Form the 4th dimensional 2nd order T to find its determinant and eigenvalues.












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A 4th dimensional 2nd order tensor is given as
$overline {overline T}=2vec e_1vec f_1+2vec e_2vec f_2+vec e_1vec f_2+vec e_2vec f_1+epsilon:vec e_1vec e_2$ where $vec e_i.vec f_j=delta_{ij}$ and $epsilon$ is 4-D permutation tensor. Also $vec f_3=2vec e_3-vec e_4$ and $vec f_4=vec e_4-vec e_3$ and $epsilon :vec e_1 vec e_2vec e_3vec e_4=5$. How I can define the tensor T so I can find its determinant and eigenvalues?










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    0












    $begingroup$


    A 4th dimensional 2nd order tensor is given as
    $overline {overline T}=2vec e_1vec f_1+2vec e_2vec f_2+vec e_1vec f_2+vec e_2vec f_1+epsilon:vec e_1vec e_2$ where $vec e_i.vec f_j=delta_{ij}$ and $epsilon$ is 4-D permutation tensor. Also $vec f_3=2vec e_3-vec e_4$ and $vec f_4=vec e_4-vec e_3$ and $epsilon :vec e_1 vec e_2vec e_3vec e_4=5$. How I can define the tensor T so I can find its determinant and eigenvalues?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      A 4th dimensional 2nd order tensor is given as
      $overline {overline T}=2vec e_1vec f_1+2vec e_2vec f_2+vec e_1vec f_2+vec e_2vec f_1+epsilon:vec e_1vec e_2$ where $vec e_i.vec f_j=delta_{ij}$ and $epsilon$ is 4-D permutation tensor. Also $vec f_3=2vec e_3-vec e_4$ and $vec f_4=vec e_4-vec e_3$ and $epsilon :vec e_1 vec e_2vec e_3vec e_4=5$. How I can define the tensor T so I can find its determinant and eigenvalues?










      share|cite|improve this question









      $endgroup$




      A 4th dimensional 2nd order tensor is given as
      $overline {overline T}=2vec e_1vec f_1+2vec e_2vec f_2+vec e_1vec f_2+vec e_2vec f_1+epsilon:vec e_1vec e_2$ where $vec e_i.vec f_j=delta_{ij}$ and $epsilon$ is 4-D permutation tensor. Also $vec f_3=2vec e_3-vec e_4$ and $vec f_4=vec e_4-vec e_3$ and $epsilon :vec e_1 vec e_2vec e_3vec e_4=5$. How I can define the tensor T so I can find its determinant and eigenvalues?







      linear-algebra tensors






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      share|cite|improve this question










      asked Dec 8 '18 at 21:02









      Alex ParkerAlex Parker

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