Flatten array for properties in nested array of JSON objects using jq

Having JSON with (simplified) Jira data like:

{

    "issues": [

        {

            "key": "TEST-A",

            "fields": { "issuelinks":  }

        },

        {

            "key": "TEST-B",

            "fields": {

                "issuelinks": [

                    { "inwardIssue": { "key": "TEST-1" } },

                    { "outwardIssue": { "key": "TEST-2" } },

                    { "outwardIssue": { "key": "TEST-3" } }

                ]

            }

        }

    ]

}

Would like to get output like:

[

    { "key": "TEST-A", "inward": null, "outward": null },

    { "key": "TEST-B", "inward": ["TEST-1"], "outward": ["TEST-2", "TEST-3"] }

]

Tried (ignoring the inward links for now):

cat data.json | 

jq '.issues | {"key":.key, "outward":.fields.issuelinks.outwardIssue.key }'

But I get:

{ "key": "TEST-B", "outward": "TEST-1" }

{ "key": "TEST-B", "outward": "TEST-2" }

{ "key": "TEST-B", "outward": null }

Note: would expect 1) TEST-A for the last one, 2) TEST-2 and TEST-3 for the first two and would like to 3) have TEST-2 and TEST-3 combined in an array.

Suggestions?

edited Nov 21 '18 at 20:06

peak

34.1k94161

asked Nov 21 '18 at 16:20

wivku

788724

add a comment |

Having JSON with (simplified) Jira data like:

{

    "issues": [

        {

            "key": "TEST-A",

            "fields": { "issuelinks":  }

        },

        {

            "key": "TEST-B",

            "fields": {

                "issuelinks": [

                    { "inwardIssue": { "key": "TEST-1" } },

                    { "outwardIssue": { "key": "TEST-2" } },

                    { "outwardIssue": { "key": "TEST-3" } }

                ]

            }

        }

    ]

}

Would like to get output like:

[

    { "key": "TEST-A", "inward": null, "outward": null },

    { "key": "TEST-B", "inward": ["TEST-1"], "outward": ["TEST-2", "TEST-3"] }

]

Tried (ignoring the inward links for now):

cat data.json | 

jq '.issues | {"key":.key, "outward":.fields.issuelinks.outwardIssue.key }'

But I get:

{ "key": "TEST-B", "outward": "TEST-1" }

{ "key": "TEST-B", "outward": "TEST-2" }

{ "key": "TEST-B", "outward": null }

Note: would expect 1) TEST-A for the last one, 2) TEST-2 and TEST-3 for the first two and would like to 3) have TEST-2 and TEST-3 combined in an array.

Suggestions?

edited Nov 21 '18 at 20:06

peak

34.1k94161

asked Nov 21 '18 at 16:20

wivku

788724

add a comment |

Having JSON with (simplified) Jira data like:

{

    "issues": [

        {

            "key": "TEST-A",

            "fields": { "issuelinks":  }

        },

        {

            "key": "TEST-B",

            "fields": {

                "issuelinks": [

                    { "inwardIssue": { "key": "TEST-1" } },

                    { "outwardIssue": { "key": "TEST-2" } },

                    { "outwardIssue": { "key": "TEST-3" } }

                ]

            }

        }

    ]

}

Would like to get output like:

[

    { "key": "TEST-A", "inward": null, "outward": null },

    { "key": "TEST-B", "inward": ["TEST-1"], "outward": ["TEST-2", "TEST-3"] }

]

Tried (ignoring the inward links for now):

cat data.json | 

jq '.issues | {"key":.key, "outward":.fields.issuelinks.outwardIssue.key }'

But I get:

{ "key": "TEST-B", "outward": "TEST-1" }

{ "key": "TEST-B", "outward": "TEST-2" }

{ "key": "TEST-B", "outward": null }

Note: would expect 1) TEST-A for the last one, 2) TEST-2 and TEST-3 for the first two and would like to 3) have TEST-2 and TEST-3 combined in an array.

Suggestions?

edited Nov 21 '18 at 20:06

peak

34.1k94161

asked Nov 21 '18 at 16:20

wivku

788724

Having JSON with (simplified) Jira data like:

{

    "issues": [

        {

            "key": "TEST-A",

            "fields": { "issuelinks":  }

        },

        {

            "key": "TEST-B",

            "fields": {

                "issuelinks": [

                    { "inwardIssue": { "key": "TEST-1" } },

                    { "outwardIssue": { "key": "TEST-2" } },

                    { "outwardIssue": { "key": "TEST-3" } }

                ]

            }

        }

    ]

}

Would like to get output like:

[

    { "key": "TEST-A", "inward": null, "outward": null },

    { "key": "TEST-B", "inward": ["TEST-1"], "outward": ["TEST-2", "TEST-3"] }

]

Tried (ignoring the inward links for now):

cat data.json | 

jq '.issues | {"key":.key, "outward":.fields.issuelinks.outwardIssue.key }'

But I get:

{ "key": "TEST-B", "outward": "TEST-1" }

{ "key": "TEST-B", "outward": "TEST-2" }

{ "key": "TEST-B", "outward": null }

Note: would expect 1) TEST-A for the last one, 2) TEST-2 and TEST-3 for the first two and would like to 3) have TEST-2 and TEST-3 combined in an array.

Suggestions?

json jq flatten

edited Nov 21 '18 at 20:06

peak

34.1k94161

asked Nov 21 '18 at 16:20

wivku

788724

edited Nov 21 '18 at 20:06

peak

34.1k94161

asked Nov 21 '18 at 16:20

wivku

788724

edited Nov 21 '18 at 20:06

peak

34.1k94161

edited Nov 21 '18 at 20:06

peak

34.1k94161

edited Nov 21 '18 at 20:06

peak

34.1k94161

asked Nov 21 '18 at 16:20

wivku

788724

asked Nov 21 '18 at 16:20

wivku

788724

asked Nov 21 '18 at 16:20

wivku

788724

add a comment |

1 Answer
1

active

oldest

votes

Let's start with a variation of your first attempt:

.issues

 | {key,

   inward: .fields.issuelinks|map(.inwardIssue.key // empty),

   outward: .fields.issuelinks|map(.outwardIssue.key // empty) }

With your example, this produces:

{"key":"TEST-A","inward":,"outward":}

{"key":"TEST-B","inward":["TEST-1"],"outward":["TEST-2","TEST-3"]}

So two repairs are needed to achieve the stated goal:

Produce an array (e.g., by wrapping the above expression in square brackets)

Replace the empty arrays by null.

(2) is dubious but easy to accomplish, e.g. using the helper function defined below.

Solution

def extract(f): map(f // empty) | if length ==0 then null else . end;



.issues

| map(

   {key,

    inward: .fields.issuelinks|extract(.inwardIssue.key),

    outward: .fields.issuelinks|extract(.outwardIssue.key)})

Caveat

If extract should retain null and false values, then its def should be modified accordingly.

edited Nov 21 '18 at 20:03

answered Nov 21 '18 at 19:58

peak

34.1k94161

add a comment |

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1 Answer
1

active

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votes

1 Answer
1

active

oldest

votes

Let's start with a variation of your first attempt:

.issues

 | {key,

   inward: .fields.issuelinks|map(.inwardIssue.key // empty),

   outward: .fields.issuelinks|map(.outwardIssue.key // empty) }

With your example, this produces:

{"key":"TEST-A","inward":,"outward":}

{"key":"TEST-B","inward":["TEST-1"],"outward":["TEST-2","TEST-3"]}

So two repairs are needed to achieve the stated goal:

Produce an array (e.g., by wrapping the above expression in square brackets)

Replace the empty arrays by null.

(2) is dubious but easy to accomplish, e.g. using the helper function defined below.

Solution

def extract(f): map(f // empty) | if length ==0 then null else . end;



.issues

| map(

   {key,

    inward: .fields.issuelinks|extract(.inwardIssue.key),

    outward: .fields.issuelinks|extract(.outwardIssue.key)})

Caveat

If extract should retain null and false values, then its def should be modified accordingly.

edited Nov 21 '18 at 20:03

answered Nov 21 '18 at 19:58

peak

34.1k94161

add a comment |

Let's start with a variation of your first attempt:

.issues

 | {key,

   inward: .fields.issuelinks|map(.inwardIssue.key // empty),

   outward: .fields.issuelinks|map(.outwardIssue.key // empty) }

With your example, this produces:

{"key":"TEST-A","inward":,"outward":}

{"key":"TEST-B","inward":["TEST-1"],"outward":["TEST-2","TEST-3"]}

So two repairs are needed to achieve the stated goal:

Produce an array (e.g., by wrapping the above expression in square brackets)

Replace the empty arrays by null.

(2) is dubious but easy to accomplish, e.g. using the helper function defined below.

Solution

def extract(f): map(f // empty) | if length ==0 then null else . end;



.issues

| map(

   {key,

    inward: .fields.issuelinks|extract(.inwardIssue.key),

    outward: .fields.issuelinks|extract(.outwardIssue.key)})

Caveat

If extract should retain null and false values, then its def should be modified accordingly.

edited Nov 21 '18 at 20:03

answered Nov 21 '18 at 19:58

peak

34.1k94161

add a comment |

Let's start with a variation of your first attempt:

.issues

 | {key,

   inward: .fields.issuelinks|map(.inwardIssue.key // empty),

   outward: .fields.issuelinks|map(.outwardIssue.key // empty) }

With your example, this produces:

{"key":"TEST-A","inward":,"outward":}

{"key":"TEST-B","inward":["TEST-1"],"outward":["TEST-2","TEST-3"]}

So two repairs are needed to achieve the stated goal:

Produce an array (e.g., by wrapping the above expression in square brackets)

Replace the empty arrays by null.

(2) is dubious but easy to accomplish, e.g. using the helper function defined below.

Solution

def extract(f): map(f // empty) | if length ==0 then null else . end;



.issues

| map(

   {key,

    inward: .fields.issuelinks|extract(.inwardIssue.key),

    outward: .fields.issuelinks|extract(.outwardIssue.key)})

Caveat

If extract should retain null and false values, then its def should be modified accordingly.

edited Nov 21 '18 at 20:03

answered Nov 21 '18 at 19:58

peak

34.1k94161

Let's start with a variation of your first attempt:

.issues

 | {key,

   inward: .fields.issuelinks|map(.inwardIssue.key // empty),

   outward: .fields.issuelinks|map(.outwardIssue.key // empty) }

With your example, this produces:

{"key":"TEST-A","inward":,"outward":}

{"key":"TEST-B","inward":["TEST-1"],"outward":["TEST-2","TEST-3"]}

So two repairs are needed to achieve the stated goal:

Produce an array (e.g., by wrapping the above expression in square brackets)

Replace the empty arrays by null.

(2) is dubious but easy to accomplish, e.g. using the helper function defined below.

Solution

def extract(f): map(f // empty) | if length ==0 then null else . end;



.issues

| map(

   {key,

    inward: .fields.issuelinks|extract(.inwardIssue.key),

    outward: .fields.issuelinks|extract(.outwardIssue.key)})

Caveat

If extract should retain null and false values, then its def should be modified accordingly.

edited Nov 21 '18 at 20:03

answered Nov 21 '18 at 19:58

peak

34.1k94161

edited Nov 21 '18 at 20:03

answered Nov 21 '18 at 19:58

peak

34.1k94161

answered Nov 21 '18 at 19:58

peak

34.1k94161

answered Nov 21 '18 at 19:58

peak

34.1k94161

add a comment |

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