Using “like” wildcard in prepared statement

141

I am using prepared statements to execute mysql database queries. And I want to implement a search functionality based on a keyword of sorts.

For that I need to use LIKE keyword, that much I know. And I have also used prepared statements before, but I do not know how to use it with LIKE because from the following code where would I add the 'keyword%'?

Can I directly use it in the pstmt.setString(1, notes) as (1, notes+"%") or something like that. I see a lot of posts on this on the web but no good answer anywhere.

PreparedStatement pstmt = con.prepareStatement(

      "SELECT * FROM analysis WHERE notes like ?");

pstmt.setString(1, notes);

ResultSet rs = pstmt.executeQuery();

edited Jan 21 '12 at 1:34

user806549

asked Nov 23 '11 at 19:28

ssn

93331322

add a comment |

141

I am using prepared statements to execute mysql database queries. And I want to implement a search functionality based on a keyword of sorts.

Can I directly use it in the pstmt.setString(1, notes) as (1, notes+"%") or something like that. I see a lot of posts on this on the web but no good answer anywhere.

PreparedStatement pstmt = con.prepareStatement(

      "SELECT * FROM analysis WHERE notes like ?");

pstmt.setString(1, notes);

ResultSet rs = pstmt.executeQuery();

edited Jan 21 '12 at 1:34

user806549

asked Nov 23 '11 at 19:28

ssn

93331322

add a comment |

141

I am using prepared statements to execute mysql database queries. And I want to implement a search functionality based on a keyword of sorts.

Can I directly use it in the pstmt.setString(1, notes) as (1, notes+"%") or something like that. I see a lot of posts on this on the web but no good answer anywhere.

PreparedStatement pstmt = con.prepareStatement(

      "SELECT * FROM analysis WHERE notes like ?");

pstmt.setString(1, notes);

ResultSet rs = pstmt.executeQuery();

edited Jan 21 '12 at 1:34

user806549

asked Nov 23 '11 at 19:28

ssn

93331322

I am using prepared statements to execute mysql database queries. And I want to implement a search functionality based on a keyword of sorts.

Can I directly use it in the pstmt.setString(1, notes) as (1, notes+"%") or something like that. I see a lot of posts on this on the web but no good answer anywhere.

PreparedStatement pstmt = con.prepareStatement(

      "SELECT * FROM analysis WHERE notes like ?");

pstmt.setString(1, notes);

ResultSet rs = pstmt.executeQuery();

java mysql jdbc prepared-statement

edited Jan 21 '12 at 1:34

user806549

asked Nov 23 '11 at 19:28

ssn

93331322

edited Jan 21 '12 at 1:34

user806549

asked Nov 23 '11 at 19:28

ssn

93331322

edited Jan 21 '12 at 1:34

user806549

edited Jan 21 '12 at 1:34

user806549

edited Jan 21 '12 at 1:34

user806549

asked Nov 23 '11 at 19:28

ssn

93331322

asked Nov 23 '11 at 19:28

ssn

93331322

asked Nov 23 '11 at 19:28

ssn

93331322

add a comment |

5 Answers
5

active

oldest

votes

238

You need to set it in the value itself, not in the prepared statement SQL string.

So, this should do for a prefix-match:

notes = notes

    .replace("!", "!!")

    .replace("%", "!%")

    .replace("_", "!_")

    .replace("[", "![");

PreparedStatement pstmt = con.prepareStatement(

        "SELECT * FROM analysis WHERE notes LIKE ? ESCAPE '!'");

pstmt.setString(1, notes + "%");

or a suffix-match:

pstmt.setString(1, "%" + notes);

or a global match:

pstmt.setString(1, "%" + notes + "%");

edited Dec 23 '15 at 22:23

Alain O'Dea

14.2k13455

answered Nov 23 '11 at 19:35

BalusC

848k29831443217

16

+1 The OP could "set" it in the SQL — as by ... LIKE '%' || ? || '%' or similar — but that's much less flexible.

– pilcrow
Nov 23 '11 at 19:42

how do i do it with NON-CASE SENSITIVE mode? :)

– Alpha Gabriel V. Timbol
Aug 26 '15 at 13:52

1

Non-case-sensitive can still use WHERE UPPER(?) LIKE UPPER(?) when using pstmt.setString(2, "%" + notes + "%")

– Zig
Nov 20 '15 at 17:30

1

@Alain: Thank you. Just wondering, does this apply to all RDBMS the world is aware of? Perhaps '%' || ? || '%' as mentioned in 1st comment was better, after all? I don't have the opportunity to experiment right now.

– BalusC
Dec 23 '15 at 22:47

2

@BalusC this applies to MSSQL, Postgres, and MySQL in my testing. The String being made into a parameter is itself interpreted as a mix of data and control instructions. SQL concatenation occurs before it is interpreted and preserves the vulnerability. The IEEE Center for Secure Design says to Strictly Separate Data and Control Instructions, and Never Process Control Instructions Received from Untrusted Sources.

– Alain O'Dea
Dec 24 '15 at 2:18

|
show 6 more comments

Code it like this:

PreparedStatement pstmt = con.prepareStatement(

    "SELECT * FROM analysis WHERE notes like ?");

pstmt.setString(1, notes + "%");`

Make sure that you DO NOT include the quotes ' ' like below as they will cause an exception.

pstmt.setString(1,"'%"+ notes + "%'");

edited Sep 5 '17 at 12:36

Vlad Schnakovszki

5,08434992

answered Mar 14 '15 at 13:24

The Wedding Wolf

23722

3

Thanks for your answer. You might want to read How do I write a good answer? to maximize the potential of your answers. Correct grammar and spelling as well as a thought out structure helps people to read and understand your intention.

– Markus W Mahlberg
Mar 14 '15 at 14:01

1

Though it sounds like someone won't run into this assumption, it's actually very valid especially when working with Oracle. Thanks for pointing out!

– asgs
Jun 14 '15 at 20:27

add a comment |

PreparedStatement ps = cn.prepareStatement("Select * from Users where User_FirstName LIKE ?");

ps.setString(1, name + '%');

Try this out.

answered Mar 10 '16 at 18:01

Faiz

33525

add a comment |

String fname = "Samu0025";



PreparedStatement ps= conn.prepareStatement("SELECT * FROM Users WHERE User_FirstName LIKE ? ");



ps.setString(1, fname);

edited Jun 13 '18 at 16:15

Young Emil

1,46011124

answered Nov 15 '17 at 13:27

Ram Kumar

111

2

Could you elaborate the answer rather than just giving the answer? See: stackoverflow.com/help/how-to-answer

– Sketchy Coder
Nov 15 '17 at 13:32

add a comment |

-4

String query="select * from test1 where "+selected+" like '%"+SelectedStr+"%';";





PreparedStatement preparedStatement=con.prepareStatement(query);





// where seleced and SelectedStr are String Variables in my program

edited Oct 5 '18 at 3:08

Jayendran

3,34331337

answered Oct 5 '18 at 0:33

mahesh dhote

Unsafe + anti-pattern; downvoted.

– 6infinity8
Oct 12 '18 at 22:12

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f8247970%2fusing-like-wildcard-in-prepared-statement%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

5 Answers
5

active

oldest

votes

5 Answers
5

active

oldest

votes

238

You need to set it in the value itself, not in the prepared statement SQL string.

So, this should do for a prefix-match:

notes = notes

    .replace("!", "!!")

    .replace("%", "!%")

    .replace("_", "!_")

    .replace("[", "![");

PreparedStatement pstmt = con.prepareStatement(

        "SELECT * FROM analysis WHERE notes LIKE ? ESCAPE '!'");

pstmt.setString(1, notes + "%");

or a suffix-match:

pstmt.setString(1, "%" + notes);

or a global match:

pstmt.setString(1, "%" + notes + "%");

edited Dec 23 '15 at 22:23

Alain O'Dea

14.2k13455

answered Nov 23 '11 at 19:35

BalusC

848k29831443217

16

+1 The OP could "set" it in the SQL — as by ... LIKE '%' || ? || '%' or similar — but that's much less flexible.

– pilcrow
Nov 23 '11 at 19:42

how do i do it with NON-CASE SENSITIVE mode? :)

– Alpha Gabriel V. Timbol
Aug 26 '15 at 13:52

1

Non-case-sensitive can still use WHERE UPPER(?) LIKE UPPER(?) when using pstmt.setString(2, "%" + notes + "%")

– Zig
Nov 20 '15 at 17:30

1

@Alain: Thank you. Just wondering, does this apply to all RDBMS the world is aware of? Perhaps '%' || ? || '%' as mentioned in 1st comment was better, after all? I don't have the opportunity to experiment right now.

– BalusC
Dec 23 '15 at 22:47

2

@BalusC this applies to MSSQL, Postgres, and MySQL in my testing. The String being made into a parameter is itself interpreted as a mix of data and control instructions. SQL concatenation occurs before it is interpreted and preserves the vulnerability. The IEEE Center for Secure Design says to Strictly Separate Data and Control Instructions, and Never Process Control Instructions Received from Untrusted Sources.

– Alain O'Dea
Dec 24 '15 at 2:18

|
show 6 more comments

238

You need to set it in the value itself, not in the prepared statement SQL string.

So, this should do for a prefix-match:

notes = notes

    .replace("!", "!!")

    .replace("%", "!%")

    .replace("_", "!_")

    .replace("[", "![");

PreparedStatement pstmt = con.prepareStatement(

        "SELECT * FROM analysis WHERE notes LIKE ? ESCAPE '!'");

pstmt.setString(1, notes + "%");

or a suffix-match:

pstmt.setString(1, "%" + notes);

or a global match:

pstmt.setString(1, "%" + notes + "%");

edited Dec 23 '15 at 22:23

Alain O'Dea

14.2k13455

answered Nov 23 '11 at 19:35

BalusC

848k29831443217

16

+1 The OP could "set" it in the SQL — as by ... LIKE '%' || ? || '%' or similar — but that's much less flexible.

– pilcrow
Nov 23 '11 at 19:42

how do i do it with NON-CASE SENSITIVE mode? :)

– Alpha Gabriel V. Timbol
Aug 26 '15 at 13:52

1

Non-case-sensitive can still use WHERE UPPER(?) LIKE UPPER(?) when using pstmt.setString(2, "%" + notes + "%")

– Zig
Nov 20 '15 at 17:30

1

@Alain: Thank you. Just wondering, does this apply to all RDBMS the world is aware of? Perhaps '%' || ? || '%' as mentioned in 1st comment was better, after all? I don't have the opportunity to experiment right now.

– BalusC
Dec 23 '15 at 22:47

2

@BalusC this applies to MSSQL, Postgres, and MySQL in my testing. The String being made into a parameter is itself interpreted as a mix of data and control instructions. SQL concatenation occurs before it is interpreted and preserves the vulnerability. The IEEE Center for Secure Design says to Strictly Separate Data and Control Instructions, and Never Process Control Instructions Received from Untrusted Sources.

– Alain O'Dea
Dec 24 '15 at 2:18

|
show 6 more comments

238

You need to set it in the value itself, not in the prepared statement SQL string.

So, this should do for a prefix-match:

notes = notes

    .replace("!", "!!")

    .replace("%", "!%")

    .replace("_", "!_")

    .replace("[", "![");

PreparedStatement pstmt = con.prepareStatement(

        "SELECT * FROM analysis WHERE notes LIKE ? ESCAPE '!'");

pstmt.setString(1, notes + "%");

or a suffix-match:

pstmt.setString(1, "%" + notes);

or a global match:

pstmt.setString(1, "%" + notes + "%");

edited Dec 23 '15 at 22:23

Alain O'Dea

14.2k13455

answered Nov 23 '11 at 19:35

BalusC

848k29831443217

You need to set it in the value itself, not in the prepared statement SQL string.

So, this should do for a prefix-match:

notes = notes

    .replace("!", "!!")

    .replace("%", "!%")

    .replace("_", "!_")

    .replace("[", "![");

PreparedStatement pstmt = con.prepareStatement(

        "SELECT * FROM analysis WHERE notes LIKE ? ESCAPE '!'");

pstmt.setString(1, notes + "%");

or a suffix-match:

pstmt.setString(1, "%" + notes);

or a global match:

pstmt.setString(1, "%" + notes + "%");

edited Dec 23 '15 at 22:23

Alain O'Dea

14.2k13455

answered Nov 23 '11 at 19:35

BalusC

848k29831443217

edited Dec 23 '15 at 22:23

Alain O'Dea

14.2k13455

edited Dec 23 '15 at 22:23

Alain O'Dea

14.2k13455

edited Dec 23 '15 at 22:23

Alain O'Dea

14.2k13455

answered Nov 23 '11 at 19:35

BalusC

848k29831443217

answered Nov 23 '11 at 19:35

BalusC

848k29831443217

answered Nov 23 '11 at 19:35

BalusC

848k29831443217

16

+1 The OP could "set" it in the SQL — as by ... LIKE '%' || ? || '%' or similar — but that's much less flexible.

– pilcrow
Nov 23 '11 at 19:42

how do i do it with NON-CASE SENSITIVE mode? :)

– Alpha Gabriel V. Timbol
Aug 26 '15 at 13:52

1

Non-case-sensitive can still use WHERE UPPER(?) LIKE UPPER(?) when using pstmt.setString(2, "%" + notes + "%")

– Zig
Nov 20 '15 at 17:30

1

@Alain: Thank you. Just wondering, does this apply to all RDBMS the world is aware of? Perhaps '%' || ? || '%' as mentioned in 1st comment was better, after all? I don't have the opportunity to experiment right now.

– BalusC
Dec 23 '15 at 22:47

2

@BalusC this applies to MSSQL, Postgres, and MySQL in my testing. The String being made into a parameter is itself interpreted as a mix of data and control instructions. SQL concatenation occurs before it is interpreted and preserves the vulnerability. The IEEE Center for Secure Design says to Strictly Separate Data and Control Instructions, and Never Process Control Instructions Received from Untrusted Sources.

– Alain O'Dea
Dec 24 '15 at 2:18

|
show 6 more comments

16

+1 The OP could "set" it in the SQL — as by ... LIKE '%' || ? || '%' or similar — but that's much less flexible.

– pilcrow
Nov 23 '11 at 19:42

how do i do it with NON-CASE SENSITIVE mode? :)

– Alpha Gabriel V. Timbol
Aug 26 '15 at 13:52

1

Non-case-sensitive can still use WHERE UPPER(?) LIKE UPPER(?) when using pstmt.setString(2, "%" + notes + "%")

– Zig
Nov 20 '15 at 17:30

1

@Alain: Thank you. Just wondering, does this apply to all RDBMS the world is aware of? Perhaps '%' || ? || '%' as mentioned in 1st comment was better, after all? I don't have the opportunity to experiment right now.

– BalusC
Dec 23 '15 at 22:47

2

@BalusC this applies to MSSQL, Postgres, and MySQL in my testing. The String being made into a parameter is itself interpreted as a mix of data and control instructions. SQL concatenation occurs before it is interpreted and preserves the vulnerability. The IEEE Center for Secure Design says to Strictly Separate Data and Control Instructions, and Never Process Control Instructions Received from Untrusted Sources.

– Alain O'Dea
Dec 24 '15 at 2:18

+1 The OP could "set" it in the SQL — as by ... LIKE '%' || ? || '%' or similar — but that's much less flexible.

– pilcrow
Nov 23 '11 at 19:42

how do i do it with NON-CASE SENSITIVE mode? :)

– Alpha Gabriel V. Timbol
Aug 26 '15 at 13:52

Non-case-sensitive can still use WHERE UPPER(?) LIKE UPPER(?) when using pstmt.setString(2, "%" + notes + "%")

– Zig
Nov 20 '15 at 17:30

@Alain: Thank you. Just wondering, does this apply to all RDBMS the world is aware of? Perhaps '%' || ? || '%' as mentioned in 1st comment was better, after all? I don't have the opportunity to experiment right now.

– BalusC
Dec 23 '15 at 22:47

@BalusC this applies to MSSQL, Postgres, and MySQL in my testing. The String being made into a parameter is itself interpreted as a mix of data and control instructions. SQL concatenation occurs before it is interpreted and preserves the vulnerability. The IEEE Center for Secure Design says to Strictly Separate Data and Control Instructions, and Never Process Control Instructions Received from Untrusted Sources.

– Alain O'Dea
Dec 24 '15 at 2:18

|
show 6 more comments

Code it like this:

PreparedStatement pstmt = con.prepareStatement(

    "SELECT * FROM analysis WHERE notes like ?");

pstmt.setString(1, notes + "%");`

Make sure that you DO NOT include the quotes ' ' like below as they will cause an exception.

pstmt.setString(1,"'%"+ notes + "%'");

edited Sep 5 '17 at 12:36

Vlad Schnakovszki

5,08434992

answered Mar 14 '15 at 13:24

The Wedding Wolf

23722

3

Thanks for your answer. You might want to read How do I write a good answer? to maximize the potential of your answers. Correct grammar and spelling as well as a thought out structure helps people to read and understand your intention.

– Markus W Mahlberg
Mar 14 '15 at 14:01

1

Though it sounds like someone won't run into this assumption, it's actually very valid especially when working with Oracle. Thanks for pointing out!

– asgs
Jun 14 '15 at 20:27

add a comment |

Code it like this:

PreparedStatement pstmt = con.prepareStatement(

    "SELECT * FROM analysis WHERE notes like ?");

pstmt.setString(1, notes + "%");`

Make sure that you DO NOT include the quotes ' ' like below as they will cause an exception.

pstmt.setString(1,"'%"+ notes + "%'");

edited Sep 5 '17 at 12:36

Vlad Schnakovszki

5,08434992

answered Mar 14 '15 at 13:24

The Wedding Wolf

23722

3

Thanks for your answer. You might want to read How do I write a good answer? to maximize the potential of your answers. Correct grammar and spelling as well as a thought out structure helps people to read and understand your intention.

– Markus W Mahlberg
Mar 14 '15 at 14:01

1

Though it sounds like someone won't run into this assumption, it's actually very valid especially when working with Oracle. Thanks for pointing out!

– asgs
Jun 14 '15 at 20:27

add a comment |

Code it like this:

PreparedStatement pstmt = con.prepareStatement(

    "SELECT * FROM analysis WHERE notes like ?");

pstmt.setString(1, notes + "%");`

Make sure that you DO NOT include the quotes ' ' like below as they will cause an exception.

pstmt.setString(1,"'%"+ notes + "%'");

edited Sep 5 '17 at 12:36

Vlad Schnakovszki

5,08434992

answered Mar 14 '15 at 13:24

The Wedding Wolf

23722

Code it like this:

PreparedStatement pstmt = con.prepareStatement(

    "SELECT * FROM analysis WHERE notes like ?");

pstmt.setString(1, notes + "%");`

Make sure that you DO NOT include the quotes ' ' like below as they will cause an exception.

pstmt.setString(1,"'%"+ notes + "%'");

edited Sep 5 '17 at 12:36

Vlad Schnakovszki

5,08434992

answered Mar 14 '15 at 13:24

The Wedding Wolf

23722

edited Sep 5 '17 at 12:36

Vlad Schnakovszki

5,08434992

edited Sep 5 '17 at 12:36

Vlad Schnakovszki

5,08434992

edited Sep 5 '17 at 12:36

Vlad Schnakovszki

5,08434992

answered Mar 14 '15 at 13:24

The Wedding Wolf

23722

answered Mar 14 '15 at 13:24

The Wedding Wolf

23722

answered Mar 14 '15 at 13:24

The Wedding Wolf

23722

3

Thanks for your answer. You might want to read How do I write a good answer? to maximize the potential of your answers. Correct grammar and spelling as well as a thought out structure helps people to read and understand your intention.

– Markus W Mahlberg
Mar 14 '15 at 14:01

1

Though it sounds like someone won't run into this assumption, it's actually very valid especially when working with Oracle. Thanks for pointing out!

– asgs
Jun 14 '15 at 20:27

add a comment |

3

Thanks for your answer. You might want to read How do I write a good answer? to maximize the potential of your answers. Correct grammar and spelling as well as a thought out structure helps people to read and understand your intention.

– Markus W Mahlberg
Mar 14 '15 at 14:01

1

Though it sounds like someone won't run into this assumption, it's actually very valid especially when working with Oracle. Thanks for pointing out!

– asgs
Jun 14 '15 at 20:27

Thanks for your answer. You might want to read How do I write a good answer? to maximize the potential of your answers. Correct grammar and spelling as well as a thought out structure helps people to read and understand your intention.

– Markus W Mahlberg
Mar 14 '15 at 14:01

Though it sounds like someone won't run into this assumption, it's actually very valid especially when working with Oracle. Thanks for pointing out!

– asgs
Jun 14 '15 at 20:27

add a comment |

PreparedStatement ps = cn.prepareStatement("Select * from Users where User_FirstName LIKE ?");

ps.setString(1, name + '%');

Try this out.

answered Mar 10 '16 at 18:01

Faiz

33525

add a comment |

PreparedStatement ps = cn.prepareStatement("Select * from Users where User_FirstName LIKE ?");

ps.setString(1, name + '%');

Try this out.

answered Mar 10 '16 at 18:01

Faiz

33525

add a comment |

PreparedStatement ps = cn.prepareStatement("Select * from Users where User_FirstName LIKE ?");

ps.setString(1, name + '%');

Try this out.

answered Mar 10 '16 at 18:01

Faiz

33525

PreparedStatement ps = cn.prepareStatement("Select * from Users where User_FirstName LIKE ?");

ps.setString(1, name + '%');

Try this out.

answered Mar 10 '16 at 18:01

Faiz

33525

answered Mar 10 '16 at 18:01

Faiz

33525

answered Mar 10 '16 at 18:01

Faiz

33525

answered Mar 10 '16 at 18:01

Faiz

33525

add a comment |

String fname = "Samu0025";



PreparedStatement ps= conn.prepareStatement("SELECT * FROM Users WHERE User_FirstName LIKE ? ");



ps.setString(1, fname);

edited Jun 13 '18 at 16:15

Young Emil

1,46011124

answered Nov 15 '17 at 13:27

Ram Kumar

111

2

Could you elaborate the answer rather than just giving the answer? See: stackoverflow.com/help/how-to-answer

– Sketchy Coder
Nov 15 '17 at 13:32

add a comment |

String fname = "Samu0025";



PreparedStatement ps= conn.prepareStatement("SELECT * FROM Users WHERE User_FirstName LIKE ? ");



ps.setString(1, fname);

edited Jun 13 '18 at 16:15

Young Emil

1,46011124

answered Nov 15 '17 at 13:27

Ram Kumar

111

2

Could you elaborate the answer rather than just giving the answer? See: stackoverflow.com/help/how-to-answer

– Sketchy Coder
Nov 15 '17 at 13:32

add a comment |

String fname = "Samu0025";



PreparedStatement ps= conn.prepareStatement("SELECT * FROM Users WHERE User_FirstName LIKE ? ");



ps.setString(1, fname);

edited Jun 13 '18 at 16:15

Young Emil

1,46011124

answered Nov 15 '17 at 13:27

Ram Kumar

111

String fname = "Samu0025";



PreparedStatement ps= conn.prepareStatement("SELECT * FROM Users WHERE User_FirstName LIKE ? ");



ps.setString(1, fname);

edited Jun 13 '18 at 16:15

Young Emil

1,46011124

answered Nov 15 '17 at 13:27

Ram Kumar

111

edited Jun 13 '18 at 16:15

Young Emil

1,46011124

edited Jun 13 '18 at 16:15

Young Emil

1,46011124

edited Jun 13 '18 at 16:15

Young Emil

1,46011124

answered Nov 15 '17 at 13:27

Ram Kumar

111

answered Nov 15 '17 at 13:27

Ram Kumar

111

answered Nov 15 '17 at 13:27

Ram Kumar

111

2

Could you elaborate the answer rather than just giving the answer? See: stackoverflow.com/help/how-to-answer

– Sketchy Coder
Nov 15 '17 at 13:32

add a comment |

2

Could you elaborate the answer rather than just giving the answer? See: stackoverflow.com/help/how-to-answer

– Sketchy Coder
Nov 15 '17 at 13:32

Could you elaborate the answer rather than just giving the answer? See: stackoverflow.com/help/how-to-answer

– Sketchy Coder
Nov 15 '17 at 13:32

add a comment |

-4

String query="select * from test1 where "+selected+" like '%"+SelectedStr+"%';";





PreparedStatement preparedStatement=con.prepareStatement(query);





// where seleced and SelectedStr are String Variables in my program

edited Oct 5 '18 at 3:08

Jayendran

3,34331337

answered Oct 5 '18 at 0:33

mahesh dhote

Unsafe + anti-pattern; downvoted.

– 6infinity8
Oct 12 '18 at 22:12

add a comment |

-4

String query="select * from test1 where "+selected+" like '%"+SelectedStr+"%';";





PreparedStatement preparedStatement=con.prepareStatement(query);





// where seleced and SelectedStr are String Variables in my program

edited Oct 5 '18 at 3:08

Jayendran

3,34331337

answered Oct 5 '18 at 0:33

mahesh dhote

Unsafe + anti-pattern; downvoted.

– 6infinity8
Oct 12 '18 at 22:12

add a comment |

-4

String query="select * from test1 where "+selected+" like '%"+SelectedStr+"%';";





PreparedStatement preparedStatement=con.prepareStatement(query);





// where seleced and SelectedStr are String Variables in my program

edited Oct 5 '18 at 3:08

Jayendran

3,34331337

answered Oct 5 '18 at 0:33

mahesh dhote

String query="select * from test1 where "+selected+" like '%"+SelectedStr+"%';";





PreparedStatement preparedStatement=con.prepareStatement(query);





// where seleced and SelectedStr are String Variables in my program

edited Oct 5 '18 at 3:08

Jayendran

3,34331337

answered Oct 5 '18 at 0:33

mahesh dhote

edited Oct 5 '18 at 3:08

Jayendran

3,34331337

edited Oct 5 '18 at 3:08

Jayendran

3,34331337

edited Oct 5 '18 at 3:08

Jayendran

3,34331337

answered Oct 5 '18 at 0:33

mahesh dhote

answered Oct 5 '18 at 0:33

mahesh dhote

answered Oct 5 '18 at 0:33

mahesh dhote

Unsafe + anti-pattern; downvoted.

– 6infinity8
Oct 12 '18 at 22:12

add a comment |

Unsafe + anti-pattern; downvoted.

– 6infinity8
Oct 12 '18 at 22:12

Unsafe + anti-pattern; downvoted.

– 6infinity8
Oct 12 '18 at 22:12

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Cfrgtkky