How do I solve this $z^5 + z^3 = iz^2 + i$
-3
$begingroup$
How can I find out what z is and the zero of this function? $z^5 + z^3 = iz^2 + i$
I tried everything but I cannot solve it...
Thanks in advance!
complex-numbers
asked Dec 9 '18 at 15:19
jamyolivejamyolive
246
$endgroup$
add a comment |
-3
$begingroup$
How can I find out what z is and the zero of this function? $z^5 + z^3 = iz^2 + i$
I tried everything but I cannot solve it...
Thanks in advance!
complex-numbers
asked Dec 9 '18 at 15:19
jamyolivejamyolive
246
$endgroup$
$begingroup$
Is my suggested edit correct?
$endgroup$
– AryanSonwatikar
Dec 9 '18 at 15:24
4
$begingroup$
Hint $z^3(z^2+1)=i(z^2+1)$
$endgroup$
– egreg
Dec 9 '18 at 15:26
add a comment |
-3
-3
-3
$begingroup$
How can I find out what z is and the zero of this function? $z^5 + z^3 = iz^2 + i$
I tried everything but I cannot solve it...
Thanks in advance!
complex-numbers
asked Dec 9 '18 at 15:19
jamyolivejamyolive
246
$endgroup$
How can I find out what z is and the zero of this function? $z^5 + z^3 = iz^2 + i$
I tried everything but I cannot solve it...
Thanks in advance!
complex-numbers
complex-numbers
asked Dec 9 '18 at 15:19
jamyolivejamyolive
246
asked Dec 9 '18 at 15:19
jamyolivejamyolive
246
edited Dec 9 '18 at 15:26
jamyolive
asked Dec 9 '18 at 15:19
jamyolivejamyolive
246
asked Dec 9 '18 at 15:19
jamyolivejamyolive
246
asked Dec 9 '18 at 15:19
jamyolivejamyolive
246
246
$begingroup$
Is my suggested edit correct?
$endgroup$
– AryanSonwatikar
Dec 9 '18 at 15:24
4
$begingroup$
Hint $z^3(z^2+1)=i(z^2+1)$
$endgroup$
– egreg
Dec 9 '18 at 15:26
add a comment |
$begingroup$
Is my suggested edit correct?
$endgroup$
– AryanSonwatikar
Dec 9 '18 at 15:24
4
$begingroup$
Hint $z^3(z^2+1)=i(z^2+1)$
$endgroup$
– egreg
Dec 9 '18 at 15:26
$begingroup$
Is my suggested edit correct?
$endgroup$
– AryanSonwatikar
Dec 9 '18 at 15:24
$begingroup$
Is my suggested edit correct?
$endgroup$
– AryanSonwatikar
Dec 9 '18 at 15:24
4
4
$begingroup$
Hint $z^3(z^2+1)=i(z^2+1)$
$endgroup$
– egreg
Dec 9 '18 at 15:26
$begingroup$
Hint $z^3(z^2+1)=i(z^2+1)$
$endgroup$
– egreg
Dec 9 '18 at 15:26
add a comment |
1 Answer
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$begingroup$
HINT:
$$z^5+z^3-iz^2-i=(z^2+1)(z^3-i)=0$$
answered Dec 9 '18 at 15:42
JJacquelinJJacquelin
45k21855
$endgroup$
add a comment |
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$begingroup$
HINT:
$$z^5+z^3-iz^2-i=(z^2+1)(z^3-i)=0$$
answered Dec 9 '18 at 15:42
JJacquelinJJacquelin
45k21855
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0
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HINT:
$$z^5+z^3-iz^2-i=(z^2+1)(z^3-i)=0$$
answered Dec 9 '18 at 15:42
JJacquelinJJacquelin
45k21855
$endgroup$
add a comment |
0
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$begingroup$
HINT:
$$z^5+z^3-iz^2-i=(z^2+1)(z^3-i)=0$$
answered Dec 9 '18 at 15:42
JJacquelinJJacquelin
45k21855
$endgroup$
HINT:
$$z^5+z^3-iz^2-i=(z^2+1)(z^3-i)=0$$
answered Dec 9 '18 at 15:42
JJacquelinJJacquelin
45k21855
answered Dec 9 '18 at 15:42
JJacquelinJJacquelin
45k21855
answered Dec 9 '18 at 15:42
JJacquelinJJacquelin
45k21855
answered Dec 9 '18 at 15:42
JJacquelinJJacquelin
45k21855
45k21855
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$begingroup$
Is my suggested edit correct?
$endgroup$
– AryanSonwatikar
Dec 9 '18 at 15:24
4
$begingroup$
Hint $z^3(z^2+1)=i(z^2+1)$
$endgroup$
– egreg
Dec 9 '18 at 15:26