Question concerning isomorphism of quotient groups












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I saw a video that tells that if $p, q$ are integers such that $p|q$, then $Z_q/Z_p$ is isomorphic to $Z_{q/p}$. If it is true, can you give me a hint about how can I prove this?










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$endgroup$












  • $begingroup$
    Look at $<$p$>$, the cyclic subgroup generated by p in $mathbb{Z}_q$. How many elements are there? Since everything is abelian, the quotient group exists. How many elements are there in the quotient group?
    $endgroup$
    – Joel Pereira
    Nov 24 '18 at 1:04












  • $begingroup$
    What's $Z_q / Z_p$? I'm not just quibbling with notation. So I'm asking "What's $(mathbb{Z}/qmathbb{Z})/(mathbb{Z}/pmathbb{Z})$?" The collection $Z_p$ isn't a subset of $Z_q$. Perhaps $Z_q / pZ_q$?
    $endgroup$
    – Eric Towers
    Nov 24 '18 at 1:05
















0












$begingroup$


I saw a video that tells that if $p, q$ are integers such that $p|q$, then $Z_q/Z_p$ is isomorphic to $Z_{q/p}$. If it is true, can you give me a hint about how can I prove this?










share|cite|improve this question









$endgroup$












  • $begingroup$
    Look at $<$p$>$, the cyclic subgroup generated by p in $mathbb{Z}_q$. How many elements are there? Since everything is abelian, the quotient group exists. How many elements are there in the quotient group?
    $endgroup$
    – Joel Pereira
    Nov 24 '18 at 1:04












  • $begingroup$
    What's $Z_q / Z_p$? I'm not just quibbling with notation. So I'm asking "What's $(mathbb{Z}/qmathbb{Z})/(mathbb{Z}/pmathbb{Z})$?" The collection $Z_p$ isn't a subset of $Z_q$. Perhaps $Z_q / pZ_q$?
    $endgroup$
    – Eric Towers
    Nov 24 '18 at 1:05














0












0








0


1



$begingroup$


I saw a video that tells that if $p, q$ are integers such that $p|q$, then $Z_q/Z_p$ is isomorphic to $Z_{q/p}$. If it is true, can you give me a hint about how can I prove this?










share|cite|improve this question









$endgroup$




I saw a video that tells that if $p, q$ are integers such that $p|q$, then $Z_q/Z_p$ is isomorphic to $Z_{q/p}$. If it is true, can you give me a hint about how can I prove this?







abstract-algebra quotient-group






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asked Nov 24 '18 at 1:00









user573497user573497

16619




16619












  • $begingroup$
    Look at $<$p$>$, the cyclic subgroup generated by p in $mathbb{Z}_q$. How many elements are there? Since everything is abelian, the quotient group exists. How many elements are there in the quotient group?
    $endgroup$
    – Joel Pereira
    Nov 24 '18 at 1:04












  • $begingroup$
    What's $Z_q / Z_p$? I'm not just quibbling with notation. So I'm asking "What's $(mathbb{Z}/qmathbb{Z})/(mathbb{Z}/pmathbb{Z})$?" The collection $Z_p$ isn't a subset of $Z_q$. Perhaps $Z_q / pZ_q$?
    $endgroup$
    – Eric Towers
    Nov 24 '18 at 1:05


















  • $begingroup$
    Look at $<$p$>$, the cyclic subgroup generated by p in $mathbb{Z}_q$. How many elements are there? Since everything is abelian, the quotient group exists. How many elements are there in the quotient group?
    $endgroup$
    – Joel Pereira
    Nov 24 '18 at 1:04












  • $begingroup$
    What's $Z_q / Z_p$? I'm not just quibbling with notation. So I'm asking "What's $(mathbb{Z}/qmathbb{Z})/(mathbb{Z}/pmathbb{Z})$?" The collection $Z_p$ isn't a subset of $Z_q$. Perhaps $Z_q / pZ_q$?
    $endgroup$
    – Eric Towers
    Nov 24 '18 at 1:05
















$begingroup$
Look at $<$p$>$, the cyclic subgroup generated by p in $mathbb{Z}_q$. How many elements are there? Since everything is abelian, the quotient group exists. How many elements are there in the quotient group?
$endgroup$
– Joel Pereira
Nov 24 '18 at 1:04






$begingroup$
Look at $<$p$>$, the cyclic subgroup generated by p in $mathbb{Z}_q$. How many elements are there? Since everything is abelian, the quotient group exists. How many elements are there in the quotient group?
$endgroup$
– Joel Pereira
Nov 24 '18 at 1:04














$begingroup$
What's $Z_q / Z_p$? I'm not just quibbling with notation. So I'm asking "What's $(mathbb{Z}/qmathbb{Z})/(mathbb{Z}/pmathbb{Z})$?" The collection $Z_p$ isn't a subset of $Z_q$. Perhaps $Z_q / pZ_q$?
$endgroup$
– Eric Towers
Nov 24 '18 at 1:05




$begingroup$
What's $Z_q / Z_p$? I'm not just quibbling with notation. So I'm asking "What's $(mathbb{Z}/qmathbb{Z})/(mathbb{Z}/pmathbb{Z})$?" The collection $Z_p$ isn't a subset of $Z_q$. Perhaps $Z_q / pZ_q$?
$endgroup$
– Eric Towers
Nov 24 '18 at 1:05










1 Answer
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0












$begingroup$

Hint:



Consider the homomorphism:
begin{align}
mathbf Z/qmathbf Z&longrightarrow mathbf Z/pmathbf Z\
nbmod q&longmapsto nbmod p
end{align}

Check it is well defined and surjective. What is its kernel?






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    1 Answer
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    1 Answer
    1






    active

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    active

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    active

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    0












    $begingroup$

    Hint:



    Consider the homomorphism:
    begin{align}
    mathbf Z/qmathbf Z&longrightarrow mathbf Z/pmathbf Z\
    nbmod q&longmapsto nbmod p
    end{align}

    Check it is well defined and surjective. What is its kernel?






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      Hint:



      Consider the homomorphism:
      begin{align}
      mathbf Z/qmathbf Z&longrightarrow mathbf Z/pmathbf Z\
      nbmod q&longmapsto nbmod p
      end{align}

      Check it is well defined and surjective. What is its kernel?






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        Hint:



        Consider the homomorphism:
        begin{align}
        mathbf Z/qmathbf Z&longrightarrow mathbf Z/pmathbf Z\
        nbmod q&longmapsto nbmod p
        end{align}

        Check it is well defined and surjective. What is its kernel?






        share|cite|improve this answer









        $endgroup$



        Hint:



        Consider the homomorphism:
        begin{align}
        mathbf Z/qmathbf Z&longrightarrow mathbf Z/pmathbf Z\
        nbmod q&longmapsto nbmod p
        end{align}

        Check it is well defined and surjective. What is its kernel?







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 24 '18 at 1:33









        BernardBernard

        119k639112




        119k639112






























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