Is the action of $SO(1,2)$ in null cone proper?
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It is known that the action of the group $SO(1,2)$ on the null-cone inside the $3$-dimensional Minkowski space is free and transitive. However, is the action also proper?
lie-groups group-actions
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add a comment |
$begingroup$
It is known that the action of the group $SO(1,2)$ on the null-cone inside the $3$-dimensional Minkowski space is free and transitive. However, is the action also proper?
lie-groups group-actions
$endgroup$
1
$begingroup$
In a free group action, all the orbits are essentially a copy of the group itself. But the null-cone is 2D whereas the Lie group SO(1,2) is 3D, so how can the action be free?
$endgroup$
– arctic tern
Dec 15 '18 at 3:09
add a comment |
$begingroup$
It is known that the action of the group $SO(1,2)$ on the null-cone inside the $3$-dimensional Minkowski space is free and transitive. However, is the action also proper?
lie-groups group-actions
$endgroup$
It is known that the action of the group $SO(1,2)$ on the null-cone inside the $3$-dimensional Minkowski space is free and transitive. However, is the action also proper?
lie-groups group-actions
lie-groups group-actions
edited Dec 11 '18 at 6:00
user1101010
9011830
9011830
asked Dec 11 '18 at 5:33
VarunVarun
11
11
1
$begingroup$
In a free group action, all the orbits are essentially a copy of the group itself. But the null-cone is 2D whereas the Lie group SO(1,2) is 3D, so how can the action be free?
$endgroup$
– arctic tern
Dec 15 '18 at 3:09
add a comment |
1
$begingroup$
In a free group action, all the orbits are essentially a copy of the group itself. But the null-cone is 2D whereas the Lie group SO(1,2) is 3D, so how can the action be free?
$endgroup$
– arctic tern
Dec 15 '18 at 3:09
1
1
$begingroup$
In a free group action, all the orbits are essentially a copy of the group itself. But the null-cone is 2D whereas the Lie group SO(1,2) is 3D, so how can the action be free?
$endgroup$
– arctic tern
Dec 15 '18 at 3:09
$begingroup$
In a free group action, all the orbits are essentially a copy of the group itself. But the null-cone is 2D whereas the Lie group SO(1,2) is 3D, so how can the action be free?
$endgroup$
– arctic tern
Dec 15 '18 at 3:09
add a comment |
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$begingroup$
In a free group action, all the orbits are essentially a copy of the group itself. But the null-cone is 2D whereas the Lie group SO(1,2) is 3D, so how can the action be free?
$endgroup$
– arctic tern
Dec 15 '18 at 3:09