Optional param with query Spring-Boot jpa 1.5
I want to execute query for filter list with spring boot 1.5, I have param required (username) and optional param (email), How I can assign optional for param in query ?
@Query("SELECT u FROM User u WHERE u.username LIKE :username AND u.email=:email")
public Page getUsers(@Param("username") String username, @Param("email") String email);
http://localhost:8080/users?username=&email=test : work fine
http://localhost:8080/users?username= : Exception
java hibernate spring-boot jpa
asked Nov 19 '18 at 21:20
Taki RahalTaki Rahal
84
add a comment |
I want to execute query for filter list with spring boot 1.5, I have param required (username) and optional param (email), How I can assign optional for param in query ?
@Query("SELECT u FROM User u WHERE u.username LIKE :username AND u.email=:email")
public Page getUsers(@Param("username") String username, @Param("email") String email);
http://localhost:8080/users?username=&email=test : work fine
http://localhost:8080/users?username= : Exception
java hibernate spring-boot jpa
asked Nov 19 '18 at 21:20
Taki RahalTaki Rahal
84
Create two methods, and call one or the other depending on the presence of the email.
– JB Nizet
Nov 19 '18 at 21:25
I really have many params for filter but for this question I simply for two params, How I can execute query with required and optional param ?
– Taki Rahal
Nov 19 '18 at 21:37
Use the JPA criteria API to dynamically create the query, or QueryDSL.
– JB Nizet
Nov 19 '18 at 21:40
add a comment |
I want to execute query for filter list with spring boot 1.5, I have param required (username) and optional param (email), How I can assign optional for param in query ?
@Query("SELECT u FROM User u WHERE u.username LIKE :username AND u.email=:email")
public Page getUsers(@Param("username") String username, @Param("email") String email);
http://localhost:8080/users?username=&email=test : work fine
http://localhost:8080/users?username= : Exception
java hibernate spring-boot jpa
asked Nov 19 '18 at 21:20
Taki RahalTaki Rahal
84
I want to execute query for filter list with spring boot 1.5, I have param required (username) and optional param (email), How I can assign optional for param in query ?
@Query("SELECT u FROM User u WHERE u.username LIKE :username AND u.email=:email")
public Page getUsers(@Param("username") String username, @Param("email") String email);
http://localhost:8080/users?username=&email=test : work fine
http://localhost:8080/users?username= : Exception
java hibernate spring-boot jpa
java hibernate spring-boot jpa
asked Nov 19 '18 at 21:20
Taki RahalTaki Rahal
84
asked Nov 19 '18 at 21:20
Taki RahalTaki Rahal
84
asked Nov 19 '18 at 21:20
Taki RahalTaki Rahal
84
asked Nov 19 '18 at 21:20
Taki RahalTaki Rahal
84
asked Nov 19 '18 at 21:20
Taki RahalTaki Rahal
84
84
Create two methods, and call one or the other depending on the presence of the email.
– JB Nizet
Nov 19 '18 at 21:25
I really have many params for filter but for this question I simply for two params, How I can execute query with required and optional param ?
– Taki Rahal
Nov 19 '18 at 21:37
Use the JPA criteria API to dynamically create the query, or QueryDSL.
– JB Nizet
Nov 19 '18 at 21:40
add a comment |
Create two methods, and call one or the other depending on the presence of the email.
– JB Nizet
Nov 19 '18 at 21:25
I really have many params for filter but for this question I simply for two params, How I can execute query with required and optional param ?
– Taki Rahal
Nov 19 '18 at 21:37
Use the JPA criteria API to dynamically create the query, or QueryDSL.
– JB Nizet
Nov 19 '18 at 21:40
Create two methods, and call one or the other depending on the presence of the email.
– JB Nizet
Nov 19 '18 at 21:25
Create two methods, and call one or the other depending on the presence of the email.
– JB Nizet
Nov 19 '18 at 21:25
I really have many params for filter but for this question I simply for two params, How I can execute query with required and optional param ?
– Taki Rahal
Nov 19 '18 at 21:37
I really have many params for filter but for this question I simply for two params, How I can execute query with required and optional param ?
– Taki Rahal
Nov 19 '18 at 21:37
Use the JPA criteria API to dynamically create the query, or QueryDSL.
– JB Nizet
Nov 19 '18 at 21:40
Use the JPA criteria API to dynamically create the query, or QueryDSL.
– JB Nizet
Nov 19 '18 at 21:40
add a comment |
1 Answer
1
active
oldest
votes
Use JPA criteria API like this:
First, create a Specification object:
private Specification<Item> createSpecification(ItemSearch itemSearch) {
return (root, query, criteriaBuilder) -> criteriaBuilder.and(
Stream.of(
itemSearch.getUsername() == null ? null : criteriaBuilder.like(root.get("username"), itemSearch.getUsername()),
itemSearch.getEmail() == null ? null : criteriaBuilder.equal(root.get("email"), itemSearch.getEmail())
).filter(Objects::nonNull).toArray(Predicate::new)
);
}
Extend your repository from JpaSpecificationExecutor:
public interface ItemRepository extends CrudRepository<Item, Long>, JpaSpecificationExecutor<Item> {
}
Select all items using the specification:
List<Item> items = itemRepository.findAll(createSpecification(itemSearch))
answered Nov 19 '18 at 22:55
ygorygor
1,112615
Thank you, It work very well
– Taki Rahal
Nov 24 '18 at 22:37
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use JPA criteria API like this:
First, create a Specification object:
private Specification<Item> createSpecification(ItemSearch itemSearch) {
return (root, query, criteriaBuilder) -> criteriaBuilder.and(
Stream.of(
itemSearch.getUsername() == null ? null : criteriaBuilder.like(root.get("username"), itemSearch.getUsername()),
itemSearch.getEmail() == null ? null : criteriaBuilder.equal(root.get("email"), itemSearch.getEmail())
).filter(Objects::nonNull).toArray(Predicate::new)
);
}
Extend your repository from JpaSpecificationExecutor:
public interface ItemRepository extends CrudRepository<Item, Long>, JpaSpecificationExecutor<Item> {
}
Select all items using the specification:
List<Item> items = itemRepository.findAll(createSpecification(itemSearch))
answered Nov 19 '18 at 22:55
ygorygor
1,112615
Thank you, It work very well
– Taki Rahal
Nov 24 '18 at 22:37
add a comment |
Use JPA criteria API like this:
First, create a Specification object:
private Specification<Item> createSpecification(ItemSearch itemSearch) {
return (root, query, criteriaBuilder) -> criteriaBuilder.and(
Stream.of(
itemSearch.getUsername() == null ? null : criteriaBuilder.like(root.get("username"), itemSearch.getUsername()),
itemSearch.getEmail() == null ? null : criteriaBuilder.equal(root.get("email"), itemSearch.getEmail())
).filter(Objects::nonNull).toArray(Predicate::new)
);
}
Extend your repository from JpaSpecificationExecutor:
public interface ItemRepository extends CrudRepository<Item, Long>, JpaSpecificationExecutor<Item> {
}
Select all items using the specification:
List<Item> items = itemRepository.findAll(createSpecification(itemSearch))
answered Nov 19 '18 at 22:55
ygorygor
1,112615
Thank you, It work very well
– Taki Rahal
Nov 24 '18 at 22:37
add a comment |
Use JPA criteria API like this:
First, create a Specification object:
private Specification<Item> createSpecification(ItemSearch itemSearch) {
return (root, query, criteriaBuilder) -> criteriaBuilder.and(
Stream.of(
itemSearch.getUsername() == null ? null : criteriaBuilder.like(root.get("username"), itemSearch.getUsername()),
itemSearch.getEmail() == null ? null : criteriaBuilder.equal(root.get("email"), itemSearch.getEmail())
).filter(Objects::nonNull).toArray(Predicate::new)
);
}
Extend your repository from JpaSpecificationExecutor:
public interface ItemRepository extends CrudRepository<Item, Long>, JpaSpecificationExecutor<Item> {
}
Select all items using the specification:
List<Item> items = itemRepository.findAll(createSpecification(itemSearch))
answered Nov 19 '18 at 22:55
ygorygor
1,112615
Use JPA criteria API like this:
First, create a Specification object:
private Specification<Item> createSpecification(ItemSearch itemSearch) {
return (root, query, criteriaBuilder) -> criteriaBuilder.and(
Stream.of(
itemSearch.getUsername() == null ? null : criteriaBuilder.like(root.get("username"), itemSearch.getUsername()),
itemSearch.getEmail() == null ? null : criteriaBuilder.equal(root.get("email"), itemSearch.getEmail())
).filter(Objects::nonNull).toArray(Predicate::new)
);
}
Extend your repository from JpaSpecificationExecutor:
public interface ItemRepository extends CrudRepository<Item, Long>, JpaSpecificationExecutor<Item> {
}
Select all items using the specification:
List<Item> items = itemRepository.findAll(createSpecification(itemSearch))
answered Nov 19 '18 at 22:55
ygorygor
1,112615
edited Nov 19 '18 at 23:04
answered Nov 19 '18 at 22:55
ygorygor
1,112615
answered Nov 19 '18 at 22:55
ygorygor
1,112615
answered Nov 19 '18 at 22:55
ygorygor
1,112615
1,112615
Thank you, It work very well
– Taki Rahal
Nov 24 '18 at 22:37
add a comment |
Thank you, It work very well
– Taki Rahal
Nov 24 '18 at 22:37
Thank you, It work very well
– Taki Rahal
Nov 24 '18 at 22:37
Thank you, It work very well
– Taki Rahal
Nov 24 '18 at 22:37
add a comment |
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Create two methods, and call one or the other depending on the presence of the email.
– JB Nizet
Nov 19 '18 at 21:25
I really have many params for filter but for this question I simply for two params, How I can execute query with required and optional param ?
– Taki Rahal
Nov 19 '18 at 21:37
Use the JPA criteria API to dynamically create the query, or QueryDSL.
– JB Nizet
Nov 19 '18 at 21:40