How to draw a path to form a regular pentagon?












4















I already have a code that draws a regular hexagon the following way



begin{tikzpicture}[every node/.style={draw,shape=circle,fill=blue}]
path (0,0) node (p0) {}
(-1.5,-1) node (p1) {}
(-1.5,-2.5) node (p2) {}
(1.5,-2.5) node (p3) {}
(1.5,-1) node (p4) {}
(0,-3.5) node (p5) { };
draw (p0) -- (p1)
(p0) -- (p1)
(p0) -- (p2)
(p0) -- (p3)
(p0) -- (p4)
(p0) -- (p5)
(p1) -- (p2)
(p1) -- (p3)
(p1) -- (p4)
(p1) -- (p5)
(p2) -- (p3)
(p2) -- (p4)
(p2) -- (p5)
(p3) -- (p4)
(p3) -- (p5)
(p4) -- (p5);
end{tikzpicture}


But Now I need to remove one of the points and to draw a regular pentagon the same way. So I need to remove (P5) and to recalibrate all other points (change their coordinates) But I don't need to change the code much.



Is there a way to do it by just slightly changing my code here. ?










share|improve this question




















  • 3





    Define your points using the polar notation for radius+angle of rotation. Then you can simply make the angle 360 / number of sides, and your code is completely general...

    – Thruston
    Dec 1 '15 at 19:06
















4















I already have a code that draws a regular hexagon the following way



begin{tikzpicture}[every node/.style={draw,shape=circle,fill=blue}]
path (0,0) node (p0) {}
(-1.5,-1) node (p1) {}
(-1.5,-2.5) node (p2) {}
(1.5,-2.5) node (p3) {}
(1.5,-1) node (p4) {}
(0,-3.5) node (p5) { };
draw (p0) -- (p1)
(p0) -- (p1)
(p0) -- (p2)
(p0) -- (p3)
(p0) -- (p4)
(p0) -- (p5)
(p1) -- (p2)
(p1) -- (p3)
(p1) -- (p4)
(p1) -- (p5)
(p2) -- (p3)
(p2) -- (p4)
(p2) -- (p5)
(p3) -- (p4)
(p3) -- (p5)
(p4) -- (p5);
end{tikzpicture}


But Now I need to remove one of the points and to draw a regular pentagon the same way. So I need to remove (P5) and to recalibrate all other points (change their coordinates) But I don't need to change the code much.



Is there a way to do it by just slightly changing my code here. ?










share|improve this question




















  • 3





    Define your points using the polar notation for radius+angle of rotation. Then you can simply make the angle 360 / number of sides, and your code is completely general...

    – Thruston
    Dec 1 '15 at 19:06














4












4








4


2






I already have a code that draws a regular hexagon the following way



begin{tikzpicture}[every node/.style={draw,shape=circle,fill=blue}]
path (0,0) node (p0) {}
(-1.5,-1) node (p1) {}
(-1.5,-2.5) node (p2) {}
(1.5,-2.5) node (p3) {}
(1.5,-1) node (p4) {}
(0,-3.5) node (p5) { };
draw (p0) -- (p1)
(p0) -- (p1)
(p0) -- (p2)
(p0) -- (p3)
(p0) -- (p4)
(p0) -- (p5)
(p1) -- (p2)
(p1) -- (p3)
(p1) -- (p4)
(p1) -- (p5)
(p2) -- (p3)
(p2) -- (p4)
(p2) -- (p5)
(p3) -- (p4)
(p3) -- (p5)
(p4) -- (p5);
end{tikzpicture}


But Now I need to remove one of the points and to draw a regular pentagon the same way. So I need to remove (P5) and to recalibrate all other points (change their coordinates) But I don't need to change the code much.



Is there a way to do it by just slightly changing my code here. ?










share|improve this question
















I already have a code that draws a regular hexagon the following way



begin{tikzpicture}[every node/.style={draw,shape=circle,fill=blue}]
path (0,0) node (p0) {}
(-1.5,-1) node (p1) {}
(-1.5,-2.5) node (p2) {}
(1.5,-2.5) node (p3) {}
(1.5,-1) node (p4) {}
(0,-3.5) node (p5) { };
draw (p0) -- (p1)
(p0) -- (p1)
(p0) -- (p2)
(p0) -- (p3)
(p0) -- (p4)
(p0) -- (p5)
(p1) -- (p2)
(p1) -- (p3)
(p1) -- (p4)
(p1) -- (p5)
(p2) -- (p3)
(p2) -- (p4)
(p2) -- (p5)
(p3) -- (p4)
(p3) -- (p5)
(p4) -- (p5);
end{tikzpicture}


But Now I need to remove one of the points and to draw a regular pentagon the same way. So I need to remove (P5) and to recalibrate all other points (change their coordinates) But I don't need to change the code much.



Is there a way to do it by just slightly changing my code here. ?







tikz-pgf graphics nodes paths polygon






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 1 '15 at 19:19







alkabary

















asked Dec 1 '15 at 18:58









alkabaryalkabary

17217




17217








  • 3





    Define your points using the polar notation for radius+angle of rotation. Then you can simply make the angle 360 / number of sides, and your code is completely general...

    – Thruston
    Dec 1 '15 at 19:06














  • 3





    Define your points using the polar notation for radius+angle of rotation. Then you can simply make the angle 360 / number of sides, and your code is completely general...

    – Thruston
    Dec 1 '15 at 19:06








3




3





Define your points using the polar notation for radius+angle of rotation. Then you can simply make the angle 360 / number of sides, and your code is completely general...

– Thruston
Dec 1 '15 at 19:06





Define your points using the polar notation for radius+angle of rotation. Then you can simply make the angle 360 / number of sides, and your code is completely general...

– Thruston
Dec 1 '15 at 19:06










6 Answers
6






active

oldest

votes


















10














You can use the geometric shapes given by the shapes.geometric library



usetikzlibrary{shapes.geometric}

begin{tikzpicture}[mystyle/.style={draw,shape=circle,fill=blue}]
defngon{5}
node[regular polygon,regular polygon sides=ngon,minimum size=3cm] (p) {};
foreachx in {1,...,ngon}{node[mystyle] (px) at (p.corner x){};}
foreachx in {1,...,numexprngon-1relax}{
foreachy in {x,...,ngon}{
draw (px) -- (py);
}
}
end{tikzpicture}


For ngon being 9



enter image description here






share|improve this answer































    7














    For fun, a short code with pst-poly gets the desired result:



    documentclass[svgnames]{standalone}

    usepackage{pst-poly}
    usepackage{auto-pst-pdf}
    begin{document}

    psset{unit=3.5cm, dimen=middle, linejoin=1, dotsize=12pt}
    begin{pspicture}(-1,-1)(1,1)
    providecommand{PstPolygonNode}{psdots[dotsize=12pt, linecolor=SteelBlue](1;INode)
    }
    rput(0,0){PstPentagon[PolyName=A, linecolor=LightSteelBlue, linewidth=1.2pt] }
    rput(0,0){PstPentagon[PolyName=A, PolyOffset=2] }
    end{pspicture}

    end{document}


    enter image description here






    share|improve this answer































      7














      Maybe you like the following (based on (Thruston comment) rude solution (still need some manual calculation):



      documentclass[border=3mm,tikz]{standalone}

      begin{document}
      begin{tikzpicture}[every node/.style={draw,shape=circle,fill=blue,text=white}]
      foreach i [count=ii from 0] in {90,150,...,390}
      path (i:32mm) node (pii) {ii};
      foreach x in {0,...,5}
      foreach y in {x,...,5}
      draw (py) -- (px);
      end{tikzpicture}
      end{document}


      For change number of nodes you need to determine start angle and manually determine next and final angle of node position.



      enter image description here



      Number in nodes are only informative, you can erase it.



      Upgrade: An improved version, which itself calculate all necessary data from given number of nodes ans angle of the first node position:



      documentclass[border=3mm,tikz]{standalone}

      begin{document}
      begin{tikzpicture}[
      every node/.style={draw,shape=circle,fill=blue,text=white}]
      %%%% variable data data
      defnumpoly{8}%number of nodes
      defstartangle{30}%direction of the first node
      defpradious{33mm}
      %------- calculations of the positions angles
      pgfmathparse{int(startangle+360/numpoly)}%
      letnextangle=pgfmathresult
      pgfmathparse{int(startangle-360/numpoly+360)}%
      letendtangle=pgfmathresult
      %--- nodes
      foreach i [count=ii from 1] in {startangle,nextangle,...,endtangle}
      path (i:pradious) node (pii) {ii};
      %--- interconnections
      foreach x in {1,...,numpoly}
      foreach y in {x,...,numpoly}
      draw (py) -- (px);
      end{tikzpicture}
      end{document}


      With selection node numbers = 8 and the first node ias in direction 30 degrees, code we obtain:



      enter image description here






      share|improve this answer

































        7














        One short tikz code without use of a library.



        documentclass[border=7mm]{standalone}
        usepackage{tikz}
        begin{document}
        foreach n in {3,...,7}
        tikzforeach i in {1,...,n}
        fill (i*360/n:1) coordinate (ni) circle(2 pt)
        ifnum i>1 foreach j in {i,...,1}{(ni) edge (nj)} fi;
        end{document}


        enter image description here






        share|improve this answer


























        • surely you meant documentclass[tikz,border=7mm]{standalone}, then your answer could be even shorter :)

          – Mark Wibrow
          Dec 3 '15 at 9:43











        • @MarkWibrow yes, but the problem with [tikz] is that in this case standalone produce one page and so one image for every tikz :(

          – Kpym
          Dec 3 '15 at 10:18











        • ah yes. rather silly of me not to notice that.

          – Mark Wibrow
          Dec 3 '15 at 14:53



















        5














        With the PGF graph drawing stuff (compile with lualatex):



        documentclass[border=5]{standalone}
        usepackage{tikz}
        usetikzlibrary{graphs,graphs.standard}
        tikzgraphsset{declare={polygon_n}{[clique]foreachx intikzgraphV{x/}}}
        begin{document}
        foreach n in {3,...,7}
        tikzgraph [clockwise, nodes={circle, fill=blue, inner sep=1}]
        { polygon_n [n=n] };
        end{document}


        enter image description here






        share|improve this answer































          4














          Here is a version in Metapost for comparison. Something of an exercise in loops.



          prologues := 3;
          outputtemplate := "%j%c.eps";
          vardef polygon(expr n) = for t=0 step 360/n until 359: right rotated t -- endfor cycle enddef;
          beginfig(1);
          path p;
          for n=3 upto 7:
          p := polygon(n) scaled 20 shifted (n*48,0);
          for i=1 upto length p:
          for j=i+1 upto length p:
          draw point i of p -- point j of p;
          endfor
          endfor
          for i=1 upto length p:
          fill fullcircle scaled 3 shifted point i of p withcolor .67 red;
          endfor
          endfor
          endfig;
          end


          enter image description here






          share|improve this answer

























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            6 Answers
            6






            active

            oldest

            votes








            6 Answers
            6






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            10














            You can use the geometric shapes given by the shapes.geometric library



            usetikzlibrary{shapes.geometric}

            begin{tikzpicture}[mystyle/.style={draw,shape=circle,fill=blue}]
            defngon{5}
            node[regular polygon,regular polygon sides=ngon,minimum size=3cm] (p) {};
            foreachx in {1,...,ngon}{node[mystyle] (px) at (p.corner x){};}
            foreachx in {1,...,numexprngon-1relax}{
            foreachy in {x,...,ngon}{
            draw (px) -- (py);
            }
            }
            end{tikzpicture}


            For ngon being 9



            enter image description here






            share|improve this answer




























              10














              You can use the geometric shapes given by the shapes.geometric library



              usetikzlibrary{shapes.geometric}

              begin{tikzpicture}[mystyle/.style={draw,shape=circle,fill=blue}]
              defngon{5}
              node[regular polygon,regular polygon sides=ngon,minimum size=3cm] (p) {};
              foreachx in {1,...,ngon}{node[mystyle] (px) at (p.corner x){};}
              foreachx in {1,...,numexprngon-1relax}{
              foreachy in {x,...,ngon}{
              draw (px) -- (py);
              }
              }
              end{tikzpicture}


              For ngon being 9



              enter image description here






              share|improve this answer


























                10












                10








                10







                You can use the geometric shapes given by the shapes.geometric library



                usetikzlibrary{shapes.geometric}

                begin{tikzpicture}[mystyle/.style={draw,shape=circle,fill=blue}]
                defngon{5}
                node[regular polygon,regular polygon sides=ngon,minimum size=3cm] (p) {};
                foreachx in {1,...,ngon}{node[mystyle] (px) at (p.corner x){};}
                foreachx in {1,...,numexprngon-1relax}{
                foreachy in {x,...,ngon}{
                draw (px) -- (py);
                }
                }
                end{tikzpicture}


                For ngon being 9



                enter image description here






                share|improve this answer













                You can use the geometric shapes given by the shapes.geometric library



                usetikzlibrary{shapes.geometric}

                begin{tikzpicture}[mystyle/.style={draw,shape=circle,fill=blue}]
                defngon{5}
                node[regular polygon,regular polygon sides=ngon,minimum size=3cm] (p) {};
                foreachx in {1,...,ngon}{node[mystyle] (px) at (p.corner x){};}
                foreachx in {1,...,numexprngon-1relax}{
                foreachy in {x,...,ngon}{
                draw (px) -- (py);
                }
                }
                end{tikzpicture}


                For ngon being 9



                enter image description here







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Dec 1 '15 at 20:01









                percussepercusse

                137k14256494




                137k14256494























                    7














                    For fun, a short code with pst-poly gets the desired result:



                    documentclass[svgnames]{standalone}

                    usepackage{pst-poly}
                    usepackage{auto-pst-pdf}
                    begin{document}

                    psset{unit=3.5cm, dimen=middle, linejoin=1, dotsize=12pt}
                    begin{pspicture}(-1,-1)(1,1)
                    providecommand{PstPolygonNode}{psdots[dotsize=12pt, linecolor=SteelBlue](1;INode)
                    }
                    rput(0,0){PstPentagon[PolyName=A, linecolor=LightSteelBlue, linewidth=1.2pt] }
                    rput(0,0){PstPentagon[PolyName=A, PolyOffset=2] }
                    end{pspicture}

                    end{document}


                    enter image description here






                    share|improve this answer




























                      7














                      For fun, a short code with pst-poly gets the desired result:



                      documentclass[svgnames]{standalone}

                      usepackage{pst-poly}
                      usepackage{auto-pst-pdf}
                      begin{document}

                      psset{unit=3.5cm, dimen=middle, linejoin=1, dotsize=12pt}
                      begin{pspicture}(-1,-1)(1,1)
                      providecommand{PstPolygonNode}{psdots[dotsize=12pt, linecolor=SteelBlue](1;INode)
                      }
                      rput(0,0){PstPentagon[PolyName=A, linecolor=LightSteelBlue, linewidth=1.2pt] }
                      rput(0,0){PstPentagon[PolyName=A, PolyOffset=2] }
                      end{pspicture}

                      end{document}


                      enter image description here






                      share|improve this answer


























                        7












                        7








                        7







                        For fun, a short code with pst-poly gets the desired result:



                        documentclass[svgnames]{standalone}

                        usepackage{pst-poly}
                        usepackage{auto-pst-pdf}
                        begin{document}

                        psset{unit=3.5cm, dimen=middle, linejoin=1, dotsize=12pt}
                        begin{pspicture}(-1,-1)(1,1)
                        providecommand{PstPolygonNode}{psdots[dotsize=12pt, linecolor=SteelBlue](1;INode)
                        }
                        rput(0,0){PstPentagon[PolyName=A, linecolor=LightSteelBlue, linewidth=1.2pt] }
                        rput(0,0){PstPentagon[PolyName=A, PolyOffset=2] }
                        end{pspicture}

                        end{document}


                        enter image description here






                        share|improve this answer













                        For fun, a short code with pst-poly gets the desired result:



                        documentclass[svgnames]{standalone}

                        usepackage{pst-poly}
                        usepackage{auto-pst-pdf}
                        begin{document}

                        psset{unit=3.5cm, dimen=middle, linejoin=1, dotsize=12pt}
                        begin{pspicture}(-1,-1)(1,1)
                        providecommand{PstPolygonNode}{psdots[dotsize=12pt, linecolor=SteelBlue](1;INode)
                        }
                        rput(0,0){PstPentagon[PolyName=A, linecolor=LightSteelBlue, linewidth=1.2pt] }
                        rput(0,0){PstPentagon[PolyName=A, PolyOffset=2] }
                        end{pspicture}

                        end{document}


                        enter image description here







                        share|improve this answer












                        share|improve this answer



                        share|improve this answer










                        answered Dec 1 '15 at 23:34









                        BernardBernard

                        169k773198




                        169k773198























                            7














                            Maybe you like the following (based on (Thruston comment) rude solution (still need some manual calculation):



                            documentclass[border=3mm,tikz]{standalone}

                            begin{document}
                            begin{tikzpicture}[every node/.style={draw,shape=circle,fill=blue,text=white}]
                            foreach i [count=ii from 0] in {90,150,...,390}
                            path (i:32mm) node (pii) {ii};
                            foreach x in {0,...,5}
                            foreach y in {x,...,5}
                            draw (py) -- (px);
                            end{tikzpicture}
                            end{document}


                            For change number of nodes you need to determine start angle and manually determine next and final angle of node position.



                            enter image description here



                            Number in nodes are only informative, you can erase it.



                            Upgrade: An improved version, which itself calculate all necessary data from given number of nodes ans angle of the first node position:



                            documentclass[border=3mm,tikz]{standalone}

                            begin{document}
                            begin{tikzpicture}[
                            every node/.style={draw,shape=circle,fill=blue,text=white}]
                            %%%% variable data data
                            defnumpoly{8}%number of nodes
                            defstartangle{30}%direction of the first node
                            defpradious{33mm}
                            %------- calculations of the positions angles
                            pgfmathparse{int(startangle+360/numpoly)}%
                            letnextangle=pgfmathresult
                            pgfmathparse{int(startangle-360/numpoly+360)}%
                            letendtangle=pgfmathresult
                            %--- nodes
                            foreach i [count=ii from 1] in {startangle,nextangle,...,endtangle}
                            path (i:pradious) node (pii) {ii};
                            %--- interconnections
                            foreach x in {1,...,numpoly}
                            foreach y in {x,...,numpoly}
                            draw (py) -- (px);
                            end{tikzpicture}
                            end{document}


                            With selection node numbers = 8 and the first node ias in direction 30 degrees, code we obtain:



                            enter image description here






                            share|improve this answer






























                              7














                              Maybe you like the following (based on (Thruston comment) rude solution (still need some manual calculation):



                              documentclass[border=3mm,tikz]{standalone}

                              begin{document}
                              begin{tikzpicture}[every node/.style={draw,shape=circle,fill=blue,text=white}]
                              foreach i [count=ii from 0] in {90,150,...,390}
                              path (i:32mm) node (pii) {ii};
                              foreach x in {0,...,5}
                              foreach y in {x,...,5}
                              draw (py) -- (px);
                              end{tikzpicture}
                              end{document}


                              For change number of nodes you need to determine start angle and manually determine next and final angle of node position.



                              enter image description here



                              Number in nodes are only informative, you can erase it.



                              Upgrade: An improved version, which itself calculate all necessary data from given number of nodes ans angle of the first node position:



                              documentclass[border=3mm,tikz]{standalone}

                              begin{document}
                              begin{tikzpicture}[
                              every node/.style={draw,shape=circle,fill=blue,text=white}]
                              %%%% variable data data
                              defnumpoly{8}%number of nodes
                              defstartangle{30}%direction of the first node
                              defpradious{33mm}
                              %------- calculations of the positions angles
                              pgfmathparse{int(startangle+360/numpoly)}%
                              letnextangle=pgfmathresult
                              pgfmathparse{int(startangle-360/numpoly+360)}%
                              letendtangle=pgfmathresult
                              %--- nodes
                              foreach i [count=ii from 1] in {startangle,nextangle,...,endtangle}
                              path (i:pradious) node (pii) {ii};
                              %--- interconnections
                              foreach x in {1,...,numpoly}
                              foreach y in {x,...,numpoly}
                              draw (py) -- (px);
                              end{tikzpicture}
                              end{document}


                              With selection node numbers = 8 and the first node ias in direction 30 degrees, code we obtain:



                              enter image description here






                              share|improve this answer




























                                7












                                7








                                7







                                Maybe you like the following (based on (Thruston comment) rude solution (still need some manual calculation):



                                documentclass[border=3mm,tikz]{standalone}

                                begin{document}
                                begin{tikzpicture}[every node/.style={draw,shape=circle,fill=blue,text=white}]
                                foreach i [count=ii from 0] in {90,150,...,390}
                                path (i:32mm) node (pii) {ii};
                                foreach x in {0,...,5}
                                foreach y in {x,...,5}
                                draw (py) -- (px);
                                end{tikzpicture}
                                end{document}


                                For change number of nodes you need to determine start angle and manually determine next and final angle of node position.



                                enter image description here



                                Number in nodes are only informative, you can erase it.



                                Upgrade: An improved version, which itself calculate all necessary data from given number of nodes ans angle of the first node position:



                                documentclass[border=3mm,tikz]{standalone}

                                begin{document}
                                begin{tikzpicture}[
                                every node/.style={draw,shape=circle,fill=blue,text=white}]
                                %%%% variable data data
                                defnumpoly{8}%number of nodes
                                defstartangle{30}%direction of the first node
                                defpradious{33mm}
                                %------- calculations of the positions angles
                                pgfmathparse{int(startangle+360/numpoly)}%
                                letnextangle=pgfmathresult
                                pgfmathparse{int(startangle-360/numpoly+360)}%
                                letendtangle=pgfmathresult
                                %--- nodes
                                foreach i [count=ii from 1] in {startangle,nextangle,...,endtangle}
                                path (i:pradious) node (pii) {ii};
                                %--- interconnections
                                foreach x in {1,...,numpoly}
                                foreach y in {x,...,numpoly}
                                draw (py) -- (px);
                                end{tikzpicture}
                                end{document}


                                With selection node numbers = 8 and the first node ias in direction 30 degrees, code we obtain:



                                enter image description here






                                share|improve this answer















                                Maybe you like the following (based on (Thruston comment) rude solution (still need some manual calculation):



                                documentclass[border=3mm,tikz]{standalone}

                                begin{document}
                                begin{tikzpicture}[every node/.style={draw,shape=circle,fill=blue,text=white}]
                                foreach i [count=ii from 0] in {90,150,...,390}
                                path (i:32mm) node (pii) {ii};
                                foreach x in {0,...,5}
                                foreach y in {x,...,5}
                                draw (py) -- (px);
                                end{tikzpicture}
                                end{document}


                                For change number of nodes you need to determine start angle and manually determine next and final angle of node position.



                                enter image description here



                                Number in nodes are only informative, you can erase it.



                                Upgrade: An improved version, which itself calculate all necessary data from given number of nodes ans angle of the first node position:



                                documentclass[border=3mm,tikz]{standalone}

                                begin{document}
                                begin{tikzpicture}[
                                every node/.style={draw,shape=circle,fill=blue,text=white}]
                                %%%% variable data data
                                defnumpoly{8}%number of nodes
                                defstartangle{30}%direction of the first node
                                defpradious{33mm}
                                %------- calculations of the positions angles
                                pgfmathparse{int(startangle+360/numpoly)}%
                                letnextangle=pgfmathresult
                                pgfmathparse{int(startangle-360/numpoly+360)}%
                                letendtangle=pgfmathresult
                                %--- nodes
                                foreach i [count=ii from 1] in {startangle,nextangle,...,endtangle}
                                path (i:pradious) node (pii) {ii};
                                %--- interconnections
                                foreach x in {1,...,numpoly}
                                foreach y in {x,...,numpoly}
                                draw (py) -- (px);
                                end{tikzpicture}
                                end{document}


                                With selection node numbers = 8 and the first node ias in direction 30 degrees, code we obtain:



                                enter image description here







                                share|improve this answer














                                share|improve this answer



                                share|improve this answer








                                edited Dec 2 '15 at 1:00

























                                answered Dec 1 '15 at 20:01









                                ZarkoZarko

                                124k866163




                                124k866163























                                    7














                                    One short tikz code without use of a library.



                                    documentclass[border=7mm]{standalone}
                                    usepackage{tikz}
                                    begin{document}
                                    foreach n in {3,...,7}
                                    tikzforeach i in {1,...,n}
                                    fill (i*360/n:1) coordinate (ni) circle(2 pt)
                                    ifnum i>1 foreach j in {i,...,1}{(ni) edge (nj)} fi;
                                    end{document}


                                    enter image description here






                                    share|improve this answer


























                                    • surely you meant documentclass[tikz,border=7mm]{standalone}, then your answer could be even shorter :)

                                      – Mark Wibrow
                                      Dec 3 '15 at 9:43











                                    • @MarkWibrow yes, but the problem with [tikz] is that in this case standalone produce one page and so one image for every tikz :(

                                      – Kpym
                                      Dec 3 '15 at 10:18











                                    • ah yes. rather silly of me not to notice that.

                                      – Mark Wibrow
                                      Dec 3 '15 at 14:53
















                                    7














                                    One short tikz code without use of a library.



                                    documentclass[border=7mm]{standalone}
                                    usepackage{tikz}
                                    begin{document}
                                    foreach n in {3,...,7}
                                    tikzforeach i in {1,...,n}
                                    fill (i*360/n:1) coordinate (ni) circle(2 pt)
                                    ifnum i>1 foreach j in {i,...,1}{(ni) edge (nj)} fi;
                                    end{document}


                                    enter image description here






                                    share|improve this answer


























                                    • surely you meant documentclass[tikz,border=7mm]{standalone}, then your answer could be even shorter :)

                                      – Mark Wibrow
                                      Dec 3 '15 at 9:43











                                    • @MarkWibrow yes, but the problem with [tikz] is that in this case standalone produce one page and so one image for every tikz :(

                                      – Kpym
                                      Dec 3 '15 at 10:18











                                    • ah yes. rather silly of me not to notice that.

                                      – Mark Wibrow
                                      Dec 3 '15 at 14:53














                                    7












                                    7








                                    7







                                    One short tikz code without use of a library.



                                    documentclass[border=7mm]{standalone}
                                    usepackage{tikz}
                                    begin{document}
                                    foreach n in {3,...,7}
                                    tikzforeach i in {1,...,n}
                                    fill (i*360/n:1) coordinate (ni) circle(2 pt)
                                    ifnum i>1 foreach j in {i,...,1}{(ni) edge (nj)} fi;
                                    end{document}


                                    enter image description here






                                    share|improve this answer















                                    One short tikz code without use of a library.



                                    documentclass[border=7mm]{standalone}
                                    usepackage{tikz}
                                    begin{document}
                                    foreach n in {3,...,7}
                                    tikzforeach i in {1,...,n}
                                    fill (i*360/n:1) coordinate (ni) circle(2 pt)
                                    ifnum i>1 foreach j in {i,...,1}{(ni) edge (nj)} fi;
                                    end{document}


                                    enter image description here







                                    share|improve this answer














                                    share|improve this answer



                                    share|improve this answer








                                    edited Sep 21 '18 at 16:30

























                                    answered Dec 2 '15 at 20:28









                                    KpymKpym

                                    16.1k23987




                                    16.1k23987













                                    • surely you meant documentclass[tikz,border=7mm]{standalone}, then your answer could be even shorter :)

                                      – Mark Wibrow
                                      Dec 3 '15 at 9:43











                                    • @MarkWibrow yes, but the problem with [tikz] is that in this case standalone produce one page and so one image for every tikz :(

                                      – Kpym
                                      Dec 3 '15 at 10:18











                                    • ah yes. rather silly of me not to notice that.

                                      – Mark Wibrow
                                      Dec 3 '15 at 14:53



















                                    • surely you meant documentclass[tikz,border=7mm]{standalone}, then your answer could be even shorter :)

                                      – Mark Wibrow
                                      Dec 3 '15 at 9:43











                                    • @MarkWibrow yes, but the problem with [tikz] is that in this case standalone produce one page and so one image for every tikz :(

                                      – Kpym
                                      Dec 3 '15 at 10:18











                                    • ah yes. rather silly of me not to notice that.

                                      – Mark Wibrow
                                      Dec 3 '15 at 14:53

















                                    surely you meant documentclass[tikz,border=7mm]{standalone}, then your answer could be even shorter :)

                                    – Mark Wibrow
                                    Dec 3 '15 at 9:43





                                    surely you meant documentclass[tikz,border=7mm]{standalone}, then your answer could be even shorter :)

                                    – Mark Wibrow
                                    Dec 3 '15 at 9:43













                                    @MarkWibrow yes, but the problem with [tikz] is that in this case standalone produce one page and so one image for every tikz :(

                                    – Kpym
                                    Dec 3 '15 at 10:18





                                    @MarkWibrow yes, but the problem with [tikz] is that in this case standalone produce one page and so one image for every tikz :(

                                    – Kpym
                                    Dec 3 '15 at 10:18













                                    ah yes. rather silly of me not to notice that.

                                    – Mark Wibrow
                                    Dec 3 '15 at 14:53





                                    ah yes. rather silly of me not to notice that.

                                    – Mark Wibrow
                                    Dec 3 '15 at 14:53











                                    5














                                    With the PGF graph drawing stuff (compile with lualatex):



                                    documentclass[border=5]{standalone}
                                    usepackage{tikz}
                                    usetikzlibrary{graphs,graphs.standard}
                                    tikzgraphsset{declare={polygon_n}{[clique]foreachx intikzgraphV{x/}}}
                                    begin{document}
                                    foreach n in {3,...,7}
                                    tikzgraph [clockwise, nodes={circle, fill=blue, inner sep=1}]
                                    { polygon_n [n=n] };
                                    end{document}


                                    enter image description here






                                    share|improve this answer




























                                      5














                                      With the PGF graph drawing stuff (compile with lualatex):



                                      documentclass[border=5]{standalone}
                                      usepackage{tikz}
                                      usetikzlibrary{graphs,graphs.standard}
                                      tikzgraphsset{declare={polygon_n}{[clique]foreachx intikzgraphV{x/}}}
                                      begin{document}
                                      foreach n in {3,...,7}
                                      tikzgraph [clockwise, nodes={circle, fill=blue, inner sep=1}]
                                      { polygon_n [n=n] };
                                      end{document}


                                      enter image description here






                                      share|improve this answer


























                                        5












                                        5








                                        5







                                        With the PGF graph drawing stuff (compile with lualatex):



                                        documentclass[border=5]{standalone}
                                        usepackage{tikz}
                                        usetikzlibrary{graphs,graphs.standard}
                                        tikzgraphsset{declare={polygon_n}{[clique]foreachx intikzgraphV{x/}}}
                                        begin{document}
                                        foreach n in {3,...,7}
                                        tikzgraph [clockwise, nodes={circle, fill=blue, inner sep=1}]
                                        { polygon_n [n=n] };
                                        end{document}


                                        enter image description here






                                        share|improve this answer













                                        With the PGF graph drawing stuff (compile with lualatex):



                                        documentclass[border=5]{standalone}
                                        usepackage{tikz}
                                        usetikzlibrary{graphs,graphs.standard}
                                        tikzgraphsset{declare={polygon_n}{[clique]foreachx intikzgraphV{x/}}}
                                        begin{document}
                                        foreach n in {3,...,7}
                                        tikzgraph [clockwise, nodes={circle, fill=blue, inner sep=1}]
                                        { polygon_n [n=n] };
                                        end{document}


                                        enter image description here







                                        share|improve this answer












                                        share|improve this answer



                                        share|improve this answer










                                        answered Dec 2 '15 at 14:43









                                        Mark WibrowMark Wibrow

                                        61.9k4112176




                                        61.9k4112176























                                            4














                                            Here is a version in Metapost for comparison. Something of an exercise in loops.



                                            prologues := 3;
                                            outputtemplate := "%j%c.eps";
                                            vardef polygon(expr n) = for t=0 step 360/n until 359: right rotated t -- endfor cycle enddef;
                                            beginfig(1);
                                            path p;
                                            for n=3 upto 7:
                                            p := polygon(n) scaled 20 shifted (n*48,0);
                                            for i=1 upto length p:
                                            for j=i+1 upto length p:
                                            draw point i of p -- point j of p;
                                            endfor
                                            endfor
                                            for i=1 upto length p:
                                            fill fullcircle scaled 3 shifted point i of p withcolor .67 red;
                                            endfor
                                            endfor
                                            endfig;
                                            end


                                            enter image description here






                                            share|improve this answer






























                                              4














                                              Here is a version in Metapost for comparison. Something of an exercise in loops.



                                              prologues := 3;
                                              outputtemplate := "%j%c.eps";
                                              vardef polygon(expr n) = for t=0 step 360/n until 359: right rotated t -- endfor cycle enddef;
                                              beginfig(1);
                                              path p;
                                              for n=3 upto 7:
                                              p := polygon(n) scaled 20 shifted (n*48,0);
                                              for i=1 upto length p:
                                              for j=i+1 upto length p:
                                              draw point i of p -- point j of p;
                                              endfor
                                              endfor
                                              for i=1 upto length p:
                                              fill fullcircle scaled 3 shifted point i of p withcolor .67 red;
                                              endfor
                                              endfor
                                              endfig;
                                              end


                                              enter image description here






                                              share|improve this answer




























                                                4












                                                4








                                                4







                                                Here is a version in Metapost for comparison. Something of an exercise in loops.



                                                prologues := 3;
                                                outputtemplate := "%j%c.eps";
                                                vardef polygon(expr n) = for t=0 step 360/n until 359: right rotated t -- endfor cycle enddef;
                                                beginfig(1);
                                                path p;
                                                for n=3 upto 7:
                                                p := polygon(n) scaled 20 shifted (n*48,0);
                                                for i=1 upto length p:
                                                for j=i+1 upto length p:
                                                draw point i of p -- point j of p;
                                                endfor
                                                endfor
                                                for i=1 upto length p:
                                                fill fullcircle scaled 3 shifted point i of p withcolor .67 red;
                                                endfor
                                                endfor
                                                endfig;
                                                end


                                                enter image description here






                                                share|improve this answer















                                                Here is a version in Metapost for comparison. Something of an exercise in loops.



                                                prologues := 3;
                                                outputtemplate := "%j%c.eps";
                                                vardef polygon(expr n) = for t=0 step 360/n until 359: right rotated t -- endfor cycle enddef;
                                                beginfig(1);
                                                path p;
                                                for n=3 upto 7:
                                                p := polygon(n) scaled 20 shifted (n*48,0);
                                                for i=1 upto length p:
                                                for j=i+1 upto length p:
                                                draw point i of p -- point j of p;
                                                endfor
                                                endfor
                                                for i=1 upto length p:
                                                fill fullcircle scaled 3 shifted point i of p withcolor .67 red;
                                                endfor
                                                endfor
                                                endfig;
                                                end


                                                enter image description here







                                                share|improve this answer














                                                share|improve this answer



                                                share|improve this answer








                                                edited Apr 13 '17 at 12:34









                                                Community

                                                1




                                                1










                                                answered Dec 2 '15 at 0:41









                                                ThrustonThruston

                                                26.2k24290




                                                26.2k24290






























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