IOError: [Errno 22] Invalid argument with url











up vote
0
down vote

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I am newbie in python and i am trying to open an localhost with write mode
but i got following errors



with io.open('http:\localhost:3000\assets\i18n\locale-ru.json', 'w') as outfile:


IOError: [Errno 22] Invalid argument: 'http:\localhost:3000\assets\i18n\locale-ru.json'



Here is a piece of code:



 with io.open('http://localhost:3000//assets//i18n//locale-ru.json', 'w') as outfile:

  str_ = json.dumps(data_ru,

                    indent=4, sort_keys=True,

                    separators=(',', ': '), ensure_ascii=False)

  outfile.write(to_unicode(str_))





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  • 1




    Just a note, you have only one slash after `http:`.
    – vishes_shell
    Nov 12 at 19:42










  • with io.open('http:/localhost:3000//assets//i18n//locale-ru.json', 'w') as outfile: IOError: [Errno 22] Invalid argument: 'http:/localhost:3000//assets//i18n//locale-ru.json'
    – user987
    Nov 12 at 19:46










  • still got error
    – user987
    Nov 12 at 19:47















up vote
0
down vote

favorite












I am newbie in python and i am trying to open an localhost with write mode
but i got following errors



with io.open('http:\localhost:3000\assets\i18n\locale-ru.json', 'w') as outfile:


IOError: [Errno 22] Invalid argument: 'http:\localhost:3000\assets\i18n\locale-ru.json'



Here is a piece of code:



 with io.open('http://localhost:3000//assets//i18n//locale-ru.json', 'w') as outfile:

  str_ = json.dumps(data_ru,

                    indent=4, sort_keys=True,

                    separators=(',', ': '), ensure_ascii=False)

  outfile.write(to_unicode(str_))





python flask







share|improve this question




















  • 1




    Just a note, you have only one slash after `http:`.
    – vishes_shell
    Nov 12 at 19:42










  • with io.open('http:/localhost:3000//assets//i18n//locale-ru.json', 'w') as outfile: IOError: [Errno 22] Invalid argument: 'http:/localhost:3000//assets//i18n//locale-ru.json'
    – user987
    Nov 12 at 19:46










  • still got error
    – user987
    Nov 12 at 19:47













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am newbie in python and i am trying to open an localhost with write mode
but i got following errors



with io.open('http:\localhost:3000\assets\i18n\locale-ru.json', 'w') as outfile:


IOError: [Errno 22] Invalid argument: 'http:\localhost:3000\assets\i18n\locale-ru.json'



Here is a piece of code:



 with io.open('http://localhost:3000//assets//i18n//locale-ru.json', 'w') as outfile:

  str_ = json.dumps(data_ru,

                    indent=4, sort_keys=True,

                    separators=(',', ': '), ensure_ascii=False)

  outfile.write(to_unicode(str_))





python flask







share|improve this question















I am newbie in python and i am trying to open an localhost with write mode
but i got following errors



with io.open('http:\localhost:3000\assets\i18n\locale-ru.json', 'w') as outfile:


IOError: [Errno 22] Invalid argument: 'http:\localhost:3000\assets\i18n\locale-ru.json'



Here is a piece of code:



 with io.open('http://localhost:3000//assets//i18n//locale-ru.json', 'w') as outfile:

  str_ = json.dumps(data_ru,

                    indent=4, sort_keys=True,

                    separators=(',', ': '), ensure_ascii=False)

  outfile.write(to_unicode(str_))





python flask




python flask






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 at 20:04









vencaslac

1,010217




1,010217










asked Nov 12 at 19:40









user987

11




11








  • 1




    Just a note, you have only one slash after `http:`.
    – vishes_shell
    Nov 12 at 19:42










  • with io.open('http:/localhost:3000//assets//i18n//locale-ru.json', 'w') as outfile: IOError: [Errno 22] Invalid argument: 'http:/localhost:3000//assets//i18n//locale-ru.json'
    – user987
    Nov 12 at 19:46










  • still got error
    – user987
    Nov 12 at 19:47














  • 1




    Just a note, you have only one slash after `http:`.
    – vishes_shell
    Nov 12 at 19:42










  • with io.open('http:/localhost:3000//assets//i18n//locale-ru.json', 'w') as outfile: IOError: [Errno 22] Invalid argument: 'http:/localhost:3000//assets//i18n//locale-ru.json'
    – user987
    Nov 12 at 19:46










  • still got error
    – user987
    Nov 12 at 19:47








1




1




Just a note, you have only one slash after `http:`.
– vishes_shell
Nov 12 at 19:42




Just a note, you have only one slash after `http:`.
– vishes_shell
Nov 12 at 19:42












with io.open('http:/localhost:3000//assets//i18n//locale-ru.json', 'w') as outfile: IOError: [Errno 22] Invalid argument: 'http:/localhost:3000//assets//i18n//locale-ru.json'
– user987
Nov 12 at 19:46




with io.open('http:/localhost:3000//assets//i18n//locale-ru.json', 'w') as outfile: IOError: [Errno 22] Invalid argument: 'http:/localhost:3000//assets//i18n//locale-ru.json'
– user987
Nov 12 at 19:46












still got error
– user987
Nov 12 at 19:47




still got error
– user987
Nov 12 at 19:47












1 Answer
1






active

oldest

votes

















up vote
0
down vote













According to the doc, the io.open function only reads a local file given a file path. Considering you're trying to read from a http url, I guess a better tools might be requests






share|improve this answer





















  • getting struggle with reguests documentation, i would really appreciate if you send me with source code
    – user987
    Nov 12 at 20:10










  • what about urllib.urlopen in Python 2.7
    – user987
    Nov 13 at 11:24










  • ` with urllib.urlopen('localhost:3000//assets/i18n//locale-kg.json', 'w') as outfile: str_ = json.dumps(data_kg, indent=4, sort_keys=True, separators=(',', ': '), ensure_ascii=False) outfile.write(to_unicode(str_))`
    – user987
    Nov 13 at 11:25










  • As far as I know, to update a file via HTTP you have to send a POST or a PUT request with a file on your local, just like you upload a file to some website. So if I wanted to update a file via an URL, I would firstly download it to my local, then do changes on it, and finally upload the file back. As for file uploading, you could refer stackoverflow.com/a/26791188/2191173 for details.
    – Old Panda
    Nov 13 at 18:26











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1 Answer
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active

oldest

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oldest

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oldest

votes








up vote
0
down vote













According to the doc, the io.open function only reads a local file given a file path. Considering you're trying to read from a http url, I guess a better tools might be requests






share|improve this answer





















  • getting struggle with reguests documentation, i would really appreciate if you send me with source code
    – user987
    Nov 12 at 20:10










  • what about urllib.urlopen in Python 2.7
    – user987
    Nov 13 at 11:24










  • ` with urllib.urlopen('localhost:3000//assets/i18n//locale-kg.json', 'w') as outfile: str_ = json.dumps(data_kg, indent=4, sort_keys=True, separators=(',', ': '), ensure_ascii=False) outfile.write(to_unicode(str_))`
    – user987
    Nov 13 at 11:25










  • As far as I know, to update a file via HTTP you have to send a POST or a PUT request with a file on your local, just like you upload a file to some website. So if I wanted to update a file via an URL, I would firstly download it to my local, then do changes on it, and finally upload the file back. As for file uploading, you could refer stackoverflow.com/a/26791188/2191173 for details.
    – Old Panda
    Nov 13 at 18:26















up vote
0
down vote













According to the doc, the io.open function only reads a local file given a file path. Considering you're trying to read from a http url, I guess a better tools might be requests






share|improve this answer





















  • getting struggle with reguests documentation, i would really appreciate if you send me with source code
    – user987
    Nov 12 at 20:10










  • what about urllib.urlopen in Python 2.7
    – user987
    Nov 13 at 11:24










  • ` with urllib.urlopen('localhost:3000//assets/i18n//locale-kg.json', 'w') as outfile: str_ = json.dumps(data_kg, indent=4, sort_keys=True, separators=(',', ': '), ensure_ascii=False) outfile.write(to_unicode(str_))`
    – user987
    Nov 13 at 11:25










  • As far as I know, to update a file via HTTP you have to send a POST or a PUT request with a file on your local, just like you upload a file to some website. So if I wanted to update a file via an URL, I would firstly download it to my local, then do changes on it, and finally upload the file back. As for file uploading, you could refer stackoverflow.com/a/26791188/2191173 for details.
    – Old Panda
    Nov 13 at 18:26













up vote
0
down vote










up vote
0
down vote









According to the doc, the io.open function only reads a local file given a file path. Considering you're trying to read from a http url, I guess a better tools might be requests






share|improve this answer












According to the doc, the io.open function only reads a local file given a file path. Considering you're trying to read from a http url, I guess a better tools might be requests







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 12 at 19:44









Old Panda

570621




570621












  • getting struggle with reguests documentation, i would really appreciate if you send me with source code
    – user987
    Nov 12 at 20:10










  • what about urllib.urlopen in Python 2.7
    – user987
    Nov 13 at 11:24










  • ` with urllib.urlopen('localhost:3000//assets/i18n//locale-kg.json', 'w') as outfile: str_ = json.dumps(data_kg, indent=4, sort_keys=True, separators=(',', ': '), ensure_ascii=False) outfile.write(to_unicode(str_))`
    – user987
    Nov 13 at 11:25










  • As far as I know, to update a file via HTTP you have to send a POST or a PUT request with a file on your local, just like you upload a file to some website. So if I wanted to update a file via an URL, I would firstly download it to my local, then do changes on it, and finally upload the file back. As for file uploading, you could refer stackoverflow.com/a/26791188/2191173 for details.
    – Old Panda
    Nov 13 at 18:26


















  • getting struggle with reguests documentation, i would really appreciate if you send me with source code
    – user987
    Nov 12 at 20:10










  • what about urllib.urlopen in Python 2.7
    – user987
    Nov 13 at 11:24










  • ` with urllib.urlopen('localhost:3000//assets/i18n//locale-kg.json', 'w') as outfile: str_ = json.dumps(data_kg, indent=4, sort_keys=True, separators=(',', ': '), ensure_ascii=False) outfile.write(to_unicode(str_))`
    – user987
    Nov 13 at 11:25










  • As far as I know, to update a file via HTTP you have to send a POST or a PUT request with a file on your local, just like you upload a file to some website. So if I wanted to update a file via an URL, I would firstly download it to my local, then do changes on it, and finally upload the file back. As for file uploading, you could refer stackoverflow.com/a/26791188/2191173 for details.
    – Old Panda
    Nov 13 at 18:26
















getting struggle with reguests documentation, i would really appreciate if you send me with source code
– user987
Nov 12 at 20:10




getting struggle with reguests documentation, i would really appreciate if you send me with source code
– user987
Nov 12 at 20:10












what about urllib.urlopen in Python 2.7
– user987
Nov 13 at 11:24




what about urllib.urlopen in Python 2.7
– user987
Nov 13 at 11:24












` with urllib.urlopen('localhost:3000//assets/i18n//locale-kg.json', 'w') as outfile: str_ = json.dumps(data_kg, indent=4, sort_keys=True, separators=(',', ': '), ensure_ascii=False) outfile.write(to_unicode(str_))`
– user987
Nov 13 at 11:25




` with urllib.urlopen('localhost:3000//assets/i18n//locale-kg.json', 'w') as outfile: str_ = json.dumps(data_kg, indent=4, sort_keys=True, separators=(',', ': '), ensure_ascii=False) outfile.write(to_unicode(str_))`
– user987
Nov 13 at 11:25












As far as I know, to update a file via HTTP you have to send a POST or a PUT request with a file on your local, just like you upload a file to some website. So if I wanted to update a file via an URL, I would firstly download it to my local, then do changes on it, and finally upload the file back. As for file uploading, you could refer stackoverflow.com/a/26791188/2191173 for details.
– Old Panda
Nov 13 at 18:26




As far as I know, to update a file via HTTP you have to send a POST or a PUT request with a file on your local, just like you upload a file to some website. So if I wanted to update a file via an URL, I would firstly download it to my local, then do changes on it, and finally upload the file back. As for file uploading, you could refer stackoverflow.com/a/26791188/2191173 for details.
– Old Panda
Nov 13 at 18:26


















 

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