Finding position at given distance in a GeoPath












9














Is there a way to find the geoposition of a given distance from start in a GeoPath? I want to mark equidistant positions along a track, for example, a mark every 500 km along the path given by



path=GeoGraphics[
GeoPath[{
Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
}, "Rhumb"]
]


Is there a way to find the pos that gives GeoDistance[Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],pos]==500 km along the path?










share|improve this question





























    9














    Is there a way to find the geoposition of a given distance from start in a GeoPath? I want to mark equidistant positions along a track, for example, a mark every 500 km along the path given by



    path=GeoGraphics[
    GeoPath[{
    Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
    Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
    Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
    }, "Rhumb"]
    ]


    Is there a way to find the pos that gives GeoDistance[Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],pos]==500 km along the path?










    share|improve this question



























      9












      9








      9


      4





      Is there a way to find the geoposition of a given distance from start in a GeoPath? I want to mark equidistant positions along a track, for example, a mark every 500 km along the path given by



      path=GeoGraphics[
      GeoPath[{
      Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
      Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
      Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
      }, "Rhumb"]
      ]


      Is there a way to find the pos that gives GeoDistance[Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],pos]==500 km along the path?










      share|improve this question















      Is there a way to find the geoposition of a given distance from start in a GeoPath? I want to mark equidistant positions along a track, for example, a mark every 500 km along the path given by



      path=GeoGraphics[
      GeoPath[{
      Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
      Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
      Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
      }, "Rhumb"]
      ]


      Is there a way to find the pos that gives GeoDistance[Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],pos]==500 km along the path?







      geographics






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 28 at 13:10









      Kuba

      103k12201515




      103k12201515










      asked Nov 28 at 12:57









      Gunnar

      462




      462






















          2 Answers
          2






          active

          oldest

          votes


















          7














          Here's my attempt to parametrize the path by arclength, where here arclength is GeoLength.



          First I build up a function that can be used on many values:



          ParametrizeGeoPath[g_GeoPath, t_] := ParametrizeGeoPath[g][t]

          ParametrizeGeoPath[GeoPath[locs_, args___]] :=
          Block[{line, nodes, lens, acc, nf, n1, n2, solver},
          line = GeoGraphics`GeoEvaluate[GeoPath[locs, args]];
          nodes = GeoPosition /@ Reverse[line[[1]], {2}];
          lens = QuantityMagnitude[UnitConvert[GeoLength[GeoPath[#, args]]& /@ Partition[nodes, 2, 1], "Kilometers"]];
          acc = Accumulate[lens];
          nf = Nearest[acc -> {"Index", "Element"}];

          GeoPathParametricFunction[acc, nodes, nf, args]
          ]


          Given a target distance, we can invert GeoLength with FindRoot:



          GeoPathParametricFunction[_, nodes_, __][d_] /; d == 0 := First[nodes]

          GeoPathParametricFunction[acc_, nodes_, __][d_] /; d == Last[acc] := Last[nodes]

          GeoPathParametricFunction[acc_, nodes_, nf_, args___][d_] /; 0 < d < Last[acc] :=
          Block[{i, v, s, n1, n2, dist, root, t = Unique["t"]},
          {i, v} = First[nf[d]];
          If[v > d, i--];
          s = If[i == 0, 0, acc[[i]]];
          n1 = nodes[[i+1, 1]];
          n2 = nodes[[i+2, 1]];

          dist[t_?NumericQ] := s + QuantityMagnitude[UnitConvert[GeoLength[GeoPath[{GeoPosition[n1], GeoPosition[(1-t)n1 + t n2]}, args]], "Kilometers"]];

          root = Quiet@FindRoot[dist[t] == d, {t, .5, 0, 1}];

          (
          GeoPosition[(1-t)n1 + t n2] /. root

          ) /; MatchQ[root, {t -> _Real}]
          ]

          GeoPathParametricFunction[___][d_?NumericQ] = Indeterminate;

          GeoPathParametricFunction /: MakeBoxes[expr:GeoPathParametricFunction[__], _] := InterpretationBox[RowBox[{"GeoPathParametricFunction", "[", ""[Ellipsis]"", "]"}], expr]


          Your example:



          path = GeoPath[{
          Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
          Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
          Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
          }, "Rhumb"];

          gpf = ParametrizeGeoPath[path];

          gpf[500]



           GeoPosition[{43.0932, -77.0359}]



          Manipulate[GeoGraphics[{
          path,
          GeoMarker[gpf[d]]
          },
          PlotLabel -> Row[{"Distance: ", Quantity[d, "Kilometers"]}]],
          {d, 0, gpf[[1, -1]]}
          ]


          enter image description here



          The points returned are very close to the initial path:



          ListLinePlot[
          GeoDistance[path, g /@ Range[0, 1300, 100]],
          TargetUnits -> "Meters",
          AxesLabel -> Automatic,
          DataRange -> {0, 1300}
          ]


          enter image description here






          share|improve this answer























          • Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
            – kickert
            Nov 28 at 16:01



















          4














          Here is a function for finding GeoPositions between 2 cities with certain step



          city1 = Entity["City", {"Boston", "Massachusetts", "UnitedStates"}];
          city2 = Entity["City", {"Rochester", "NewYork", "UnitedStates"}];
          city3 = Entity["City", {"Chicago", "Illinois", "UnitedStates"}];

          geopath[c1_, c2_, step_] := Module[{s = First@GeoDistance[c1, c2],
          a = GeoDirection[c1, c2]},
          GeoPath[NestList[GeoDestination[#,{1000 step,a}]&,c1,Floor[s/step]],"Rhumb"]]


          Now if you want to find positions from city1 to city2 every 100 km, type



          geopath[city1, city2, 100]    


          and you will get the positions




          GeoPath[{Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
          GeoPosition[{42.5124, -72.2106}], GeoPosition[{42.6928, -73.4044}],
          GeoPosition[{42.8732, -74.6017}], GeoPosition[{43.0535, -75.8026}],
          GeoPosition[{43.2338, -77.0069}]}, "Rhumb"]







          share|improve this answer























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            7














            Here's my attempt to parametrize the path by arclength, where here arclength is GeoLength.



            First I build up a function that can be used on many values:



            ParametrizeGeoPath[g_GeoPath, t_] := ParametrizeGeoPath[g][t]

            ParametrizeGeoPath[GeoPath[locs_, args___]] :=
            Block[{line, nodes, lens, acc, nf, n1, n2, solver},
            line = GeoGraphics`GeoEvaluate[GeoPath[locs, args]];
            nodes = GeoPosition /@ Reverse[line[[1]], {2}];
            lens = QuantityMagnitude[UnitConvert[GeoLength[GeoPath[#, args]]& /@ Partition[nodes, 2, 1], "Kilometers"]];
            acc = Accumulate[lens];
            nf = Nearest[acc -> {"Index", "Element"}];

            GeoPathParametricFunction[acc, nodes, nf, args]
            ]


            Given a target distance, we can invert GeoLength with FindRoot:



            GeoPathParametricFunction[_, nodes_, __][d_] /; d == 0 := First[nodes]

            GeoPathParametricFunction[acc_, nodes_, __][d_] /; d == Last[acc] := Last[nodes]

            GeoPathParametricFunction[acc_, nodes_, nf_, args___][d_] /; 0 < d < Last[acc] :=
            Block[{i, v, s, n1, n2, dist, root, t = Unique["t"]},
            {i, v} = First[nf[d]];
            If[v > d, i--];
            s = If[i == 0, 0, acc[[i]]];
            n1 = nodes[[i+1, 1]];
            n2 = nodes[[i+2, 1]];

            dist[t_?NumericQ] := s + QuantityMagnitude[UnitConvert[GeoLength[GeoPath[{GeoPosition[n1], GeoPosition[(1-t)n1 + t n2]}, args]], "Kilometers"]];

            root = Quiet@FindRoot[dist[t] == d, {t, .5, 0, 1}];

            (
            GeoPosition[(1-t)n1 + t n2] /. root

            ) /; MatchQ[root, {t -> _Real}]
            ]

            GeoPathParametricFunction[___][d_?NumericQ] = Indeterminate;

            GeoPathParametricFunction /: MakeBoxes[expr:GeoPathParametricFunction[__], _] := InterpretationBox[RowBox[{"GeoPathParametricFunction", "[", ""[Ellipsis]"", "]"}], expr]


            Your example:



            path = GeoPath[{
            Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
            Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
            Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
            }, "Rhumb"];

            gpf = ParametrizeGeoPath[path];

            gpf[500]



             GeoPosition[{43.0932, -77.0359}]



            Manipulate[GeoGraphics[{
            path,
            GeoMarker[gpf[d]]
            },
            PlotLabel -> Row[{"Distance: ", Quantity[d, "Kilometers"]}]],
            {d, 0, gpf[[1, -1]]}
            ]


            enter image description here



            The points returned are very close to the initial path:



            ListLinePlot[
            GeoDistance[path, g /@ Range[0, 1300, 100]],
            TargetUnits -> "Meters",
            AxesLabel -> Automatic,
            DataRange -> {0, 1300}
            ]


            enter image description here






            share|improve this answer























            • Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
              – kickert
              Nov 28 at 16:01
















            7














            Here's my attempt to parametrize the path by arclength, where here arclength is GeoLength.



            First I build up a function that can be used on many values:



            ParametrizeGeoPath[g_GeoPath, t_] := ParametrizeGeoPath[g][t]

            ParametrizeGeoPath[GeoPath[locs_, args___]] :=
            Block[{line, nodes, lens, acc, nf, n1, n2, solver},
            line = GeoGraphics`GeoEvaluate[GeoPath[locs, args]];
            nodes = GeoPosition /@ Reverse[line[[1]], {2}];
            lens = QuantityMagnitude[UnitConvert[GeoLength[GeoPath[#, args]]& /@ Partition[nodes, 2, 1], "Kilometers"]];
            acc = Accumulate[lens];
            nf = Nearest[acc -> {"Index", "Element"}];

            GeoPathParametricFunction[acc, nodes, nf, args]
            ]


            Given a target distance, we can invert GeoLength with FindRoot:



            GeoPathParametricFunction[_, nodes_, __][d_] /; d == 0 := First[nodes]

            GeoPathParametricFunction[acc_, nodes_, __][d_] /; d == Last[acc] := Last[nodes]

            GeoPathParametricFunction[acc_, nodes_, nf_, args___][d_] /; 0 < d < Last[acc] :=
            Block[{i, v, s, n1, n2, dist, root, t = Unique["t"]},
            {i, v} = First[nf[d]];
            If[v > d, i--];
            s = If[i == 0, 0, acc[[i]]];
            n1 = nodes[[i+1, 1]];
            n2 = nodes[[i+2, 1]];

            dist[t_?NumericQ] := s + QuantityMagnitude[UnitConvert[GeoLength[GeoPath[{GeoPosition[n1], GeoPosition[(1-t)n1 + t n2]}, args]], "Kilometers"]];

            root = Quiet@FindRoot[dist[t] == d, {t, .5, 0, 1}];

            (
            GeoPosition[(1-t)n1 + t n2] /. root

            ) /; MatchQ[root, {t -> _Real}]
            ]

            GeoPathParametricFunction[___][d_?NumericQ] = Indeterminate;

            GeoPathParametricFunction /: MakeBoxes[expr:GeoPathParametricFunction[__], _] := InterpretationBox[RowBox[{"GeoPathParametricFunction", "[", ""[Ellipsis]"", "]"}], expr]


            Your example:



            path = GeoPath[{
            Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
            Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
            Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
            }, "Rhumb"];

            gpf = ParametrizeGeoPath[path];

            gpf[500]



             GeoPosition[{43.0932, -77.0359}]



            Manipulate[GeoGraphics[{
            path,
            GeoMarker[gpf[d]]
            },
            PlotLabel -> Row[{"Distance: ", Quantity[d, "Kilometers"]}]],
            {d, 0, gpf[[1, -1]]}
            ]


            enter image description here



            The points returned are very close to the initial path:



            ListLinePlot[
            GeoDistance[path, g /@ Range[0, 1300, 100]],
            TargetUnits -> "Meters",
            AxesLabel -> Automatic,
            DataRange -> {0, 1300}
            ]


            enter image description here






            share|improve this answer























            • Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
              – kickert
              Nov 28 at 16:01














            7












            7








            7






            Here's my attempt to parametrize the path by arclength, where here arclength is GeoLength.



            First I build up a function that can be used on many values:



            ParametrizeGeoPath[g_GeoPath, t_] := ParametrizeGeoPath[g][t]

            ParametrizeGeoPath[GeoPath[locs_, args___]] :=
            Block[{line, nodes, lens, acc, nf, n1, n2, solver},
            line = GeoGraphics`GeoEvaluate[GeoPath[locs, args]];
            nodes = GeoPosition /@ Reverse[line[[1]], {2}];
            lens = QuantityMagnitude[UnitConvert[GeoLength[GeoPath[#, args]]& /@ Partition[nodes, 2, 1], "Kilometers"]];
            acc = Accumulate[lens];
            nf = Nearest[acc -> {"Index", "Element"}];

            GeoPathParametricFunction[acc, nodes, nf, args]
            ]


            Given a target distance, we can invert GeoLength with FindRoot:



            GeoPathParametricFunction[_, nodes_, __][d_] /; d == 0 := First[nodes]

            GeoPathParametricFunction[acc_, nodes_, __][d_] /; d == Last[acc] := Last[nodes]

            GeoPathParametricFunction[acc_, nodes_, nf_, args___][d_] /; 0 < d < Last[acc] :=
            Block[{i, v, s, n1, n2, dist, root, t = Unique["t"]},
            {i, v} = First[nf[d]];
            If[v > d, i--];
            s = If[i == 0, 0, acc[[i]]];
            n1 = nodes[[i+1, 1]];
            n2 = nodes[[i+2, 1]];

            dist[t_?NumericQ] := s + QuantityMagnitude[UnitConvert[GeoLength[GeoPath[{GeoPosition[n1], GeoPosition[(1-t)n1 + t n2]}, args]], "Kilometers"]];

            root = Quiet@FindRoot[dist[t] == d, {t, .5, 0, 1}];

            (
            GeoPosition[(1-t)n1 + t n2] /. root

            ) /; MatchQ[root, {t -> _Real}]
            ]

            GeoPathParametricFunction[___][d_?NumericQ] = Indeterminate;

            GeoPathParametricFunction /: MakeBoxes[expr:GeoPathParametricFunction[__], _] := InterpretationBox[RowBox[{"GeoPathParametricFunction", "[", ""[Ellipsis]"", "]"}], expr]


            Your example:



            path = GeoPath[{
            Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
            Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
            Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
            }, "Rhumb"];

            gpf = ParametrizeGeoPath[path];

            gpf[500]



             GeoPosition[{43.0932, -77.0359}]



            Manipulate[GeoGraphics[{
            path,
            GeoMarker[gpf[d]]
            },
            PlotLabel -> Row[{"Distance: ", Quantity[d, "Kilometers"]}]],
            {d, 0, gpf[[1, -1]]}
            ]


            enter image description here



            The points returned are very close to the initial path:



            ListLinePlot[
            GeoDistance[path, g /@ Range[0, 1300, 100]],
            TargetUnits -> "Meters",
            AxesLabel -> Automatic,
            DataRange -> {0, 1300}
            ]


            enter image description here






            share|improve this answer














            Here's my attempt to parametrize the path by arclength, where here arclength is GeoLength.



            First I build up a function that can be used on many values:



            ParametrizeGeoPath[g_GeoPath, t_] := ParametrizeGeoPath[g][t]

            ParametrizeGeoPath[GeoPath[locs_, args___]] :=
            Block[{line, nodes, lens, acc, nf, n1, n2, solver},
            line = GeoGraphics`GeoEvaluate[GeoPath[locs, args]];
            nodes = GeoPosition /@ Reverse[line[[1]], {2}];
            lens = QuantityMagnitude[UnitConvert[GeoLength[GeoPath[#, args]]& /@ Partition[nodes, 2, 1], "Kilometers"]];
            acc = Accumulate[lens];
            nf = Nearest[acc -> {"Index", "Element"}];

            GeoPathParametricFunction[acc, nodes, nf, args]
            ]


            Given a target distance, we can invert GeoLength with FindRoot:



            GeoPathParametricFunction[_, nodes_, __][d_] /; d == 0 := First[nodes]

            GeoPathParametricFunction[acc_, nodes_, __][d_] /; d == Last[acc] := Last[nodes]

            GeoPathParametricFunction[acc_, nodes_, nf_, args___][d_] /; 0 < d < Last[acc] :=
            Block[{i, v, s, n1, n2, dist, root, t = Unique["t"]},
            {i, v} = First[nf[d]];
            If[v > d, i--];
            s = If[i == 0, 0, acc[[i]]];
            n1 = nodes[[i+1, 1]];
            n2 = nodes[[i+2, 1]];

            dist[t_?NumericQ] := s + QuantityMagnitude[UnitConvert[GeoLength[GeoPath[{GeoPosition[n1], GeoPosition[(1-t)n1 + t n2]}, args]], "Kilometers"]];

            root = Quiet@FindRoot[dist[t] == d, {t, .5, 0, 1}];

            (
            GeoPosition[(1-t)n1 + t n2] /. root

            ) /; MatchQ[root, {t -> _Real}]
            ]

            GeoPathParametricFunction[___][d_?NumericQ] = Indeterminate;

            GeoPathParametricFunction /: MakeBoxes[expr:GeoPathParametricFunction[__], _] := InterpretationBox[RowBox[{"GeoPathParametricFunction", "[", ""[Ellipsis]"", "]"}], expr]


            Your example:



            path = GeoPath[{
            Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
            Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
            Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
            }, "Rhumb"];

            gpf = ParametrizeGeoPath[path];

            gpf[500]



             GeoPosition[{43.0932, -77.0359}]



            Manipulate[GeoGraphics[{
            path,
            GeoMarker[gpf[d]]
            },
            PlotLabel -> Row[{"Distance: ", Quantity[d, "Kilometers"]}]],
            {d, 0, gpf[[1, -1]]}
            ]


            enter image description here



            The points returned are very close to the initial path:



            ListLinePlot[
            GeoDistance[path, g /@ Range[0, 1300, 100]],
            TargetUnits -> "Meters",
            AxesLabel -> Automatic,
            DataRange -> {0, 1300}
            ]


            enter image description here







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 28 at 18:54

























            answered Nov 28 at 15:52









            Chip Hurst

            20.2k15686




            20.2k15686












            • Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
              – kickert
              Nov 28 at 16:01


















            • Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
              – kickert
              Nov 28 at 16:01
















            Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
            – kickert
            Nov 28 at 16:01




            Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
            – kickert
            Nov 28 at 16:01











            4














            Here is a function for finding GeoPositions between 2 cities with certain step



            city1 = Entity["City", {"Boston", "Massachusetts", "UnitedStates"}];
            city2 = Entity["City", {"Rochester", "NewYork", "UnitedStates"}];
            city3 = Entity["City", {"Chicago", "Illinois", "UnitedStates"}];

            geopath[c1_, c2_, step_] := Module[{s = First@GeoDistance[c1, c2],
            a = GeoDirection[c1, c2]},
            GeoPath[NestList[GeoDestination[#,{1000 step,a}]&,c1,Floor[s/step]],"Rhumb"]]


            Now if you want to find positions from city1 to city2 every 100 km, type



            geopath[city1, city2, 100]    


            and you will get the positions




            GeoPath[{Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
            GeoPosition[{42.5124, -72.2106}], GeoPosition[{42.6928, -73.4044}],
            GeoPosition[{42.8732, -74.6017}], GeoPosition[{43.0535, -75.8026}],
            GeoPosition[{43.2338, -77.0069}]}, "Rhumb"]







            share|improve this answer




























              4














              Here is a function for finding GeoPositions between 2 cities with certain step



              city1 = Entity["City", {"Boston", "Massachusetts", "UnitedStates"}];
              city2 = Entity["City", {"Rochester", "NewYork", "UnitedStates"}];
              city3 = Entity["City", {"Chicago", "Illinois", "UnitedStates"}];

              geopath[c1_, c2_, step_] := Module[{s = First@GeoDistance[c1, c2],
              a = GeoDirection[c1, c2]},
              GeoPath[NestList[GeoDestination[#,{1000 step,a}]&,c1,Floor[s/step]],"Rhumb"]]


              Now if you want to find positions from city1 to city2 every 100 km, type



              geopath[city1, city2, 100]    


              and you will get the positions




              GeoPath[{Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
              GeoPosition[{42.5124, -72.2106}], GeoPosition[{42.6928, -73.4044}],
              GeoPosition[{42.8732, -74.6017}], GeoPosition[{43.0535, -75.8026}],
              GeoPosition[{43.2338, -77.0069}]}, "Rhumb"]







              share|improve this answer


























                4












                4








                4






                Here is a function for finding GeoPositions between 2 cities with certain step



                city1 = Entity["City", {"Boston", "Massachusetts", "UnitedStates"}];
                city2 = Entity["City", {"Rochester", "NewYork", "UnitedStates"}];
                city3 = Entity["City", {"Chicago", "Illinois", "UnitedStates"}];

                geopath[c1_, c2_, step_] := Module[{s = First@GeoDistance[c1, c2],
                a = GeoDirection[c1, c2]},
                GeoPath[NestList[GeoDestination[#,{1000 step,a}]&,c1,Floor[s/step]],"Rhumb"]]


                Now if you want to find positions from city1 to city2 every 100 km, type



                geopath[city1, city2, 100]    


                and you will get the positions




                GeoPath[{Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
                GeoPosition[{42.5124, -72.2106}], GeoPosition[{42.6928, -73.4044}],
                GeoPosition[{42.8732, -74.6017}], GeoPosition[{43.0535, -75.8026}],
                GeoPosition[{43.2338, -77.0069}]}, "Rhumb"]







                share|improve this answer














                Here is a function for finding GeoPositions between 2 cities with certain step



                city1 = Entity["City", {"Boston", "Massachusetts", "UnitedStates"}];
                city2 = Entity["City", {"Rochester", "NewYork", "UnitedStates"}];
                city3 = Entity["City", {"Chicago", "Illinois", "UnitedStates"}];

                geopath[c1_, c2_, step_] := Module[{s = First@GeoDistance[c1, c2],
                a = GeoDirection[c1, c2]},
                GeoPath[NestList[GeoDestination[#,{1000 step,a}]&,c1,Floor[s/step]],"Rhumb"]]


                Now if you want to find positions from city1 to city2 every 100 km, type



                geopath[city1, city2, 100]    


                and you will get the positions




                GeoPath[{Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
                GeoPosition[{42.5124, -72.2106}], GeoPosition[{42.6928, -73.4044}],
                GeoPosition[{42.8732, -74.6017}], GeoPosition[{43.0535, -75.8026}],
                GeoPosition[{43.2338, -77.0069}]}, "Rhumb"]








                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 28 at 15:40

























                answered Nov 28 at 13:37









                J42161217

                3,712220




                3,712220






























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