how to apply sorting in ui-grid?
0
I have one angularjs project in which I am using ui-grid.
As you can see in my code, I have some attribute in cell-template. I have to perform sorting based on "rating-percentage".
So I am trying to write a sorting algorithm which required row.entity property.
My question is that how can I add rating percentage in row.entity.
What is the right way to perform sorting using "rating-percentage"?
Below is my code:
define([
'angular'
], function (angular) {
function SelectToolController($scope, $timeout, $filter) {
var vm = this,
_gridApi,
_cellTemplate,
_columnDefs,
_starRatingTemplate,
_starRatingColumn;
_starRatingTemplate =[
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" >',
'<opr-star-rating rating-percentage="{{rowRenderIndex}}"',
'total-count="23"',
'suffix-display="true"',
'rating-display="true"',
'count-display="22">',
'</opr-star-rating>',
'</div>',
'</div>'
].join('');
_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
}
_columnDefs.push(_starRatingColumn);
})();
angularjs angular-ui-grid ui-grid
asked Nov 20 '18 at 4:44
Anubha GuptaAnubha Gupta
469
add a comment |
0
I have one angularjs project in which I am using ui-grid.
As you can see in my code, I have some attribute in cell-template. I have to perform sorting based on "rating-percentage".
So I am trying to write a sorting algorithm which required row.entity property.
My question is that how can I add rating percentage in row.entity.
What is the right way to perform sorting using "rating-percentage"?
Below is my code:
define([
'angular'
], function (angular) {
function SelectToolController($scope, $timeout, $filter) {
var vm = this,
_gridApi,
_cellTemplate,
_columnDefs,
_starRatingTemplate,
_starRatingColumn;
_starRatingTemplate =[
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" >',
'<opr-star-rating rating-percentage="{{rowRenderIndex}}"',
'total-count="23"',
'suffix-display="true"',
'rating-display="true"',
'count-display="22">',
'</opr-star-rating>',
'</div>',
'</div>'
].join('');
_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
}
_columnDefs.push(_starRatingColumn);
})();
angularjs angular-ui-grid ui-grid
asked Nov 20 '18 at 4:44
Anubha GuptaAnubha Gupta
469
add a comment |
0
0
0
I have one angularjs project in which I am using ui-grid.
As you can see in my code, I have some attribute in cell-template. I have to perform sorting based on "rating-percentage".
So I am trying to write a sorting algorithm which required row.entity property.
My question is that how can I add rating percentage in row.entity.
What is the right way to perform sorting using "rating-percentage"?
Below is my code:
define([
'angular'
], function (angular) {
function SelectToolController($scope, $timeout, $filter) {
var vm = this,
_gridApi,
_cellTemplate,
_columnDefs,
_starRatingTemplate,
_starRatingColumn;
_starRatingTemplate =[
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" >',
'<opr-star-rating rating-percentage="{{rowRenderIndex}}"',
'total-count="23"',
'suffix-display="true"',
'rating-display="true"',
'count-display="22">',
'</opr-star-rating>',
'</div>',
'</div>'
].join('');
_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
}
_columnDefs.push(_starRatingColumn);
})();
angularjs angular-ui-grid ui-grid
asked Nov 20 '18 at 4:44
Anubha GuptaAnubha Gupta
469
I have one angularjs project in which I am using ui-grid.
As you can see in my code, I have some attribute in cell-template. I have to perform sorting based on "rating-percentage".
So I am trying to write a sorting algorithm which required row.entity property.
My question is that how can I add rating percentage in row.entity.
What is the right way to perform sorting using "rating-percentage"?
Below is my code:
define([
'angular'
], function (angular) {
function SelectToolController($scope, $timeout, $filter) {
var vm = this,
_gridApi,
_cellTemplate,
_columnDefs,
_starRatingTemplate,
_starRatingColumn;
_starRatingTemplate =[
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" >',
'<opr-star-rating rating-percentage="{{rowRenderIndex}}"',
'total-count="23"',
'suffix-display="true"',
'rating-display="true"',
'count-display="22">',
'</opr-star-rating>',
'</div>',
'</div>'
].join('');
_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
}
_columnDefs.push(_starRatingColumn);
})();
angularjs angular-ui-grid ui-grid
angularjs angular-ui-grid ui-grid
asked Nov 20 '18 at 4:44
Anubha GuptaAnubha Gupta
469
asked Nov 20 '18 at 4:44
Anubha GuptaAnubha Gupta
469
asked Nov 20 '18 at 4:44
Anubha GuptaAnubha Gupta
469
asked Nov 20 '18 at 4:44
Anubha GuptaAnubha Gupta
469
asked Nov 20 '18 at 4:44
Anubha GuptaAnubha Gupta
469
469
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
0
You can define your custom sorting function then link this function to column definition.
$scope.sortFun=function(a, b) {
///.... your logic
}
_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
'sortingAlgorithm': $scope.sortFun
}
change your template.
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" ng-class="col.colIndex() >',
'<opr-star-rating rating-percentage="{{row.entity}}"',
'total-count="23"',
'suffix-display="true"',
'rating-display="true"',
'count-display="22">',
'</opr-star-rating>',
'</div>',
'</div>'
answered Nov 20 '18 at 4:55
SameerSameer
316210
actually, what I am not able to understand is, how to get the value of ratingPercentage in sorting function?
– Anubha Gupta
Nov 20 '18 at 5:06
change cell template according to this.
– Sameer
Nov 20 '18 at 5:33
It is not recognizing col property itself
– Anubha Gupta
Nov 20 '18 at 6:02
you can also use row.entity. you rating-percentage attribute will receive complete object of array result
– Sameer
Nov 20 '18 at 6:04
Yes I am trying with row.entity only. Problem is that it is not getting any of attribute mentioned in cellTemplate in row.entity. I am trying to get rating-percentage in row.entity. But no luck!
– Anubha Gupta
Nov 20 '18 at 6:06
|
show 1 more comment
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1 Answer
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oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You can define your custom sorting function then link this function to column definition.
$scope.sortFun=function(a, b) {
///.... your logic
}
_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
'sortingAlgorithm': $scope.sortFun
}
change your template.
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" ng-class="col.colIndex() >',
'<opr-star-rating rating-percentage="{{row.entity}}"',
'total-count="23"',
'suffix-display="true"',
'rating-display="true"',
'count-display="22">',
'</opr-star-rating>',
'</div>',
'</div>'
answered Nov 20 '18 at 4:55
SameerSameer
316210
actually, what I am not able to understand is, how to get the value of ratingPercentage in sorting function?
– Anubha Gupta
Nov 20 '18 at 5:06
change cell template according to this.
– Sameer
Nov 20 '18 at 5:33
It is not recognizing col property itself
– Anubha Gupta
Nov 20 '18 at 6:02
you can also use row.entity. you rating-percentage attribute will receive complete object of array result
– Sameer
Nov 20 '18 at 6:04
Yes I am trying with row.entity only. Problem is that it is not getting any of attribute mentioned in cellTemplate in row.entity. I am trying to get rating-percentage in row.entity. But no luck!
– Anubha Gupta
Nov 20 '18 at 6:06
|
show 1 more comment
0
You can define your custom sorting function then link this function to column definition.
$scope.sortFun=function(a, b) {
///.... your logic
}
_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
'sortingAlgorithm': $scope.sortFun
}
change your template.
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" ng-class="col.colIndex() >',
'<opr-star-rating rating-percentage="{{row.entity}}"',
'total-count="23"',
'suffix-display="true"',
'rating-display="true"',
'count-display="22">',
'</opr-star-rating>',
'</div>',
'</div>'
answered Nov 20 '18 at 4:55
SameerSameer
316210
actually, what I am not able to understand is, how to get the value of ratingPercentage in sorting function?
– Anubha Gupta
Nov 20 '18 at 5:06
change cell template according to this.
– Sameer
Nov 20 '18 at 5:33
It is not recognizing col property itself
– Anubha Gupta
Nov 20 '18 at 6:02
you can also use row.entity. you rating-percentage attribute will receive complete object of array result
– Sameer
Nov 20 '18 at 6:04
Yes I am trying with row.entity only. Problem is that it is not getting any of attribute mentioned in cellTemplate in row.entity. I am trying to get rating-percentage in row.entity. But no luck!
– Anubha Gupta
Nov 20 '18 at 6:06
|
show 1 more comment
0
0
0
You can define your custom sorting function then link this function to column definition.
$scope.sortFun=function(a, b) {
///.... your logic
}
_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
'sortingAlgorithm': $scope.sortFun
}
change your template.
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" ng-class="col.colIndex() >',
'<opr-star-rating rating-percentage="{{row.entity}}"',
'total-count="23"',
'suffix-display="true"',
'rating-display="true"',
'count-display="22">',
'</opr-star-rating>',
'</div>',
'</div>'
answered Nov 20 '18 at 4:55
SameerSameer
316210
You can define your custom sorting function then link this function to column definition.
$scope.sortFun=function(a, b) {
///.... your logic
}
_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
'sortingAlgorithm': $scope.sortFun
}
change your template.
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" ng-class="col.colIndex() >',
'<opr-star-rating rating-percentage="{{row.entity}}"',
'total-count="23"',
'suffix-display="true"',
'rating-display="true"',
'count-display="22">',
'</opr-star-rating>',
'</div>',
'</div>'
answered Nov 20 '18 at 4:55
SameerSameer
316210
edited Nov 20 '18 at 6:03
answered Nov 20 '18 at 4:55
SameerSameer
316210
answered Nov 20 '18 at 4:55
SameerSameer
316210
answered Nov 20 '18 at 4:55
SameerSameer
316210
316210
actually, what I am not able to understand is, how to get the value of ratingPercentage in sorting function?
– Anubha Gupta
Nov 20 '18 at 5:06
change cell template according to this.
– Sameer
Nov 20 '18 at 5:33
It is not recognizing col property itself
– Anubha Gupta
Nov 20 '18 at 6:02
you can also use row.entity. you rating-percentage attribute will receive complete object of array result
– Sameer
Nov 20 '18 at 6:04
Yes I am trying with row.entity only. Problem is that it is not getting any of attribute mentioned in cellTemplate in row.entity. I am trying to get rating-percentage in row.entity. But no luck!
– Anubha Gupta
Nov 20 '18 at 6:06
|
show 1 more comment
actually, what I am not able to understand is, how to get the value of ratingPercentage in sorting function?
– Anubha Gupta
Nov 20 '18 at 5:06
change cell template according to this.
– Sameer
Nov 20 '18 at 5:33
It is not recognizing col property itself
– Anubha Gupta
Nov 20 '18 at 6:02
you can also use row.entity. you rating-percentage attribute will receive complete object of array result
– Sameer
Nov 20 '18 at 6:04
Yes I am trying with row.entity only. Problem is that it is not getting any of attribute mentioned in cellTemplate in row.entity. I am trying to get rating-percentage in row.entity. But no luck!
– Anubha Gupta
Nov 20 '18 at 6:06
actually, what I am not able to understand is, how to get the value of ratingPercentage in sorting function?
– Anubha Gupta
Nov 20 '18 at 5:06
actually, what I am not able to understand is, how to get the value of ratingPercentage in sorting function?
– Anubha Gupta
Nov 20 '18 at 5:06
change cell template according to this.
– Sameer
Nov 20 '18 at 5:33
change cell template according to this.
– Sameer
Nov 20 '18 at 5:33
It is not recognizing col property itself
– Anubha Gupta
Nov 20 '18 at 6:02
It is not recognizing col property itself
– Anubha Gupta
Nov 20 '18 at 6:02
you can also use row.entity. you rating-percentage attribute will receive complete object of array result
– Sameer
Nov 20 '18 at 6:04
you can also use row.entity. you rating-percentage attribute will receive complete object of array result
– Sameer
Nov 20 '18 at 6:04
Yes I am trying with row.entity only. Problem is that it is not getting any of attribute mentioned in cellTemplate in row.entity. I am trying to get rating-percentage in row.entity. But no luck!
– Anubha Gupta
Nov 20 '18 at 6:06
Yes I am trying with row.entity only. Problem is that it is not getting any of attribute mentioned in cellTemplate in row.entity. I am trying to get rating-percentage in row.entity. But no luck!
– Anubha Gupta
Nov 20 '18 at 6:06
|
show 1 more comment
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