,2)'


            We can quote substitution with whatever we want:



            s/foo/bar/;
            s'foo'bar';
            s(foo)(bar);


            If we choose single quotes, variables will not be interpolated, but we still have to escape dollar sign in pattern side, because it will be treated as "end of line" by re engine.



            K Keep the stuff left of the K



            more information in perldoc perlre






            share|improve this answer
























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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              2














              I have obviously been spending too much time using VIM. The problem with my code was that I needed to escape the round brackets so they were not interpreted as a subpattern.



                  $line       =~ s/strtolower(.value)/strtolower(substr($value,0,2))/;





              share|improve this answer




























                2














                I have obviously been spending too much time using VIM. The problem with my code was that I needed to escape the round brackets so they were not interpreted as a subpattern.



                    $line       =~ s/strtolower(.value)/strtolower(substr($value,0,2))/;





                share|improve this answer


























                  2












                  2








                  2







                  I have obviously been spending too much time using VIM. The problem with my code was that I needed to escape the round brackets so they were not interpreted as a subpattern.



                      $line       =~ s/strtolower(.value)/strtolower(substr($value,0,2))/;





                  share|improve this answer













                  I have obviously been spending too much time using VIM. The problem with my code was that I needed to escape the round brackets so they were not interpreted as a subpattern.



                      $line       =~ s/strtolower(.value)/strtolower(substr($value,0,2))/;






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 23 '18 at 2:16









                  James CobbanJames Cobban

                  654




                  654

























                      0














                      Just want to show some hacks, maybe it will be interesting for you:



                      s'strtolower(K$value'substr($value,0,2)'


                      We can quote substitution with whatever we want:



                      s/foo/bar/;
                      s'foo'bar';
                      s(foo)(bar);


                      If we choose single quotes, variables will not be interpolated, but we still have to escape dollar sign in pattern side, because it will be treated as "end of line" by re engine.



                      K Keep the stuff left of the K



                      more information in perldoc perlre






                      share|improve this answer




























                        0














                        Just want to show some hacks, maybe it will be interesting for you:



                        s'strtolower(K$value'substr($value,0,2)'


                        We can quote substitution with whatever we want:



                        s/foo/bar/;
                        s'foo'bar';
                        s(foo)(bar);


                        If we choose single quotes, variables will not be interpolated, but we still have to escape dollar sign in pattern side, because it will be treated as "end of line" by re engine.



                        K Keep the stuff left of the K



                        more information in perldoc perlre






                        share|improve this answer


























                          0












                          0








                          0







                          Just want to show some hacks, maybe it will be interesting for you:



                          s'strtolower(K$value'substr($value,0,2)'


                          We can quote substitution with whatever we want:



                          s/foo/bar/;
                          s'foo'bar';
                          s(foo)(bar);


                          If we choose single quotes, variables will not be interpolated, but we still have to escape dollar sign in pattern side, because it will be treated as "end of line" by re engine.



                          K Keep the stuff left of the K



                          more information in perldoc perlre






                          share|improve this answer













                          Just want to show some hacks, maybe it will be interesting for you:



                          s'strtolower(K$value'substr($value,0,2)'


                          We can quote substitution with whatever we want:



                          s/foo/bar/;
                          s'foo'bar';
                          s(foo)(bar);


                          If we choose single quotes, variables will not be interpolated, but we still have to escape dollar sign in pattern side, because it will be treated as "end of line" by re engine.



                          K Keep the stuff left of the K



                          more information in perldoc perlre







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 25 '18 at 5:24









                          k-mxk-mx

                          2113




                          2113






























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