Drawing a bordered square with least time complexity in JS





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-2















I just wrote a code that draws a bordered square.



Given the square size of 5 for example, the code should print the following multi-line string:



#####
# #
# #
# #
#####


and I was wondering if there's anyway of simplifying this more and reduce time complexity.






var BoxFiller = "#";
var BoxSize = 8;
var Row = "";

function DrawSquare() {

for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;

if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}

console.log(Row);

}
}

DrawSquare();












share|improve this question




















  • 2





    I think this question would be more suitable posted on Code Review Stack Exchange

    – NewToJS
    Nov 23 '18 at 1:55






  • 1





    There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

    – Mike 'Pomax' Kamermans
    Nov 23 '18 at 1:57




















-2















I just wrote a code that draws a bordered square.



Given the square size of 5 for example, the code should print the following multi-line string:



#####
# #
# #
# #
#####


and I was wondering if there's anyway of simplifying this more and reduce time complexity.






var BoxFiller = "#";
var BoxSize = 8;
var Row = "";

function DrawSquare() {

for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;

if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}

console.log(Row);

}
}

DrawSquare();












share|improve this question




















  • 2





    I think this question would be more suitable posted on Code Review Stack Exchange

    – NewToJS
    Nov 23 '18 at 1:55






  • 1





    There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

    – Mike 'Pomax' Kamermans
    Nov 23 '18 at 1:57
















-2












-2








-2








I just wrote a code that draws a bordered square.



Given the square size of 5 for example, the code should print the following multi-line string:



#####
# #
# #
# #
#####


and I was wondering if there's anyway of simplifying this more and reduce time complexity.






var BoxFiller = "#";
var BoxSize = 8;
var Row = "";

function DrawSquare() {

for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;

if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}

console.log(Row);

}
}

DrawSquare();












share|improve this question
















I just wrote a code that draws a bordered square.



Given the square size of 5 for example, the code should print the following multi-line string:



#####
# #
# #
# #
#####


and I was wondering if there's anyway of simplifying this more and reduce time complexity.






var BoxFiller = "#";
var BoxSize = 8;
var Row = "";

function DrawSquare() {

for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;

if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}

console.log(Row);

}
}

DrawSquare();








var BoxFiller = "#";
var BoxSize = 8;
var Row = "";

function DrawSquare() {

for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;

if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}

console.log(Row);

}
}

DrawSquare();





var BoxFiller = "#";
var BoxSize = 8;
var Row = "";

function DrawSquare() {

for (i = 0; i < BoxSize; i++) {
var r = BoxSize - 1;

if (i == 0 || i == r) {
Row = BoxFiller.repeat(BoxSize);
} else {
Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;
}

console.log(Row);

}
}

DrawSquare();






javascript time-complexity






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share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 1:52









Ele

25.5k52251




25.5k52251










asked Nov 23 '18 at 1:49









CoreDoCoreDo

1,02841118




1,02841118








  • 2





    I think this question would be more suitable posted on Code Review Stack Exchange

    – NewToJS
    Nov 23 '18 at 1:55






  • 1





    There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

    – Mike 'Pomax' Kamermans
    Nov 23 '18 at 1:57
















  • 2





    I think this question would be more suitable posted on Code Review Stack Exchange

    – NewToJS
    Nov 23 '18 at 1:55






  • 1





    There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

    – Mike 'Pomax' Kamermans
    Nov 23 '18 at 1:57










2




2





I think this question would be more suitable posted on Code Review Stack Exchange

– NewToJS
Nov 23 '18 at 1:55





I think this question would be more suitable posted on Code Review Stack Exchange

– NewToJS
Nov 23 '18 at 1:55




1




1





There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57







There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57














3 Answers
3






active

oldest

votes


















2














This is an alternative which reduces Space and Time complexity.



Time complexity: O(n)






var BoxFiller = "#";
var BoxSize = 8;
var Row = "";
var spaces = " ".repeat(BoxSize - 2);
var hashtags = BoxFiller.repeat(BoxSize);

function DrawSquare() {
console.log(hashtags);

for (var i = 1; i < BoxSize - 1; i++) {
console.log(BoxFiller + spaces + BoxFiller);
}

console.log(hashtags);
}

DrawSquare();

.as-console-wrapper { max-height: 100% !important; top: 0; }








share|improve this answer

































    0














    Can use recursion






    let BoxFiller = "#";
    let Row = "";
    var spaces, hashtags;

    function DrawRow(BoxSize, CurrPos) {
    if(CurrPos >= BoxSize - 2)
    return;

    console.log(BoxFiller + spaces + BoxFiller);
    DrawRow(BoxSize, CurrPos + 1);
    }

    function DrawSquare(BoxSize) {
    spaces = " ".repeat(BoxSize - 2);
    hashtags = BoxFiller.repeat(BoxSize);
    console.log(hashtags);
    DrawRow(BoxSize, 0);
    console.log(hashtags);
    }

    DrawSquare(8);

    .as-console-wrapper { max-height: 100% !important; top: 0; }








    share|improve this answer































      0














      Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.






      function DrawSquare(size, filler) { 
      const line = filler.repeat(size);
      const mid = filler+' '.repeat(size-2)+filler;
      let lines = [line];

      for (var i = 1; i < size - 1; i++) {
      lines.push(mid);
      }

      lines.push(line);

      console.log(lines.join('n'));
      }

      DrawSquare(8, '*');





      If I was going to redraw the same thing several times I would change it to look like this:






      const cache = {};

      function DrawSquare(size, filler) {
      if (!cache[size]) {
      const line = filler.repeat(size);
      const mid = filler+' '.repeat(size-2)+filler;
      let lines = [line];

      for (var i = 1; i < size - 1; i++) {
      lines.push(mid);
      }

      lines.push(line);

      cache[size] = lines.join('n');
      }

      console.log(cache[size]);
      }


      console.time('first');
      DrawSquare(12, '*');
      console.timeEnd('first');

      console.time('second');
      DrawSquare(12, '*');
      console.timeEnd('second');








      share|improve this answer
























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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2














        This is an alternative which reduces Space and Time complexity.



        Time complexity: O(n)






        var BoxFiller = "#";
        var BoxSize = 8;
        var Row = "";
        var spaces = " ".repeat(BoxSize - 2);
        var hashtags = BoxFiller.repeat(BoxSize);

        function DrawSquare() {
        console.log(hashtags);

        for (var i = 1; i < BoxSize - 1; i++) {
        console.log(BoxFiller + spaces + BoxFiller);
        }

        console.log(hashtags);
        }

        DrawSquare();

        .as-console-wrapper { max-height: 100% !important; top: 0; }








        share|improve this answer






























          2














          This is an alternative which reduces Space and Time complexity.



          Time complexity: O(n)






          var BoxFiller = "#";
          var BoxSize = 8;
          var Row = "";
          var spaces = " ".repeat(BoxSize - 2);
          var hashtags = BoxFiller.repeat(BoxSize);

          function DrawSquare() {
          console.log(hashtags);

          for (var i = 1; i < BoxSize - 1; i++) {
          console.log(BoxFiller + spaces + BoxFiller);
          }

          console.log(hashtags);
          }

          DrawSquare();

          .as-console-wrapper { max-height: 100% !important; top: 0; }








          share|improve this answer




























            2












            2








            2







            This is an alternative which reduces Space and Time complexity.



            Time complexity: O(n)






            var BoxFiller = "#";
            var BoxSize = 8;
            var Row = "";
            var spaces = " ".repeat(BoxSize - 2);
            var hashtags = BoxFiller.repeat(BoxSize);

            function DrawSquare() {
            console.log(hashtags);

            for (var i = 1; i < BoxSize - 1; i++) {
            console.log(BoxFiller + spaces + BoxFiller);
            }

            console.log(hashtags);
            }

            DrawSquare();

            .as-console-wrapper { max-height: 100% !important; top: 0; }








            share|improve this answer















            This is an alternative which reduces Space and Time complexity.



            Time complexity: O(n)






            var BoxFiller = "#";
            var BoxSize = 8;
            var Row = "";
            var spaces = " ".repeat(BoxSize - 2);
            var hashtags = BoxFiller.repeat(BoxSize);

            function DrawSquare() {
            console.log(hashtags);

            for (var i = 1; i < BoxSize - 1; i++) {
            console.log(BoxFiller + spaces + BoxFiller);
            }

            console.log(hashtags);
            }

            DrawSquare();

            .as-console-wrapper { max-height: 100% !important; top: 0; }








            var BoxFiller = "#";
            var BoxSize = 8;
            var Row = "";
            var spaces = " ".repeat(BoxSize - 2);
            var hashtags = BoxFiller.repeat(BoxSize);

            function DrawSquare() {
            console.log(hashtags);

            for (var i = 1; i < BoxSize - 1; i++) {
            console.log(BoxFiller + spaces + BoxFiller);
            }

            console.log(hashtags);
            }

            DrawSquare();

            .as-console-wrapper { max-height: 100% !important; top: 0; }





            var BoxFiller = "#";
            var BoxSize = 8;
            var Row = "";
            var spaces = " ".repeat(BoxSize - 2);
            var hashtags = BoxFiller.repeat(BoxSize);

            function DrawSquare() {
            console.log(hashtags);

            for (var i = 1; i < BoxSize - 1; i++) {
            console.log(BoxFiller + spaces + BoxFiller);
            }

            console.log(hashtags);
            }

            DrawSquare();

            .as-console-wrapper { max-height: 100% !important; top: 0; }






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 23 '18 at 15:59

























            answered Nov 23 '18 at 2:04









            EleEle

            25.5k52251




            25.5k52251

























                0














                Can use recursion






                let BoxFiller = "#";
                let Row = "";
                var spaces, hashtags;

                function DrawRow(BoxSize, CurrPos) {
                if(CurrPos >= BoxSize - 2)
                return;

                console.log(BoxFiller + spaces + BoxFiller);
                DrawRow(BoxSize, CurrPos + 1);
                }

                function DrawSquare(BoxSize) {
                spaces = " ".repeat(BoxSize - 2);
                hashtags = BoxFiller.repeat(BoxSize);
                console.log(hashtags);
                DrawRow(BoxSize, 0);
                console.log(hashtags);
                }

                DrawSquare(8);

                .as-console-wrapper { max-height: 100% !important; top: 0; }








                share|improve this answer




























                  0














                  Can use recursion






                  let BoxFiller = "#";
                  let Row = "";
                  var spaces, hashtags;

                  function DrawRow(BoxSize, CurrPos) {
                  if(CurrPos >= BoxSize - 2)
                  return;

                  console.log(BoxFiller + spaces + BoxFiller);
                  DrawRow(BoxSize, CurrPos + 1);
                  }

                  function DrawSquare(BoxSize) {
                  spaces = " ".repeat(BoxSize - 2);
                  hashtags = BoxFiller.repeat(BoxSize);
                  console.log(hashtags);
                  DrawRow(BoxSize, 0);
                  console.log(hashtags);
                  }

                  DrawSquare(8);

                  .as-console-wrapper { max-height: 100% !important; top: 0; }








                  share|improve this answer


























                    0












                    0








                    0







                    Can use recursion






                    let BoxFiller = "#";
                    let Row = "";
                    var spaces, hashtags;

                    function DrawRow(BoxSize, CurrPos) {
                    if(CurrPos >= BoxSize - 2)
                    return;

                    console.log(BoxFiller + spaces + BoxFiller);
                    DrawRow(BoxSize, CurrPos + 1);
                    }

                    function DrawSquare(BoxSize) {
                    spaces = " ".repeat(BoxSize - 2);
                    hashtags = BoxFiller.repeat(BoxSize);
                    console.log(hashtags);
                    DrawRow(BoxSize, 0);
                    console.log(hashtags);
                    }

                    DrawSquare(8);

                    .as-console-wrapper { max-height: 100% !important; top: 0; }








                    share|improve this answer













                    Can use recursion






                    let BoxFiller = "#";
                    let Row = "";
                    var spaces, hashtags;

                    function DrawRow(BoxSize, CurrPos) {
                    if(CurrPos >= BoxSize - 2)
                    return;

                    console.log(BoxFiller + spaces + BoxFiller);
                    DrawRow(BoxSize, CurrPos + 1);
                    }

                    function DrawSquare(BoxSize) {
                    spaces = " ".repeat(BoxSize - 2);
                    hashtags = BoxFiller.repeat(BoxSize);
                    console.log(hashtags);
                    DrawRow(BoxSize, 0);
                    console.log(hashtags);
                    }

                    DrawSquare(8);

                    .as-console-wrapper { max-height: 100% !important; top: 0; }








                    let BoxFiller = "#";
                    let Row = "";
                    var spaces, hashtags;

                    function DrawRow(BoxSize, CurrPos) {
                    if(CurrPos >= BoxSize - 2)
                    return;

                    console.log(BoxFiller + spaces + BoxFiller);
                    DrawRow(BoxSize, CurrPos + 1);
                    }

                    function DrawSquare(BoxSize) {
                    spaces = " ".repeat(BoxSize - 2);
                    hashtags = BoxFiller.repeat(BoxSize);
                    console.log(hashtags);
                    DrawRow(BoxSize, 0);
                    console.log(hashtags);
                    }

                    DrawSquare(8);

                    .as-console-wrapper { max-height: 100% !important; top: 0; }





                    let BoxFiller = "#";
                    let Row = "";
                    var spaces, hashtags;

                    function DrawRow(BoxSize, CurrPos) {
                    if(CurrPos >= BoxSize - 2)
                    return;

                    console.log(BoxFiller + spaces + BoxFiller);
                    DrawRow(BoxSize, CurrPos + 1);
                    }

                    function DrawSquare(BoxSize) {
                    spaces = " ".repeat(BoxSize - 2);
                    hashtags = BoxFiller.repeat(BoxSize);
                    console.log(hashtags);
                    DrawRow(BoxSize, 0);
                    console.log(hashtags);
                    }

                    DrawSquare(8);

                    .as-console-wrapper { max-height: 100% !important; top: 0; }






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 23 '18 at 2:58









                    Miller Cy ChanMiller Cy Chan

                    423511




                    423511























                        0














                        Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.






                        function DrawSquare(size, filler) { 
                        const line = filler.repeat(size);
                        const mid = filler+' '.repeat(size-2)+filler;
                        let lines = [line];

                        for (var i = 1; i < size - 1; i++) {
                        lines.push(mid);
                        }

                        lines.push(line);

                        console.log(lines.join('n'));
                        }

                        DrawSquare(8, '*');





                        If I was going to redraw the same thing several times I would change it to look like this:






                        const cache = {};

                        function DrawSquare(size, filler) {
                        if (!cache[size]) {
                        const line = filler.repeat(size);
                        const mid = filler+' '.repeat(size-2)+filler;
                        let lines = [line];

                        for (var i = 1; i < size - 1; i++) {
                        lines.push(mid);
                        }

                        lines.push(line);

                        cache[size] = lines.join('n');
                        }

                        console.log(cache[size]);
                        }


                        console.time('first');
                        DrawSquare(12, '*');
                        console.timeEnd('first');

                        console.time('second');
                        DrawSquare(12, '*');
                        console.timeEnd('second');








                        share|improve this answer




























                          0














                          Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.






                          function DrawSquare(size, filler) { 
                          const line = filler.repeat(size);
                          const mid = filler+' '.repeat(size-2)+filler;
                          let lines = [line];

                          for (var i = 1; i < size - 1; i++) {
                          lines.push(mid);
                          }

                          lines.push(line);

                          console.log(lines.join('n'));
                          }

                          DrawSquare(8, '*');





                          If I was going to redraw the same thing several times I would change it to look like this:






                          const cache = {};

                          function DrawSquare(size, filler) {
                          if (!cache[size]) {
                          const line = filler.repeat(size);
                          const mid = filler+' '.repeat(size-2)+filler;
                          let lines = [line];

                          for (var i = 1; i < size - 1; i++) {
                          lines.push(mid);
                          }

                          lines.push(line);

                          cache[size] = lines.join('n');
                          }

                          console.log(cache[size]);
                          }


                          console.time('first');
                          DrawSquare(12, '*');
                          console.timeEnd('first');

                          console.time('second');
                          DrawSquare(12, '*');
                          console.timeEnd('second');








                          share|improve this answer


























                            0












                            0








                            0







                            Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.






                            function DrawSquare(size, filler) { 
                            const line = filler.repeat(size);
                            const mid = filler+' '.repeat(size-2)+filler;
                            let lines = [line];

                            for (var i = 1; i < size - 1; i++) {
                            lines.push(mid);
                            }

                            lines.push(line);

                            console.log(lines.join('n'));
                            }

                            DrawSquare(8, '*');





                            If I was going to redraw the same thing several times I would change it to look like this:






                            const cache = {};

                            function DrawSquare(size, filler) {
                            if (!cache[size]) {
                            const line = filler.repeat(size);
                            const mid = filler+' '.repeat(size-2)+filler;
                            let lines = [line];

                            for (var i = 1; i < size - 1; i++) {
                            lines.push(mid);
                            }

                            lines.push(line);

                            cache[size] = lines.join('n');
                            }

                            console.log(cache[size]);
                            }


                            console.time('first');
                            DrawSquare(12, '*');
                            console.timeEnd('first');

                            console.time('second');
                            DrawSquare(12, '*');
                            console.timeEnd('second');








                            share|improve this answer













                            Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.






                            function DrawSquare(size, filler) { 
                            const line = filler.repeat(size);
                            const mid = filler+' '.repeat(size-2)+filler;
                            let lines = [line];

                            for (var i = 1; i < size - 1; i++) {
                            lines.push(mid);
                            }

                            lines.push(line);

                            console.log(lines.join('n'));
                            }

                            DrawSquare(8, '*');





                            If I was going to redraw the same thing several times I would change it to look like this:






                            const cache = {};

                            function DrawSquare(size, filler) {
                            if (!cache[size]) {
                            const line = filler.repeat(size);
                            const mid = filler+' '.repeat(size-2)+filler;
                            let lines = [line];

                            for (var i = 1; i < size - 1; i++) {
                            lines.push(mid);
                            }

                            lines.push(line);

                            cache[size] = lines.join('n');
                            }

                            console.log(cache[size]);
                            }


                            console.time('first');
                            DrawSquare(12, '*');
                            console.timeEnd('first');

                            console.time('second');
                            DrawSquare(12, '*');
                            console.timeEnd('second');








                            function DrawSquare(size, filler) { 
                            const line = filler.repeat(size);
                            const mid = filler+' '.repeat(size-2)+filler;
                            let lines = [line];

                            for (var i = 1; i < size - 1; i++) {
                            lines.push(mid);
                            }

                            lines.push(line);

                            console.log(lines.join('n'));
                            }

                            DrawSquare(8, '*');





                            function DrawSquare(size, filler) { 
                            const line = filler.repeat(size);
                            const mid = filler+' '.repeat(size-2)+filler;
                            let lines = [line];

                            for (var i = 1; i < size - 1; i++) {
                            lines.push(mid);
                            }

                            lines.push(line);

                            console.log(lines.join('n'));
                            }

                            DrawSquare(8, '*');





                            const cache = {};

                            function DrawSquare(size, filler) {
                            if (!cache[size]) {
                            const line = filler.repeat(size);
                            const mid = filler+' '.repeat(size-2)+filler;
                            let lines = [line];

                            for (var i = 1; i < size - 1; i++) {
                            lines.push(mid);
                            }

                            lines.push(line);

                            cache[size] = lines.join('n');
                            }

                            console.log(cache[size]);
                            }


                            console.time('first');
                            DrawSquare(12, '*');
                            console.timeEnd('first');

                            console.time('second');
                            DrawSquare(12, '*');
                            console.timeEnd('second');





                            const cache = {};

                            function DrawSquare(size, filler) {
                            if (!cache[size]) {
                            const line = filler.repeat(size);
                            const mid = filler+' '.repeat(size-2)+filler;
                            let lines = [line];

                            for (var i = 1; i < size - 1; i++) {
                            lines.push(mid);
                            }

                            lines.push(line);

                            cache[size] = lines.join('n');
                            }

                            console.log(cache[size]);
                            }


                            console.time('first');
                            DrawSquare(12, '*');
                            console.timeEnd('first');

                            console.time('second');
                            DrawSquare(12, '*');
                            console.timeEnd('second');






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                            answered Nov 23 '18 at 3:17









                            IntervaliaIntervalia

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