Drawing a bordered square with least time complexity in JS
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I just wrote a code that draws a bordered square.
Given the square size of 5 for example, the code should print the following multi-line string:
#####
# #
# #
# #
#####
and I was wondering if there's anyway of simplifying this more and reduce time complexity.
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
function DrawSquare() {
for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;
if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}
console.log(Row);
}
}
DrawSquare();
javascript time-complexity
add a comment |
I just wrote a code that draws a bordered square.
Given the square size of 5 for example, the code should print the following multi-line string:
#####
# #
# #
# #
#####
and I was wondering if there's anyway of simplifying this more and reduce time complexity.
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
function DrawSquare() {
for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;
if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}
console.log(Row);
}
}
DrawSquare();
javascript time-complexity
2
I think this question would be more suitable posted on Code Review Stack Exchange
– NewToJS
Nov 23 '18 at 1:55
1
There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.
– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57
add a comment |
I just wrote a code that draws a bordered square.
Given the square size of 5 for example, the code should print the following multi-line string:
#####
# #
# #
# #
#####
and I was wondering if there's anyway of simplifying this more and reduce time complexity.
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
function DrawSquare() {
for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;
if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}
console.log(Row);
}
}
DrawSquare();
javascript time-complexity
I just wrote a code that draws a bordered square.
Given the square size of 5 for example, the code should print the following multi-line string:
#####
# #
# #
# #
#####
and I was wondering if there's anyway of simplifying this more and reduce time complexity.
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
function DrawSquare() {
for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;
if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}
console.log(Row);
}
}
DrawSquare();
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
function DrawSquare() {
for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;
if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}
console.log(Row);
}
}
DrawSquare();
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
function DrawSquare() {
for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;
if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}
console.log(Row);
}
}
DrawSquare();
javascript time-complexity
javascript time-complexity
edited Nov 23 '18 at 1:52
Ele
25.5k52251
25.5k52251
asked Nov 23 '18 at 1:49
CoreDoCoreDo
1,02841118
1,02841118
2
I think this question would be more suitable posted on Code Review Stack Exchange
– NewToJS
Nov 23 '18 at 1:55
1
There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.
– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57
add a comment |
2
I think this question would be more suitable posted on Code Review Stack Exchange
– NewToJS
Nov 23 '18 at 1:55
1
There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.
– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57
2
2
I think this question would be more suitable posted on Code Review Stack Exchange
– NewToJS
Nov 23 '18 at 1:55
I think this question would be more suitable posted on Code Review Stack Exchange
– NewToJS
Nov 23 '18 at 1:55
1
1
There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.
– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57
There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.
– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57
add a comment |
3 Answers
3
active
oldest
votes
This is an alternative which reduces Space and Time complexity.
Time complexity: O(n)
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
var spaces = " ".repeat(BoxSize - 2);
var hashtags = BoxFiller.repeat(BoxSize);
function DrawSquare() {
console.log(hashtags);
for (var i = 1; i < BoxSize - 1; i++) {
console.log(BoxFiller + spaces + BoxFiller);
}
console.log(hashtags);
}
DrawSquare();
.as-console-wrapper { max-height: 100% !important; top: 0; }
add a comment |
Can use recursion
let BoxFiller = "#";
let Row = "";
var spaces, hashtags;
function DrawRow(BoxSize, CurrPos) {
if(CurrPos >= BoxSize - 2)
return;
console.log(BoxFiller + spaces + BoxFiller);
DrawRow(BoxSize, CurrPos + 1);
}
function DrawSquare(BoxSize) {
spaces = " ".repeat(BoxSize - 2);
hashtags = BoxFiller.repeat(BoxSize);
console.log(hashtags);
DrawRow(BoxSize, 0);
console.log(hashtags);
}
DrawSquare(8);
.as-console-wrapper { max-height: 100% !important; top: 0; }
add a comment |
Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.
function DrawSquare(size, filler) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
console.log(lines.join('n'));
}
DrawSquare(8, '*');
If I was going to redraw the same thing several times I would change it to look like this:
const cache = {};
function DrawSquare(size, filler) {
if (!cache[size]) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
cache[size] = lines.join('n');
}
console.log(cache[size]);
}
console.time('first');
DrawSquare(12, '*');
console.timeEnd('first');
console.time('second');
DrawSquare(12, '*');
console.timeEnd('second');
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
This is an alternative which reduces Space and Time complexity.
Time complexity: O(n)
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
var spaces = " ".repeat(BoxSize - 2);
var hashtags = BoxFiller.repeat(BoxSize);
function DrawSquare() {
console.log(hashtags);
for (var i = 1; i < BoxSize - 1; i++) {
console.log(BoxFiller + spaces + BoxFiller);
}
console.log(hashtags);
}
DrawSquare();
.as-console-wrapper { max-height: 100% !important; top: 0; }
add a comment |
This is an alternative which reduces Space and Time complexity.
Time complexity: O(n)
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
var spaces = " ".repeat(BoxSize - 2);
var hashtags = BoxFiller.repeat(BoxSize);
function DrawSquare() {
console.log(hashtags);
for (var i = 1; i < BoxSize - 1; i++) {
console.log(BoxFiller + spaces + BoxFiller);
}
console.log(hashtags);
}
DrawSquare();
.as-console-wrapper { max-height: 100% !important; top: 0; }
add a comment |
This is an alternative which reduces Space and Time complexity.
Time complexity: O(n)
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
var spaces = " ".repeat(BoxSize - 2);
var hashtags = BoxFiller.repeat(BoxSize);
function DrawSquare() {
console.log(hashtags);
for (var i = 1; i < BoxSize - 1; i++) {
console.log(BoxFiller + spaces + BoxFiller);
}
console.log(hashtags);
}
DrawSquare();
.as-console-wrapper { max-height: 100% !important; top: 0; }
This is an alternative which reduces Space and Time complexity.
Time complexity: O(n)
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
var spaces = " ".repeat(BoxSize - 2);
var hashtags = BoxFiller.repeat(BoxSize);
function DrawSquare() {
console.log(hashtags);
for (var i = 1; i < BoxSize - 1; i++) {
console.log(BoxFiller + spaces + BoxFiller);
}
console.log(hashtags);
}
DrawSquare();
.as-console-wrapper { max-height: 100% !important; top: 0; }
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
var spaces = " ".repeat(BoxSize - 2);
var hashtags = BoxFiller.repeat(BoxSize);
function DrawSquare() {
console.log(hashtags);
for (var i = 1; i < BoxSize - 1; i++) {
console.log(BoxFiller + spaces + BoxFiller);
}
console.log(hashtags);
}
DrawSquare();
.as-console-wrapper { max-height: 100% !important; top: 0; }
var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
var spaces = " ".repeat(BoxSize - 2);
var hashtags = BoxFiller.repeat(BoxSize);
function DrawSquare() {
console.log(hashtags);
for (var i = 1; i < BoxSize - 1; i++) {
console.log(BoxFiller + spaces + BoxFiller);
}
console.log(hashtags);
}
DrawSquare();
.as-console-wrapper { max-height: 100% !important; top: 0; }
edited Nov 23 '18 at 15:59
answered Nov 23 '18 at 2:04
EleEle
25.5k52251
25.5k52251
add a comment |
add a comment |
Can use recursion
let BoxFiller = "#";
let Row = "";
var spaces, hashtags;
function DrawRow(BoxSize, CurrPos) {
if(CurrPos >= BoxSize - 2)
return;
console.log(BoxFiller + spaces + BoxFiller);
DrawRow(BoxSize, CurrPos + 1);
}
function DrawSquare(BoxSize) {
spaces = " ".repeat(BoxSize - 2);
hashtags = BoxFiller.repeat(BoxSize);
console.log(hashtags);
DrawRow(BoxSize, 0);
console.log(hashtags);
}
DrawSquare(8);
.as-console-wrapper { max-height: 100% !important; top: 0; }
add a comment |
Can use recursion
let BoxFiller = "#";
let Row = "";
var spaces, hashtags;
function DrawRow(BoxSize, CurrPos) {
if(CurrPos >= BoxSize - 2)
return;
console.log(BoxFiller + spaces + BoxFiller);
DrawRow(BoxSize, CurrPos + 1);
}
function DrawSquare(BoxSize) {
spaces = " ".repeat(BoxSize - 2);
hashtags = BoxFiller.repeat(BoxSize);
console.log(hashtags);
DrawRow(BoxSize, 0);
console.log(hashtags);
}
DrawSquare(8);
.as-console-wrapper { max-height: 100% !important; top: 0; }
add a comment |
Can use recursion
let BoxFiller = "#";
let Row = "";
var spaces, hashtags;
function DrawRow(BoxSize, CurrPos) {
if(CurrPos >= BoxSize - 2)
return;
console.log(BoxFiller + spaces + BoxFiller);
DrawRow(BoxSize, CurrPos + 1);
}
function DrawSquare(BoxSize) {
spaces = " ".repeat(BoxSize - 2);
hashtags = BoxFiller.repeat(BoxSize);
console.log(hashtags);
DrawRow(BoxSize, 0);
console.log(hashtags);
}
DrawSquare(8);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Can use recursion
let BoxFiller = "#";
let Row = "";
var spaces, hashtags;
function DrawRow(BoxSize, CurrPos) {
if(CurrPos >= BoxSize - 2)
return;
console.log(BoxFiller + spaces + BoxFiller);
DrawRow(BoxSize, CurrPos + 1);
}
function DrawSquare(BoxSize) {
spaces = " ".repeat(BoxSize - 2);
hashtags = BoxFiller.repeat(BoxSize);
console.log(hashtags);
DrawRow(BoxSize, 0);
console.log(hashtags);
}
DrawSquare(8);
.as-console-wrapper { max-height: 100% !important; top: 0; }
let BoxFiller = "#";
let Row = "";
var spaces, hashtags;
function DrawRow(BoxSize, CurrPos) {
if(CurrPos >= BoxSize - 2)
return;
console.log(BoxFiller + spaces + BoxFiller);
DrawRow(BoxSize, CurrPos + 1);
}
function DrawSquare(BoxSize) {
spaces = " ".repeat(BoxSize - 2);
hashtags = BoxFiller.repeat(BoxSize);
console.log(hashtags);
DrawRow(BoxSize, 0);
console.log(hashtags);
}
DrawSquare(8);
.as-console-wrapper { max-height: 100% !important; top: 0; }
let BoxFiller = "#";
let Row = "";
var spaces, hashtags;
function DrawRow(BoxSize, CurrPos) {
if(CurrPos >= BoxSize - 2)
return;
console.log(BoxFiller + spaces + BoxFiller);
DrawRow(BoxSize, CurrPos + 1);
}
function DrawSquare(BoxSize) {
spaces = " ".repeat(BoxSize - 2);
hashtags = BoxFiller.repeat(BoxSize);
console.log(hashtags);
DrawRow(BoxSize, 0);
console.log(hashtags);
}
DrawSquare(8);
.as-console-wrapper { max-height: 100% !important; top: 0; }
answered Nov 23 '18 at 2:58
Miller Cy ChanMiller Cy Chan
423511
423511
add a comment |
add a comment |
Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.
function DrawSquare(size, filler) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
console.log(lines.join('n'));
}
DrawSquare(8, '*');
If I was going to redraw the same thing several times I would change it to look like this:
const cache = {};
function DrawSquare(size, filler) {
if (!cache[size]) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
cache[size] = lines.join('n');
}
console.log(cache[size]);
}
console.time('first');
DrawSquare(12, '*');
console.timeEnd('first');
console.time('second');
DrawSquare(12, '*');
console.timeEnd('second');
add a comment |
Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.
function DrawSquare(size, filler) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
console.log(lines.join('n'));
}
DrawSquare(8, '*');
If I was going to redraw the same thing several times I would change it to look like this:
const cache = {};
function DrawSquare(size, filler) {
if (!cache[size]) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
cache[size] = lines.join('n');
}
console.log(cache[size]);
}
console.time('first');
DrawSquare(12, '*');
console.timeEnd('first');
console.time('second');
DrawSquare(12, '*');
console.timeEnd('second');
add a comment |
Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.
function DrawSquare(size, filler) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
console.log(lines.join('n'));
}
DrawSquare(8, '*');
If I was going to redraw the same thing several times I would change it to look like this:
const cache = {};
function DrawSquare(size, filler) {
if (!cache[size]) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
cache[size] = lines.join('n');
}
console.log(cache[size]);
}
console.time('first');
DrawSquare(12, '*');
console.timeEnd('first');
console.time('second');
DrawSquare(12, '*');
console.timeEnd('second');
Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.
function DrawSquare(size, filler) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
console.log(lines.join('n'));
}
DrawSquare(8, '*');
If I was going to redraw the same thing several times I would change it to look like this:
const cache = {};
function DrawSquare(size, filler) {
if (!cache[size]) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
cache[size] = lines.join('n');
}
console.log(cache[size]);
}
console.time('first');
DrawSquare(12, '*');
console.timeEnd('first');
console.time('second');
DrawSquare(12, '*');
console.timeEnd('second');
function DrawSquare(size, filler) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
console.log(lines.join('n'));
}
DrawSquare(8, '*');
function DrawSquare(size, filler) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
console.log(lines.join('n'));
}
DrawSquare(8, '*');
const cache = {};
function DrawSquare(size, filler) {
if (!cache[size]) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
cache[size] = lines.join('n');
}
console.log(cache[size]);
}
console.time('first');
DrawSquare(12, '*');
console.timeEnd('first');
console.time('second');
DrawSquare(12, '*');
console.timeEnd('second');
const cache = {};
function DrawSquare(size, filler) {
if (!cache[size]) {
const line = filler.repeat(size);
const mid = filler+' '.repeat(size-2)+filler;
let lines = [line];
for (var i = 1; i < size - 1; i++) {
lines.push(mid);
}
lines.push(line);
cache[size] = lines.join('n');
}
console.log(cache[size]);
}
console.time('first');
DrawSquare(12, '*');
console.timeEnd('first');
console.time('second');
DrawSquare(12, '*');
console.timeEnd('second');
answered Nov 23 '18 at 3:17
IntervaliaIntervalia
5,16511135
5,16511135
add a comment |
add a comment |
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2
I think this question would be more suitable posted on Code Review Stack Exchange
– NewToJS
Nov 23 '18 at 1:55
1
There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.
– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57