How can I exclude my count from my grade average?
0
I'm trying to figure out how to have a count when when I want to display my file, but not have the count get added into my grade average.
def main():
choice = "q"
while choice != "X":
print_menu()
choice = input("Enter an option (D, C, X): ")
if choice == "D":
DisplayScores()
elif choice == "C":
CalcAverage()
def print_menu():
print("D. Display Grades")
print("C. Calculate Average")
print("X. Exit Application")
def DisplayScores():
try:
infile = open("data.txt",'r')
count = 0
for line in infile:
count += 1
print(count,line.rstrip("n"))
line = infile.readline()
infile.close()
except IOError:
print("File does not exist.")
except:
print("Unknown error.")
def CalcAverage():
Average = 0.0
try:
datafile = open("data.txt", 'r')
for grade in datafile:
total = float(grade)
Average += total
print("The average of the class is: ", format(Average/29, '.2f'))
except IOError:
print("Something is wrong with the file.")
print("Unknown Error.")
datafile.close()
main()
python count
edited Nov 21 '18 at 2:01
Obsidian Age
28k72344
asked Nov 21 '18 at 1:58
Brady AlgerBrady Alger
31
add a comment |
0
I'm trying to figure out how to have a count when when I want to display my file, but not have the count get added into my grade average.
def main():
choice = "q"
while choice != "X":
print_menu()
choice = input("Enter an option (D, C, X): ")
if choice == "D":
DisplayScores()
elif choice == "C":
CalcAverage()
def print_menu():
print("D. Display Grades")
print("C. Calculate Average")
print("X. Exit Application")
def DisplayScores():
try:
infile = open("data.txt",'r')
count = 0
for line in infile:
count += 1
print(count,line.rstrip("n"))
line = infile.readline()
infile.close()
except IOError:
print("File does not exist.")
except:
print("Unknown error.")
def CalcAverage():
Average = 0.0
try:
datafile = open("data.txt", 'r')
for grade in datafile:
total = float(grade)
Average += total
print("The average of the class is: ", format(Average/29, '.2f'))
except IOError:
print("Something is wrong with the file.")
print("Unknown Error.")
datafile.close()
main()
python count
edited Nov 21 '18 at 2:01
Obsidian Age
28k72344
asked Nov 21 '18 at 1:58
Brady AlgerBrady Alger
31
What format is the data from the text file in?
– Cory L
Nov 21 '18 at 2:04
Welcome to SO, I'm seeing the question as very valid in nature, but please show us whatdata.txtcontains or at least a sample of.. This way it's easier to formulate a response
– Jab
Nov 21 '18 at 2:09
2
I'm trying to figure out how to have a count when when I want to display my file A count of what?
– John Gordon
Nov 21 '18 at 2:10
the file contains grades ranging from 62 to 100 EX: 65 78 76 99 87 etc. in my program i need it to have a number before each grade as if it was a student
– Brady Alger
Nov 21 '18 at 2:22
add a comment |
0
0
0
I'm trying to figure out how to have a count when when I want to display my file, but not have the count get added into my grade average.
def main():
choice = "q"
while choice != "X":
print_menu()
choice = input("Enter an option (D, C, X): ")
if choice == "D":
DisplayScores()
elif choice == "C":
CalcAverage()
def print_menu():
print("D. Display Grades")
print("C. Calculate Average")
print("X. Exit Application")
def DisplayScores():
try:
infile = open("data.txt",'r')
count = 0
for line in infile:
count += 1
print(count,line.rstrip("n"))
line = infile.readline()
infile.close()
except IOError:
print("File does not exist.")
except:
print("Unknown error.")
def CalcAverage():
Average = 0.0
try:
datafile = open("data.txt", 'r')
for grade in datafile:
total = float(grade)
Average += total
print("The average of the class is: ", format(Average/29, '.2f'))
except IOError:
print("Something is wrong with the file.")
print("Unknown Error.")
datafile.close()
main()
python count
edited Nov 21 '18 at 2:01
Obsidian Age
28k72344
asked Nov 21 '18 at 1:58
Brady AlgerBrady Alger
31
I'm trying to figure out how to have a count when when I want to display my file, but not have the count get added into my grade average.
def main():
choice = "q"
while choice != "X":
print_menu()
choice = input("Enter an option (D, C, X): ")
if choice == "D":
DisplayScores()
elif choice == "C":
CalcAverage()
def print_menu():
print("D. Display Grades")
print("C. Calculate Average")
print("X. Exit Application")
def DisplayScores():
try:
infile = open("data.txt",'r')
count = 0
for line in infile:
count += 1
print(count,line.rstrip("n"))
line = infile.readline()
infile.close()
except IOError:
print("File does not exist.")
except:
print("Unknown error.")
def CalcAverage():
Average = 0.0
try:
datafile = open("data.txt", 'r')
for grade in datafile:
total = float(grade)
Average += total
print("The average of the class is: ", format(Average/29, '.2f'))
except IOError:
print("Something is wrong with the file.")
print("Unknown Error.")
datafile.close()
main()
python count
python count
edited Nov 21 '18 at 2:01
Obsidian Age
28k72344
asked Nov 21 '18 at 1:58
Brady AlgerBrady Alger
31
edited Nov 21 '18 at 2:01
Obsidian Age
28k72344
asked Nov 21 '18 at 1:58
Brady AlgerBrady Alger
31
edited Nov 21 '18 at 2:01
Obsidian Age
28k72344
edited Nov 21 '18 at 2:01
Obsidian Age
28k72344
edited Nov 21 '18 at 2:01
Obsidian Age
28k72344
28k72344
asked Nov 21 '18 at 1:58
Brady AlgerBrady Alger
31
asked Nov 21 '18 at 1:58
Brady AlgerBrady Alger
31
asked Nov 21 '18 at 1:58
Brady AlgerBrady Alger
31
31
What format is the data from the text file in?
– Cory L
Nov 21 '18 at 2:04
Welcome to SO, I'm seeing the question as very valid in nature, but please show us whatdata.txtcontains or at least a sample of.. This way it's easier to formulate a response
– Jab
Nov 21 '18 at 2:09
2
I'm trying to figure out how to have a count when when I want to display my file A count of what?
– John Gordon
Nov 21 '18 at 2:10
the file contains grades ranging from 62 to 100 EX: 65 78 76 99 87 etc. in my program i need it to have a number before each grade as if it was a student
– Brady Alger
Nov 21 '18 at 2:22
add a comment |
What format is the data from the text file in?
– Cory L
Nov 21 '18 at 2:04
Welcome to SO, I'm seeing the question as very valid in nature, but please show us whatdata.txtcontains or at least a sample of.. This way it's easier to formulate a response
– Jab
Nov 21 '18 at 2:09
2
I'm trying to figure out how to have a count when when I want to display my file A count of what?
– John Gordon
Nov 21 '18 at 2:10
the file contains grades ranging from 62 to 100 EX: 65 78 76 99 87 etc. in my program i need it to have a number before each grade as if it was a student
– Brady Alger
Nov 21 '18 at 2:22
What format is the data from the text file in?
– Cory L
Nov 21 '18 at 2:04
What format is the data from the text file in?
– Cory L
Nov 21 '18 at 2:04
Welcome to SO, I'm seeing the question as very valid in nature, but please show us what
data.txt contains or at least a sample of.. This way it's easier to formulate a response– Jab
Nov 21 '18 at 2:09
Welcome to SO, I'm seeing the question as very valid in nature, but please show us what
data.txt contains or at least a sample of.. This way it's easier to formulate a response– Jab
Nov 21 '18 at 2:09
2
2
I'm trying to figure out how to have a count when when I want to display my file A count of what?
– John Gordon
Nov 21 '18 at 2:10
I'm trying to figure out how to have a count when when I want to display my file A count of what?
– John Gordon
Nov 21 '18 at 2:10
the file contains grades ranging from 62 to 100 EX: 65 78 76 99 87 etc. in my program i need it to have a number before each grade as if it was a student
– Brady Alger
Nov 21 '18 at 2:22
the file contains grades ranging from 62 to 100 EX: 65 78 76 99 87 etc. in my program i need it to have a number before each grade as if it was a student
– Brady Alger
Nov 21 '18 at 2:22
add a comment |
1 Answer
1
active
oldest
votes
0
Why are you printing the average each time through the loop? You can't know what the average is until the loop is finished. Also, it would be better to divide by the actual number of grades in the file, instead of assuming 29. Try this instead:
total = 0.0
grades = 0
try:
datafile = open("data.txt", 'r')
for grade in datafile:
grades += 1
total += float(grade)
print("The average of the class is: ", format(total/grades, '.2f'))
answered Nov 21 '18 at 2:29
John GordonJohn Gordon
10.1k51730
Holy Crap its so clear now thank you so much!!!!
– Brady Alger
Nov 21 '18 at 2:48
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Why are you printing the average each time through the loop? You can't know what the average is until the loop is finished. Also, it would be better to divide by the actual number of grades in the file, instead of assuming 29. Try this instead:
total = 0.0
grades = 0
try:
datafile = open("data.txt", 'r')
for grade in datafile:
grades += 1
total += float(grade)
print("The average of the class is: ", format(total/grades, '.2f'))
answered Nov 21 '18 at 2:29
John GordonJohn Gordon
10.1k51730
Holy Crap its so clear now thank you so much!!!!
– Brady Alger
Nov 21 '18 at 2:48
add a comment |
0
Why are you printing the average each time through the loop? You can't know what the average is until the loop is finished. Also, it would be better to divide by the actual number of grades in the file, instead of assuming 29. Try this instead:
total = 0.0
grades = 0
try:
datafile = open("data.txt", 'r')
for grade in datafile:
grades += 1
total += float(grade)
print("The average of the class is: ", format(total/grades, '.2f'))
answered Nov 21 '18 at 2:29
John GordonJohn Gordon
10.1k51730
Holy Crap its so clear now thank you so much!!!!
– Brady Alger
Nov 21 '18 at 2:48
add a comment |
0
0
0
Why are you printing the average each time through the loop? You can't know what the average is until the loop is finished. Also, it would be better to divide by the actual number of grades in the file, instead of assuming 29. Try this instead:
total = 0.0
grades = 0
try:
datafile = open("data.txt", 'r')
for grade in datafile:
grades += 1
total += float(grade)
print("The average of the class is: ", format(total/grades, '.2f'))
answered Nov 21 '18 at 2:29
John GordonJohn Gordon
10.1k51730
Why are you printing the average each time through the loop? You can't know what the average is until the loop is finished. Also, it would be better to divide by the actual number of grades in the file, instead of assuming 29. Try this instead:
total = 0.0
grades = 0
try:
datafile = open("data.txt", 'r')
for grade in datafile:
grades += 1
total += float(grade)
print("The average of the class is: ", format(total/grades, '.2f'))
answered Nov 21 '18 at 2:29
John GordonJohn Gordon
10.1k51730
answered Nov 21 '18 at 2:29
John GordonJohn Gordon
10.1k51730
answered Nov 21 '18 at 2:29
John GordonJohn Gordon
10.1k51730
answered Nov 21 '18 at 2:29
John GordonJohn Gordon
10.1k51730
10.1k51730
Holy Crap its so clear now thank you so much!!!!
– Brady Alger
Nov 21 '18 at 2:48
add a comment |
Holy Crap its so clear now thank you so much!!!!
– Brady Alger
Nov 21 '18 at 2:48
Holy Crap its so clear now thank you so much!!!!
– Brady Alger
Nov 21 '18 at 2:48
Holy Crap its so clear now thank you so much!!!!
– Brady Alger
Nov 21 '18 at 2:48
add a comment |
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What format is the data from the text file in?
– Cory L
Nov 21 '18 at 2:04
Welcome to SO, I'm seeing the question as very valid in nature, but please show us what
data.txtcontains or at least a sample of.. This way it's easier to formulate a response– Jab
Nov 21 '18 at 2:09
2
I'm trying to figure out how to have a count when when I want to display my file A count of what?
– John Gordon
Nov 21 '18 at 2:10
the file contains grades ranging from 62 to 100 EX: 65 78 76 99 87 etc. in my program i need it to have a number before each grade as if it was a student
– Brady Alger
Nov 21 '18 at 2:22