Almost normal subgroups: Is there any notion which is weaker than normal subgroup?












8












$begingroup$


Let $G$ be a group then $N$ a subgroup of $G$ is said to be normal subgroup of $G$ if $forall g in G$, $g^{-1}Ng = N$.



Is there any notion which is weaker than normal subgroup? I mean something like almost normal subgroup or nearly normal subgroup in which some of the elements only follow the normality condition.










share|cite|improve this question











$endgroup$








  • 3




    $begingroup$
    Groupprops lists some - groupprops.subwiki.org/wiki/Normal_subgroup#Weaker_properties
    $endgroup$
    – Eevee Trainer
    Feb 21 at 6:11
















8












$begingroup$


Let $G$ be a group then $N$ a subgroup of $G$ is said to be normal subgroup of $G$ if $forall g in G$, $g^{-1}Ng = N$.



Is there any notion which is weaker than normal subgroup? I mean something like almost normal subgroup or nearly normal subgroup in which some of the elements only follow the normality condition.










share|cite|improve this question











$endgroup$








  • 3




    $begingroup$
    Groupprops lists some - groupprops.subwiki.org/wiki/Normal_subgroup#Weaker_properties
    $endgroup$
    – Eevee Trainer
    Feb 21 at 6:11














8












8








8


3



$begingroup$


Let $G$ be a group then $N$ a subgroup of $G$ is said to be normal subgroup of $G$ if $forall g in G$, $g^{-1}Ng = N$.



Is there any notion which is weaker than normal subgroup? I mean something like almost normal subgroup or nearly normal subgroup in which some of the elements only follow the normality condition.










share|cite|improve this question











$endgroup$




Let $G$ be a group then $N$ a subgroup of $G$ is said to be normal subgroup of $G$ if $forall g in G$, $g^{-1}Ng = N$.



Is there any notion which is weaker than normal subgroup? I mean something like almost normal subgroup or nearly normal subgroup in which some of the elements only follow the normality condition.







group-theory definition normal-subgroups






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Feb 21 at 15:50









Shaun

9,310113684




9,310113684










asked Feb 21 at 6:10









I_wil_break_wallI_wil_break_wall

805




805








  • 3




    $begingroup$
    Groupprops lists some - groupprops.subwiki.org/wiki/Normal_subgroup#Weaker_properties
    $endgroup$
    – Eevee Trainer
    Feb 21 at 6:11














  • 3




    $begingroup$
    Groupprops lists some - groupprops.subwiki.org/wiki/Normal_subgroup#Weaker_properties
    $endgroup$
    – Eevee Trainer
    Feb 21 at 6:11








3




3




$begingroup$
Groupprops lists some - groupprops.subwiki.org/wiki/Normal_subgroup#Weaker_properties
$endgroup$
– Eevee Trainer
Feb 21 at 6:11




$begingroup$
Groupprops lists some - groupprops.subwiki.org/wiki/Normal_subgroup#Weaker_properties
$endgroup$
– Eevee Trainer
Feb 21 at 6:11










5 Answers
5






active

oldest

votes


















8












$begingroup$

A very important notion is that of subnormality: a subgroup $H$ of $G$ is called subnormal if there is a series $H=H_0 lhd H_1 lhd cdots lhd H_{n-1} lhd H_n=G$. Of course every normal subgroup is subnormal, but the converse is not true in general. Helmut Wielandt basically established the theory in 1939, one of his famous results being the Zipper Lemma.



Other notions to be considered are pronormal subgroups and quasinormal or permutable subgroups, each of which generalizes a certain property of normal subgroups.






share|cite|improve this answer











$endgroup$





















    6












    $begingroup$

    Consider the set of all conjugates of a subgroup $Hleq G$, defined by $C={gHg^{-1}mid gin G}$. If $H$ is normal, clearly $|C|=1$, so $|C|$ can be considered to be a measure of "how far away from being normal" a subgroup is.






    share|cite|improve this answer









    $endgroup$





















      3












      $begingroup$

      What about $N$ admits only a finite number oof conjugates ? For instance, when the group $G$ acts on a finite space, the stabilizer of a point has this property.






      share|cite|improve this answer









      $endgroup$













      • $begingroup$
        The second sentence characterizes finite index subgroups.
        $endgroup$
        – YCor
        Feb 22 at 10:14



















      2












      $begingroup$

      In the contex of locally compact topological groups which are equiped with the Haar measure, one can consider the following:
      "For almost all $gin G$ we have $g^{-1} Ng=N$"



      In the context of Lie groups, one can consider $g^{-1} N g$ would be isometric to $N$ with metric they inherit from a left (but not right) invariant metric.



      In the context of abstract groups one can says "$cap_g g^{-1} N g$ has finite index in $N$.






      share|cite|improve this answer











      $endgroup$





















        1












        $begingroup$

        $N$ is said to be a commensurated subgroup if $[N:Ncap gNg^{-1}]$ is finite for every $gin G$. This has many other names (almost normal, $(G,N)$ is a Hecke pair, etc). This notion occurs in various contexts.






        share|cite|improve this answer









        $endgroup$













          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "69"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3121058%2falmost-normal-subgroups-is-there-any-notion-which-is-weaker-than-normal-subgrou%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          5 Answers
          5






          active

          oldest

          votes








          5 Answers
          5






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          8












          $begingroup$

          A very important notion is that of subnormality: a subgroup $H$ of $G$ is called subnormal if there is a series $H=H_0 lhd H_1 lhd cdots lhd H_{n-1} lhd H_n=G$. Of course every normal subgroup is subnormal, but the converse is not true in general. Helmut Wielandt basically established the theory in 1939, one of his famous results being the Zipper Lemma.



          Other notions to be considered are pronormal subgroups and quasinormal or permutable subgroups, each of which generalizes a certain property of normal subgroups.






          share|cite|improve this answer











          $endgroup$


















            8












            $begingroup$

            A very important notion is that of subnormality: a subgroup $H$ of $G$ is called subnormal if there is a series $H=H_0 lhd H_1 lhd cdots lhd H_{n-1} lhd H_n=G$. Of course every normal subgroup is subnormal, but the converse is not true in general. Helmut Wielandt basically established the theory in 1939, one of his famous results being the Zipper Lemma.



            Other notions to be considered are pronormal subgroups and quasinormal or permutable subgroups, each of which generalizes a certain property of normal subgroups.






            share|cite|improve this answer











            $endgroup$
















              8












              8








              8





              $begingroup$

              A very important notion is that of subnormality: a subgroup $H$ of $G$ is called subnormal if there is a series $H=H_0 lhd H_1 lhd cdots lhd H_{n-1} lhd H_n=G$. Of course every normal subgroup is subnormal, but the converse is not true in general. Helmut Wielandt basically established the theory in 1939, one of his famous results being the Zipper Lemma.



              Other notions to be considered are pronormal subgroups and quasinormal or permutable subgroups, each of which generalizes a certain property of normal subgroups.






              share|cite|improve this answer











              $endgroup$



              A very important notion is that of subnormality: a subgroup $H$ of $G$ is called subnormal if there is a series $H=H_0 lhd H_1 lhd cdots lhd H_{n-1} lhd H_n=G$. Of course every normal subgroup is subnormal, but the converse is not true in general. Helmut Wielandt basically established the theory in 1939, one of his famous results being the Zipper Lemma.



              Other notions to be considered are pronormal subgroups and quasinormal or permutable subgroups, each of which generalizes a certain property of normal subgroups.







              share|cite|improve this answer














              share|cite|improve this answer



              share|cite|improve this answer








              edited Feb 21 at 16:10

























              answered Feb 21 at 9:54









              Nicky HeksterNicky Hekster

              28.8k63456




              28.8k63456























                  6












                  $begingroup$

                  Consider the set of all conjugates of a subgroup $Hleq G$, defined by $C={gHg^{-1}mid gin G}$. If $H$ is normal, clearly $|C|=1$, so $|C|$ can be considered to be a measure of "how far away from being normal" a subgroup is.






                  share|cite|improve this answer









                  $endgroup$


















                    6












                    $begingroup$

                    Consider the set of all conjugates of a subgroup $Hleq G$, defined by $C={gHg^{-1}mid gin G}$. If $H$ is normal, clearly $|C|=1$, so $|C|$ can be considered to be a measure of "how far away from being normal" a subgroup is.






                    share|cite|improve this answer









                    $endgroup$
















                      6












                      6








                      6





                      $begingroup$

                      Consider the set of all conjugates of a subgroup $Hleq G$, defined by $C={gHg^{-1}mid gin G}$. If $H$ is normal, clearly $|C|=1$, so $|C|$ can be considered to be a measure of "how far away from being normal" a subgroup is.






                      share|cite|improve this answer









                      $endgroup$



                      Consider the set of all conjugates of a subgroup $Hleq G$, defined by $C={gHg^{-1}mid gin G}$. If $H$ is normal, clearly $|C|=1$, so $|C|$ can be considered to be a measure of "how far away from being normal" a subgroup is.







                      share|cite|improve this answer












                      share|cite|improve this answer



                      share|cite|improve this answer










                      answered Feb 21 at 7:19









                      YiFanYiFan

                      4,3391627




                      4,3391627























                          3












                          $begingroup$

                          What about $N$ admits only a finite number oof conjugates ? For instance, when the group $G$ acts on a finite space, the stabilizer of a point has this property.






                          share|cite|improve this answer









                          $endgroup$













                          • $begingroup$
                            The second sentence characterizes finite index subgroups.
                            $endgroup$
                            – YCor
                            Feb 22 at 10:14
















                          3












                          $begingroup$

                          What about $N$ admits only a finite number oof conjugates ? For instance, when the group $G$ acts on a finite space, the stabilizer of a point has this property.






                          share|cite|improve this answer









                          $endgroup$













                          • $begingroup$
                            The second sentence characterizes finite index subgroups.
                            $endgroup$
                            – YCor
                            Feb 22 at 10:14














                          3












                          3








                          3





                          $begingroup$

                          What about $N$ admits only a finite number oof conjugates ? For instance, when the group $G$ acts on a finite space, the stabilizer of a point has this property.






                          share|cite|improve this answer









                          $endgroup$



                          What about $N$ admits only a finite number oof conjugates ? For instance, when the group $G$ acts on a finite space, the stabilizer of a point has this property.







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered Feb 21 at 6:59









                          ThomasThomas

                          4,102510




                          4,102510












                          • $begingroup$
                            The second sentence characterizes finite index subgroups.
                            $endgroup$
                            – YCor
                            Feb 22 at 10:14


















                          • $begingroup$
                            The second sentence characterizes finite index subgroups.
                            $endgroup$
                            – YCor
                            Feb 22 at 10:14
















                          $begingroup$
                          The second sentence characterizes finite index subgroups.
                          $endgroup$
                          – YCor
                          Feb 22 at 10:14




                          $begingroup$
                          The second sentence characterizes finite index subgroups.
                          $endgroup$
                          – YCor
                          Feb 22 at 10:14











                          2












                          $begingroup$

                          In the contex of locally compact topological groups which are equiped with the Haar measure, one can consider the following:
                          "For almost all $gin G$ we have $g^{-1} Ng=N$"



                          In the context of Lie groups, one can consider $g^{-1} N g$ would be isometric to $N$ with metric they inherit from a left (but not right) invariant metric.



                          In the context of abstract groups one can says "$cap_g g^{-1} N g$ has finite index in $N$.






                          share|cite|improve this answer











                          $endgroup$


















                            2












                            $begingroup$

                            In the contex of locally compact topological groups which are equiped with the Haar measure, one can consider the following:
                            "For almost all $gin G$ we have $g^{-1} Ng=N$"



                            In the context of Lie groups, one can consider $g^{-1} N g$ would be isometric to $N$ with metric they inherit from a left (but not right) invariant metric.



                            In the context of abstract groups one can says "$cap_g g^{-1} N g$ has finite index in $N$.






                            share|cite|improve this answer











                            $endgroup$
















                              2












                              2








                              2





                              $begingroup$

                              In the contex of locally compact topological groups which are equiped with the Haar measure, one can consider the following:
                              "For almost all $gin G$ we have $g^{-1} Ng=N$"



                              In the context of Lie groups, one can consider $g^{-1} N g$ would be isometric to $N$ with metric they inherit from a left (but not right) invariant metric.



                              In the context of abstract groups one can says "$cap_g g^{-1} N g$ has finite index in $N$.






                              share|cite|improve this answer











                              $endgroup$



                              In the contex of locally compact topological groups which are equiped with the Haar measure, one can consider the following:
                              "For almost all $gin G$ we have $g^{-1} Ng=N$"



                              In the context of Lie groups, one can consider $g^{-1} N g$ would be isometric to $N$ with metric they inherit from a left (but not right) invariant metric.



                              In the context of abstract groups one can says "$cap_g g^{-1} N g$ has finite index in $N$.







                              share|cite|improve this answer














                              share|cite|improve this answer



                              share|cite|improve this answer








                              edited Feb 21 at 9:30

























                              answered Feb 21 at 7:37









                              Ali TaghaviAli Taghavi

                              257330




                              257330























                                  1












                                  $begingroup$

                                  $N$ is said to be a commensurated subgroup if $[N:Ncap gNg^{-1}]$ is finite for every $gin G$. This has many other names (almost normal, $(G,N)$ is a Hecke pair, etc). This notion occurs in various contexts.






                                  share|cite|improve this answer









                                  $endgroup$


















                                    1












                                    $begingroup$

                                    $N$ is said to be a commensurated subgroup if $[N:Ncap gNg^{-1}]$ is finite for every $gin G$. This has many other names (almost normal, $(G,N)$ is a Hecke pair, etc). This notion occurs in various contexts.






                                    share|cite|improve this answer









                                    $endgroup$
















                                      1












                                      1








                                      1





                                      $begingroup$

                                      $N$ is said to be a commensurated subgroup if $[N:Ncap gNg^{-1}]$ is finite for every $gin G$. This has many other names (almost normal, $(G,N)$ is a Hecke pair, etc). This notion occurs in various contexts.






                                      share|cite|improve this answer









                                      $endgroup$



                                      $N$ is said to be a commensurated subgroup if $[N:Ncap gNg^{-1}]$ is finite for every $gin G$. This has many other names (almost normal, $(G,N)$ is a Hecke pair, etc). This notion occurs in various contexts.







                                      share|cite|improve this answer












                                      share|cite|improve this answer



                                      share|cite|improve this answer










                                      answered Feb 22 at 10:14









                                      YCorYCor

                                      7,798929




                                      7,798929






























                                          draft saved

                                          draft discarded




















































                                          Thanks for contributing an answer to Mathematics Stack Exchange!


                                          • Please be sure to answer the question. Provide details and share your research!

                                          But avoid



                                          • Asking for help, clarification, or responding to other answers.

                                          • Making statements based on opinion; back them up with references or personal experience.


                                          Use MathJax to format equations. MathJax reference.


                                          To learn more, see our tips on writing great answers.




                                          draft saved


                                          draft discarded














                                          StackExchange.ready(
                                          function () {
                                          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3121058%2falmost-normal-subgroups-is-there-any-notion-which-is-weaker-than-normal-subgrou%23new-answer', 'question_page');
                                          }
                                          );

                                          Post as a guest















                                          Required, but never shown





















































                                          Required, but never shown














                                          Required, but never shown












                                          Required, but never shown







                                          Required, but never shown

































                                          Required, but never shown














                                          Required, but never shown












                                          Required, but never shown







                                          Required, but never shown







                                          Popular posts from this blog

                                          How to send String Array data to Server using php in android

                                          Title Spacing in Bjornstrup Chapter, Removing Chapter Number From Contents

                                          Is anime1.com a legal site for watching anime?