Can 4 = 6 and 10 = 1000? : Another Grandpa Question
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Grandpa likes PSE. He is amazed at the smart puzzle solvers who seem to solve any of his riddles. So he constantly tries to think of new challenging questions.
So he says:
"Ask Tom, SteveV, Jafe, Rand, elguest, hex, Bass and other smart guys
Is it possible to prove
4 = 6
and
10 = 1000
using same logic (that is what I call it)
and no math operations?"
uvag guvax ebgguvegrra
knowledge lateral-thinking
edited Jan 24 at 15:07
JonMark Perry
18.9k63891
asked Jan 23 at 12:37
DEEMDEEM
5,717118104
$endgroup$
|
show 2 more comments
$begingroup$
Grandpa likes PSE. He is amazed at the smart puzzle solvers who seem to solve any of his riddles. So he constantly tries to think of new challenging questions.
So he says:
"Ask Tom, SteveV, Jafe, Rand, elguest, hex, Bass and other smart guys
Is it possible to prove
4 = 6
and
10 = 1000
using same logic (that is what I call it)
and no math operations?"
uvag guvax ebgguvegrra
knowledge lateral-thinking
edited Jan 24 at 15:07
JonMark Perry
18.9k63891
asked Jan 23 at 12:37
DEEMDEEM
5,717118104
$endgroup$
$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
Jan 23 at 14:05
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Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
Jan 23 at 14:14
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And you already have it!
$endgroup$
– DEEM
Jan 23 at 14:15
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that2*2 = 4, but we could have accepted that2*2 = a fluffy white rabbit.
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– Eugene Anisiutkin
Jan 23 at 14:59
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
Jan 23 at 15:07
|
show 2 more comments
$begingroup$
Grandpa likes PSE. He is amazed at the smart puzzle solvers who seem to solve any of his riddles. So he constantly tries to think of new challenging questions.
So he says:
"Ask Tom, SteveV, Jafe, Rand, elguest, hex, Bass and other smart guys
Is it possible to prove
4 = 6
and
10 = 1000
using same logic (that is what I call it)
and no math operations?"
uvag guvax ebgguvegrra
knowledge lateral-thinking
edited Jan 24 at 15:07
JonMark Perry
18.9k63891
asked Jan 23 at 12:37
DEEMDEEM
5,717118104
$endgroup$
Grandpa likes PSE. He is amazed at the smart puzzle solvers who seem to solve any of his riddles. So he constantly tries to think of new challenging questions.
So he says:
"Ask Tom, SteveV, Jafe, Rand, elguest, hex, Bass and other smart guys
Is it possible to prove
4 = 6
and
10 = 1000
using same logic (that is what I call it)
and no math operations?"
uvag guvax ebgguvegrra
knowledge lateral-thinking
knowledge lateral-thinking
edited Jan 24 at 15:07
JonMark Perry
18.9k63891
asked Jan 23 at 12:37
DEEMDEEM
5,717118104
edited Jan 24 at 15:07
JonMark Perry
18.9k63891
asked Jan 23 at 12:37
DEEMDEEM
5,717118104
edited Jan 24 at 15:07
JonMark Perry
18.9k63891
edited Jan 24 at 15:07
JonMark Perry
18.9k63891
edited Jan 24 at 15:07
JonMark Perry
18.9k63891
18.9k63891
asked Jan 23 at 12:37
DEEMDEEM
5,717118104
asked Jan 23 at 12:37
DEEMDEEM
5,717118104
asked Jan 23 at 12:37
DEEMDEEM
5,717118104
5,717118104
$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
Jan 23 at 14:05
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
Jan 23 at 14:14
$begingroup$
And you already have it!
$endgroup$
– DEEM
Jan 23 at 14:15
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that2*2 = 4, but we could have accepted that2*2 = a fluffy white rabbit.
$endgroup$
– Eugene Anisiutkin
Jan 23 at 14:59
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
Jan 23 at 15:07
|
show 2 more comments
$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
Jan 23 at 14:05
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
Jan 23 at 14:14
$begingroup$
And you already have it!
$endgroup$
– DEEM
Jan 23 at 14:15
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that2*2 = 4, but we could have accepted that2*2 = a fluffy white rabbit.
$endgroup$
– Eugene Anisiutkin
Jan 23 at 14:59
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
Jan 23 at 15:07
$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
Jan 23 at 14:05
$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
Jan 23 at 14:05
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
Jan 23 at 14:14
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
Jan 23 at 14:14
$begingroup$
And you already have it!
$endgroup$
– DEEM
Jan 23 at 14:15
$begingroup$
And you already have it!
$endgroup$
– DEEM
Jan 23 at 14:15
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that
2*2 = 4, but we could have accepted that 2*2 = a fluffy white rabbit.$endgroup$
– Eugene Anisiutkin
Jan 23 at 14:59
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that
2*2 = 4, but we could have accepted that 2*2 = a fluffy white rabbit.$endgroup$
– Eugene Anisiutkin
Jan 23 at 14:59
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
Jan 23 at 15:07
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
Jan 23 at 15:07
|
show 2 more comments
5 Answers
5
active
oldest
votes
$begingroup$
My final answer:
For 4=6:
In Roman, 4 is IV.
But rot13(IV) is VI!
VI in Roman is 6,
so 4=6.
Similarly
For 1000=10
In Roman, 10 is X.
But rot13(X) is K.
K isn’t roman for 1000, but it does mean 1000.
So 10=1000.
Attempt 2(wrong again!):
My guess would be:
From @Rand al’Thor
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
But I seem to have the answer.
For 10=1000
The number of votes you need for a gold badge is 1000, which is 10 times those for bronze.
For 4=6
I just browsed the six user profiles, and except for Rand al’Thor
and El-Guest, the remaining four have silver or below in the riddle tag.
ORIGINAL ANSWER(INCORRECT):
Partial answer:
4=6
This can be proven by using Roman numerals
4=IV
6=VI
IV=VI
So 4=6
Then for part 2:
10 = 1000 if we consider 0 to have no value - literally!
answered Jan 23 at 12:48
Krad CigolKrad Cigol
50117
$endgroup$
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
Jan 23 at 13:00
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
Jan 23 at 13:01
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
Jan 23 at 14:13
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
Jan 24 at 14:10
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
Jan 24 at 14:28
|
show 5 more comments
$begingroup$
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
answered Jan 23 at 18:10
Rand al'ThorRand al'Thor
69.5k14231465
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it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
Jan 23 at 19:00
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
Jan 23 at 19:36
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@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
Jan 23 at 20:49
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How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
Jan 23 at 23:11
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@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
Jan 24 at 6:19
|
show 1 more comment
$begingroup$
Just going to give this a try. Was not even aware that this stackExchange existed!
4=6 -> 4=IV, 6 = VI
10=1000 -> 10=X, 1000=M
IV=VI
X=M
Step 1, remove all vertical lines
Step 2, cut off the lower half of the character
IV=VI --> V=V --> /=/
X=M --> X=v* --> V=V
*the v is floating in the air, its the "v" part of M once the vertical lines are removed
answered Jan 23 at 17:01
JeffreyJeffrey
1914
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add a comment |
$begingroup$
Well...
in many tribal languages, for example that of the Caquintes, numerals higher than two or three are just a word that means "many" (in Caquinte language's case, "oshequi").
So our expressions become "oshequi" = "oshequi" and "oshequi" = "oshequi". Voilà!
answered Jan 23 at 17:05
LinuxBlanketLinuxBlanket
1,374515
$endgroup$
add a comment |
$begingroup$
If you are asking a smart group of guys a question. aka: Tom, SteveV, Jafe, Rand, elguest, hex, Bass and others. They are all part of the same group no matter if its four people or six people
answered Jan 23 at 22:22
jakeopsjakeops
1
$endgroup$
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
My final answer:
For 4=6:
In Roman, 4 is IV.
But rot13(IV) is VI!
VI in Roman is 6,
so 4=6.
Similarly
For 1000=10
In Roman, 10 is X.
But rot13(X) is K.
K isn’t roman for 1000, but it does mean 1000.
So 10=1000.
Attempt 2(wrong again!):
My guess would be:
From @Rand al’Thor
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
But I seem to have the answer.
For 10=1000
The number of votes you need for a gold badge is 1000, which is 10 times those for bronze.
For 4=6
I just browsed the six user profiles, and except for Rand al’Thor
and El-Guest, the remaining four have silver or below in the riddle tag.
ORIGINAL ANSWER(INCORRECT):
Partial answer:
4=6
This can be proven by using Roman numerals
4=IV
6=VI
IV=VI
So 4=6
Then for part 2:
10 = 1000 if we consider 0 to have no value - literally!
answered Jan 23 at 12:48
Krad CigolKrad Cigol
50117
$endgroup$
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
Jan 23 at 13:00
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
Jan 23 at 13:01
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
Jan 23 at 14:13
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
Jan 24 at 14:10
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
Jan 24 at 14:28
|
show 5 more comments
$begingroup$
My final answer:
For 4=6:
In Roman, 4 is IV.
But rot13(IV) is VI!
VI in Roman is 6,
so 4=6.
Similarly
For 1000=10
In Roman, 10 is X.
But rot13(X) is K.
K isn’t roman for 1000, but it does mean 1000.
So 10=1000.
Attempt 2(wrong again!):
My guess would be:
From @Rand al’Thor
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
But I seem to have the answer.
For 10=1000
The number of votes you need for a gold badge is 1000, which is 10 times those for bronze.
For 4=6
I just browsed the six user profiles, and except for Rand al’Thor
and El-Guest, the remaining four have silver or below in the riddle tag.
ORIGINAL ANSWER(INCORRECT):
Partial answer:
4=6
This can be proven by using Roman numerals
4=IV
6=VI
IV=VI
So 4=6
Then for part 2:
10 = 1000 if we consider 0 to have no value - literally!
answered Jan 23 at 12:48
Krad CigolKrad Cigol
50117
$endgroup$
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
Jan 23 at 13:00
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
Jan 23 at 13:01
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
Jan 23 at 14:13
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
Jan 24 at 14:10
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
Jan 24 at 14:28
|
show 5 more comments
$begingroup$
My final answer:
For 4=6:
In Roman, 4 is IV.
But rot13(IV) is VI!
VI in Roman is 6,
so 4=6.
Similarly
For 1000=10
In Roman, 10 is X.
But rot13(X) is K.
K isn’t roman for 1000, but it does mean 1000.
So 10=1000.
Attempt 2(wrong again!):
My guess would be:
From @Rand al’Thor
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
But I seem to have the answer.
For 10=1000
The number of votes you need for a gold badge is 1000, which is 10 times those for bronze.
For 4=6
I just browsed the six user profiles, and except for Rand al’Thor
and El-Guest, the remaining four have silver or below in the riddle tag.
ORIGINAL ANSWER(INCORRECT):
Partial answer:
4=6
This can be proven by using Roman numerals
4=IV
6=VI
IV=VI
So 4=6
Then for part 2:
10 = 1000 if we consider 0 to have no value - literally!
answered Jan 23 at 12:48
Krad CigolKrad Cigol
50117
$endgroup$
My final answer:
For 4=6:
In Roman, 4 is IV.
But rot13(IV) is VI!
VI in Roman is 6,
so 4=6.
Similarly
For 1000=10
In Roman, 10 is X.
But rot13(X) is K.
K isn’t roman for 1000, but it does mean 1000.
So 10=1000.
Attempt 2(wrong again!):
My guess would be:
From @Rand al’Thor
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
But I seem to have the answer.
For 10=1000
The number of votes you need for a gold badge is 1000, which is 10 times those for bronze.
For 4=6
I just browsed the six user profiles, and except for Rand al’Thor
and El-Guest, the remaining four have silver or below in the riddle tag.
ORIGINAL ANSWER(INCORRECT):
Partial answer:
4=6
This can be proven by using Roman numerals
4=IV
6=VI
IV=VI
So 4=6
Then for part 2:
10 = 1000 if we consider 0 to have no value - literally!
answered Jan 23 at 12:48
Krad CigolKrad Cigol
50117
edited Jan 24 at 14:13
answered Jan 23 at 12:48
Krad CigolKrad Cigol
50117
answered Jan 23 at 12:48
Krad CigolKrad Cigol
50117
answered Jan 23 at 12:48
Krad CigolKrad Cigol
50117
50117
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
Jan 23 at 13:00
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
Jan 23 at 13:01
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
Jan 23 at 14:13
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
Jan 24 at 14:10
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
Jan 24 at 14:28
|
show 5 more comments
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
Jan 23 at 13:00
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
Jan 23 at 13:01
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
Jan 23 at 14:13
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
Jan 24 at 14:10
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
Jan 24 at 14:28
1
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
Jan 23 at 13:00
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
Jan 23 at 13:00
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
Jan 23 at 13:01
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
Jan 23 at 13:01
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
Jan 23 at 14:13
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
Jan 23 at 14:13
2
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
Jan 24 at 14:10
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
Jan 24 at 14:10
2
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
Jan 24 at 14:28
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
Jan 24 at 14:28
|
show 5 more comments
$begingroup$
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
answered Jan 23 at 18:10
Rand al'ThorRand al'Thor
69.5k14231465
$endgroup$
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
Jan 23 at 19:00
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
Jan 23 at 19:36
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
Jan 23 at 20:49
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
Jan 23 at 23:11
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
Jan 24 at 6:19
|
show 1 more comment
$begingroup$
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
answered Jan 23 at 18:10
Rand al'ThorRand al'Thor
69.5k14231465
$endgroup$
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
Jan 23 at 19:00
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
Jan 23 at 19:36
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
Jan 23 at 20:49
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
Jan 23 at 23:11
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
Jan 24 at 6:19
|
show 1 more comment
$begingroup$
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
answered Jan 23 at 18:10
Rand al'ThorRand al'Thor
69.5k14231465
$endgroup$
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
answered Jan 23 at 18:10
Rand al'ThorRand al'Thor
69.5k14231465
answered Jan 23 at 18:10
Rand al'ThorRand al'Thor
69.5k14231465
answered Jan 23 at 18:10
Rand al'ThorRand al'Thor
69.5k14231465
answered Jan 23 at 18:10
Rand al'ThorRand al'Thor
69.5k14231465
69.5k14231465
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
Jan 23 at 19:00
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
Jan 23 at 19:36
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
Jan 23 at 20:49
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
Jan 23 at 23:11
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
Jan 24 at 6:19
|
show 1 more comment
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
Jan 23 at 19:00
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
Jan 23 at 19:36
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
Jan 23 at 20:49
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
Jan 23 at 23:11
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
Jan 24 at 6:19
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
Jan 23 at 19:00
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
Jan 23 at 19:00
2
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
Jan 23 at 19:36
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
Jan 23 at 19:36
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
Jan 23 at 20:49
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
Jan 23 at 20:49
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
Jan 23 at 23:11
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
Jan 23 at 23:11
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
Jan 24 at 6:19
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
Jan 24 at 6:19
|
show 1 more comment
$begingroup$
Just going to give this a try. Was not even aware that this stackExchange existed!
4=6 -> 4=IV, 6 = VI
10=1000 -> 10=X, 1000=M
IV=VI
X=M
Step 1, remove all vertical lines
Step 2, cut off the lower half of the character
IV=VI --> V=V --> /=/
X=M --> X=v* --> V=V
*the v is floating in the air, its the "v" part of M once the vertical lines are removed
answered Jan 23 at 17:01
JeffreyJeffrey
1914
$endgroup$
add a comment |
$begingroup$
Just going to give this a try. Was not even aware that this stackExchange existed!
4=6 -> 4=IV, 6 = VI
10=1000 -> 10=X, 1000=M
IV=VI
X=M
Step 1, remove all vertical lines
Step 2, cut off the lower half of the character
IV=VI --> V=V --> /=/
X=M --> X=v* --> V=V
*the v is floating in the air, its the "v" part of M once the vertical lines are removed
answered Jan 23 at 17:01
JeffreyJeffrey
1914
$endgroup$
add a comment |
$begingroup$
Just going to give this a try. Was not even aware that this stackExchange existed!
4=6 -> 4=IV, 6 = VI
10=1000 -> 10=X, 1000=M
IV=VI
X=M
Step 1, remove all vertical lines
Step 2, cut off the lower half of the character
IV=VI --> V=V --> /=/
X=M --> X=v* --> V=V
*the v is floating in the air, its the "v" part of M once the vertical lines are removed
answered Jan 23 at 17:01
JeffreyJeffrey
1914
$endgroup$
Just going to give this a try. Was not even aware that this stackExchange existed!
4=6 -> 4=IV, 6 = VI
10=1000 -> 10=X, 1000=M
IV=VI
X=M
Step 1, remove all vertical lines
Step 2, cut off the lower half of the character
IV=VI --> V=V --> /=/
X=M --> X=v* --> V=V
*the v is floating in the air, its the "v" part of M once the vertical lines are removed
answered Jan 23 at 17:01
JeffreyJeffrey
1914
edited Jan 23 at 17:10
answered Jan 23 at 17:01
JeffreyJeffrey
1914
answered Jan 23 at 17:01
JeffreyJeffrey
1914
answered Jan 23 at 17:01
JeffreyJeffrey
1914
1914
add a comment |
add a comment |
$begingroup$
Well...
in many tribal languages, for example that of the Caquintes, numerals higher than two or three are just a word that means "many" (in Caquinte language's case, "oshequi").
So our expressions become "oshequi" = "oshequi" and "oshequi" = "oshequi". Voilà!
answered Jan 23 at 17:05
LinuxBlanketLinuxBlanket
1,374515
$endgroup$
add a comment |
$begingroup$
Well...
in many tribal languages, for example that of the Caquintes, numerals higher than two or three are just a word that means "many" (in Caquinte language's case, "oshequi").
So our expressions become "oshequi" = "oshequi" and "oshequi" = "oshequi". Voilà!
answered Jan 23 at 17:05
LinuxBlanketLinuxBlanket
1,374515
$endgroup$
add a comment |
$begingroup$
Well...
in many tribal languages, for example that of the Caquintes, numerals higher than two or three are just a word that means "many" (in Caquinte language's case, "oshequi").
So our expressions become "oshequi" = "oshequi" and "oshequi" = "oshequi". Voilà!
answered Jan 23 at 17:05
LinuxBlanketLinuxBlanket
1,374515
$endgroup$
Well...
in many tribal languages, for example that of the Caquintes, numerals higher than two or three are just a word that means "many" (in Caquinte language's case, "oshequi").
So our expressions become "oshequi" = "oshequi" and "oshequi" = "oshequi". Voilà!
answered Jan 23 at 17:05
LinuxBlanketLinuxBlanket
1,374515
edited Jan 24 at 9:11
answered Jan 23 at 17:05
LinuxBlanketLinuxBlanket
1,374515
answered Jan 23 at 17:05
LinuxBlanketLinuxBlanket
1,374515
answered Jan 23 at 17:05
LinuxBlanketLinuxBlanket
1,374515
1,374515
add a comment |
add a comment |
$begingroup$
If you are asking a smart group of guys a question. aka: Tom, SteveV, Jafe, Rand, elguest, hex, Bass and others. They are all part of the same group no matter if its four people or six people
answered Jan 23 at 22:22
jakeopsjakeops
1
$endgroup$
add a comment |
$begingroup$
If you are asking a smart group of guys a question. aka: Tom, SteveV, Jafe, Rand, elguest, hex, Bass and others. They are all part of the same group no matter if its four people or six people
answered Jan 23 at 22:22
jakeopsjakeops
1
$endgroup$
add a comment |
$begingroup$
If you are asking a smart group of guys a question. aka: Tom, SteveV, Jafe, Rand, elguest, hex, Bass and others. They are all part of the same group no matter if its four people or six people
answered Jan 23 at 22:22
jakeopsjakeops
1
$endgroup$
If you are asking a smart group of guys a question. aka: Tom, SteveV, Jafe, Rand, elguest, hex, Bass and others. They are all part of the same group no matter if its four people or six people
answered Jan 23 at 22:22
jakeopsjakeops
1
answered Jan 23 at 22:22
jakeopsjakeops
1
answered Jan 23 at 22:22
jakeopsjakeops
1
answered Jan 23 at 22:22
jakeopsjakeops
1
1
add a comment |
add a comment |
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$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
Jan 23 at 14:05
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
Jan 23 at 14:14
$begingroup$
And you already have it!
$endgroup$
– DEEM
Jan 23 at 14:15
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that
2*2 = 4, but we could have accepted that2*2 = a fluffy white rabbit.$endgroup$
– Eugene Anisiutkin
Jan 23 at 14:59
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
Jan 23 at 15:07