Push array items into another array












737















I have a JavaScript array dataArray which I want to push into a new array newArray. Except I don't want newArray[0] to be dataArray. I want to push in all the items into the new array:



var newArray = ;

newArray.pushValues(dataArray1);
newArray.pushValues(dataArray2);
// ...


or even better:



var newArray = new Array (
dataArray1.values(),
dataArray2.values(),
// ... where values() (or something equivalent) would push the individual values into the array, rather than the array itself
);


So now the new array contains all the values of the individual data arrays. Is there some shorthand like pushValues available so I don't have to iterate over each individual dataArray, adding the items one by one?










share|improve this question

























  • See this url stackoverflow.com/questions/351409/appending-to-array

    – Jakir Hossain
    Jan 10 '16 at 10:50











  • This should be the answer davidwalsh.name/combining-js-arrays

    – starikovs
    Sep 22 '17 at 8:24
















737















I have a JavaScript array dataArray which I want to push into a new array newArray. Except I don't want newArray[0] to be dataArray. I want to push in all the items into the new array:



var newArray = ;

newArray.pushValues(dataArray1);
newArray.pushValues(dataArray2);
// ...


or even better:



var newArray = new Array (
dataArray1.values(),
dataArray2.values(),
// ... where values() (or something equivalent) would push the individual values into the array, rather than the array itself
);


So now the new array contains all the values of the individual data arrays. Is there some shorthand like pushValues available so I don't have to iterate over each individual dataArray, adding the items one by one?










share|improve this question

























  • See this url stackoverflow.com/questions/351409/appending-to-array

    – Jakir Hossain
    Jan 10 '16 at 10:50











  • This should be the answer davidwalsh.name/combining-js-arrays

    – starikovs
    Sep 22 '17 at 8:24














737












737








737


101






I have a JavaScript array dataArray which I want to push into a new array newArray. Except I don't want newArray[0] to be dataArray. I want to push in all the items into the new array:



var newArray = ;

newArray.pushValues(dataArray1);
newArray.pushValues(dataArray2);
// ...


or even better:



var newArray = new Array (
dataArray1.values(),
dataArray2.values(),
// ... where values() (or something equivalent) would push the individual values into the array, rather than the array itself
);


So now the new array contains all the values of the individual data arrays. Is there some shorthand like pushValues available so I don't have to iterate over each individual dataArray, adding the items one by one?










share|improve this question
















I have a JavaScript array dataArray which I want to push into a new array newArray. Except I don't want newArray[0] to be dataArray. I want to push in all the items into the new array:



var newArray = ;

newArray.pushValues(dataArray1);
newArray.pushValues(dataArray2);
// ...


or even better:



var newArray = new Array (
dataArray1.values(),
dataArray2.values(),
// ... where values() (or something equivalent) would push the individual values into the array, rather than the array itself
);


So now the new array contains all the values of the individual data arrays. Is there some shorthand like pushValues available so I don't have to iterate over each individual dataArray, adding the items one by one?







javascript arrays






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Sep 6 '18 at 22:36









Alexander Abakumov

4,53844169




4,53844169










asked Nov 11 '10 at 15:33









bbabba

4,78192525




4,78192525













  • See this url stackoverflow.com/questions/351409/appending-to-array

    – Jakir Hossain
    Jan 10 '16 at 10:50











  • This should be the answer davidwalsh.name/combining-js-arrays

    – starikovs
    Sep 22 '17 at 8:24



















  • See this url stackoverflow.com/questions/351409/appending-to-array

    – Jakir Hossain
    Jan 10 '16 at 10:50











  • This should be the answer davidwalsh.name/combining-js-arrays

    – starikovs
    Sep 22 '17 at 8:24

















See this url stackoverflow.com/questions/351409/appending-to-array

– Jakir Hossain
Jan 10 '16 at 10:50





See this url stackoverflow.com/questions/351409/appending-to-array

– Jakir Hossain
Jan 10 '16 at 10:50













This should be the answer davidwalsh.name/combining-js-arrays

– starikovs
Sep 22 '17 at 8:24





This should be the answer davidwalsh.name/combining-js-arrays

– starikovs
Sep 22 '17 at 8:24












15 Answers
15






active

oldest

votes


















985














Use the concat function, like so:



var arrayA = [1, 2];
var arrayB = [3, 4];
var newArray = arrayA.concat(arrayB);


The value of newArray will be [1, 2, 3, 4] (arrayA and arrayB remain unchanged; concat creates and returns a new array for the result).






share|improve this answer





















  • 5





    A better reference would be: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/… [1]: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/…

    – Jamund Ferguson
    Feb 23 '11 at 5:41








  • 71





    Slow though: jsperf.com/concat-vs-push-apply/10

    – w00t
    Aug 20 '12 at 19:42






  • 11





    I agree that performant execution is very nice. BUT isn't concat exactly for that purpose to concat to arrays? So it should be standard. Or is there other better things to do with concat? And it might be slow only because of bad implementation of the JS engine of the browser or wherever you're using it in? It might be fixed one day. I would choose code maintainability over hacky speed optimizations. Hmm ....

    – Bitterblue
    Jun 10 '16 at 9:04






  • 1





    Also I just benchmarked the situation: concat vs. push.apply. Google Chrome: fast (concat = winner), Opera: fast (concat = winner), IE: slower (concat = winner), Firefox: slow (push.apply = winner, yet 10 times slower than Chrome's concat) ... speak of bad JS engine implementation.

    – Bitterblue
    Jun 10 '16 at 9:25








  • 4





    How is concatenating two arrays the accepted answer for how to push one into another?! Those are two different operations.

    – kaqqao
    Mar 6 '17 at 19:18





















607














Provided your arrays are not huge (see caveat below), you can use the push() method of the array to which you wish to append values. push() can take multiple parameters so you can use its apply() method to pass the array of values to be pushed as a list of function parameters. This has the advantage over using concat() of adding elements to the array in place rather than creating a new array.



However, it seems that for large arrays (of the order of 100,000 members or more), this trick can fail. For such arrays, using a loop is a better approach. See https://stackoverflow.com/a/17368101/96100 for details.



var newArray = ;
newArray.push.apply(newArray, dataArray1);
newArray.push.apply(newArray, dataArray2);


You might want to generalize this into a function:



function pushArray(arr, arr2) {
arr.push.apply(arr, arr2);
}


... or add it to Array's prototype:



Array.prototype.pushArray = function(arr) {
this.push.apply(this, arr);
};

var newArray = ;
newArray.pushArray(dataArray1);
newArray.pushArray(dataArray2);


... or emulate the original push() method by allowing multiple parameters using the fact that concat(), like push(), allows multiple parameters:



Array.prototype.pushArray = function() {
this.push.apply(this, this.concat.apply(, arguments));
};

var newArray = ;
newArray.pushArray(dataArray1, dataArray2);


Here's a loop-based version of the last example, suitable for large arrays and all major browsers, including IE <= 8:



Array.prototype.pushArray = function() {
var toPush = this.concat.apply(, arguments);
for (var i = 0, len = toPush.length; i < len; ++i) {
this.push(toPush[i]);
}
};





share|improve this answer





















  • 8





    note: newArray.push.apply(newArray, dataArray1); gives the same as Array.prototype.push.applay(newArray,dataArra1);

    – user669677
    Jul 5 '13 at 11:02













  • Is this compatible with older browsers?

    – Damien Ó Ceallaigh
    Apr 6 '18 at 0:53











  • developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

    – Damien Ó Ceallaigh
    Apr 6 '18 at 0:53






  • 1





    @DamienÓCeallaigh: Yes. This is all compatible with browsers going back to IE 6 and even earlier.

    – Tim Down
    Apr 9 '18 at 11:16











  • This is the epitome of poor programming practices. Array.prototype.concat is not bad, rather it is simply misunderstood and sometimes misused. Under these circumstances, it is only misunderstood, but not misused.

    – Jack Giffin
    Aug 15 '18 at 10:23



















283














I will add one more "future-proof" reply



In ECMAScript 6, you can use the spread operator:



var arr1 = [0, 1, 2];
var arr2 = [3, 4, 5];
arr1.push(...arr2);


Spread operator is not yet included in all major browsers. For the current compatibility, see this (continuously updated) compatibility table.



You can, however, use spread operator with Babel.js.



edit:



See Jack Giffin reply below for more comments on performance. It seems concat is still better and faster than spread operator.






share|improve this answer





















  • 3





    You can also use the spread operator if you are using TypeScript. If you target ES5, it will compile to newArray.apply(newArray, dataArray1).

    – AJ Richardson
    Feb 26 '16 at 21:28






  • 4





    Note: if you need the result in a third array (thus not modifying arr1, as the initial question seemed to require), you can do newArray = [...arr1, ...arr2]

    – dim
    Sep 29 '17 at 19:42











  • Oh I didn't know that. Thanks. I have added an edit comment.

    – Karel Bílek
    Aug 17 '18 at 5:47













  • Similar to how concat would function then, with the bonus of being persistent (mutating the original array).

    – robertmylne
    Sep 1 '18 at 8:37











  • @robertmylne The spread operator obviously does not modify the original array, instead creating a new copy of all the arrays contents desparsed.

    – Jack Giffin
    Nov 20 '18 at 2:44





















134














Found an elegant way from MDN



var vegetables = ['parsnip', 'potato'];
var moreVegs = ['celery', 'beetroot'];

// Merge the second array into the first one
// Equivalent to vegetables.push('celery', 'beetroot');
Array.prototype.push.apply(vegetables, moreVegs);

console.log(vegetables); // ['parsnip', 'potato', 'celery', 'beetroot']


Or you can use the spread operator feature of ES6:



let fruits = [ 'apple', 'banana'];
const moreFruits = [ 'orange', 'plum' ];

fruits.push(...moreFruits); // ["apple", "banana", "orange", "plum"]





share|improve this answer


























  • This is not what the question was asking for. The question is asking for a way to create a new array each time, not modify an old array.

    – Jack Giffin
    Aug 15 '18 at 9:16



















12














var a=new Array('a','b','c');
var b=new Array('d','e','f');
var d=new Array('x','y','z');
var c=a.concat(b,d)


Does that solve your problem ?






share|improve this answer































    12














    The following seems simplest to me:



    var newArray = dataArray1.slice();
    newArray.push.apply(newArray, dataArray2);


    As "push" takes a variable number of arguments, you can use the apply method of the push function to push all of the elements of another array. It constructs
    a call to push using its first argument ("newArray" here) as "this" and the
    elements of the array as the remaining arguments.



    The slice in the first statement gets a copy of the first array, so you don't modify it.



    Update If you are using a version of javascript with slice available, you can simplify the push expression to:



    newArray.push(...dataArray2)





    share|improve this answer





















    • 1





      Is also mentioned here at MDN as an example for "Merging two arrays"

      – Wilt
      Apr 27 '18 at 15:48



















    9














    There are a number of answers talking about Array.prototype.push.apply. Here is a clear example:






    var dataArray1 = [1, 2];
    var dataArray2 = [3, 4, 5];
    var newArray = [ ];
    Array.prototype.push.apply(newArray, dataArray1); // newArray = [1, 2]
    Array.prototype.push.apply(newArray, dataArray2); // newArray = [1, 2, 3, 4, 5]
    console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]





    If you have ES6 syntax:






    var dataArray1 = [1, 2];
    var dataArray2 = [3, 4, 5];
    var newArray = [ ];
    newArray.push(...dataArray1); // newArray = [1, 2]
    newArray.push(...dataArray2); // newArray = [1, 2, 3, 4, 5]
    console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]








    share|improve this answer

































      7














      The function below doesn't have an issue with the length of arrays and performs better than all suggested solutions:



      function pushArray(list, other) {
      var len = other.length;
      var start = list.length;
      list.length = start + len;
      for (var i = 0; i < len; i++ , start++) {
      list[start] = other[i];
      }
      }


      unfortunately, jspref refuses to accept my submissions, so here they are the results using benchmark.js



              Name            |   ops/sec   |  ± %  | runs sampled
      for loop and push | 177506 | 0.92 | 63
      Push Apply | 234280 | 0.77 | 66
      spread operator | 259725 | 0.40 | 67
      set length and for loop | 284223 | 0.41 | 66


      where



      for loop and push is:



          for (var i = 0, l = source.length; i < l; i++) {
      target.push(source[i]);
      }


      Push Apply:



      target.push.apply(target, source);


      spread operator:



          target.push(...source);


      and finally the 'set length and for loop' is the above function






      share|improve this answer
























      • This question is looking for a way to create a new array each time, not modify an existing array.

        – Jack Giffin
        Aug 15 '18 at 9:17



















      7














      With JavaScript ES6, you can use the ... operator as a spread operator which will essentially convert the array into values. Then, you can do something like this:



      const myArray = [1,2,3,4,5];
      const moreData = [6,7,8,9,10];

      const newArray = [
      ...myArray,
      ...moreData,
      ];


      While the syntax is concise, I do not know how this works internally and what the performance implications are on large arrays.






      share|improve this answer





















      • 2





        If you take a look at how babel converts it, you'll see that it should not be any slower than using Array.push.apply technique.

        – emil.c
        Dec 11 '17 at 9:19








      • 1





        @JackGiffin I was just referring to what Ryan mentioned that he doesn't know how it works internally and what are performance implications, I wasn't actually suggesting this approach. In any case, you've done a very good job on your answer, nice research, it's always good to know such details.

        – emil.c
        Nov 22 '18 at 19:50



















      3














      Here's the ES6 way






      var newArray = ;
      let dataArray1 = [1,2,3,4]
      let dataArray2 = [5,6,7,8]
      newArray = [...dataArray1, ...dataArray2]
      console.log(newArray)






      The above method is good to go for most of the cases and the cases it is not please consider concat, like you have hundred thousands of items in arrays.







          let dataArray1 = [1,2,3,4]
      let dataArray2 = [5,6,7,8]
      let newArray = dataArray1.concat(dataArray2);
      console.log(newArray)








      share|improve this answer


























      • Hey budd there was a reason to develop and surely the reason wasn't speed . Speed matters when you have quite large array in that case concat is better

        – Black Mamba
        Nov 20 '18 at 3:37



















      3














      Research And Results



      For the facts, a performance test at jsperf and checking some things in the console are performed. For the research, the website irt.org is used. Below is a collection of all these sources put together plus an example function at the bottom.



      ╔═══════════════╦══════╦═════════════════╦═══════════════╦═════════╦══════════╗
      ║ Method ║Concat║slice&push.apply ║ push.apply x2 ║ ForLoop ║Spread ║
      ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
      ║ mOps/Sec ║179 ║104 ║ 76 ║ 81 ║28 ║
      ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
      ║ Sparse arrays ║YES! ║Only the sliced ║ no ║ Maybe2 ║no ║
      ║ kept sparse ║ ║array (1st arg) ║ ║ ║ ║
      ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
      ║ Support ║MSIE 4║MSIE 5.5 ║ MSIE 5.5 ║ MSIE 4 ║Edge 12 ║
      ║ (source) ║NNav 4║NNav 4.06 ║ NNav 4.06 ║ NNav 3 ║MSIE NNav
      ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
      ║Array-like acts║no ║Only the pushed ║ YES! ║ YES! ║If have ║
      ║like an array ║ ║array (2nd arg) ║ ║ ║iterator1
      ╚═══════════════╩══════╩═════════════════╩═══════════════╩═════════╩══════════╝
      1 If the array-like object does not have a Symbol.iterator property, then trying
      to spread it will throw an exception.
      2 Depends on the code. The following example code "YES" preserves sparseness.


      function mergeCopyTogether(inputOne, inputTwo){
      var oneLen = inputOne.length, twoLen = inputTwo.length;
      var newArr = , newLen = newArr.length = oneLen + twoLen;
      for (var i=0, tmp=inputOne[0]; i !== oneLen; ++i) {
      tmp = inputOne[i];
      if (tmp !== undefined || inputOne.hasOwnProperty(i)) newArr[i] = tmp;
      }
      for (var two=0; i !== newLen; ++i, ++two) {
      tmp = inputTwo[two];
      if (tmp !== undefined || inputTwo.hasOwnProperty(two)) newArr[i] = tmp;
      }
      return newArr;
      }


      As seen above, I would argue that Concat is almost always the way to go for both performance and the ability to retain the sparseness of spare arrays. Then, for array-likes (such as DOMNodeLists like document.body.children), I would recommend using the for loop because it is both the 2nd most performant and the only other method that retains sparse arrays. Below, we will quickly go over what is meant by sparse arrays and array-likes to clear up confusion.



      The Future



      At first, some people may think that this is a fluke and that browser vendors will eventually get around to optimizing Array.prototype.push to be fast enough to beat Array.prototype.concat. WRONG! Array.prototype.concat will always be faster (in principle at least) because it is a simple copy-n-paste over the data. Below is a simplified persuado-visual diagram of what a 32-bit array implementation might look like (please note real implementations are a LOT more complicated)



      Byte ║ Data here
      ═════╬═══════════
      0x00 ║ int nonNumericPropertiesLength = 0x00000000
      0x01 ║ ibid
      0x02 ║ ibid
      0x03 ║ ibid
      0x00 ║ int length = 0x00000001
      0x01 ║ ibid
      0x02 ║ ibid
      0x03 ║ ibid
      0x00 ║ int valueIndex = 0x00000000
      0x01 ║ ibid
      0x02 ║ ibid
      0x03 ║ ibid
      0x00 ║ int valueType = JS_PRIMITIVE_NUMBER
      0x01 ║ ibid
      0x02 ║ ibid
      0x03 ║ ibid
      0x00 ║ uintptr_t valuePointer = 0x38d9eb60 (or whereever it is in memory)
      0x01 ║ ibid
      0x02 ║ ibid
      0x03 ║ ibid


      As seen above, all you need to do to copy something like that is almost as simple as copying it byte for byte. With Array.prototype.push.apply, it is a lot more than a simple copy-n-paste over the data. The ".apply" has to check each index in the array and convert it to a set of arguments before passing it to Array.prototype.push. Then, Array.prototype.push has to additionally allocate more memory each time, and (for some browser implementations) maybe even recalculate some position-lookup data for sparseness.



      An alternative way to think of it is this. The source array one is a large stack of papers stapled together. The source array two is also another large stack of papers. Would it be faster for you to




      1. Go to the store, buy enough paper needed for a copy of each source array. Then put each source array stacks of paper through a copy-machine and staple the resulting two copies together.

      2. Go to the store, buy enough paper for a single copy of the first source array. Then, copy the source array to the new paper by hand, ensuring to fill in any blank sparse spots. Then, go back to the store, buy enough paper for the second source array. Then, go through the second source array and copy it while ensuring no blank gaps in the copy. Then, staple all the copied papers together.


      In the above analogy, option #1 represents Array.prototype.concat while #2 represents Array.prototype.push.apply. Let us test this out with a similar JSperf differing only in that this one tests the methods over sparse arrays, not solid arrays. One can find it right here.



      Therefore, I rest my case that the future of performance for this particular use case lies not in Array.prototype.push, but rather in Array.prototype.concat.



      Clarifications



      Spare Arrays



      When certain members of the array are simply missing. For example:






      // This is just as an example. In actual code, 
      // do not mix different types like this.
      var mySparseArray = ;
      mySparseArray[0] = "foo";
      mySparseArray[10] = undefined;
      mySparseArray[11] = {};
      mySparseArray[12] = 10;
      mySparseArray[17] = "bar";
      console.log("Length: ", mySparseArray.length);
      console.log("0 in it: ", 0 in mySparseArray);
      console.log("arr[0]: ", mySparseArray[0]);
      console.log("10 in it: ", 10 in mySparseArray);
      console.log("arr[10] ", mySparseArray[10]);
      console.log("20 in it: ", 20 in mySparseArray);
      console.log("arr[20]: ", mySparseArray[20]);





      Alternatively, javascript allows you to initialize spare arrays easily.



      var mySparseArray = ["foo",,,,,,,,,,undefined,{},10,,,,,"bar"];


      Array-Likes



      An array-like is an object that has at least a length property, but was not initialized with new Array or ; For example, the below objects are classified as array-like.



      {0: "foo", 1: "bar", length:2}


      document.body.children


      new Uint8Array(3)



      • This is array-like because although it's a(n) (typed) array, coercing it to an array changes the constructor.


      (function(){return arguments})()


      Observe what happens using a method that does coerce array-likes into arrays like slice.






      var slice = Array.prototype.slice;
      // For arrays:
      console.log(slice.call(["not an array-like, rather a real array"]));
      // For array-likes:
      console.log(slice.call({0: "foo", 1: "bar", length:2}));
      console.log(slice.call(document.body.children));
      console.log(slice.call(new Uint8Array(3)));
      console.log(slice.call( function(){return arguments}() ));






      • NOTE: It is bad practice to slice function argument because of performance.


      Observe what happens using a method that does not coerce array-likes into arrays like concat.






      var empty = ;
      // For arrays:
      console.log(empty.concat(["not an array-like, rather a real array"]));
      // For array-likes:
      console.log(empty.concat({0: "foo", 1: "bar", length:2}));
      console.log(empty.concat(document.body.children));
      console.log(empty.concat(new Uint8Array(3)));
      console.log(empty.concat( function(){return arguments}() ));








      share|improve this answer

































        0














        We have two array a and b. the code what did here is array a value is pushed into array b.



        let a = [2, 4, 6, 8, 9, 15]

        function transform(a) {
        let b = ['4', '16', '64']
        a.forEach(function(e) {
        b.push(e.toString());
        });
        return b;
        }

        transform(a)

        [ '4', '16', '64', '2', '4', '6', '8', '9', '15' ]





        share|improve this answer





















        • 1





          Please don't just post code as an answer. Explain what the code does and how it solves the problem.

          – Patrick Hund
          Jun 7 '17 at 18:28



















        -2














        instead of push() function use concat function for IE. example,



        var a=a.concat(a,new Array('amin'));





        share|improve this answer
























        • both are very IE compatible

          – Jack Giffin
          Aug 16 '18 at 8:38



















        -3














        Тhis is a working code and it works fine:



        var els = document.getElementsByTagName('input'), i;
        var invnum = new Array();
        var k = els.length;
        for(i = 0; i < k; i++){invnum.push(new Array(els[i].id,els[i].value))}





        share|improve this answer































          -4














          Most simple:



          var newArray = dataArray1.slice(0);





          share|improve this answer



















          • 1





            This does not cover the problem in the question: concatenating two arrays.

            – frasertweedale
            May 8 '15 at 9:40











          • How does this try to answer the question?

            – user6490459
            Jan 30 at 15:05










          protected by T J Jan 4 '16 at 17:12



          Thank you for your interest in this question.
          Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).



          Would you like to answer one of these unanswered questions instead?














          15 Answers
          15






          active

          oldest

          votes








          15 Answers
          15






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          985














          Use the concat function, like so:



          var arrayA = [1, 2];
          var arrayB = [3, 4];
          var newArray = arrayA.concat(arrayB);


          The value of newArray will be [1, 2, 3, 4] (arrayA and arrayB remain unchanged; concat creates and returns a new array for the result).






          share|improve this answer





















          • 5





            A better reference would be: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/… [1]: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/…

            – Jamund Ferguson
            Feb 23 '11 at 5:41








          • 71





            Slow though: jsperf.com/concat-vs-push-apply/10

            – w00t
            Aug 20 '12 at 19:42






          • 11





            I agree that performant execution is very nice. BUT isn't concat exactly for that purpose to concat to arrays? So it should be standard. Or is there other better things to do with concat? And it might be slow only because of bad implementation of the JS engine of the browser or wherever you're using it in? It might be fixed one day. I would choose code maintainability over hacky speed optimizations. Hmm ....

            – Bitterblue
            Jun 10 '16 at 9:04






          • 1





            Also I just benchmarked the situation: concat vs. push.apply. Google Chrome: fast (concat = winner), Opera: fast (concat = winner), IE: slower (concat = winner), Firefox: slow (push.apply = winner, yet 10 times slower than Chrome's concat) ... speak of bad JS engine implementation.

            – Bitterblue
            Jun 10 '16 at 9:25








          • 4





            How is concatenating two arrays the accepted answer for how to push one into another?! Those are two different operations.

            – kaqqao
            Mar 6 '17 at 19:18


















          985














          Use the concat function, like so:



          var arrayA = [1, 2];
          var arrayB = [3, 4];
          var newArray = arrayA.concat(arrayB);


          The value of newArray will be [1, 2, 3, 4] (arrayA and arrayB remain unchanged; concat creates and returns a new array for the result).






          share|improve this answer





















          • 5





            A better reference would be: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/… [1]: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/…

            – Jamund Ferguson
            Feb 23 '11 at 5:41








          • 71





            Slow though: jsperf.com/concat-vs-push-apply/10

            – w00t
            Aug 20 '12 at 19:42






          • 11





            I agree that performant execution is very nice. BUT isn't concat exactly for that purpose to concat to arrays? So it should be standard. Or is there other better things to do with concat? And it might be slow only because of bad implementation of the JS engine of the browser or wherever you're using it in? It might be fixed one day. I would choose code maintainability over hacky speed optimizations. Hmm ....

            – Bitterblue
            Jun 10 '16 at 9:04






          • 1





            Also I just benchmarked the situation: concat vs. push.apply. Google Chrome: fast (concat = winner), Opera: fast (concat = winner), IE: slower (concat = winner), Firefox: slow (push.apply = winner, yet 10 times slower than Chrome's concat) ... speak of bad JS engine implementation.

            – Bitterblue
            Jun 10 '16 at 9:25








          • 4





            How is concatenating two arrays the accepted answer for how to push one into another?! Those are two different operations.

            – kaqqao
            Mar 6 '17 at 19:18
















          985












          985








          985







          Use the concat function, like so:



          var arrayA = [1, 2];
          var arrayB = [3, 4];
          var newArray = arrayA.concat(arrayB);


          The value of newArray will be [1, 2, 3, 4] (arrayA and arrayB remain unchanged; concat creates and returns a new array for the result).






          share|improve this answer















          Use the concat function, like so:



          var arrayA = [1, 2];
          var arrayB = [3, 4];
          var newArray = arrayA.concat(arrayB);


          The value of newArray will be [1, 2, 3, 4] (arrayA and arrayB remain unchanged; concat creates and returns a new array for the result).







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Apr 22 '14 at 18:15









          Tom Wadley

          98.9k11928




          98.9k11928










          answered Nov 11 '10 at 15:37









          WiseGuyEhWiseGuyEh

          12.1k11620




          12.1k11620








          • 5





            A better reference would be: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/… [1]: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/…

            – Jamund Ferguson
            Feb 23 '11 at 5:41








          • 71





            Slow though: jsperf.com/concat-vs-push-apply/10

            – w00t
            Aug 20 '12 at 19:42






          • 11





            I agree that performant execution is very nice. BUT isn't concat exactly for that purpose to concat to arrays? So it should be standard. Or is there other better things to do with concat? And it might be slow only because of bad implementation of the JS engine of the browser or wherever you're using it in? It might be fixed one day. I would choose code maintainability over hacky speed optimizations. Hmm ....

            – Bitterblue
            Jun 10 '16 at 9:04






          • 1





            Also I just benchmarked the situation: concat vs. push.apply. Google Chrome: fast (concat = winner), Opera: fast (concat = winner), IE: slower (concat = winner), Firefox: slow (push.apply = winner, yet 10 times slower than Chrome's concat) ... speak of bad JS engine implementation.

            – Bitterblue
            Jun 10 '16 at 9:25








          • 4





            How is concatenating two arrays the accepted answer for how to push one into another?! Those are two different operations.

            – kaqqao
            Mar 6 '17 at 19:18
















          • 5





            A better reference would be: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/… [1]: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/…

            – Jamund Ferguson
            Feb 23 '11 at 5:41








          • 71





            Slow though: jsperf.com/concat-vs-push-apply/10

            – w00t
            Aug 20 '12 at 19:42






          • 11





            I agree that performant execution is very nice. BUT isn't concat exactly for that purpose to concat to arrays? So it should be standard. Or is there other better things to do with concat? And it might be slow only because of bad implementation of the JS engine of the browser or wherever you're using it in? It might be fixed one day. I would choose code maintainability over hacky speed optimizations. Hmm ....

            – Bitterblue
            Jun 10 '16 at 9:04






          • 1





            Also I just benchmarked the situation: concat vs. push.apply. Google Chrome: fast (concat = winner), Opera: fast (concat = winner), IE: slower (concat = winner), Firefox: slow (push.apply = winner, yet 10 times slower than Chrome's concat) ... speak of bad JS engine implementation.

            – Bitterblue
            Jun 10 '16 at 9:25








          • 4





            How is concatenating two arrays the accepted answer for how to push one into another?! Those are two different operations.

            – kaqqao
            Mar 6 '17 at 19:18










          5




          5





          A better reference would be: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/… [1]: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/…

          – Jamund Ferguson
          Feb 23 '11 at 5:41







          A better reference would be: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/… [1]: developer.mozilla.org/en/JavaScript/Reference/Global_Objects/…

          – Jamund Ferguson
          Feb 23 '11 at 5:41






          71




          71





          Slow though: jsperf.com/concat-vs-push-apply/10

          – w00t
          Aug 20 '12 at 19:42





          Slow though: jsperf.com/concat-vs-push-apply/10

          – w00t
          Aug 20 '12 at 19:42




          11




          11





          I agree that performant execution is very nice. BUT isn't concat exactly for that purpose to concat to arrays? So it should be standard. Or is there other better things to do with concat? And it might be slow only because of bad implementation of the JS engine of the browser or wherever you're using it in? It might be fixed one day. I would choose code maintainability over hacky speed optimizations. Hmm ....

          – Bitterblue
          Jun 10 '16 at 9:04





          I agree that performant execution is very nice. BUT isn't concat exactly for that purpose to concat to arrays? So it should be standard. Or is there other better things to do with concat? And it might be slow only because of bad implementation of the JS engine of the browser or wherever you're using it in? It might be fixed one day. I would choose code maintainability over hacky speed optimizations. Hmm ....

          – Bitterblue
          Jun 10 '16 at 9:04




          1




          1





          Also I just benchmarked the situation: concat vs. push.apply. Google Chrome: fast (concat = winner), Opera: fast (concat = winner), IE: slower (concat = winner), Firefox: slow (push.apply = winner, yet 10 times slower than Chrome's concat) ... speak of bad JS engine implementation.

          – Bitterblue
          Jun 10 '16 at 9:25







          Also I just benchmarked the situation: concat vs. push.apply. Google Chrome: fast (concat = winner), Opera: fast (concat = winner), IE: slower (concat = winner), Firefox: slow (push.apply = winner, yet 10 times slower than Chrome's concat) ... speak of bad JS engine implementation.

          – Bitterblue
          Jun 10 '16 at 9:25






          4




          4





          How is concatenating two arrays the accepted answer for how to push one into another?! Those are two different operations.

          – kaqqao
          Mar 6 '17 at 19:18







          How is concatenating two arrays the accepted answer for how to push one into another?! Those are two different operations.

          – kaqqao
          Mar 6 '17 at 19:18















          607














          Provided your arrays are not huge (see caveat below), you can use the push() method of the array to which you wish to append values. push() can take multiple parameters so you can use its apply() method to pass the array of values to be pushed as a list of function parameters. This has the advantage over using concat() of adding elements to the array in place rather than creating a new array.



          However, it seems that for large arrays (of the order of 100,000 members or more), this trick can fail. For such arrays, using a loop is a better approach. See https://stackoverflow.com/a/17368101/96100 for details.



          var newArray = ;
          newArray.push.apply(newArray, dataArray1);
          newArray.push.apply(newArray, dataArray2);


          You might want to generalize this into a function:



          function pushArray(arr, arr2) {
          arr.push.apply(arr, arr2);
          }


          ... or add it to Array's prototype:



          Array.prototype.pushArray = function(arr) {
          this.push.apply(this, arr);
          };

          var newArray = ;
          newArray.pushArray(dataArray1);
          newArray.pushArray(dataArray2);


          ... or emulate the original push() method by allowing multiple parameters using the fact that concat(), like push(), allows multiple parameters:



          Array.prototype.pushArray = function() {
          this.push.apply(this, this.concat.apply(, arguments));
          };

          var newArray = ;
          newArray.pushArray(dataArray1, dataArray2);


          Here's a loop-based version of the last example, suitable for large arrays and all major browsers, including IE <= 8:



          Array.prototype.pushArray = function() {
          var toPush = this.concat.apply(, arguments);
          for (var i = 0, len = toPush.length; i < len; ++i) {
          this.push(toPush[i]);
          }
          };





          share|improve this answer





















          • 8





            note: newArray.push.apply(newArray, dataArray1); gives the same as Array.prototype.push.applay(newArray,dataArra1);

            – user669677
            Jul 5 '13 at 11:02













          • Is this compatible with older browsers?

            – Damien Ó Ceallaigh
            Apr 6 '18 at 0:53











          • developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

            – Damien Ó Ceallaigh
            Apr 6 '18 at 0:53






          • 1





            @DamienÓCeallaigh: Yes. This is all compatible with browsers going back to IE 6 and even earlier.

            – Tim Down
            Apr 9 '18 at 11:16











          • This is the epitome of poor programming practices. Array.prototype.concat is not bad, rather it is simply misunderstood and sometimes misused. Under these circumstances, it is only misunderstood, but not misused.

            – Jack Giffin
            Aug 15 '18 at 10:23
















          607














          Provided your arrays are not huge (see caveat below), you can use the push() method of the array to which you wish to append values. push() can take multiple parameters so you can use its apply() method to pass the array of values to be pushed as a list of function parameters. This has the advantage over using concat() of adding elements to the array in place rather than creating a new array.



          However, it seems that for large arrays (of the order of 100,000 members or more), this trick can fail. For such arrays, using a loop is a better approach. See https://stackoverflow.com/a/17368101/96100 for details.



          var newArray = ;
          newArray.push.apply(newArray, dataArray1);
          newArray.push.apply(newArray, dataArray2);


          You might want to generalize this into a function:



          function pushArray(arr, arr2) {
          arr.push.apply(arr, arr2);
          }


          ... or add it to Array's prototype:



          Array.prototype.pushArray = function(arr) {
          this.push.apply(this, arr);
          };

          var newArray = ;
          newArray.pushArray(dataArray1);
          newArray.pushArray(dataArray2);


          ... or emulate the original push() method by allowing multiple parameters using the fact that concat(), like push(), allows multiple parameters:



          Array.prototype.pushArray = function() {
          this.push.apply(this, this.concat.apply(, arguments));
          };

          var newArray = ;
          newArray.pushArray(dataArray1, dataArray2);


          Here's a loop-based version of the last example, suitable for large arrays and all major browsers, including IE <= 8:



          Array.prototype.pushArray = function() {
          var toPush = this.concat.apply(, arguments);
          for (var i = 0, len = toPush.length; i < len; ++i) {
          this.push(toPush[i]);
          }
          };





          share|improve this answer





















          • 8





            note: newArray.push.apply(newArray, dataArray1); gives the same as Array.prototype.push.applay(newArray,dataArra1);

            – user669677
            Jul 5 '13 at 11:02













          • Is this compatible with older browsers?

            – Damien Ó Ceallaigh
            Apr 6 '18 at 0:53











          • developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

            – Damien Ó Ceallaigh
            Apr 6 '18 at 0:53






          • 1





            @DamienÓCeallaigh: Yes. This is all compatible with browsers going back to IE 6 and even earlier.

            – Tim Down
            Apr 9 '18 at 11:16











          • This is the epitome of poor programming practices. Array.prototype.concat is not bad, rather it is simply misunderstood and sometimes misused. Under these circumstances, it is only misunderstood, but not misused.

            – Jack Giffin
            Aug 15 '18 at 10:23














          607












          607








          607







          Provided your arrays are not huge (see caveat below), you can use the push() method of the array to which you wish to append values. push() can take multiple parameters so you can use its apply() method to pass the array of values to be pushed as a list of function parameters. This has the advantage over using concat() of adding elements to the array in place rather than creating a new array.



          However, it seems that for large arrays (of the order of 100,000 members or more), this trick can fail. For such arrays, using a loop is a better approach. See https://stackoverflow.com/a/17368101/96100 for details.



          var newArray = ;
          newArray.push.apply(newArray, dataArray1);
          newArray.push.apply(newArray, dataArray2);


          You might want to generalize this into a function:



          function pushArray(arr, arr2) {
          arr.push.apply(arr, arr2);
          }


          ... or add it to Array's prototype:



          Array.prototype.pushArray = function(arr) {
          this.push.apply(this, arr);
          };

          var newArray = ;
          newArray.pushArray(dataArray1);
          newArray.pushArray(dataArray2);


          ... or emulate the original push() method by allowing multiple parameters using the fact that concat(), like push(), allows multiple parameters:



          Array.prototype.pushArray = function() {
          this.push.apply(this, this.concat.apply(, arguments));
          };

          var newArray = ;
          newArray.pushArray(dataArray1, dataArray2);


          Here's a loop-based version of the last example, suitable for large arrays and all major browsers, including IE <= 8:



          Array.prototype.pushArray = function() {
          var toPush = this.concat.apply(, arguments);
          for (var i = 0, len = toPush.length; i < len; ++i) {
          this.push(toPush[i]);
          }
          };





          share|improve this answer















          Provided your arrays are not huge (see caveat below), you can use the push() method of the array to which you wish to append values. push() can take multiple parameters so you can use its apply() method to pass the array of values to be pushed as a list of function parameters. This has the advantage over using concat() of adding elements to the array in place rather than creating a new array.



          However, it seems that for large arrays (of the order of 100,000 members or more), this trick can fail. For such arrays, using a loop is a better approach. See https://stackoverflow.com/a/17368101/96100 for details.



          var newArray = ;
          newArray.push.apply(newArray, dataArray1);
          newArray.push.apply(newArray, dataArray2);


          You might want to generalize this into a function:



          function pushArray(arr, arr2) {
          arr.push.apply(arr, arr2);
          }


          ... or add it to Array's prototype:



          Array.prototype.pushArray = function(arr) {
          this.push.apply(this, arr);
          };

          var newArray = ;
          newArray.pushArray(dataArray1);
          newArray.pushArray(dataArray2);


          ... or emulate the original push() method by allowing multiple parameters using the fact that concat(), like push(), allows multiple parameters:



          Array.prototype.pushArray = function() {
          this.push.apply(this, this.concat.apply(, arguments));
          };

          var newArray = ;
          newArray.pushArray(dataArray1, dataArray2);


          Here's a loop-based version of the last example, suitable for large arrays and all major browsers, including IE <= 8:



          Array.prototype.pushArray = function() {
          var toPush = this.concat.apply(, arguments);
          for (var i = 0, len = toPush.length; i < len; ++i) {
          this.push(toPush[i]);
          }
          };






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited May 23 '17 at 11:47









          Community

          11




          11










          answered Nov 11 '10 at 15:38









          Tim DownTim Down

          250k56375463




          250k56375463








          • 8





            note: newArray.push.apply(newArray, dataArray1); gives the same as Array.prototype.push.applay(newArray,dataArra1);

            – user669677
            Jul 5 '13 at 11:02













          • Is this compatible with older browsers?

            – Damien Ó Ceallaigh
            Apr 6 '18 at 0:53











          • developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

            – Damien Ó Ceallaigh
            Apr 6 '18 at 0:53






          • 1





            @DamienÓCeallaigh: Yes. This is all compatible with browsers going back to IE 6 and even earlier.

            – Tim Down
            Apr 9 '18 at 11:16











          • This is the epitome of poor programming practices. Array.prototype.concat is not bad, rather it is simply misunderstood and sometimes misused. Under these circumstances, it is only misunderstood, but not misused.

            – Jack Giffin
            Aug 15 '18 at 10:23














          • 8





            note: newArray.push.apply(newArray, dataArray1); gives the same as Array.prototype.push.applay(newArray,dataArra1);

            – user669677
            Jul 5 '13 at 11:02













          • Is this compatible with older browsers?

            – Damien Ó Ceallaigh
            Apr 6 '18 at 0:53











          • developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

            – Damien Ó Ceallaigh
            Apr 6 '18 at 0:53






          • 1





            @DamienÓCeallaigh: Yes. This is all compatible with browsers going back to IE 6 and even earlier.

            – Tim Down
            Apr 9 '18 at 11:16











          • This is the epitome of poor programming practices. Array.prototype.concat is not bad, rather it is simply misunderstood and sometimes misused. Under these circumstances, it is only misunderstood, but not misused.

            – Jack Giffin
            Aug 15 '18 at 10:23








          8




          8





          note: newArray.push.apply(newArray, dataArray1); gives the same as Array.prototype.push.applay(newArray,dataArra1);

          – user669677
          Jul 5 '13 at 11:02







          note: newArray.push.apply(newArray, dataArray1); gives the same as Array.prototype.push.applay(newArray,dataArra1);

          – user669677
          Jul 5 '13 at 11:02















          Is this compatible with older browsers?

          – Damien Ó Ceallaigh
          Apr 6 '18 at 0:53





          Is this compatible with older browsers?

          – Damien Ó Ceallaigh
          Apr 6 '18 at 0:53













          developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

          – Damien Ó Ceallaigh
          Apr 6 '18 at 0:53





          developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

          – Damien Ó Ceallaigh
          Apr 6 '18 at 0:53




          1




          1





          @DamienÓCeallaigh: Yes. This is all compatible with browsers going back to IE 6 and even earlier.

          – Tim Down
          Apr 9 '18 at 11:16





          @DamienÓCeallaigh: Yes. This is all compatible with browsers going back to IE 6 and even earlier.

          – Tim Down
          Apr 9 '18 at 11:16













          This is the epitome of poor programming practices. Array.prototype.concat is not bad, rather it is simply misunderstood and sometimes misused. Under these circumstances, it is only misunderstood, but not misused.

          – Jack Giffin
          Aug 15 '18 at 10:23





          This is the epitome of poor programming practices. Array.prototype.concat is not bad, rather it is simply misunderstood and sometimes misused. Under these circumstances, it is only misunderstood, but not misused.

          – Jack Giffin
          Aug 15 '18 at 10:23











          283














          I will add one more "future-proof" reply



          In ECMAScript 6, you can use the spread operator:



          var arr1 = [0, 1, 2];
          var arr2 = [3, 4, 5];
          arr1.push(...arr2);


          Spread operator is not yet included in all major browsers. For the current compatibility, see this (continuously updated) compatibility table.



          You can, however, use spread operator with Babel.js.



          edit:



          See Jack Giffin reply below for more comments on performance. It seems concat is still better and faster than spread operator.






          share|improve this answer





















          • 3





            You can also use the spread operator if you are using TypeScript. If you target ES5, it will compile to newArray.apply(newArray, dataArray1).

            – AJ Richardson
            Feb 26 '16 at 21:28






          • 4





            Note: if you need the result in a third array (thus not modifying arr1, as the initial question seemed to require), you can do newArray = [...arr1, ...arr2]

            – dim
            Sep 29 '17 at 19:42











          • Oh I didn't know that. Thanks. I have added an edit comment.

            – Karel Bílek
            Aug 17 '18 at 5:47













          • Similar to how concat would function then, with the bonus of being persistent (mutating the original array).

            – robertmylne
            Sep 1 '18 at 8:37











          • @robertmylne The spread operator obviously does not modify the original array, instead creating a new copy of all the arrays contents desparsed.

            – Jack Giffin
            Nov 20 '18 at 2:44


















          283














          I will add one more "future-proof" reply



          In ECMAScript 6, you can use the spread operator:



          var arr1 = [0, 1, 2];
          var arr2 = [3, 4, 5];
          arr1.push(...arr2);


          Spread operator is not yet included in all major browsers. For the current compatibility, see this (continuously updated) compatibility table.



          You can, however, use spread operator with Babel.js.



          edit:



          See Jack Giffin reply below for more comments on performance. It seems concat is still better and faster than spread operator.






          share|improve this answer





















          • 3





            You can also use the spread operator if you are using TypeScript. If you target ES5, it will compile to newArray.apply(newArray, dataArray1).

            – AJ Richardson
            Feb 26 '16 at 21:28






          • 4





            Note: if you need the result in a third array (thus not modifying arr1, as the initial question seemed to require), you can do newArray = [...arr1, ...arr2]

            – dim
            Sep 29 '17 at 19:42











          • Oh I didn't know that. Thanks. I have added an edit comment.

            – Karel Bílek
            Aug 17 '18 at 5:47













          • Similar to how concat would function then, with the bonus of being persistent (mutating the original array).

            – robertmylne
            Sep 1 '18 at 8:37











          • @robertmylne The spread operator obviously does not modify the original array, instead creating a new copy of all the arrays contents desparsed.

            – Jack Giffin
            Nov 20 '18 at 2:44
















          283












          283








          283







          I will add one more "future-proof" reply



          In ECMAScript 6, you can use the spread operator:



          var arr1 = [0, 1, 2];
          var arr2 = [3, 4, 5];
          arr1.push(...arr2);


          Spread operator is not yet included in all major browsers. For the current compatibility, see this (continuously updated) compatibility table.



          You can, however, use spread operator with Babel.js.



          edit:



          See Jack Giffin reply below for more comments on performance. It seems concat is still better and faster than spread operator.






          share|improve this answer















          I will add one more "future-proof" reply



          In ECMAScript 6, you can use the spread operator:



          var arr1 = [0, 1, 2];
          var arr2 = [3, 4, 5];
          arr1.push(...arr2);


          Spread operator is not yet included in all major browsers. For the current compatibility, see this (continuously updated) compatibility table.



          You can, however, use spread operator with Babel.js.



          edit:



          See Jack Giffin reply below for more comments on performance. It seems concat is still better and faster than spread operator.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Aug 17 '18 at 5:47


























          community wiki





          4 revs, 3 users 70%
          Karel Bílek









          • 3





            You can also use the spread operator if you are using TypeScript. If you target ES5, it will compile to newArray.apply(newArray, dataArray1).

            – AJ Richardson
            Feb 26 '16 at 21:28






          • 4





            Note: if you need the result in a third array (thus not modifying arr1, as the initial question seemed to require), you can do newArray = [...arr1, ...arr2]

            – dim
            Sep 29 '17 at 19:42











          • Oh I didn't know that. Thanks. I have added an edit comment.

            – Karel Bílek
            Aug 17 '18 at 5:47













          • Similar to how concat would function then, with the bonus of being persistent (mutating the original array).

            – robertmylne
            Sep 1 '18 at 8:37











          • @robertmylne The spread operator obviously does not modify the original array, instead creating a new copy of all the arrays contents desparsed.

            – Jack Giffin
            Nov 20 '18 at 2:44
















          • 3





            You can also use the spread operator if you are using TypeScript. If you target ES5, it will compile to newArray.apply(newArray, dataArray1).

            – AJ Richardson
            Feb 26 '16 at 21:28






          • 4





            Note: if you need the result in a third array (thus not modifying arr1, as the initial question seemed to require), you can do newArray = [...arr1, ...arr2]

            – dim
            Sep 29 '17 at 19:42











          • Oh I didn't know that. Thanks. I have added an edit comment.

            – Karel Bílek
            Aug 17 '18 at 5:47













          • Similar to how concat would function then, with the bonus of being persistent (mutating the original array).

            – robertmylne
            Sep 1 '18 at 8:37











          • @robertmylne The spread operator obviously does not modify the original array, instead creating a new copy of all the arrays contents desparsed.

            – Jack Giffin
            Nov 20 '18 at 2:44










          3




          3





          You can also use the spread operator if you are using TypeScript. If you target ES5, it will compile to newArray.apply(newArray, dataArray1).

          – AJ Richardson
          Feb 26 '16 at 21:28





          You can also use the spread operator if you are using TypeScript. If you target ES5, it will compile to newArray.apply(newArray, dataArray1).

          – AJ Richardson
          Feb 26 '16 at 21:28




          4




          4





          Note: if you need the result in a third array (thus not modifying arr1, as the initial question seemed to require), you can do newArray = [...arr1, ...arr2]

          – dim
          Sep 29 '17 at 19:42





          Note: if you need the result in a third array (thus not modifying arr1, as the initial question seemed to require), you can do newArray = [...arr1, ...arr2]

          – dim
          Sep 29 '17 at 19:42













          Oh I didn't know that. Thanks. I have added an edit comment.

          – Karel Bílek
          Aug 17 '18 at 5:47







          Oh I didn't know that. Thanks. I have added an edit comment.

          – Karel Bílek
          Aug 17 '18 at 5:47















          Similar to how concat would function then, with the bonus of being persistent (mutating the original array).

          – robertmylne
          Sep 1 '18 at 8:37





          Similar to how concat would function then, with the bonus of being persistent (mutating the original array).

          – robertmylne
          Sep 1 '18 at 8:37













          @robertmylne The spread operator obviously does not modify the original array, instead creating a new copy of all the arrays contents desparsed.

          – Jack Giffin
          Nov 20 '18 at 2:44







          @robertmylne The spread operator obviously does not modify the original array, instead creating a new copy of all the arrays contents desparsed.

          – Jack Giffin
          Nov 20 '18 at 2:44













          134














          Found an elegant way from MDN



          var vegetables = ['parsnip', 'potato'];
          var moreVegs = ['celery', 'beetroot'];

          // Merge the second array into the first one
          // Equivalent to vegetables.push('celery', 'beetroot');
          Array.prototype.push.apply(vegetables, moreVegs);

          console.log(vegetables); // ['parsnip', 'potato', 'celery', 'beetroot']


          Or you can use the spread operator feature of ES6:



          let fruits = [ 'apple', 'banana'];
          const moreFruits = [ 'orange', 'plum' ];

          fruits.push(...moreFruits); // ["apple", "banana", "orange", "plum"]





          share|improve this answer


























          • This is not what the question was asking for. The question is asking for a way to create a new array each time, not modify an old array.

            – Jack Giffin
            Aug 15 '18 at 9:16
















          134














          Found an elegant way from MDN



          var vegetables = ['parsnip', 'potato'];
          var moreVegs = ['celery', 'beetroot'];

          // Merge the second array into the first one
          // Equivalent to vegetables.push('celery', 'beetroot');
          Array.prototype.push.apply(vegetables, moreVegs);

          console.log(vegetables); // ['parsnip', 'potato', 'celery', 'beetroot']


          Or you can use the spread operator feature of ES6:



          let fruits = [ 'apple', 'banana'];
          const moreFruits = [ 'orange', 'plum' ];

          fruits.push(...moreFruits); // ["apple", "banana", "orange", "plum"]





          share|improve this answer


























          • This is not what the question was asking for. The question is asking for a way to create a new array each time, not modify an old array.

            – Jack Giffin
            Aug 15 '18 at 9:16














          134












          134








          134







          Found an elegant way from MDN



          var vegetables = ['parsnip', 'potato'];
          var moreVegs = ['celery', 'beetroot'];

          // Merge the second array into the first one
          // Equivalent to vegetables.push('celery', 'beetroot');
          Array.prototype.push.apply(vegetables, moreVegs);

          console.log(vegetables); // ['parsnip', 'potato', 'celery', 'beetroot']


          Or you can use the spread operator feature of ES6:



          let fruits = [ 'apple', 'banana'];
          const moreFruits = [ 'orange', 'plum' ];

          fruits.push(...moreFruits); // ["apple", "banana", "orange", "plum"]





          share|improve this answer















          Found an elegant way from MDN



          var vegetables = ['parsnip', 'potato'];
          var moreVegs = ['celery', 'beetroot'];

          // Merge the second array into the first one
          // Equivalent to vegetables.push('celery', 'beetroot');
          Array.prototype.push.apply(vegetables, moreVegs);

          console.log(vegetables); // ['parsnip', 'potato', 'celery', 'beetroot']


          Or you can use the spread operator feature of ES6:



          let fruits = [ 'apple', 'banana'];
          const moreFruits = [ 'orange', 'plum' ];

          fruits.push(...moreFruits); // ["apple", "banana", "orange", "plum"]






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jul 9 '16 at 16:18

























          answered Sep 10 '15 at 21:12









          Believe2014Believe2014

          2,82011833




          2,82011833













          • This is not what the question was asking for. The question is asking for a way to create a new array each time, not modify an old array.

            – Jack Giffin
            Aug 15 '18 at 9:16



















          • This is not what the question was asking for. The question is asking for a way to create a new array each time, not modify an old array.

            – Jack Giffin
            Aug 15 '18 at 9:16

















          This is not what the question was asking for. The question is asking for a way to create a new array each time, not modify an old array.

          – Jack Giffin
          Aug 15 '18 at 9:16





          This is not what the question was asking for. The question is asking for a way to create a new array each time, not modify an old array.

          – Jack Giffin
          Aug 15 '18 at 9:16











          12














          var a=new Array('a','b','c');
          var b=new Array('d','e','f');
          var d=new Array('x','y','z');
          var c=a.concat(b,d)


          Does that solve your problem ?






          share|improve this answer




























            12














            var a=new Array('a','b','c');
            var b=new Array('d','e','f');
            var d=new Array('x','y','z');
            var c=a.concat(b,d)


            Does that solve your problem ?






            share|improve this answer


























              12












              12








              12







              var a=new Array('a','b','c');
              var b=new Array('d','e','f');
              var d=new Array('x','y','z');
              var c=a.concat(b,d)


              Does that solve your problem ?






              share|improve this answer













              var a=new Array('a','b','c');
              var b=new Array('d','e','f');
              var d=new Array('x','y','z');
              var c=a.concat(b,d)


              Does that solve your problem ?







              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Nov 11 '10 at 15:37









              Sébastien VINCENTSébastien VINCENT

              971511




              971511























                  12














                  The following seems simplest to me:



                  var newArray = dataArray1.slice();
                  newArray.push.apply(newArray, dataArray2);


                  As "push" takes a variable number of arguments, you can use the apply method of the push function to push all of the elements of another array. It constructs
                  a call to push using its first argument ("newArray" here) as "this" and the
                  elements of the array as the remaining arguments.



                  The slice in the first statement gets a copy of the first array, so you don't modify it.



                  Update If you are using a version of javascript with slice available, you can simplify the push expression to:



                  newArray.push(...dataArray2)





                  share|improve this answer





















                  • 1





                    Is also mentioned here at MDN as an example for "Merging two arrays"

                    – Wilt
                    Apr 27 '18 at 15:48
















                  12














                  The following seems simplest to me:



                  var newArray = dataArray1.slice();
                  newArray.push.apply(newArray, dataArray2);


                  As "push" takes a variable number of arguments, you can use the apply method of the push function to push all of the elements of another array. It constructs
                  a call to push using its first argument ("newArray" here) as "this" and the
                  elements of the array as the remaining arguments.



                  The slice in the first statement gets a copy of the first array, so you don't modify it.



                  Update If you are using a version of javascript with slice available, you can simplify the push expression to:



                  newArray.push(...dataArray2)





                  share|improve this answer





















                  • 1





                    Is also mentioned here at MDN as an example for "Merging two arrays"

                    – Wilt
                    Apr 27 '18 at 15:48














                  12












                  12








                  12







                  The following seems simplest to me:



                  var newArray = dataArray1.slice();
                  newArray.push.apply(newArray, dataArray2);


                  As "push" takes a variable number of arguments, you can use the apply method of the push function to push all of the elements of another array. It constructs
                  a call to push using its first argument ("newArray" here) as "this" and the
                  elements of the array as the remaining arguments.



                  The slice in the first statement gets a copy of the first array, so you don't modify it.



                  Update If you are using a version of javascript with slice available, you can simplify the push expression to:



                  newArray.push(...dataArray2)





                  share|improve this answer















                  The following seems simplest to me:



                  var newArray = dataArray1.slice();
                  newArray.push.apply(newArray, dataArray2);


                  As "push" takes a variable number of arguments, you can use the apply method of the push function to push all of the elements of another array. It constructs
                  a call to push using its first argument ("newArray" here) as "this" and the
                  elements of the array as the remaining arguments.



                  The slice in the first statement gets a copy of the first array, so you don't modify it.



                  Update If you are using a version of javascript with slice available, you can simplify the push expression to:



                  newArray.push(...dataArray2)






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Mar 19 '18 at 13:58

























                  answered Apr 11 '16 at 4:32









                  shauncshaunc

                  2,7371935




                  2,7371935








                  • 1





                    Is also mentioned here at MDN as an example for "Merging two arrays"

                    – Wilt
                    Apr 27 '18 at 15:48














                  • 1





                    Is also mentioned here at MDN as an example for "Merging two arrays"

                    – Wilt
                    Apr 27 '18 at 15:48








                  1




                  1





                  Is also mentioned here at MDN as an example for "Merging two arrays"

                  – Wilt
                  Apr 27 '18 at 15:48





                  Is also mentioned here at MDN as an example for "Merging two arrays"

                  – Wilt
                  Apr 27 '18 at 15:48











                  9














                  There are a number of answers talking about Array.prototype.push.apply. Here is a clear example:






                  var dataArray1 = [1, 2];
                  var dataArray2 = [3, 4, 5];
                  var newArray = [ ];
                  Array.prototype.push.apply(newArray, dataArray1); // newArray = [1, 2]
                  Array.prototype.push.apply(newArray, dataArray2); // newArray = [1, 2, 3, 4, 5]
                  console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]





                  If you have ES6 syntax:






                  var dataArray1 = [1, 2];
                  var dataArray2 = [3, 4, 5];
                  var newArray = [ ];
                  newArray.push(...dataArray1); // newArray = [1, 2]
                  newArray.push(...dataArray2); // newArray = [1, 2, 3, 4, 5]
                  console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]








                  share|improve this answer






























                    9














                    There are a number of answers talking about Array.prototype.push.apply. Here is a clear example:






                    var dataArray1 = [1, 2];
                    var dataArray2 = [3, 4, 5];
                    var newArray = [ ];
                    Array.prototype.push.apply(newArray, dataArray1); // newArray = [1, 2]
                    Array.prototype.push.apply(newArray, dataArray2); // newArray = [1, 2, 3, 4, 5]
                    console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]





                    If you have ES6 syntax:






                    var dataArray1 = [1, 2];
                    var dataArray2 = [3, 4, 5];
                    var newArray = [ ];
                    newArray.push(...dataArray1); // newArray = [1, 2]
                    newArray.push(...dataArray2); // newArray = [1, 2, 3, 4, 5]
                    console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]








                    share|improve this answer




























                      9












                      9








                      9







                      There are a number of answers talking about Array.prototype.push.apply. Here is a clear example:






                      var dataArray1 = [1, 2];
                      var dataArray2 = [3, 4, 5];
                      var newArray = [ ];
                      Array.prototype.push.apply(newArray, dataArray1); // newArray = [1, 2]
                      Array.prototype.push.apply(newArray, dataArray2); // newArray = [1, 2, 3, 4, 5]
                      console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]





                      If you have ES6 syntax:






                      var dataArray1 = [1, 2];
                      var dataArray2 = [3, 4, 5];
                      var newArray = [ ];
                      newArray.push(...dataArray1); // newArray = [1, 2]
                      newArray.push(...dataArray2); // newArray = [1, 2, 3, 4, 5]
                      console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]








                      share|improve this answer















                      There are a number of answers talking about Array.prototype.push.apply. Here is a clear example:






                      var dataArray1 = [1, 2];
                      var dataArray2 = [3, 4, 5];
                      var newArray = [ ];
                      Array.prototype.push.apply(newArray, dataArray1); // newArray = [1, 2]
                      Array.prototype.push.apply(newArray, dataArray2); // newArray = [1, 2, 3, 4, 5]
                      console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]





                      If you have ES6 syntax:






                      var dataArray1 = [1, 2];
                      var dataArray2 = [3, 4, 5];
                      var newArray = [ ];
                      newArray.push(...dataArray1); // newArray = [1, 2]
                      newArray.push(...dataArray2); // newArray = [1, 2, 3, 4, 5]
                      console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]








                      var dataArray1 = [1, 2];
                      var dataArray2 = [3, 4, 5];
                      var newArray = [ ];
                      Array.prototype.push.apply(newArray, dataArray1); // newArray = [1, 2]
                      Array.prototype.push.apply(newArray, dataArray2); // newArray = [1, 2, 3, 4, 5]
                      console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]





                      var dataArray1 = [1, 2];
                      var dataArray2 = [3, 4, 5];
                      var newArray = [ ];
                      Array.prototype.push.apply(newArray, dataArray1); // newArray = [1, 2]
                      Array.prototype.push.apply(newArray, dataArray2); // newArray = [1, 2, 3, 4, 5]
                      console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]





                      var dataArray1 = [1, 2];
                      var dataArray2 = [3, 4, 5];
                      var newArray = [ ];
                      newArray.push(...dataArray1); // newArray = [1, 2]
                      newArray.push(...dataArray2); // newArray = [1, 2, 3, 4, 5]
                      console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]





                      var dataArray1 = [1, 2];
                      var dataArray2 = [3, 4, 5];
                      var newArray = [ ];
                      newArray.push(...dataArray1); // newArray = [1, 2]
                      newArray.push(...dataArray2); // newArray = [1, 2, 3, 4, 5]
                      console.log(JSON.stringify(newArray)); // Outputs: [1, 2, 3, 4, 5]






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Sep 23 '17 at 1:14

























                      answered Jul 3 '17 at 1:36









                      Stephen QuanStephen Quan

                      11.4k25054




                      11.4k25054























                          7














                          The function below doesn't have an issue with the length of arrays and performs better than all suggested solutions:



                          function pushArray(list, other) {
                          var len = other.length;
                          var start = list.length;
                          list.length = start + len;
                          for (var i = 0; i < len; i++ , start++) {
                          list[start] = other[i];
                          }
                          }


                          unfortunately, jspref refuses to accept my submissions, so here they are the results using benchmark.js



                                  Name            |   ops/sec   |  ± %  | runs sampled
                          for loop and push | 177506 | 0.92 | 63
                          Push Apply | 234280 | 0.77 | 66
                          spread operator | 259725 | 0.40 | 67
                          set length and for loop | 284223 | 0.41 | 66


                          where



                          for loop and push is:



                              for (var i = 0, l = source.length; i < l; i++) {
                          target.push(source[i]);
                          }


                          Push Apply:



                          target.push.apply(target, source);


                          spread operator:



                              target.push(...source);


                          and finally the 'set length and for loop' is the above function






                          share|improve this answer
























                          • This question is looking for a way to create a new array each time, not modify an existing array.

                            – Jack Giffin
                            Aug 15 '18 at 9:17
















                          7














                          The function below doesn't have an issue with the length of arrays and performs better than all suggested solutions:



                          function pushArray(list, other) {
                          var len = other.length;
                          var start = list.length;
                          list.length = start + len;
                          for (var i = 0; i < len; i++ , start++) {
                          list[start] = other[i];
                          }
                          }


                          unfortunately, jspref refuses to accept my submissions, so here they are the results using benchmark.js



                                  Name            |   ops/sec   |  ± %  | runs sampled
                          for loop and push | 177506 | 0.92 | 63
                          Push Apply | 234280 | 0.77 | 66
                          spread operator | 259725 | 0.40 | 67
                          set length and for loop | 284223 | 0.41 | 66


                          where



                          for loop and push is:



                              for (var i = 0, l = source.length; i < l; i++) {
                          target.push(source[i]);
                          }


                          Push Apply:



                          target.push.apply(target, source);


                          spread operator:



                              target.push(...source);


                          and finally the 'set length and for loop' is the above function






                          share|improve this answer
























                          • This question is looking for a way to create a new array each time, not modify an existing array.

                            – Jack Giffin
                            Aug 15 '18 at 9:17














                          7












                          7








                          7







                          The function below doesn't have an issue with the length of arrays and performs better than all suggested solutions:



                          function pushArray(list, other) {
                          var len = other.length;
                          var start = list.length;
                          list.length = start + len;
                          for (var i = 0; i < len; i++ , start++) {
                          list[start] = other[i];
                          }
                          }


                          unfortunately, jspref refuses to accept my submissions, so here they are the results using benchmark.js



                                  Name            |   ops/sec   |  ± %  | runs sampled
                          for loop and push | 177506 | 0.92 | 63
                          Push Apply | 234280 | 0.77 | 66
                          spread operator | 259725 | 0.40 | 67
                          set length and for loop | 284223 | 0.41 | 66


                          where



                          for loop and push is:



                              for (var i = 0, l = source.length; i < l; i++) {
                          target.push(source[i]);
                          }


                          Push Apply:



                          target.push.apply(target, source);


                          spread operator:



                              target.push(...source);


                          and finally the 'set length and for loop' is the above function






                          share|improve this answer













                          The function below doesn't have an issue with the length of arrays and performs better than all suggested solutions:



                          function pushArray(list, other) {
                          var len = other.length;
                          var start = list.length;
                          list.length = start + len;
                          for (var i = 0; i < len; i++ , start++) {
                          list[start] = other[i];
                          }
                          }


                          unfortunately, jspref refuses to accept my submissions, so here they are the results using benchmark.js



                                  Name            |   ops/sec   |  ± %  | runs sampled
                          for loop and push | 177506 | 0.92 | 63
                          Push Apply | 234280 | 0.77 | 66
                          spread operator | 259725 | 0.40 | 67
                          set length and for loop | 284223 | 0.41 | 66


                          where



                          for loop and push is:



                              for (var i = 0, l = source.length; i < l; i++) {
                          target.push(source[i]);
                          }


                          Push Apply:



                          target.push.apply(target, source);


                          spread operator:



                              target.push(...source);


                          and finally the 'set length and for loop' is the above function







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered May 20 '17 at 15:01









                          Panos TheofPanos Theof

                          1,05411923




                          1,05411923













                          • This question is looking for a way to create a new array each time, not modify an existing array.

                            – Jack Giffin
                            Aug 15 '18 at 9:17



















                          • This question is looking for a way to create a new array each time, not modify an existing array.

                            – Jack Giffin
                            Aug 15 '18 at 9:17

















                          This question is looking for a way to create a new array each time, not modify an existing array.

                          – Jack Giffin
                          Aug 15 '18 at 9:17





                          This question is looking for a way to create a new array each time, not modify an existing array.

                          – Jack Giffin
                          Aug 15 '18 at 9:17











                          7














                          With JavaScript ES6, you can use the ... operator as a spread operator which will essentially convert the array into values. Then, you can do something like this:



                          const myArray = [1,2,3,4,5];
                          const moreData = [6,7,8,9,10];

                          const newArray = [
                          ...myArray,
                          ...moreData,
                          ];


                          While the syntax is concise, I do not know how this works internally and what the performance implications are on large arrays.






                          share|improve this answer





















                          • 2





                            If you take a look at how babel converts it, you'll see that it should not be any slower than using Array.push.apply technique.

                            – emil.c
                            Dec 11 '17 at 9:19








                          • 1





                            @JackGiffin I was just referring to what Ryan mentioned that he doesn't know how it works internally and what are performance implications, I wasn't actually suggesting this approach. In any case, you've done a very good job on your answer, nice research, it's always good to know such details.

                            – emil.c
                            Nov 22 '18 at 19:50
















                          7














                          With JavaScript ES6, you can use the ... operator as a spread operator which will essentially convert the array into values. Then, you can do something like this:



                          const myArray = [1,2,3,4,5];
                          const moreData = [6,7,8,9,10];

                          const newArray = [
                          ...myArray,
                          ...moreData,
                          ];


                          While the syntax is concise, I do not know how this works internally and what the performance implications are on large arrays.






                          share|improve this answer





















                          • 2





                            If you take a look at how babel converts it, you'll see that it should not be any slower than using Array.push.apply technique.

                            – emil.c
                            Dec 11 '17 at 9:19








                          • 1





                            @JackGiffin I was just referring to what Ryan mentioned that he doesn't know how it works internally and what are performance implications, I wasn't actually suggesting this approach. In any case, you've done a very good job on your answer, nice research, it's always good to know such details.

                            – emil.c
                            Nov 22 '18 at 19:50














                          7












                          7








                          7







                          With JavaScript ES6, you can use the ... operator as a spread operator which will essentially convert the array into values. Then, you can do something like this:



                          const myArray = [1,2,3,4,5];
                          const moreData = [6,7,8,9,10];

                          const newArray = [
                          ...myArray,
                          ...moreData,
                          ];


                          While the syntax is concise, I do not know how this works internally and what the performance implications are on large arrays.






                          share|improve this answer















                          With JavaScript ES6, you can use the ... operator as a spread operator which will essentially convert the array into values. Then, you can do something like this:



                          const myArray = [1,2,3,4,5];
                          const moreData = [6,7,8,9,10];

                          const newArray = [
                          ...myArray,
                          ...moreData,
                          ];


                          While the syntax is concise, I do not know how this works internally and what the performance implications are on large arrays.







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Oct 25 '18 at 15:23

























                          answered Jun 29 '16 at 18:24









                          Ryan H.Ryan H.

                          2,3392130




                          2,3392130








                          • 2





                            If you take a look at how babel converts it, you'll see that it should not be any slower than using Array.push.apply technique.

                            – emil.c
                            Dec 11 '17 at 9:19








                          • 1





                            @JackGiffin I was just referring to what Ryan mentioned that he doesn't know how it works internally and what are performance implications, I wasn't actually suggesting this approach. In any case, you've done a very good job on your answer, nice research, it's always good to know such details.

                            – emil.c
                            Nov 22 '18 at 19:50














                          • 2





                            If you take a look at how babel converts it, you'll see that it should not be any slower than using Array.push.apply technique.

                            – emil.c
                            Dec 11 '17 at 9:19








                          • 1





                            @JackGiffin I was just referring to what Ryan mentioned that he doesn't know how it works internally and what are performance implications, I wasn't actually suggesting this approach. In any case, you've done a very good job on your answer, nice research, it's always good to know such details.

                            – emil.c
                            Nov 22 '18 at 19:50








                          2




                          2





                          If you take a look at how babel converts it, you'll see that it should not be any slower than using Array.push.apply technique.

                          – emil.c
                          Dec 11 '17 at 9:19







                          If you take a look at how babel converts it, you'll see that it should not be any slower than using Array.push.apply technique.

                          – emil.c
                          Dec 11 '17 at 9:19






                          1




                          1





                          @JackGiffin I was just referring to what Ryan mentioned that he doesn't know how it works internally and what are performance implications, I wasn't actually suggesting this approach. In any case, you've done a very good job on your answer, nice research, it's always good to know such details.

                          – emil.c
                          Nov 22 '18 at 19:50





                          @JackGiffin I was just referring to what Ryan mentioned that he doesn't know how it works internally and what are performance implications, I wasn't actually suggesting this approach. In any case, you've done a very good job on your answer, nice research, it's always good to know such details.

                          – emil.c
                          Nov 22 '18 at 19:50











                          3














                          Here's the ES6 way






                          var newArray = ;
                          let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          newArray = [...dataArray1, ...dataArray2]
                          console.log(newArray)






                          The above method is good to go for most of the cases and the cases it is not please consider concat, like you have hundred thousands of items in arrays.







                              let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          let newArray = dataArray1.concat(dataArray2);
                          console.log(newArray)








                          share|improve this answer


























                          • Hey budd there was a reason to develop and surely the reason wasn't speed . Speed matters when you have quite large array in that case concat is better

                            – Black Mamba
                            Nov 20 '18 at 3:37
















                          3














                          Here's the ES6 way






                          var newArray = ;
                          let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          newArray = [...dataArray1, ...dataArray2]
                          console.log(newArray)






                          The above method is good to go for most of the cases and the cases it is not please consider concat, like you have hundred thousands of items in arrays.







                              let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          let newArray = dataArray1.concat(dataArray2);
                          console.log(newArray)








                          share|improve this answer


























                          • Hey budd there was a reason to develop and surely the reason wasn't speed . Speed matters when you have quite large array in that case concat is better

                            – Black Mamba
                            Nov 20 '18 at 3:37














                          3












                          3








                          3







                          Here's the ES6 way






                          var newArray = ;
                          let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          newArray = [...dataArray1, ...dataArray2]
                          console.log(newArray)






                          The above method is good to go for most of the cases and the cases it is not please consider concat, like you have hundred thousands of items in arrays.







                              let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          let newArray = dataArray1.concat(dataArray2);
                          console.log(newArray)








                          share|improve this answer















                          Here's the ES6 way






                          var newArray = ;
                          let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          newArray = [...dataArray1, ...dataArray2]
                          console.log(newArray)






                          The above method is good to go for most of the cases and the cases it is not please consider concat, like you have hundred thousands of items in arrays.







                              let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          let newArray = dataArray1.concat(dataArray2);
                          console.log(newArray)








                          var newArray = ;
                          let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          newArray = [...dataArray1, ...dataArray2]
                          console.log(newArray)





                          var newArray = ;
                          let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          newArray = [...dataArray1, ...dataArray2]
                          console.log(newArray)





                              let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          let newArray = dataArray1.concat(dataArray2);
                          console.log(newArray)





                              let dataArray1 = [1,2,3,4]
                          let dataArray2 = [5,6,7,8]
                          let newArray = dataArray1.concat(dataArray2);
                          console.log(newArray)






                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Nov 20 '18 at 6:46

























                          answered Jun 15 '18 at 5:10









                          Black MambaBlack Mamba

                          2,78912139




                          2,78912139













                          • Hey budd there was a reason to develop and surely the reason wasn't speed . Speed matters when you have quite large array in that case concat is better

                            – Black Mamba
                            Nov 20 '18 at 3:37



















                          • Hey budd there was a reason to develop and surely the reason wasn't speed . Speed matters when you have quite large array in that case concat is better

                            – Black Mamba
                            Nov 20 '18 at 3:37

















                          Hey budd there was a reason to develop and surely the reason wasn't speed . Speed matters when you have quite large array in that case concat is better

                          – Black Mamba
                          Nov 20 '18 at 3:37





                          Hey budd there was a reason to develop and surely the reason wasn't speed . Speed matters when you have quite large array in that case concat is better

                          – Black Mamba
                          Nov 20 '18 at 3:37











                          3














                          Research And Results



                          For the facts, a performance test at jsperf and checking some things in the console are performed. For the research, the website irt.org is used. Below is a collection of all these sources put together plus an example function at the bottom.



                          ╔═══════════════╦══════╦═════════════════╦═══════════════╦═════════╦══════════╗
                          ║ Method ║Concat║slice&push.apply ║ push.apply x2 ║ ForLoop ║Spread ║
                          ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                          ║ mOps/Sec ║179 ║104 ║ 76 ║ 81 ║28 ║
                          ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                          ║ Sparse arrays ║YES! ║Only the sliced ║ no ║ Maybe2 ║no ║
                          ║ kept sparse ║ ║array (1st arg) ║ ║ ║ ║
                          ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                          ║ Support ║MSIE 4║MSIE 5.5 ║ MSIE 5.5 ║ MSIE 4 ║Edge 12 ║
                          ║ (source) ║NNav 4║NNav 4.06 ║ NNav 4.06 ║ NNav 3 ║MSIE NNav
                          ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                          ║Array-like acts║no ║Only the pushed ║ YES! ║ YES! ║If have ║
                          ║like an array ║ ║array (2nd arg) ║ ║ ║iterator1
                          ╚═══════════════╩══════╩═════════════════╩═══════════════╩═════════╩══════════╝
                          1 If the array-like object does not have a Symbol.iterator property, then trying
                          to spread it will throw an exception.
                          2 Depends on the code. The following example code "YES" preserves sparseness.


                          function mergeCopyTogether(inputOne, inputTwo){
                          var oneLen = inputOne.length, twoLen = inputTwo.length;
                          var newArr = , newLen = newArr.length = oneLen + twoLen;
                          for (var i=0, tmp=inputOne[0]; i !== oneLen; ++i) {
                          tmp = inputOne[i];
                          if (tmp !== undefined || inputOne.hasOwnProperty(i)) newArr[i] = tmp;
                          }
                          for (var two=0; i !== newLen; ++i, ++two) {
                          tmp = inputTwo[two];
                          if (tmp !== undefined || inputTwo.hasOwnProperty(two)) newArr[i] = tmp;
                          }
                          return newArr;
                          }


                          As seen above, I would argue that Concat is almost always the way to go for both performance and the ability to retain the sparseness of spare arrays. Then, for array-likes (such as DOMNodeLists like document.body.children), I would recommend using the for loop because it is both the 2nd most performant and the only other method that retains sparse arrays. Below, we will quickly go over what is meant by sparse arrays and array-likes to clear up confusion.



                          The Future



                          At first, some people may think that this is a fluke and that browser vendors will eventually get around to optimizing Array.prototype.push to be fast enough to beat Array.prototype.concat. WRONG! Array.prototype.concat will always be faster (in principle at least) because it is a simple copy-n-paste over the data. Below is a simplified persuado-visual diagram of what a 32-bit array implementation might look like (please note real implementations are a LOT more complicated)



                          Byte ║ Data here
                          ═════╬═══════════
                          0x00 ║ int nonNumericPropertiesLength = 0x00000000
                          0x01 ║ ibid
                          0x02 ║ ibid
                          0x03 ║ ibid
                          0x00 ║ int length = 0x00000001
                          0x01 ║ ibid
                          0x02 ║ ibid
                          0x03 ║ ibid
                          0x00 ║ int valueIndex = 0x00000000
                          0x01 ║ ibid
                          0x02 ║ ibid
                          0x03 ║ ibid
                          0x00 ║ int valueType = JS_PRIMITIVE_NUMBER
                          0x01 ║ ibid
                          0x02 ║ ibid
                          0x03 ║ ibid
                          0x00 ║ uintptr_t valuePointer = 0x38d9eb60 (or whereever it is in memory)
                          0x01 ║ ibid
                          0x02 ║ ibid
                          0x03 ║ ibid


                          As seen above, all you need to do to copy something like that is almost as simple as copying it byte for byte. With Array.prototype.push.apply, it is a lot more than a simple copy-n-paste over the data. The ".apply" has to check each index in the array and convert it to a set of arguments before passing it to Array.prototype.push. Then, Array.prototype.push has to additionally allocate more memory each time, and (for some browser implementations) maybe even recalculate some position-lookup data for sparseness.



                          An alternative way to think of it is this. The source array one is a large stack of papers stapled together. The source array two is also another large stack of papers. Would it be faster for you to




                          1. Go to the store, buy enough paper needed for a copy of each source array. Then put each source array stacks of paper through a copy-machine and staple the resulting two copies together.

                          2. Go to the store, buy enough paper for a single copy of the first source array. Then, copy the source array to the new paper by hand, ensuring to fill in any blank sparse spots. Then, go back to the store, buy enough paper for the second source array. Then, go through the second source array and copy it while ensuring no blank gaps in the copy. Then, staple all the copied papers together.


                          In the above analogy, option #1 represents Array.prototype.concat while #2 represents Array.prototype.push.apply. Let us test this out with a similar JSperf differing only in that this one tests the methods over sparse arrays, not solid arrays. One can find it right here.



                          Therefore, I rest my case that the future of performance for this particular use case lies not in Array.prototype.push, but rather in Array.prototype.concat.



                          Clarifications



                          Spare Arrays



                          When certain members of the array are simply missing. For example:






                          // This is just as an example. In actual code, 
                          // do not mix different types like this.
                          var mySparseArray = ;
                          mySparseArray[0] = "foo";
                          mySparseArray[10] = undefined;
                          mySparseArray[11] = {};
                          mySparseArray[12] = 10;
                          mySparseArray[17] = "bar";
                          console.log("Length: ", mySparseArray.length);
                          console.log("0 in it: ", 0 in mySparseArray);
                          console.log("arr[0]: ", mySparseArray[0]);
                          console.log("10 in it: ", 10 in mySparseArray);
                          console.log("arr[10] ", mySparseArray[10]);
                          console.log("20 in it: ", 20 in mySparseArray);
                          console.log("arr[20]: ", mySparseArray[20]);





                          Alternatively, javascript allows you to initialize spare arrays easily.



                          var mySparseArray = ["foo",,,,,,,,,,undefined,{},10,,,,,"bar"];


                          Array-Likes



                          An array-like is an object that has at least a length property, but was not initialized with new Array or ; For example, the below objects are classified as array-like.



                          {0: "foo", 1: "bar", length:2}


                          document.body.children


                          new Uint8Array(3)



                          • This is array-like because although it's a(n) (typed) array, coercing it to an array changes the constructor.


                          (function(){return arguments})()


                          Observe what happens using a method that does coerce array-likes into arrays like slice.






                          var slice = Array.prototype.slice;
                          // For arrays:
                          console.log(slice.call(["not an array-like, rather a real array"]));
                          // For array-likes:
                          console.log(slice.call({0: "foo", 1: "bar", length:2}));
                          console.log(slice.call(document.body.children));
                          console.log(slice.call(new Uint8Array(3)));
                          console.log(slice.call( function(){return arguments}() ));






                          • NOTE: It is bad practice to slice function argument because of performance.


                          Observe what happens using a method that does not coerce array-likes into arrays like concat.






                          var empty = ;
                          // For arrays:
                          console.log(empty.concat(["not an array-like, rather a real array"]));
                          // For array-likes:
                          console.log(empty.concat({0: "foo", 1: "bar", length:2}));
                          console.log(empty.concat(document.body.children));
                          console.log(empty.concat(new Uint8Array(3)));
                          console.log(empty.concat( function(){return arguments}() ));








                          share|improve this answer






























                            3














                            Research And Results



                            For the facts, a performance test at jsperf and checking some things in the console are performed. For the research, the website irt.org is used. Below is a collection of all these sources put together plus an example function at the bottom.



                            ╔═══════════════╦══════╦═════════════════╦═══════════════╦═════════╦══════════╗
                            ║ Method ║Concat║slice&push.apply ║ push.apply x2 ║ ForLoop ║Spread ║
                            ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                            ║ mOps/Sec ║179 ║104 ║ 76 ║ 81 ║28 ║
                            ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                            ║ Sparse arrays ║YES! ║Only the sliced ║ no ║ Maybe2 ║no ║
                            ║ kept sparse ║ ║array (1st arg) ║ ║ ║ ║
                            ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                            ║ Support ║MSIE 4║MSIE 5.5 ║ MSIE 5.5 ║ MSIE 4 ║Edge 12 ║
                            ║ (source) ║NNav 4║NNav 4.06 ║ NNav 4.06 ║ NNav 3 ║MSIE NNav
                            ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                            ║Array-like acts║no ║Only the pushed ║ YES! ║ YES! ║If have ║
                            ║like an array ║ ║array (2nd arg) ║ ║ ║iterator1
                            ╚═══════════════╩══════╩═════════════════╩═══════════════╩═════════╩══════════╝
                            1 If the array-like object does not have a Symbol.iterator property, then trying
                            to spread it will throw an exception.
                            2 Depends on the code. The following example code "YES" preserves sparseness.


                            function mergeCopyTogether(inputOne, inputTwo){
                            var oneLen = inputOne.length, twoLen = inputTwo.length;
                            var newArr = , newLen = newArr.length = oneLen + twoLen;
                            for (var i=0, tmp=inputOne[0]; i !== oneLen; ++i) {
                            tmp = inputOne[i];
                            if (tmp !== undefined || inputOne.hasOwnProperty(i)) newArr[i] = tmp;
                            }
                            for (var two=0; i !== newLen; ++i, ++two) {
                            tmp = inputTwo[two];
                            if (tmp !== undefined || inputTwo.hasOwnProperty(two)) newArr[i] = tmp;
                            }
                            return newArr;
                            }


                            As seen above, I would argue that Concat is almost always the way to go for both performance and the ability to retain the sparseness of spare arrays. Then, for array-likes (such as DOMNodeLists like document.body.children), I would recommend using the for loop because it is both the 2nd most performant and the only other method that retains sparse arrays. Below, we will quickly go over what is meant by sparse arrays and array-likes to clear up confusion.



                            The Future



                            At first, some people may think that this is a fluke and that browser vendors will eventually get around to optimizing Array.prototype.push to be fast enough to beat Array.prototype.concat. WRONG! Array.prototype.concat will always be faster (in principle at least) because it is a simple copy-n-paste over the data. Below is a simplified persuado-visual diagram of what a 32-bit array implementation might look like (please note real implementations are a LOT more complicated)



                            Byte ║ Data here
                            ═════╬═══════════
                            0x00 ║ int nonNumericPropertiesLength = 0x00000000
                            0x01 ║ ibid
                            0x02 ║ ibid
                            0x03 ║ ibid
                            0x00 ║ int length = 0x00000001
                            0x01 ║ ibid
                            0x02 ║ ibid
                            0x03 ║ ibid
                            0x00 ║ int valueIndex = 0x00000000
                            0x01 ║ ibid
                            0x02 ║ ibid
                            0x03 ║ ibid
                            0x00 ║ int valueType = JS_PRIMITIVE_NUMBER
                            0x01 ║ ibid
                            0x02 ║ ibid
                            0x03 ║ ibid
                            0x00 ║ uintptr_t valuePointer = 0x38d9eb60 (or whereever it is in memory)
                            0x01 ║ ibid
                            0x02 ║ ibid
                            0x03 ║ ibid


                            As seen above, all you need to do to copy something like that is almost as simple as copying it byte for byte. With Array.prototype.push.apply, it is a lot more than a simple copy-n-paste over the data. The ".apply" has to check each index in the array and convert it to a set of arguments before passing it to Array.prototype.push. Then, Array.prototype.push has to additionally allocate more memory each time, and (for some browser implementations) maybe even recalculate some position-lookup data for sparseness.



                            An alternative way to think of it is this. The source array one is a large stack of papers stapled together. The source array two is also another large stack of papers. Would it be faster for you to




                            1. Go to the store, buy enough paper needed for a copy of each source array. Then put each source array stacks of paper through a copy-machine and staple the resulting two copies together.

                            2. Go to the store, buy enough paper for a single copy of the first source array. Then, copy the source array to the new paper by hand, ensuring to fill in any blank sparse spots. Then, go back to the store, buy enough paper for the second source array. Then, go through the second source array and copy it while ensuring no blank gaps in the copy. Then, staple all the copied papers together.


                            In the above analogy, option #1 represents Array.prototype.concat while #2 represents Array.prototype.push.apply. Let us test this out with a similar JSperf differing only in that this one tests the methods over sparse arrays, not solid arrays. One can find it right here.



                            Therefore, I rest my case that the future of performance for this particular use case lies not in Array.prototype.push, but rather in Array.prototype.concat.



                            Clarifications



                            Spare Arrays



                            When certain members of the array are simply missing. For example:






                            // This is just as an example. In actual code, 
                            // do not mix different types like this.
                            var mySparseArray = ;
                            mySparseArray[0] = "foo";
                            mySparseArray[10] = undefined;
                            mySparseArray[11] = {};
                            mySparseArray[12] = 10;
                            mySparseArray[17] = "bar";
                            console.log("Length: ", mySparseArray.length);
                            console.log("0 in it: ", 0 in mySparseArray);
                            console.log("arr[0]: ", mySparseArray[0]);
                            console.log("10 in it: ", 10 in mySparseArray);
                            console.log("arr[10] ", mySparseArray[10]);
                            console.log("20 in it: ", 20 in mySparseArray);
                            console.log("arr[20]: ", mySparseArray[20]);





                            Alternatively, javascript allows you to initialize spare arrays easily.



                            var mySparseArray = ["foo",,,,,,,,,,undefined,{},10,,,,,"bar"];


                            Array-Likes



                            An array-like is an object that has at least a length property, but was not initialized with new Array or ; For example, the below objects are classified as array-like.



                            {0: "foo", 1: "bar", length:2}


                            document.body.children


                            new Uint8Array(3)



                            • This is array-like because although it's a(n) (typed) array, coercing it to an array changes the constructor.


                            (function(){return arguments})()


                            Observe what happens using a method that does coerce array-likes into arrays like slice.






                            var slice = Array.prototype.slice;
                            // For arrays:
                            console.log(slice.call(["not an array-like, rather a real array"]));
                            // For array-likes:
                            console.log(slice.call({0: "foo", 1: "bar", length:2}));
                            console.log(slice.call(document.body.children));
                            console.log(slice.call(new Uint8Array(3)));
                            console.log(slice.call( function(){return arguments}() ));






                            • NOTE: It is bad practice to slice function argument because of performance.


                            Observe what happens using a method that does not coerce array-likes into arrays like concat.






                            var empty = ;
                            // For arrays:
                            console.log(empty.concat(["not an array-like, rather a real array"]));
                            // For array-likes:
                            console.log(empty.concat({0: "foo", 1: "bar", length:2}));
                            console.log(empty.concat(document.body.children));
                            console.log(empty.concat(new Uint8Array(3)));
                            console.log(empty.concat( function(){return arguments}() ));








                            share|improve this answer




























                              3












                              3








                              3







                              Research And Results



                              For the facts, a performance test at jsperf and checking some things in the console are performed. For the research, the website irt.org is used. Below is a collection of all these sources put together plus an example function at the bottom.



                              ╔═══════════════╦══════╦═════════════════╦═══════════════╦═════════╦══════════╗
                              ║ Method ║Concat║slice&push.apply ║ push.apply x2 ║ ForLoop ║Spread ║
                              ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                              ║ mOps/Sec ║179 ║104 ║ 76 ║ 81 ║28 ║
                              ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                              ║ Sparse arrays ║YES! ║Only the sliced ║ no ║ Maybe2 ║no ║
                              ║ kept sparse ║ ║array (1st arg) ║ ║ ║ ║
                              ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                              ║ Support ║MSIE 4║MSIE 5.5 ║ MSIE 5.5 ║ MSIE 4 ║Edge 12 ║
                              ║ (source) ║NNav 4║NNav 4.06 ║ NNav 4.06 ║ NNav 3 ║MSIE NNav
                              ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                              ║Array-like acts║no ║Only the pushed ║ YES! ║ YES! ║If have ║
                              ║like an array ║ ║array (2nd arg) ║ ║ ║iterator1
                              ╚═══════════════╩══════╩═════════════════╩═══════════════╩═════════╩══════════╝
                              1 If the array-like object does not have a Symbol.iterator property, then trying
                              to spread it will throw an exception.
                              2 Depends on the code. The following example code "YES" preserves sparseness.


                              function mergeCopyTogether(inputOne, inputTwo){
                              var oneLen = inputOne.length, twoLen = inputTwo.length;
                              var newArr = , newLen = newArr.length = oneLen + twoLen;
                              for (var i=0, tmp=inputOne[0]; i !== oneLen; ++i) {
                              tmp = inputOne[i];
                              if (tmp !== undefined || inputOne.hasOwnProperty(i)) newArr[i] = tmp;
                              }
                              for (var two=0; i !== newLen; ++i, ++two) {
                              tmp = inputTwo[two];
                              if (tmp !== undefined || inputTwo.hasOwnProperty(two)) newArr[i] = tmp;
                              }
                              return newArr;
                              }


                              As seen above, I would argue that Concat is almost always the way to go for both performance and the ability to retain the sparseness of spare arrays. Then, for array-likes (such as DOMNodeLists like document.body.children), I would recommend using the for loop because it is both the 2nd most performant and the only other method that retains sparse arrays. Below, we will quickly go over what is meant by sparse arrays and array-likes to clear up confusion.



                              The Future



                              At first, some people may think that this is a fluke and that browser vendors will eventually get around to optimizing Array.prototype.push to be fast enough to beat Array.prototype.concat. WRONG! Array.prototype.concat will always be faster (in principle at least) because it is a simple copy-n-paste over the data. Below is a simplified persuado-visual diagram of what a 32-bit array implementation might look like (please note real implementations are a LOT more complicated)



                              Byte ║ Data here
                              ═════╬═══════════
                              0x00 ║ int nonNumericPropertiesLength = 0x00000000
                              0x01 ║ ibid
                              0x02 ║ ibid
                              0x03 ║ ibid
                              0x00 ║ int length = 0x00000001
                              0x01 ║ ibid
                              0x02 ║ ibid
                              0x03 ║ ibid
                              0x00 ║ int valueIndex = 0x00000000
                              0x01 ║ ibid
                              0x02 ║ ibid
                              0x03 ║ ibid
                              0x00 ║ int valueType = JS_PRIMITIVE_NUMBER
                              0x01 ║ ibid
                              0x02 ║ ibid
                              0x03 ║ ibid
                              0x00 ║ uintptr_t valuePointer = 0x38d9eb60 (or whereever it is in memory)
                              0x01 ║ ibid
                              0x02 ║ ibid
                              0x03 ║ ibid


                              As seen above, all you need to do to copy something like that is almost as simple as copying it byte for byte. With Array.prototype.push.apply, it is a lot more than a simple copy-n-paste over the data. The ".apply" has to check each index in the array and convert it to a set of arguments before passing it to Array.prototype.push. Then, Array.prototype.push has to additionally allocate more memory each time, and (for some browser implementations) maybe even recalculate some position-lookup data for sparseness.



                              An alternative way to think of it is this. The source array one is a large stack of papers stapled together. The source array two is also another large stack of papers. Would it be faster for you to




                              1. Go to the store, buy enough paper needed for a copy of each source array. Then put each source array stacks of paper through a copy-machine and staple the resulting two copies together.

                              2. Go to the store, buy enough paper for a single copy of the first source array. Then, copy the source array to the new paper by hand, ensuring to fill in any blank sparse spots. Then, go back to the store, buy enough paper for the second source array. Then, go through the second source array and copy it while ensuring no blank gaps in the copy. Then, staple all the copied papers together.


                              In the above analogy, option #1 represents Array.prototype.concat while #2 represents Array.prototype.push.apply. Let us test this out with a similar JSperf differing only in that this one tests the methods over sparse arrays, not solid arrays. One can find it right here.



                              Therefore, I rest my case that the future of performance for this particular use case lies not in Array.prototype.push, but rather in Array.prototype.concat.



                              Clarifications



                              Spare Arrays



                              When certain members of the array are simply missing. For example:






                              // This is just as an example. In actual code, 
                              // do not mix different types like this.
                              var mySparseArray = ;
                              mySparseArray[0] = "foo";
                              mySparseArray[10] = undefined;
                              mySparseArray[11] = {};
                              mySparseArray[12] = 10;
                              mySparseArray[17] = "bar";
                              console.log("Length: ", mySparseArray.length);
                              console.log("0 in it: ", 0 in mySparseArray);
                              console.log("arr[0]: ", mySparseArray[0]);
                              console.log("10 in it: ", 10 in mySparseArray);
                              console.log("arr[10] ", mySparseArray[10]);
                              console.log("20 in it: ", 20 in mySparseArray);
                              console.log("arr[20]: ", mySparseArray[20]);





                              Alternatively, javascript allows you to initialize spare arrays easily.



                              var mySparseArray = ["foo",,,,,,,,,,undefined,{},10,,,,,"bar"];


                              Array-Likes



                              An array-like is an object that has at least a length property, but was not initialized with new Array or ; For example, the below objects are classified as array-like.



                              {0: "foo", 1: "bar", length:2}


                              document.body.children


                              new Uint8Array(3)



                              • This is array-like because although it's a(n) (typed) array, coercing it to an array changes the constructor.


                              (function(){return arguments})()


                              Observe what happens using a method that does coerce array-likes into arrays like slice.






                              var slice = Array.prototype.slice;
                              // For arrays:
                              console.log(slice.call(["not an array-like, rather a real array"]));
                              // For array-likes:
                              console.log(slice.call({0: "foo", 1: "bar", length:2}));
                              console.log(slice.call(document.body.children));
                              console.log(slice.call(new Uint8Array(3)));
                              console.log(slice.call( function(){return arguments}() ));






                              • NOTE: It is bad practice to slice function argument because of performance.


                              Observe what happens using a method that does not coerce array-likes into arrays like concat.






                              var empty = ;
                              // For arrays:
                              console.log(empty.concat(["not an array-like, rather a real array"]));
                              // For array-likes:
                              console.log(empty.concat({0: "foo", 1: "bar", length:2}));
                              console.log(empty.concat(document.body.children));
                              console.log(empty.concat(new Uint8Array(3)));
                              console.log(empty.concat( function(){return arguments}() ));








                              share|improve this answer















                              Research And Results



                              For the facts, a performance test at jsperf and checking some things in the console are performed. For the research, the website irt.org is used. Below is a collection of all these sources put together plus an example function at the bottom.



                              ╔═══════════════╦══════╦═════════════════╦═══════════════╦═════════╦══════════╗
                              ║ Method ║Concat║slice&push.apply ║ push.apply x2 ║ ForLoop ║Spread ║
                              ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                              ║ mOps/Sec ║179 ║104 ║ 76 ║ 81 ║28 ║
                              ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                              ║ Sparse arrays ║YES! ║Only the sliced ║ no ║ Maybe2 ║no ║
                              ║ kept sparse ║ ║array (1st arg) ║ ║ ║ ║
                              ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                              ║ Support ║MSIE 4║MSIE 5.5 ║ MSIE 5.5 ║ MSIE 4 ║Edge 12 ║
                              ║ (source) ║NNav 4║NNav 4.06 ║ NNav 4.06 ║ NNav 3 ║MSIE NNav
                              ╠═══════════════╬══════╬═════════════════╬═══════════════╬═════════╬══════════╣
                              ║Array-like acts║no ║Only the pushed ║ YES! ║ YES! ║If have ║
                              ║like an array ║ ║array (2nd arg) ║ ║ ║iterator1
                              ╚═══════════════╩══════╩═════════════════╩═══════════════╩═════════╩══════════╝
                              1 If the array-like object does not have a Symbol.iterator property, then trying
                              to spread it will throw an exception.
                              2 Depends on the code. The following example code "YES" preserves sparseness.


                              function mergeCopyTogether(inputOne, inputTwo){
                              var oneLen = inputOne.length, twoLen = inputTwo.length;
                              var newArr = , newLen = newArr.length = oneLen + twoLen;
                              for (var i=0, tmp=inputOne[0]; i !== oneLen; ++i) {
                              tmp = inputOne[i];
                              if (tmp !== undefined || inputOne.hasOwnProperty(i)) newArr[i] = tmp;
                              }
                              for (var two=0; i !== newLen; ++i, ++two) {
                              tmp = inputTwo[two];
                              if (tmp !== undefined || inputTwo.hasOwnProperty(two)) newArr[i] = tmp;
                              }
                              return newArr;
                              }


                              As seen above, I would argue that Concat is almost always the way to go for both performance and the ability to retain the sparseness of spare arrays. Then, for array-likes (such as DOMNodeLists like document.body.children), I would recommend using the for loop because it is both the 2nd most performant and the only other method that retains sparse arrays. Below, we will quickly go over what is meant by sparse arrays and array-likes to clear up confusion.



                              The Future



                              At first, some people may think that this is a fluke and that browser vendors will eventually get around to optimizing Array.prototype.push to be fast enough to beat Array.prototype.concat. WRONG! Array.prototype.concat will always be faster (in principle at least) because it is a simple copy-n-paste over the data. Below is a simplified persuado-visual diagram of what a 32-bit array implementation might look like (please note real implementations are a LOT more complicated)



                              Byte ║ Data here
                              ═════╬═══════════
                              0x00 ║ int nonNumericPropertiesLength = 0x00000000
                              0x01 ║ ibid
                              0x02 ║ ibid
                              0x03 ║ ibid
                              0x00 ║ int length = 0x00000001
                              0x01 ║ ibid
                              0x02 ║ ibid
                              0x03 ║ ibid
                              0x00 ║ int valueIndex = 0x00000000
                              0x01 ║ ibid
                              0x02 ║ ibid
                              0x03 ║ ibid
                              0x00 ║ int valueType = JS_PRIMITIVE_NUMBER
                              0x01 ║ ibid
                              0x02 ║ ibid
                              0x03 ║ ibid
                              0x00 ║ uintptr_t valuePointer = 0x38d9eb60 (or whereever it is in memory)
                              0x01 ║ ibid
                              0x02 ║ ibid
                              0x03 ║ ibid


                              As seen above, all you need to do to copy something like that is almost as simple as copying it byte for byte. With Array.prototype.push.apply, it is a lot more than a simple copy-n-paste over the data. The ".apply" has to check each index in the array and convert it to a set of arguments before passing it to Array.prototype.push. Then, Array.prototype.push has to additionally allocate more memory each time, and (for some browser implementations) maybe even recalculate some position-lookup data for sparseness.



                              An alternative way to think of it is this. The source array one is a large stack of papers stapled together. The source array two is also another large stack of papers. Would it be faster for you to




                              1. Go to the store, buy enough paper needed for a copy of each source array. Then put each source array stacks of paper through a copy-machine and staple the resulting two copies together.

                              2. Go to the store, buy enough paper for a single copy of the first source array. Then, copy the source array to the new paper by hand, ensuring to fill in any blank sparse spots. Then, go back to the store, buy enough paper for the second source array. Then, go through the second source array and copy it while ensuring no blank gaps in the copy. Then, staple all the copied papers together.


                              In the above analogy, option #1 represents Array.prototype.concat while #2 represents Array.prototype.push.apply. Let us test this out with a similar JSperf differing only in that this one tests the methods over sparse arrays, not solid arrays. One can find it right here.



                              Therefore, I rest my case that the future of performance for this particular use case lies not in Array.prototype.push, but rather in Array.prototype.concat.



                              Clarifications



                              Spare Arrays



                              When certain members of the array are simply missing. For example:






                              // This is just as an example. In actual code, 
                              // do not mix different types like this.
                              var mySparseArray = ;
                              mySparseArray[0] = "foo";
                              mySparseArray[10] = undefined;
                              mySparseArray[11] = {};
                              mySparseArray[12] = 10;
                              mySparseArray[17] = "bar";
                              console.log("Length: ", mySparseArray.length);
                              console.log("0 in it: ", 0 in mySparseArray);
                              console.log("arr[0]: ", mySparseArray[0]);
                              console.log("10 in it: ", 10 in mySparseArray);
                              console.log("arr[10] ", mySparseArray[10]);
                              console.log("20 in it: ", 20 in mySparseArray);
                              console.log("arr[20]: ", mySparseArray[20]);





                              Alternatively, javascript allows you to initialize spare arrays easily.



                              var mySparseArray = ["foo",,,,,,,,,,undefined,{},10,,,,,"bar"];


                              Array-Likes



                              An array-like is an object that has at least a length property, but was not initialized with new Array or ; For example, the below objects are classified as array-like.



                              {0: "foo", 1: "bar", length:2}


                              document.body.children


                              new Uint8Array(3)



                              • This is array-like because although it's a(n) (typed) array, coercing it to an array changes the constructor.


                              (function(){return arguments})()


                              Observe what happens using a method that does coerce array-likes into arrays like slice.






                              var slice = Array.prototype.slice;
                              // For arrays:
                              console.log(slice.call(["not an array-like, rather a real array"]));
                              // For array-likes:
                              console.log(slice.call({0: "foo", 1: "bar", length:2}));
                              console.log(slice.call(document.body.children));
                              console.log(slice.call(new Uint8Array(3)));
                              console.log(slice.call( function(){return arguments}() ));






                              • NOTE: It is bad practice to slice function argument because of performance.


                              Observe what happens using a method that does not coerce array-likes into arrays like concat.






                              var empty = ;
                              // For arrays:
                              console.log(empty.concat(["not an array-like, rather a real array"]));
                              // For array-likes:
                              console.log(empty.concat({0: "foo", 1: "bar", length:2}));
                              console.log(empty.concat(document.body.children));
                              console.log(empty.concat(new Uint8Array(3)));
                              console.log(empty.concat( function(){return arguments}() ));








                              // This is just as an example. In actual code, 
                              // do not mix different types like this.
                              var mySparseArray = ;
                              mySparseArray[0] = "foo";
                              mySparseArray[10] = undefined;
                              mySparseArray[11] = {};
                              mySparseArray[12] = 10;
                              mySparseArray[17] = "bar";
                              console.log("Length: ", mySparseArray.length);
                              console.log("0 in it: ", 0 in mySparseArray);
                              console.log("arr[0]: ", mySparseArray[0]);
                              console.log("10 in it: ", 10 in mySparseArray);
                              console.log("arr[10] ", mySparseArray[10]);
                              console.log("20 in it: ", 20 in mySparseArray);
                              console.log("arr[20]: ", mySparseArray[20]);





                              // This is just as an example. In actual code, 
                              // do not mix different types like this.
                              var mySparseArray = ;
                              mySparseArray[0] = "foo";
                              mySparseArray[10] = undefined;
                              mySparseArray[11] = {};
                              mySparseArray[12] = 10;
                              mySparseArray[17] = "bar";
                              console.log("Length: ", mySparseArray.length);
                              console.log("0 in it: ", 0 in mySparseArray);
                              console.log("arr[0]: ", mySparseArray[0]);
                              console.log("10 in it: ", 10 in mySparseArray);
                              console.log("arr[10] ", mySparseArray[10]);
                              console.log("20 in it: ", 20 in mySparseArray);
                              console.log("arr[20]: ", mySparseArray[20]);





                              var slice = Array.prototype.slice;
                              // For arrays:
                              console.log(slice.call(["not an array-like, rather a real array"]));
                              // For array-likes:
                              console.log(slice.call({0: "foo", 1: "bar", length:2}));
                              console.log(slice.call(document.body.children));
                              console.log(slice.call(new Uint8Array(3)));
                              console.log(slice.call( function(){return arguments}() ));





                              var slice = Array.prototype.slice;
                              // For arrays:
                              console.log(slice.call(["not an array-like, rather a real array"]));
                              // For array-likes:
                              console.log(slice.call({0: "foo", 1: "bar", length:2}));
                              console.log(slice.call(document.body.children));
                              console.log(slice.call(new Uint8Array(3)));
                              console.log(slice.call( function(){return arguments}() ));





                              var empty = ;
                              // For arrays:
                              console.log(empty.concat(["not an array-like, rather a real array"]));
                              // For array-likes:
                              console.log(empty.concat({0: "foo", 1: "bar", length:2}));
                              console.log(empty.concat(document.body.children));
                              console.log(empty.concat(new Uint8Array(3)));
                              console.log(empty.concat( function(){return arguments}() ));





                              var empty = ;
                              // For arrays:
                              console.log(empty.concat(["not an array-like, rather a real array"]));
                              // For array-likes:
                              console.log(empty.concat({0: "foo", 1: "bar", length:2}));
                              console.log(empty.concat(document.body.children));
                              console.log(empty.concat(new Uint8Array(3)));
                              console.log(empty.concat( function(){return arguments}() ));






                              share|improve this answer














                              share|improve this answer



                              share|improve this answer








                              edited Nov 22 '18 at 14:22

























                              answered Aug 15 '18 at 14:43









                              Jack GiffinJack Giffin

                              1,032925




                              1,032925























                                  0














                                  We have two array a and b. the code what did here is array a value is pushed into array b.



                                  let a = [2, 4, 6, 8, 9, 15]

                                  function transform(a) {
                                  let b = ['4', '16', '64']
                                  a.forEach(function(e) {
                                  b.push(e.toString());
                                  });
                                  return b;
                                  }

                                  transform(a)

                                  [ '4', '16', '64', '2', '4', '6', '8', '9', '15' ]





                                  share|improve this answer





















                                  • 1





                                    Please don't just post code as an answer. Explain what the code does and how it solves the problem.

                                    – Patrick Hund
                                    Jun 7 '17 at 18:28
















                                  0














                                  We have two array a and b. the code what did here is array a value is pushed into array b.



                                  let a = [2, 4, 6, 8, 9, 15]

                                  function transform(a) {
                                  let b = ['4', '16', '64']
                                  a.forEach(function(e) {
                                  b.push(e.toString());
                                  });
                                  return b;
                                  }

                                  transform(a)

                                  [ '4', '16', '64', '2', '4', '6', '8', '9', '15' ]





                                  share|improve this answer





















                                  • 1





                                    Please don't just post code as an answer. Explain what the code does and how it solves the problem.

                                    – Patrick Hund
                                    Jun 7 '17 at 18:28














                                  0












                                  0








                                  0







                                  We have two array a and b. the code what did here is array a value is pushed into array b.



                                  let a = [2, 4, 6, 8, 9, 15]

                                  function transform(a) {
                                  let b = ['4', '16', '64']
                                  a.forEach(function(e) {
                                  b.push(e.toString());
                                  });
                                  return b;
                                  }

                                  transform(a)

                                  [ '4', '16', '64', '2', '4', '6', '8', '9', '15' ]





                                  share|improve this answer















                                  We have two array a and b. the code what did here is array a value is pushed into array b.



                                  let a = [2, 4, 6, 8, 9, 15]

                                  function transform(a) {
                                  let b = ['4', '16', '64']
                                  a.forEach(function(e) {
                                  b.push(e.toString());
                                  });
                                  return b;
                                  }

                                  transform(a)

                                  [ '4', '16', '64', '2', '4', '6', '8', '9', '15' ]






                                  share|improve this answer














                                  share|improve this answer



                                  share|improve this answer








                                  edited Jan 9 '18 at 7:02

























                                  answered Jun 7 '17 at 14:33









                                  KARTHIKEYAN.AKARTHIKEYAN.A

                                  5,13534054




                                  5,13534054








                                  • 1





                                    Please don't just post code as an answer. Explain what the code does and how it solves the problem.

                                    – Patrick Hund
                                    Jun 7 '17 at 18:28














                                  • 1





                                    Please don't just post code as an answer. Explain what the code does and how it solves the problem.

                                    – Patrick Hund
                                    Jun 7 '17 at 18:28








                                  1




                                  1





                                  Please don't just post code as an answer. Explain what the code does and how it solves the problem.

                                  – Patrick Hund
                                  Jun 7 '17 at 18:28





                                  Please don't just post code as an answer. Explain what the code does and how it solves the problem.

                                  – Patrick Hund
                                  Jun 7 '17 at 18:28











                                  -2














                                  instead of push() function use concat function for IE. example,



                                  var a=a.concat(a,new Array('amin'));





                                  share|improve this answer
























                                  • both are very IE compatible

                                    – Jack Giffin
                                    Aug 16 '18 at 8:38
















                                  -2














                                  instead of push() function use concat function for IE. example,



                                  var a=a.concat(a,new Array('amin'));





                                  share|improve this answer
























                                  • both are very IE compatible

                                    – Jack Giffin
                                    Aug 16 '18 at 8:38














                                  -2












                                  -2








                                  -2







                                  instead of push() function use concat function for IE. example,



                                  var a=a.concat(a,new Array('amin'));





                                  share|improve this answer













                                  instead of push() function use concat function for IE. example,



                                  var a=a.concat(a,new Array('amin'));






                                  share|improve this answer












                                  share|improve this answer



                                  share|improve this answer










                                  answered Dec 27 '13 at 1:06









                                  user1911703user1911703

                                  3294620




                                  3294620













                                  • both are very IE compatible

                                    – Jack Giffin
                                    Aug 16 '18 at 8:38



















                                  • both are very IE compatible

                                    – Jack Giffin
                                    Aug 16 '18 at 8:38

















                                  both are very IE compatible

                                  – Jack Giffin
                                  Aug 16 '18 at 8:38





                                  both are very IE compatible

                                  – Jack Giffin
                                  Aug 16 '18 at 8:38











                                  -3














                                  Тhis is a working code and it works fine:



                                  var els = document.getElementsByTagName('input'), i;
                                  var invnum = new Array();
                                  var k = els.length;
                                  for(i = 0; i < k; i++){invnum.push(new Array(els[i].id,els[i].value))}





                                  share|improve this answer




























                                    -3














                                    Тhis is a working code and it works fine:



                                    var els = document.getElementsByTagName('input'), i;
                                    var invnum = new Array();
                                    var k = els.length;
                                    for(i = 0; i < k; i++){invnum.push(new Array(els[i].id,els[i].value))}





                                    share|improve this answer


























                                      -3












                                      -3








                                      -3







                                      Тhis is a working code and it works fine:



                                      var els = document.getElementsByTagName('input'), i;
                                      var invnum = new Array();
                                      var k = els.length;
                                      for(i = 0; i < k; i++){invnum.push(new Array(els[i].id,els[i].value))}





                                      share|improve this answer













                                      Тhis is a working code and it works fine:



                                      var els = document.getElementsByTagName('input'), i;
                                      var invnum = new Array();
                                      var k = els.length;
                                      for(i = 0; i < k; i++){invnum.push(new Array(els[i].id,els[i].value))}






                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered Dec 12 '14 at 12:31









                                      user4354031user4354031

                                      21




                                      21























                                          -4














                                          Most simple:



                                          var newArray = dataArray1.slice(0);





                                          share|improve this answer



















                                          • 1





                                            This does not cover the problem in the question: concatenating two arrays.

                                            – frasertweedale
                                            May 8 '15 at 9:40











                                          • How does this try to answer the question?

                                            – user6490459
                                            Jan 30 at 15:05
















                                          -4














                                          Most simple:



                                          var newArray = dataArray1.slice(0);





                                          share|improve this answer



















                                          • 1





                                            This does not cover the problem in the question: concatenating two arrays.

                                            – frasertweedale
                                            May 8 '15 at 9:40











                                          • How does this try to answer the question?

                                            – user6490459
                                            Jan 30 at 15:05














                                          -4












                                          -4








                                          -4







                                          Most simple:



                                          var newArray = dataArray1.slice(0);





                                          share|improve this answer













                                          Most simple:



                                          var newArray = dataArray1.slice(0);






                                          share|improve this answer












                                          share|improve this answer



                                          share|improve this answer










                                          answered May 8 '15 at 9:36









                                          PhuLuongPhuLuong

                                          463311




                                          463311








                                          • 1





                                            This does not cover the problem in the question: concatenating two arrays.

                                            – frasertweedale
                                            May 8 '15 at 9:40











                                          • How does this try to answer the question?

                                            – user6490459
                                            Jan 30 at 15:05














                                          • 1





                                            This does not cover the problem in the question: concatenating two arrays.

                                            – frasertweedale
                                            May 8 '15 at 9:40











                                          • How does this try to answer the question?

                                            – user6490459
                                            Jan 30 at 15:05








                                          1




                                          1





                                          This does not cover the problem in the question: concatenating two arrays.

                                          – frasertweedale
                                          May 8 '15 at 9:40





                                          This does not cover the problem in the question: concatenating two arrays.

                                          – frasertweedale
                                          May 8 '15 at 9:40













                                          How does this try to answer the question?

                                          – user6490459
                                          Jan 30 at 15:05





                                          How does this try to answer the question?

                                          – user6490459
                                          Jan 30 at 15:05





                                          protected by T J Jan 4 '16 at 17:12



                                          Thank you for your interest in this question.
                                          Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).



                                          Would you like to answer one of these unanswered questions instead?



                                          Popular posts from this blog

                                          How to change which sound is reproduced for terminal bell?

                                          Title Spacing in Bjornstrup Chapter, Removing Chapter Number From Contents

                                          Can I use Tabulator js library in my java Spring + Thymeleaf project?