How to invert Logic Gate input in Circuitikz












5















I have drawn the following circuit, but how could the inputs of a Logic Gate be inverted? (As in the scanned picture, but it does not matter which gate exactly, just generally)



The circuit



The negated Inputs



documentclass[a4paper,12pt]{article}

usepackage{tikz} %vectorgraphics
usetikzlibrary{shapes,arrows,shadows,
decorations.pathreplacing,backgrounds,calc}
%graph/flowchart
usepackage[siunitx]{circuitikz}

begin{document}
begin{circuitikz} draw

(0,0) node[nand port] (nand1) {}
(3,0) node[nand port] (nand2) {}
(5,0) node[nand port] (nand3) {}

(3,2) node[nand port] (nand4) {}
(5,2) node[nand port] (nand5) {}

(3,4) node[nand port] (nand6) {}
(5,4) node[nand port] (nand7) {}

(0,4) node[nand port] (nand8) {}

(nand1.out) |- (nand2.in 2)
(nand2.out) -| node[circ,midway]{} (nand3.in 1)
(nand2.out) -| (nand3.in 2)

(nand8.out) |- (nand6.in 1)
(nand6.out) -| node[circ,midway]{} (nand7.in 2)
(nand6.out) -| (nand7.in 1)

(nand4.out) -| node[circ,midway]{} (nand5.in 2)
(nand4.out) -| (nand5.in 1)

(-2,1) node(B1)[anchor=east] {B}
(-2,1) -| node[circ,midway]{} (nand1.in 1)
to[short,*-] (nand1.in 2)
(-2,1) -| (nand4.in 2)
(1,1) node[circ]{} |- (nand6.in 2)


(-2,3) node[anchor=east] {A}
(-2,3) -| node[circ,midway]{} (nand8.in 2)
to[short,*-] (nand8.in 1)
(-2,3) -| (nand4.in 1)
(0.5,3) node[circ]{} |- (nand2.in 1)

(6,1.97) node[anchor=east] {O2}
(6,0.0) node[anchor=east] {O3}
(6,4) node[anchor=east] {O1}

;end{circuitikz}

end{document}









share|improve this question


















  • 2





    Nice question. I'll look over it tomorrow (it's nighttime here), but I don't think it could be easily done with the current implementation. But seems a valuable enhancement proposal, anyway.

    – Rmano
    Mar 13 at 22:41











  • I am considering it as a enhancement proposal; if you want you can open an issue at github.com/circuitikz/circuitikz/issues

    – Rmano
    Mar 14 at 7:24






  • 1





    With current circuitikz you cannot achieve this. However, you can use tikz's stock ciruit option to achieve it. Nevertheless, a very useful question though.

    – Raaja
    Mar 14 at 11:51


















5















I have drawn the following circuit, but how could the inputs of a Logic Gate be inverted? (As in the scanned picture, but it does not matter which gate exactly, just generally)



The circuit



The negated Inputs



documentclass[a4paper,12pt]{article}

usepackage{tikz} %vectorgraphics
usetikzlibrary{shapes,arrows,shadows,
decorations.pathreplacing,backgrounds,calc}
%graph/flowchart
usepackage[siunitx]{circuitikz}

begin{document}
begin{circuitikz} draw

(0,0) node[nand port] (nand1) {}
(3,0) node[nand port] (nand2) {}
(5,0) node[nand port] (nand3) {}

(3,2) node[nand port] (nand4) {}
(5,2) node[nand port] (nand5) {}

(3,4) node[nand port] (nand6) {}
(5,4) node[nand port] (nand7) {}

(0,4) node[nand port] (nand8) {}

(nand1.out) |- (nand2.in 2)
(nand2.out) -| node[circ,midway]{} (nand3.in 1)
(nand2.out) -| (nand3.in 2)

(nand8.out) |- (nand6.in 1)
(nand6.out) -| node[circ,midway]{} (nand7.in 2)
(nand6.out) -| (nand7.in 1)

(nand4.out) -| node[circ,midway]{} (nand5.in 2)
(nand4.out) -| (nand5.in 1)

(-2,1) node(B1)[anchor=east] {B}
(-2,1) -| node[circ,midway]{} (nand1.in 1)
to[short,*-] (nand1.in 2)
(-2,1) -| (nand4.in 2)
(1,1) node[circ]{} |- (nand6.in 2)


(-2,3) node[anchor=east] {A}
(-2,3) -| node[circ,midway]{} (nand8.in 2)
to[short,*-] (nand8.in 1)
(-2,3) -| (nand4.in 1)
(0.5,3) node[circ]{} |- (nand2.in 1)

(6,1.97) node[anchor=east] {O2}
(6,0.0) node[anchor=east] {O3}
(6,4) node[anchor=east] {O1}

;end{circuitikz}

end{document}









share|improve this question


















  • 2





    Nice question. I'll look over it tomorrow (it's nighttime here), but I don't think it could be easily done with the current implementation. But seems a valuable enhancement proposal, anyway.

    – Rmano
    Mar 13 at 22:41











  • I am considering it as a enhancement proposal; if you want you can open an issue at github.com/circuitikz/circuitikz/issues

    – Rmano
    Mar 14 at 7:24






  • 1





    With current circuitikz you cannot achieve this. However, you can use tikz's stock ciruit option to achieve it. Nevertheless, a very useful question though.

    – Raaja
    Mar 14 at 11:51
















5












5








5


1






I have drawn the following circuit, but how could the inputs of a Logic Gate be inverted? (As in the scanned picture, but it does not matter which gate exactly, just generally)



The circuit



The negated Inputs



documentclass[a4paper,12pt]{article}

usepackage{tikz} %vectorgraphics
usetikzlibrary{shapes,arrows,shadows,
decorations.pathreplacing,backgrounds,calc}
%graph/flowchart
usepackage[siunitx]{circuitikz}

begin{document}
begin{circuitikz} draw

(0,0) node[nand port] (nand1) {}
(3,0) node[nand port] (nand2) {}
(5,0) node[nand port] (nand3) {}

(3,2) node[nand port] (nand4) {}
(5,2) node[nand port] (nand5) {}

(3,4) node[nand port] (nand6) {}
(5,4) node[nand port] (nand7) {}

(0,4) node[nand port] (nand8) {}

(nand1.out) |- (nand2.in 2)
(nand2.out) -| node[circ,midway]{} (nand3.in 1)
(nand2.out) -| (nand3.in 2)

(nand8.out) |- (nand6.in 1)
(nand6.out) -| node[circ,midway]{} (nand7.in 2)
(nand6.out) -| (nand7.in 1)

(nand4.out) -| node[circ,midway]{} (nand5.in 2)
(nand4.out) -| (nand5.in 1)

(-2,1) node(B1)[anchor=east] {B}
(-2,1) -| node[circ,midway]{} (nand1.in 1)
to[short,*-] (nand1.in 2)
(-2,1) -| (nand4.in 2)
(1,1) node[circ]{} |- (nand6.in 2)


(-2,3) node[anchor=east] {A}
(-2,3) -| node[circ,midway]{} (nand8.in 2)
to[short,*-] (nand8.in 1)
(-2,3) -| (nand4.in 1)
(0.5,3) node[circ]{} |- (nand2.in 1)

(6,1.97) node[anchor=east] {O2}
(6,0.0) node[anchor=east] {O3}
(6,4) node[anchor=east] {O1}

;end{circuitikz}

end{document}









share|improve this question














I have drawn the following circuit, but how could the inputs of a Logic Gate be inverted? (As in the scanned picture, but it does not matter which gate exactly, just generally)



The circuit



The negated Inputs



documentclass[a4paper,12pt]{article}

usepackage{tikz} %vectorgraphics
usetikzlibrary{shapes,arrows,shadows,
decorations.pathreplacing,backgrounds,calc}
%graph/flowchart
usepackage[siunitx]{circuitikz}

begin{document}
begin{circuitikz} draw

(0,0) node[nand port] (nand1) {}
(3,0) node[nand port] (nand2) {}
(5,0) node[nand port] (nand3) {}

(3,2) node[nand port] (nand4) {}
(5,2) node[nand port] (nand5) {}

(3,4) node[nand port] (nand6) {}
(5,4) node[nand port] (nand7) {}

(0,4) node[nand port] (nand8) {}

(nand1.out) |- (nand2.in 2)
(nand2.out) -| node[circ,midway]{} (nand3.in 1)
(nand2.out) -| (nand3.in 2)

(nand8.out) |- (nand6.in 1)
(nand6.out) -| node[circ,midway]{} (nand7.in 2)
(nand6.out) -| (nand7.in 1)

(nand4.out) -| node[circ,midway]{} (nand5.in 2)
(nand4.out) -| (nand5.in 1)

(-2,1) node(B1)[anchor=east] {B}
(-2,1) -| node[circ,midway]{} (nand1.in 1)
to[short,*-] (nand1.in 2)
(-2,1) -| (nand4.in 2)
(1,1) node[circ]{} |- (nand6.in 2)


(-2,3) node[anchor=east] {A}
(-2,3) -| node[circ,midway]{} (nand8.in 2)
to[short,*-] (nand8.in 1)
(-2,3) -| (nand4.in 1)
(0.5,3) node[circ]{} |- (nand2.in 1)

(6,1.97) node[anchor=east] {O2}
(6,0.0) node[anchor=east] {O3}
(6,4) node[anchor=east] {O1}

;end{circuitikz}

end{document}






circuitikz logic






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 13 at 21:54









Roman StadlerRoman Stadler

575




575








  • 2





    Nice question. I'll look over it tomorrow (it's nighttime here), but I don't think it could be easily done with the current implementation. But seems a valuable enhancement proposal, anyway.

    – Rmano
    Mar 13 at 22:41











  • I am considering it as a enhancement proposal; if you want you can open an issue at github.com/circuitikz/circuitikz/issues

    – Rmano
    Mar 14 at 7:24






  • 1





    With current circuitikz you cannot achieve this. However, you can use tikz's stock ciruit option to achieve it. Nevertheless, a very useful question though.

    – Raaja
    Mar 14 at 11:51
















  • 2





    Nice question. I'll look over it tomorrow (it's nighttime here), but I don't think it could be easily done with the current implementation. But seems a valuable enhancement proposal, anyway.

    – Rmano
    Mar 13 at 22:41











  • I am considering it as a enhancement proposal; if you want you can open an issue at github.com/circuitikz/circuitikz/issues

    – Rmano
    Mar 14 at 7:24






  • 1





    With current circuitikz you cannot achieve this. However, you can use tikz's stock ciruit option to achieve it. Nevertheless, a very useful question though.

    – Raaja
    Mar 14 at 11:51










2




2





Nice question. I'll look over it tomorrow (it's nighttime here), but I don't think it could be easily done with the current implementation. But seems a valuable enhancement proposal, anyway.

– Rmano
Mar 13 at 22:41





Nice question. I'll look over it tomorrow (it's nighttime here), but I don't think it could be easily done with the current implementation. But seems a valuable enhancement proposal, anyway.

– Rmano
Mar 13 at 22:41













I am considering it as a enhancement proposal; if you want you can open an issue at github.com/circuitikz/circuitikz/issues

– Rmano
Mar 14 at 7:24





I am considering it as a enhancement proposal; if you want you can open an issue at github.com/circuitikz/circuitikz/issues

– Rmano
Mar 14 at 7:24




1




1





With current circuitikz you cannot achieve this. However, you can use tikz's stock ciruit option to achieve it. Nevertheless, a very useful question though.

– Raaja
Mar 14 at 11:51







With current circuitikz you cannot achieve this. However, you can use tikz's stock ciruit option to achieve it. Nevertheless, a very useful question though.

– Raaja
Mar 14 at 11:51












1 Answer
1






active

oldest

votes


















3














Using the fresh new circuitikzgit uploaded minutes ago, you can now do this:



documentclass[border=10pt]{standalone}
usepackage[siunitx, RPvoltages]{circuitikzgit}
begin{document}
begin{circuitikz}
draw (0,3) node[american and port] (A) {P1};
node at (A.bin 1) [ocirc, left]{} ;
begin{scope}
ctikzset{tripoles/american or port/height=1.6}
draw (A.out) -- ++(0.5,0) node[american or port,
number inputs=5, anchor=in 1] (B) {P2};
node at (B.bin 3) [ocirc, left]{} ;
end{scope}
draw (0,1.5) node[american or port] (C) {P3};
node at (C.bin 2) [ocirc, left]{} ;
draw (C.out) |- (B.in 2);
end{circuitikz}
end{document}


output from he above snippet



See: https://github.com/circuitikz/circuitikz/issues/166 and https://github.com/circuitikz/circuitikz/pull/168






share|improve this answer
























  • when will it be available in CTAN?

    – Raaja
    Mar 18 at 7:28











  • @Raaja I am completing a couple of things more (basically, manual overhaul and fillable shapes) and then I'll do a release. Three to five weeks, if RL doesn't create problems... ;-)

    – Rmano
    Mar 18 at 8:23













  • Good to know! Because, it seems many are interested in creating big-logic circuits with ciruittikz (see: tex.stackexchange.com/questions/480034/…). And, I think this is a really nice contribution indeed :).

    – Raaja
    Mar 18 at 8:29











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














Using the fresh new circuitikzgit uploaded minutes ago, you can now do this:



documentclass[border=10pt]{standalone}
usepackage[siunitx, RPvoltages]{circuitikzgit}
begin{document}
begin{circuitikz}
draw (0,3) node[american and port] (A) {P1};
node at (A.bin 1) [ocirc, left]{} ;
begin{scope}
ctikzset{tripoles/american or port/height=1.6}
draw (A.out) -- ++(0.5,0) node[american or port,
number inputs=5, anchor=in 1] (B) {P2};
node at (B.bin 3) [ocirc, left]{} ;
end{scope}
draw (0,1.5) node[american or port] (C) {P3};
node at (C.bin 2) [ocirc, left]{} ;
draw (C.out) |- (B.in 2);
end{circuitikz}
end{document}


output from he above snippet



See: https://github.com/circuitikz/circuitikz/issues/166 and https://github.com/circuitikz/circuitikz/pull/168






share|improve this answer
























  • when will it be available in CTAN?

    – Raaja
    Mar 18 at 7:28











  • @Raaja I am completing a couple of things more (basically, manual overhaul and fillable shapes) and then I'll do a release. Three to five weeks, if RL doesn't create problems... ;-)

    – Rmano
    Mar 18 at 8:23













  • Good to know! Because, it seems many are interested in creating big-logic circuits with ciruittikz (see: tex.stackexchange.com/questions/480034/…). And, I think this is a really nice contribution indeed :).

    – Raaja
    Mar 18 at 8:29
















3














Using the fresh new circuitikzgit uploaded minutes ago, you can now do this:



documentclass[border=10pt]{standalone}
usepackage[siunitx, RPvoltages]{circuitikzgit}
begin{document}
begin{circuitikz}
draw (0,3) node[american and port] (A) {P1};
node at (A.bin 1) [ocirc, left]{} ;
begin{scope}
ctikzset{tripoles/american or port/height=1.6}
draw (A.out) -- ++(0.5,0) node[american or port,
number inputs=5, anchor=in 1] (B) {P2};
node at (B.bin 3) [ocirc, left]{} ;
end{scope}
draw (0,1.5) node[american or port] (C) {P3};
node at (C.bin 2) [ocirc, left]{} ;
draw (C.out) |- (B.in 2);
end{circuitikz}
end{document}


output from he above snippet



See: https://github.com/circuitikz/circuitikz/issues/166 and https://github.com/circuitikz/circuitikz/pull/168






share|improve this answer
























  • when will it be available in CTAN?

    – Raaja
    Mar 18 at 7:28











  • @Raaja I am completing a couple of things more (basically, manual overhaul and fillable shapes) and then I'll do a release. Three to five weeks, if RL doesn't create problems... ;-)

    – Rmano
    Mar 18 at 8:23













  • Good to know! Because, it seems many are interested in creating big-logic circuits with ciruittikz (see: tex.stackexchange.com/questions/480034/…). And, I think this is a really nice contribution indeed :).

    – Raaja
    Mar 18 at 8:29














3












3








3







Using the fresh new circuitikzgit uploaded minutes ago, you can now do this:



documentclass[border=10pt]{standalone}
usepackage[siunitx, RPvoltages]{circuitikzgit}
begin{document}
begin{circuitikz}
draw (0,3) node[american and port] (A) {P1};
node at (A.bin 1) [ocirc, left]{} ;
begin{scope}
ctikzset{tripoles/american or port/height=1.6}
draw (A.out) -- ++(0.5,0) node[american or port,
number inputs=5, anchor=in 1] (B) {P2};
node at (B.bin 3) [ocirc, left]{} ;
end{scope}
draw (0,1.5) node[american or port] (C) {P3};
node at (C.bin 2) [ocirc, left]{} ;
draw (C.out) |- (B.in 2);
end{circuitikz}
end{document}


output from he above snippet



See: https://github.com/circuitikz/circuitikz/issues/166 and https://github.com/circuitikz/circuitikz/pull/168






share|improve this answer













Using the fresh new circuitikzgit uploaded minutes ago, you can now do this:



documentclass[border=10pt]{standalone}
usepackage[siunitx, RPvoltages]{circuitikzgit}
begin{document}
begin{circuitikz}
draw (0,3) node[american and port] (A) {P1};
node at (A.bin 1) [ocirc, left]{} ;
begin{scope}
ctikzset{tripoles/american or port/height=1.6}
draw (A.out) -- ++(0.5,0) node[american or port,
number inputs=5, anchor=in 1] (B) {P2};
node at (B.bin 3) [ocirc, left]{} ;
end{scope}
draw (0,1.5) node[american or port] (C) {P3};
node at (C.bin 2) [ocirc, left]{} ;
draw (C.out) |- (B.in 2);
end{circuitikz}
end{document}


output from he above snippet



See: https://github.com/circuitikz/circuitikz/issues/166 and https://github.com/circuitikz/circuitikz/pull/168







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 15 at 10:14









RmanoRmano

8,18121647




8,18121647













  • when will it be available in CTAN?

    – Raaja
    Mar 18 at 7:28











  • @Raaja I am completing a couple of things more (basically, manual overhaul and fillable shapes) and then I'll do a release. Three to five weeks, if RL doesn't create problems... ;-)

    – Rmano
    Mar 18 at 8:23













  • Good to know! Because, it seems many are interested in creating big-logic circuits with ciruittikz (see: tex.stackexchange.com/questions/480034/…). And, I think this is a really nice contribution indeed :).

    – Raaja
    Mar 18 at 8:29



















  • when will it be available in CTAN?

    – Raaja
    Mar 18 at 7:28











  • @Raaja I am completing a couple of things more (basically, manual overhaul and fillable shapes) and then I'll do a release. Three to five weeks, if RL doesn't create problems... ;-)

    – Rmano
    Mar 18 at 8:23













  • Good to know! Because, it seems many are interested in creating big-logic circuits with ciruittikz (see: tex.stackexchange.com/questions/480034/…). And, I think this is a really nice contribution indeed :).

    – Raaja
    Mar 18 at 8:29

















when will it be available in CTAN?

– Raaja
Mar 18 at 7:28





when will it be available in CTAN?

– Raaja
Mar 18 at 7:28













@Raaja I am completing a couple of things more (basically, manual overhaul and fillable shapes) and then I'll do a release. Three to five weeks, if RL doesn't create problems... ;-)

– Rmano
Mar 18 at 8:23







@Raaja I am completing a couple of things more (basically, manual overhaul and fillable shapes) and then I'll do a release. Three to five weeks, if RL doesn't create problems... ;-)

– Rmano
Mar 18 at 8:23















Good to know! Because, it seems many are interested in creating big-logic circuits with ciruittikz (see: tex.stackexchange.com/questions/480034/…). And, I think this is a really nice contribution indeed :).

– Raaja
Mar 18 at 8:29





Good to know! Because, it seems many are interested in creating big-logic circuits with ciruittikz (see: tex.stackexchange.com/questions/480034/…). And, I think this is a really nice contribution indeed :).

– Raaja
Mar 18 at 8:29


















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