find word that each character separated by space












1















I need a regex to select a word that each char on that word separated by whitespace. Look at the following string



Mengkapan,Sungai Apit,S I A K,Riau,


I want to select S I A K. I am stuck, I was trying to use the following regex 



s+w{1}s+


but it's not working.






regex sublimetext3







share|improve this question




















  • 1





    b[A-Za-z](?:s+[A-Za-z])+b

    – Dmitry Bychenko
    Nov 19 '18 at 7:22











  • awesome..thank you @DmitryBychenko

    – Dariel Pratama
    Nov 19 '18 at 7:24
















1















I need a regex to select a word that each char on that word separated by whitespace. Look at the following string



Mengkapan,Sungai Apit,S I A K,Riau,


I want to select S I A K. I am stuck, I was trying to use the following regex 



s+w{1}s+


but it's not working.






regex sublimetext3







share|improve this question




















  • 1





    b[A-Za-z](?:s+[A-Za-z])+b

    – Dmitry Bychenko
    Nov 19 '18 at 7:22











  • awesome..thank you @DmitryBychenko

    – Dariel Pratama
    Nov 19 '18 at 7:24














1












1








1








I need a regex to select a word that each char on that word separated by whitespace. Look at the following string



Mengkapan,Sungai Apit,S I A K,Riau,


I want to select S I A K. I am stuck, I was trying to use the following regex 



s+w{1}s+


but it's not working.






regex sublimetext3







share|improve this question
















I need a regex to select a word that each char on that word separated by whitespace. Look at the following string



Mengkapan,Sungai Apit,S I A K,Riau,


I want to select S I A K. I am stuck, I was trying to use the following regex 



s+w{1}s+


but it's not working.






regex sublimetext3




regex sublimetext3






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 '18 at 8:00









Dmitry Bychenko

106k992132




106k992132










asked Nov 19 '18 at 7:19









Dariel PratamaDariel Pratama

6981725




6981725








  • 1





    b[A-Za-z](?:s+[A-Za-z])+b

    – Dmitry Bychenko
    Nov 19 '18 at 7:22











  • awesome..thank you @DmitryBychenko

    – Dariel Pratama
    Nov 19 '18 at 7:24














  • 1





    b[A-Za-z](?:s+[A-Za-z])+b

    – Dmitry Bychenko
    Nov 19 '18 at 7:22











  • awesome..thank you @DmitryBychenko

    – Dariel Pratama
    Nov 19 '18 at 7:24








1




1





b[A-Za-z](?:s+[A-Za-z])+b

– Dmitry Bychenko
Nov 19 '18 at 7:22





b[A-Za-z](?:s+[A-Za-z])+b

– Dmitry Bychenko
Nov 19 '18 at 7:22













awesome..thank you @DmitryBychenko

– Dariel Pratama
Nov 19 '18 at 7:24





awesome..thank you @DmitryBychenko

– Dariel Pratama
Nov 19 '18 at 7:24












3 Answers
3






active

oldest

votes


















2














I suggest 



b[A-Za-z](?:s+[A-Za-z])+b


pattern, where



b           - word boundary

[A-Za-z]     - letter (exactly one)

(?:          - one or more groups of  

   s+       - white space (at least one)

   [A-Za-z]  - letter (exactly one)

)+

b           - word boundary





share|improve this answer



















  • 1





    all anwsers from people on SO are working perfectly, but Dmitry answer's deserved to be accepted answer because he's the first to comment. thank you very much.

    – Dariel Pratama
    Nov 19 '18 at 7:39



















2














For your given information, you could use



(?:[A-Za-z] ){2,}[A-Za-z]


See a demo on regex101.com.






share|improve this answer



















  • 1





    Counter example? "As I Say" will return match "s I S"

    – Dmitry Bychenko
    Nov 19 '18 at 7:42





















2














You could match a word boundary b, a word character w and repeat at least 2 times a space and a word character followed by a word boundary:



bw(?: w){2,}b



Regex demo






share|improve this answer


























  • Counter example? "As I Say" will return match "s I S"

    – Dmitry Bychenko
    Nov 19 '18 at 7:43








  • 1





    @DmitryBychenko Sharp! You are right, I have added word boundaries.

    – The fourth bird
    Nov 19 '18 at 7:46











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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














I suggest 



b[A-Za-z](?:s+[A-Za-z])+b


pattern, where



b           - word boundary

[A-Za-z]     - letter (exactly one)

(?:          - one or more groups of  

   s+       - white space (at least one)

   [A-Za-z]  - letter (exactly one)

)+

b           - word boundary





share|improve this answer



















  • 1





    all anwsers from people on SO are working perfectly, but Dmitry answer's deserved to be accepted answer because he's the first to comment. thank you very much.

    – Dariel Pratama
    Nov 19 '18 at 7:39
















2














I suggest 



b[A-Za-z](?:s+[A-Za-z])+b


pattern, where



b           - word boundary

[A-Za-z]     - letter (exactly one)

(?:          - one or more groups of  

   s+       - white space (at least one)

   [A-Za-z]  - letter (exactly one)

)+

b           - word boundary





share|improve this answer



















  • 1





    all anwsers from people on SO are working perfectly, but Dmitry answer's deserved to be accepted answer because he's the first to comment. thank you very much.

    – Dariel Pratama
    Nov 19 '18 at 7:39














2












2








2







I suggest 



b[A-Za-z](?:s+[A-Za-z])+b


pattern, where



b           - word boundary

[A-Za-z]     - letter (exactly one)

(?:          - one or more groups of  

   s+       - white space (at least one)

   [A-Za-z]  - letter (exactly one)

)+

b           - word boundary





share|improve this answer













I suggest 



b[A-Za-z](?:s+[A-Za-z])+b


pattern, where



b           - word boundary

[A-Za-z]     - letter (exactly one)

(?:          - one or more groups of  

   s+       - white space (at least one)

   [A-Za-z]  - letter (exactly one)

)+

b           - word boundary






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 19 '18 at 7:25









Dmitry BychenkoDmitry Bychenko

106k992132




106k992132








  • 1





    all anwsers from people on SO are working perfectly, but Dmitry answer's deserved to be accepted answer because he's the first to comment. thank you very much.

    – Dariel Pratama
    Nov 19 '18 at 7:39














  • 1





    all anwsers from people on SO are working perfectly, but Dmitry answer's deserved to be accepted answer because he's the first to comment. thank you very much.

    – Dariel Pratama
    Nov 19 '18 at 7:39








1




1





all anwsers from people on SO are working perfectly, but Dmitry answer's deserved to be accepted answer because he's the first to comment. thank you very much.

– Dariel Pratama
Nov 19 '18 at 7:39





all anwsers from people on SO are working perfectly, but Dmitry answer's deserved to be accepted answer because he's the first to comment. thank you very much.

– Dariel Pratama
Nov 19 '18 at 7:39













2














For your given information, you could use



(?:[A-Za-z] ){2,}[A-Za-z]


See a demo on regex101.com.






share|improve this answer



















  • 1





    Counter example? "As I Say" will return match "s I S"

    – Dmitry Bychenko
    Nov 19 '18 at 7:42


















2














For your given information, you could use



(?:[A-Za-z] ){2,}[A-Za-z]


See a demo on regex101.com.






share|improve this answer



















  • 1





    Counter example? "As I Say" will return match "s I S"

    – Dmitry Bychenko
    Nov 19 '18 at 7:42
















2












2








2







For your given information, you could use



(?:[A-Za-z] ){2,}[A-Za-z]


See a demo on regex101.com.






share|improve this answer













For your given information, you could use



(?:[A-Za-z] ){2,}[A-Za-z]


See a demo on regex101.com.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 19 '18 at 7:23









JanJan

24.3k52348




24.3k52348








  • 1





    Counter example? "As I Say" will return match "s I S"

    – Dmitry Bychenko
    Nov 19 '18 at 7:42
















  • 1





    Counter example? "As I Say" will return match "s I S"

    – Dmitry Bychenko
    Nov 19 '18 at 7:42










1




1





Counter example? "As I Say" will return match "s I S"

– Dmitry Bychenko
Nov 19 '18 at 7:42







Counter example? "As I Say" will return match "s I S"

– Dmitry Bychenko
Nov 19 '18 at 7:42













2














You could match a word boundary b, a word character w and repeat at least 2 times a space and a word character followed by a word boundary:



bw(?: w){2,}b



Regex demo






share|improve this answer


























  • Counter example? "As I Say" will return match "s I S"

    – Dmitry Bychenko
    Nov 19 '18 at 7:43








  • 1





    @DmitryBychenko Sharp! You are right, I have added word boundaries.

    – The fourth bird
    Nov 19 '18 at 7:46
















2














You could match a word boundary b, a word character w and repeat at least 2 times a space and a word character followed by a word boundary:



bw(?: w){2,}b



Regex demo






share|improve this answer


























  • Counter example? "As I Say" will return match "s I S"

    – Dmitry Bychenko
    Nov 19 '18 at 7:43








  • 1





    @DmitryBychenko Sharp! You are right, I have added word boundaries.

    – The fourth bird
    Nov 19 '18 at 7:46














2












2








2







You could match a word boundary b, a word character w and repeat at least 2 times a space and a word character followed by a word boundary:



bw(?: w){2,}b



Regex demo






share|improve this answer















You could match a word boundary b, a word character w and repeat at least 2 times a space and a word character followed by a word boundary:



bw(?: w){2,}b



Regex demo







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 19 '18 at 7:53

























answered Nov 19 '18 at 7:35









The fourth birdThe fourth bird

21k71326




21k71326













  • Counter example? "As I Say" will return match "s I S"

    – Dmitry Bychenko
    Nov 19 '18 at 7:43








  • 1





    @DmitryBychenko Sharp! You are right, I have added word boundaries.

    – The fourth bird
    Nov 19 '18 at 7:46



















  • Counter example? "As I Say" will return match "s I S"

    – Dmitry Bychenko
    Nov 19 '18 at 7:43








  • 1





    @DmitryBychenko Sharp! You are right, I have added word boundaries.

    – The fourth bird
    Nov 19 '18 at 7:46

















Counter example? "As I Say" will return match "s I S"

– Dmitry Bychenko
Nov 19 '18 at 7:43







Counter example? "As I Say" will return match "s I S"

– Dmitry Bychenko
Nov 19 '18 at 7:43






1




1





@DmitryBychenko Sharp! You are right, I have added word boundaries.

– The fourth bird
Nov 19 '18 at 7:46





@DmitryBychenko Sharp! You are right, I have added word boundaries.

– The fourth bird
Nov 19 '18 at 7:46


















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