Stanford Online Course Relational Algebra - Set Difference Operator
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Problem: Consider a relation R(A) with r tuples, all unique within R, and a relation S(A) with s tuples, all unique within S. Let t represent the number of tuples in R minus S. Which of the following triples of values (r,s,t) is possible?
Potential Answers:
(10,13,8)
(5,3,1)
(5,0,3)
(8,2,2)
I tried to solve this on my own by creating 2 example tables with R(A) and S(A). I know with bag difference, an element appears in the difference A-B
of bags as many times as it appears in A, minus the number of times it appears in B. But never less than 0 times.
Example:
Relation R
| A |
|---|
| 1 |
| 2 |
| 3 |
| 4 |
Relation S
| A |
|---|
| 4 |
| 5 |
| 6 |
| 7 |
If I do R - S I get the following result 1, 2, 3
.
Couldn't it be any of the potential answers (Except '5,0,3'
) since the amount of tuples just has to be less than the number of tuples in A or B?
relation-algebra
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add a comment |
$begingroup$
Problem: Consider a relation R(A) with r tuples, all unique within R, and a relation S(A) with s tuples, all unique within S. Let t represent the number of tuples in R minus S. Which of the following triples of values (r,s,t) is possible?
Potential Answers:
(10,13,8)
(5,3,1)
(5,0,3)
(8,2,2)
I tried to solve this on my own by creating 2 example tables with R(A) and S(A). I know with bag difference, an element appears in the difference A-B
of bags as many times as it appears in A, minus the number of times it appears in B. But never less than 0 times.
Example:
Relation R
| A |
|---|
| 1 |
| 2 |
| 3 |
| 4 |
Relation S
| A |
|---|
| 4 |
| 5 |
| 6 |
| 7 |
If I do R - S I get the following result 1, 2, 3
.
Couldn't it be any of the potential answers (Except '5,0,3'
) since the amount of tuples just has to be less than the number of tuples in A or B?
relation-algebra
$endgroup$
add a comment |
$begingroup$
Problem: Consider a relation R(A) with r tuples, all unique within R, and a relation S(A) with s tuples, all unique within S. Let t represent the number of tuples in R minus S. Which of the following triples of values (r,s,t) is possible?
Potential Answers:
(10,13,8)
(5,3,1)
(5,0,3)
(8,2,2)
I tried to solve this on my own by creating 2 example tables with R(A) and S(A). I know with bag difference, an element appears in the difference A-B
of bags as many times as it appears in A, minus the number of times it appears in B. But never less than 0 times.
Example:
Relation R
| A |
|---|
| 1 |
| 2 |
| 3 |
| 4 |
Relation S
| A |
|---|
| 4 |
| 5 |
| 6 |
| 7 |
If I do R - S I get the following result 1, 2, 3
.
Couldn't it be any of the potential answers (Except '5,0,3'
) since the amount of tuples just has to be less than the number of tuples in A or B?
relation-algebra
$endgroup$
Problem: Consider a relation R(A) with r tuples, all unique within R, and a relation S(A) with s tuples, all unique within S. Let t represent the number of tuples in R minus S. Which of the following triples of values (r,s,t) is possible?
Potential Answers:
(10,13,8)
(5,3,1)
(5,0,3)
(8,2,2)
I tried to solve this on my own by creating 2 example tables with R(A) and S(A). I know with bag difference, an element appears in the difference A-B
of bags as many times as it appears in A, minus the number of times it appears in B. But never less than 0 times.
Example:
Relation R
| A |
|---|
| 1 |
| 2 |
| 3 |
| 4 |
Relation S
| A |
|---|
| 4 |
| 5 |
| 6 |
| 7 |
If I do R - S I get the following result 1, 2, 3
.
Couldn't it be any of the potential answers (Except '5,0,3'
) since the amount of tuples just has to be less than the number of tuples in A or B?
relation-algebra
relation-algebra
asked Dec 4 '18 at 22:42
Maggie LiuMaggie Liu
11
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