Illustrating permutations as braided group - TiKZ-PGF












3















I would like to illustrate the permutation group using the braid package in TikZ-PGF, such as this image (from Wikipedia):



Permutation



In fact I would like to illustrate the permutation group for N = 3, which should have 6 total configurations. Having followed the example provided, I so far have:



documentclass[tikz]{standalone}
usepackage{pgfplots}
usepackage{braids}

pgfplotsset{compat=newest}

begin{document}

begin{tikzpicture}
braid[style strands={1}{red},style
strands={2}{blue},style strands={3}{green}] (TEST2) at (5,0) s_1
s_3^{-1} s_1 s_2^{−1} s_1 s_2^{−1};
end{tikzpicture}
end{document}


However, I am finding it difficult to understand how to change the ordering. Any help would be appreciated.










share|improve this question




















  • 1





    @marmot, there is a documentation for knots (mirrors.ibiblio.org/CTAN/graphics/pgf/contrib/spath3/knots.pdf) written by the same author as the braids package (An­drew Stacey). The braids don't have any knots, but that's all I know. I'll update the MWE.

    – Sid
    Oct 17 '18 at 2:39











  • @marmot, also pgfplots is required

    – Sid
    Oct 17 '18 at 2:43











  • On my machine it runs without usepackage{pgfplots}.

    – marmot
    Oct 17 '18 at 2:49











  • @Sid, maybe the answer and package from this question: (tex.stackexchange.com/questions/32125/braid-diagrams-in-tikz) could be useful

    – Luis Turcio
    Oct 18 '18 at 17:26
















3















I would like to illustrate the permutation group using the braid package in TikZ-PGF, such as this image (from Wikipedia):



Permutation



In fact I would like to illustrate the permutation group for N = 3, which should have 6 total configurations. Having followed the example provided, I so far have:



documentclass[tikz]{standalone}
usepackage{pgfplots}
usepackage{braids}

pgfplotsset{compat=newest}

begin{document}

begin{tikzpicture}
braid[style strands={1}{red},style
strands={2}{blue},style strands={3}{green}] (TEST2) at (5,0) s_1
s_3^{-1} s_1 s_2^{−1} s_1 s_2^{−1};
end{tikzpicture}
end{document}


However, I am finding it difficult to understand how to change the ordering. Any help would be appreciated.










share|improve this question




















  • 1





    @marmot, there is a documentation for knots (mirrors.ibiblio.org/CTAN/graphics/pgf/contrib/spath3/knots.pdf) written by the same author as the braids package (An­drew Stacey). The braids don't have any knots, but that's all I know. I'll update the MWE.

    – Sid
    Oct 17 '18 at 2:39











  • @marmot, also pgfplots is required

    – Sid
    Oct 17 '18 at 2:43











  • On my machine it runs without usepackage{pgfplots}.

    – marmot
    Oct 17 '18 at 2:49











  • @Sid, maybe the answer and package from this question: (tex.stackexchange.com/questions/32125/braid-diagrams-in-tikz) could be useful

    – Luis Turcio
    Oct 18 '18 at 17:26














3












3








3


1






I would like to illustrate the permutation group using the braid package in TikZ-PGF, such as this image (from Wikipedia):



Permutation



In fact I would like to illustrate the permutation group for N = 3, which should have 6 total configurations. Having followed the example provided, I so far have:



documentclass[tikz]{standalone}
usepackage{pgfplots}
usepackage{braids}

pgfplotsset{compat=newest}

begin{document}

begin{tikzpicture}
braid[style strands={1}{red},style
strands={2}{blue},style strands={3}{green}] (TEST2) at (5,0) s_1
s_3^{-1} s_1 s_2^{−1} s_1 s_2^{−1};
end{tikzpicture}
end{document}


However, I am finding it difficult to understand how to change the ordering. Any help would be appreciated.










share|improve this question
















I would like to illustrate the permutation group using the braid package in TikZ-PGF, such as this image (from Wikipedia):



Permutation



In fact I would like to illustrate the permutation group for N = 3, which should have 6 total configurations. Having followed the example provided, I so far have:



documentclass[tikz]{standalone}
usepackage{pgfplots}
usepackage{braids}

pgfplotsset{compat=newest}

begin{document}

begin{tikzpicture}
braid[style strands={1}{red},style
strands={2}{blue},style strands={3}{green}] (TEST2) at (5,0) s_1
s_3^{-1} s_1 s_2^{−1} s_1 s_2^{−1};
end{tikzpicture}
end{document}


However, I am finding it difficult to understand how to change the ordering. Any help would be appreciated.







tikz-pgf braids






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Oct 17 '18 at 2:43







Sid

















asked Oct 17 '18 at 1:55









SidSid

694314




694314








  • 1





    @marmot, there is a documentation for knots (mirrors.ibiblio.org/CTAN/graphics/pgf/contrib/spath3/knots.pdf) written by the same author as the braids package (An­drew Stacey). The braids don't have any knots, but that's all I know. I'll update the MWE.

    – Sid
    Oct 17 '18 at 2:39











  • @marmot, also pgfplots is required

    – Sid
    Oct 17 '18 at 2:43











  • On my machine it runs without usepackage{pgfplots}.

    – marmot
    Oct 17 '18 at 2:49











  • @Sid, maybe the answer and package from this question: (tex.stackexchange.com/questions/32125/braid-diagrams-in-tikz) could be useful

    – Luis Turcio
    Oct 18 '18 at 17:26














  • 1





    @marmot, there is a documentation for knots (mirrors.ibiblio.org/CTAN/graphics/pgf/contrib/spath3/knots.pdf) written by the same author as the braids package (An­drew Stacey). The braids don't have any knots, but that's all I know. I'll update the MWE.

    – Sid
    Oct 17 '18 at 2:39











  • @marmot, also pgfplots is required

    – Sid
    Oct 17 '18 at 2:43











  • On my machine it runs without usepackage{pgfplots}.

    – marmot
    Oct 17 '18 at 2:49











  • @Sid, maybe the answer and package from this question: (tex.stackexchange.com/questions/32125/braid-diagrams-in-tikz) could be useful

    – Luis Turcio
    Oct 18 '18 at 17:26








1




1





@marmot, there is a documentation for knots (mirrors.ibiblio.org/CTAN/graphics/pgf/contrib/spath3/knots.pdf) written by the same author as the braids package (An­drew Stacey). The braids don't have any knots, but that's all I know. I'll update the MWE.

– Sid
Oct 17 '18 at 2:39





@marmot, there is a documentation for knots (mirrors.ibiblio.org/CTAN/graphics/pgf/contrib/spath3/knots.pdf) written by the same author as the braids package (An­drew Stacey). The braids don't have any knots, but that's all I know. I'll update the MWE.

– Sid
Oct 17 '18 at 2:39













@marmot, also pgfplots is required

– Sid
Oct 17 '18 at 2:43





@marmot, also pgfplots is required

– Sid
Oct 17 '18 at 2:43













On my machine it runs without usepackage{pgfplots}.

– marmot
Oct 17 '18 at 2:49





On my machine it runs without usepackage{pgfplots}.

– marmot
Oct 17 '18 at 2:49













@Sid, maybe the answer and package from this question: (tex.stackexchange.com/questions/32125/braid-diagrams-in-tikz) could be useful

– Luis Turcio
Oct 18 '18 at 17:26





@Sid, maybe the answer and package from this question: (tex.stackexchange.com/questions/32125/braid-diagrams-in-tikz) could be useful

– Luis Turcio
Oct 18 '18 at 17:26










1 Answer
1






active

oldest

votes


















3














My apologies for being a bit late to the party, but here's the permutations of 3 objects represented as braids using the braids package.



documentclass[tikz,border=1cm]{standalone}
%url{https://tex.stackexchange.com/q/455488/86}
usepackage{tikz}
usepackage{braids}

begin{document}

begin{tikzpicture}[
/pgf/braid/.cd,
style strands={1}{red},
style strands={2}{blue},
style strands={3}{green},
number of strands=3
]
braid (identity) at (0,0) 1 1 1;
node at ([yshift=-1cm]identity-rev-2-e) {Identity};

braid (123) at ([xshift=2cm]identity-3-s) 1 s_2^{-1} s_1;
node at ([yshift=-1cm]123-rev-2-e) {((123))};

braid (321) at ([xshift=2cm]123-3-s) 1 s_1^{-1} s_2;
node at ([yshift=-1cm]321-rev-2-e) {((321))};

braid (12) at ([yshift=-2cm]identity-rev-1-e) 1 s_1^{-1} 1;
node at ([yshift=-1cm]12-rev-2-e) {((12))};

braid (23) at ([yshift=-2cm]123-rev-1-e) 1 s_2 1;
node at ([yshift=-1cm]23-rev-2-e) {((23))};

braid (31) at ([yshift=-2cm]321-rev-1-e) s_1^{-1} s_2 s_1^{-1};
node at ([yshift=-1cm]31-rev-2-e) {((31))};


end{tikzpicture}
end{document}


Obviously, I had free choice on the over-under crossings.



Result:



permutations in the braid group






share|improve this answer
























  • I should note that this uses the more recent version of the braids package which isn't as yet available on CTAN (but is on github).

    – Loop Space
    Mar 9 at 10:27











  • Better late than never ;) Is there some user manual? I don't get the syntax for this but it's exactly what I wanted.

    – Sid
    Mar 14 at 3:06











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














My apologies for being a bit late to the party, but here's the permutations of 3 objects represented as braids using the braids package.



documentclass[tikz,border=1cm]{standalone}
%url{https://tex.stackexchange.com/q/455488/86}
usepackage{tikz}
usepackage{braids}

begin{document}

begin{tikzpicture}[
/pgf/braid/.cd,
style strands={1}{red},
style strands={2}{blue},
style strands={3}{green},
number of strands=3
]
braid (identity) at (0,0) 1 1 1;
node at ([yshift=-1cm]identity-rev-2-e) {Identity};

braid (123) at ([xshift=2cm]identity-3-s) 1 s_2^{-1} s_1;
node at ([yshift=-1cm]123-rev-2-e) {((123))};

braid (321) at ([xshift=2cm]123-3-s) 1 s_1^{-1} s_2;
node at ([yshift=-1cm]321-rev-2-e) {((321))};

braid (12) at ([yshift=-2cm]identity-rev-1-e) 1 s_1^{-1} 1;
node at ([yshift=-1cm]12-rev-2-e) {((12))};

braid (23) at ([yshift=-2cm]123-rev-1-e) 1 s_2 1;
node at ([yshift=-1cm]23-rev-2-e) {((23))};

braid (31) at ([yshift=-2cm]321-rev-1-e) s_1^{-1} s_2 s_1^{-1};
node at ([yshift=-1cm]31-rev-2-e) {((31))};


end{tikzpicture}
end{document}


Obviously, I had free choice on the over-under crossings.



Result:



permutations in the braid group






share|improve this answer
























  • I should note that this uses the more recent version of the braids package which isn't as yet available on CTAN (but is on github).

    – Loop Space
    Mar 9 at 10:27











  • Better late than never ;) Is there some user manual? I don't get the syntax for this but it's exactly what I wanted.

    – Sid
    Mar 14 at 3:06
















3














My apologies for being a bit late to the party, but here's the permutations of 3 objects represented as braids using the braids package.



documentclass[tikz,border=1cm]{standalone}
%url{https://tex.stackexchange.com/q/455488/86}
usepackage{tikz}
usepackage{braids}

begin{document}

begin{tikzpicture}[
/pgf/braid/.cd,
style strands={1}{red},
style strands={2}{blue},
style strands={3}{green},
number of strands=3
]
braid (identity) at (0,0) 1 1 1;
node at ([yshift=-1cm]identity-rev-2-e) {Identity};

braid (123) at ([xshift=2cm]identity-3-s) 1 s_2^{-1} s_1;
node at ([yshift=-1cm]123-rev-2-e) {((123))};

braid (321) at ([xshift=2cm]123-3-s) 1 s_1^{-1} s_2;
node at ([yshift=-1cm]321-rev-2-e) {((321))};

braid (12) at ([yshift=-2cm]identity-rev-1-e) 1 s_1^{-1} 1;
node at ([yshift=-1cm]12-rev-2-e) {((12))};

braid (23) at ([yshift=-2cm]123-rev-1-e) 1 s_2 1;
node at ([yshift=-1cm]23-rev-2-e) {((23))};

braid (31) at ([yshift=-2cm]321-rev-1-e) s_1^{-1} s_2 s_1^{-1};
node at ([yshift=-1cm]31-rev-2-e) {((31))};


end{tikzpicture}
end{document}


Obviously, I had free choice on the over-under crossings.



Result:



permutations in the braid group






share|improve this answer
























  • I should note that this uses the more recent version of the braids package which isn't as yet available on CTAN (but is on github).

    – Loop Space
    Mar 9 at 10:27











  • Better late than never ;) Is there some user manual? I don't get the syntax for this but it's exactly what I wanted.

    – Sid
    Mar 14 at 3:06














3












3








3







My apologies for being a bit late to the party, but here's the permutations of 3 objects represented as braids using the braids package.



documentclass[tikz,border=1cm]{standalone}
%url{https://tex.stackexchange.com/q/455488/86}
usepackage{tikz}
usepackage{braids}

begin{document}

begin{tikzpicture}[
/pgf/braid/.cd,
style strands={1}{red},
style strands={2}{blue},
style strands={3}{green},
number of strands=3
]
braid (identity) at (0,0) 1 1 1;
node at ([yshift=-1cm]identity-rev-2-e) {Identity};

braid (123) at ([xshift=2cm]identity-3-s) 1 s_2^{-1} s_1;
node at ([yshift=-1cm]123-rev-2-e) {((123))};

braid (321) at ([xshift=2cm]123-3-s) 1 s_1^{-1} s_2;
node at ([yshift=-1cm]321-rev-2-e) {((321))};

braid (12) at ([yshift=-2cm]identity-rev-1-e) 1 s_1^{-1} 1;
node at ([yshift=-1cm]12-rev-2-e) {((12))};

braid (23) at ([yshift=-2cm]123-rev-1-e) 1 s_2 1;
node at ([yshift=-1cm]23-rev-2-e) {((23))};

braid (31) at ([yshift=-2cm]321-rev-1-e) s_1^{-1} s_2 s_1^{-1};
node at ([yshift=-1cm]31-rev-2-e) {((31))};


end{tikzpicture}
end{document}


Obviously, I had free choice on the over-under crossings.



Result:



permutations in the braid group






share|improve this answer













My apologies for being a bit late to the party, but here's the permutations of 3 objects represented as braids using the braids package.



documentclass[tikz,border=1cm]{standalone}
%url{https://tex.stackexchange.com/q/455488/86}
usepackage{tikz}
usepackage{braids}

begin{document}

begin{tikzpicture}[
/pgf/braid/.cd,
style strands={1}{red},
style strands={2}{blue},
style strands={3}{green},
number of strands=3
]
braid (identity) at (0,0) 1 1 1;
node at ([yshift=-1cm]identity-rev-2-e) {Identity};

braid (123) at ([xshift=2cm]identity-3-s) 1 s_2^{-1} s_1;
node at ([yshift=-1cm]123-rev-2-e) {((123))};

braid (321) at ([xshift=2cm]123-3-s) 1 s_1^{-1} s_2;
node at ([yshift=-1cm]321-rev-2-e) {((321))};

braid (12) at ([yshift=-2cm]identity-rev-1-e) 1 s_1^{-1} 1;
node at ([yshift=-1cm]12-rev-2-e) {((12))};

braid (23) at ([yshift=-2cm]123-rev-1-e) 1 s_2 1;
node at ([yshift=-1cm]23-rev-2-e) {((23))};

braid (31) at ([yshift=-2cm]321-rev-1-e) s_1^{-1} s_2 s_1^{-1};
node at ([yshift=-1cm]31-rev-2-e) {((31))};


end{tikzpicture}
end{document}


Obviously, I had free choice on the over-under crossings.



Result:



permutations in the braid group







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 9 at 10:19









Loop SpaceLoop Space

113k29306609




113k29306609













  • I should note that this uses the more recent version of the braids package which isn't as yet available on CTAN (but is on github).

    – Loop Space
    Mar 9 at 10:27











  • Better late than never ;) Is there some user manual? I don't get the syntax for this but it's exactly what I wanted.

    – Sid
    Mar 14 at 3:06



















  • I should note that this uses the more recent version of the braids package which isn't as yet available on CTAN (but is on github).

    – Loop Space
    Mar 9 at 10:27











  • Better late than never ;) Is there some user manual? I don't get the syntax for this but it's exactly what I wanted.

    – Sid
    Mar 14 at 3:06

















I should note that this uses the more recent version of the braids package which isn't as yet available on CTAN (but is on github).

– Loop Space
Mar 9 at 10:27





I should note that this uses the more recent version of the braids package which isn't as yet available on CTAN (but is on github).

– Loop Space
Mar 9 at 10:27













Better late than never ;) Is there some user manual? I don't get the syntax for this but it's exactly what I wanted.

– Sid
Mar 14 at 3:06





Better late than never ;) Is there some user manual? I don't get the syntax for this but it's exactly what I wanted.

– Sid
Mar 14 at 3:06


















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