How can I calculate a Bernoulli random variable that features retries?
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I have a situation modeled by a Bernoulli random variable with $p=0.4$, but with the added complication that five failures can be "rerolled" for the same probability. I can't use a binomial distribution on that, so how can I determine how many successes I'll get in a number of trials, say 20?
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asked Nov 19 at 18:56
Raiden Worley
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I have a situation modeled by a Bernoulli random variable with $p=0.4$, but with the added complication that five failures can be "rerolled" for the same probability. I can't use a binomial distribution on that, so how can I determine how many successes I'll get in a number of trials, say 20?
probability
asked Nov 19 at 18:56
Raiden Worley
18915
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a situation modeled by a Bernoulli random variable with $p=0.4$, but with the added complication that five failures can be "rerolled" for the same probability. I can't use a binomial distribution on that, so how can I determine how many successes I'll get in a number of trials, say 20?
probability
asked Nov 19 at 18:56
Raiden Worley
18915
I have a situation modeled by a Bernoulli random variable with $p=0.4$, but with the added complication that five failures can be "rerolled" for the same probability. I can't use a binomial distribution on that, so how can I determine how many successes I'll get in a number of trials, say 20?
probability
probability
asked Nov 19 at 18:56
Raiden Worley
18915
asked Nov 19 at 18:56
Raiden Worley
18915
asked Nov 19 at 18:56
Raiden Worley
18915
asked Nov 19 at 18:56
Raiden Worley
18915
asked Nov 19 at 18:56
Raiden Worley
18915
18915
add a comment |
add a comment |
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Found an answer! I used a binomial distribution to figure out how many successes and failures I would have. Then I chose 5 of the failures and figured that 0.4(5) of them would succeed after retry, and added that to the number of successes.
answered Nov 19 at 19:49
Raiden Worley
18915
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up vote
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Found an answer! I used a binomial distribution to figure out how many successes and failures I would have. Then I chose 5 of the failures and figured that 0.4(5) of them would succeed after retry, and added that to the number of successes.
answered Nov 19 at 19:49
Raiden Worley
18915
add a comment |
up vote
0
down vote
Found an answer! I used a binomial distribution to figure out how many successes and failures I would have. Then I chose 5 of the failures and figured that 0.4(5) of them would succeed after retry, and added that to the number of successes.
answered Nov 19 at 19:49
Raiden Worley
18915
add a comment |
up vote
0
down vote
up vote
0
down vote
Found an answer! I used a binomial distribution to figure out how many successes and failures I would have. Then I chose 5 of the failures and figured that 0.4(5) of them would succeed after retry, and added that to the number of successes.
answered Nov 19 at 19:49
Raiden Worley
18915
Found an answer! I used a binomial distribution to figure out how many successes and failures I would have. Then I chose 5 of the failures and figured that 0.4(5) of them would succeed after retry, and added that to the number of successes.
answered Nov 19 at 19:49
Raiden Worley
18915
answered Nov 19 at 19:49
Raiden Worley
18915
answered Nov 19 at 19:49
Raiden Worley
18915
answered Nov 19 at 19:49
Raiden Worley
18915
18915
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