Form the 4th dimensional 2nd order T to find its determinant and eigenvalues.
$begingroup$
A 4th dimensional 2nd order tensor is given as
$overline {overline T}=2vec e_1vec f_1+2vec e_2vec f_2+vec e_1vec f_2+vec e_2vec f_1+epsilon:vec e_1vec e_2$ where $vec e_i.vec f_j=delta_{ij}$ and $epsilon$ is 4-D permutation tensor. Also $vec f_3=2vec e_3-vec e_4$ and $vec f_4=vec e_4-vec e_3$ and $epsilon :vec e_1 vec e_2vec e_3vec e_4=5$. How I can define the tensor T so I can find its determinant and eigenvalues?
linear-algebra tensors
$endgroup$
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$begingroup$
A 4th dimensional 2nd order tensor is given as
$overline {overline T}=2vec e_1vec f_1+2vec e_2vec f_2+vec e_1vec f_2+vec e_2vec f_1+epsilon:vec e_1vec e_2$ where $vec e_i.vec f_j=delta_{ij}$ and $epsilon$ is 4-D permutation tensor. Also $vec f_3=2vec e_3-vec e_4$ and $vec f_4=vec e_4-vec e_3$ and $epsilon :vec e_1 vec e_2vec e_3vec e_4=5$. How I can define the tensor T so I can find its determinant and eigenvalues?
linear-algebra tensors
$endgroup$
add a comment |
$begingroup$
A 4th dimensional 2nd order tensor is given as
$overline {overline T}=2vec e_1vec f_1+2vec e_2vec f_2+vec e_1vec f_2+vec e_2vec f_1+epsilon:vec e_1vec e_2$ where $vec e_i.vec f_j=delta_{ij}$ and $epsilon$ is 4-D permutation tensor. Also $vec f_3=2vec e_3-vec e_4$ and $vec f_4=vec e_4-vec e_3$ and $epsilon :vec e_1 vec e_2vec e_3vec e_4=5$. How I can define the tensor T so I can find its determinant and eigenvalues?
linear-algebra tensors
$endgroup$
A 4th dimensional 2nd order tensor is given as
$overline {overline T}=2vec e_1vec f_1+2vec e_2vec f_2+vec e_1vec f_2+vec e_2vec f_1+epsilon:vec e_1vec e_2$ where $vec e_i.vec f_j=delta_{ij}$ and $epsilon$ is 4-D permutation tensor. Also $vec f_3=2vec e_3-vec e_4$ and $vec f_4=vec e_4-vec e_3$ and $epsilon :vec e_1 vec e_2vec e_3vec e_4=5$. How I can define the tensor T so I can find its determinant and eigenvalues?
linear-algebra tensors
linear-algebra tensors
asked Dec 8 '18 at 21:02
Alex ParkerAlex Parker
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