Using foreach to show only certain elements in a list












0















I'm quite new to c# and I've been trying to search for an answer/solution online but couldn't.



Basically, I've read a csv file in C#, separated the lines by a comma (',') and stored the three sets of data in a table. For eg, one line of the csv file is like: name, date1, date2



You can see the code below (a RHM class has also been created):



List<RHM> data1 = new List<RHM>();

List<string> lines = File.ReadAllLines(filePath).ToList();
lines.RemoveAt(0);
foreach (var line in lines)
{
string entries = line.Split(',');
RHM nRHM = new RMH
{
Name = entries[0],
Date1 = entries[1],
Date2 = entries[2]
};

data1.Add(nRMH);

}


Now that I've imported it successfully, I just want to display e.g. the 5 line in the Name list. So far, I've only managed to display all the names using a foreach loop:



foreach (var RMH in data1)
{
Console.WriteLine(RMH.Name);
}


I've tried using .skip but that will only remove one element from the list. I need a way to show for eg, lines 23, 34, 15.










share|improve this question




















  • 4





    You can use your variable data1 as it was an array data1[4] is the fifth element (an RHM) added to that list, and thus data1[4].Name

    – Steve
    Nov 20 '18 at 14:42


















0















I'm quite new to c# and I've been trying to search for an answer/solution online but couldn't.



Basically, I've read a csv file in C#, separated the lines by a comma (',') and stored the three sets of data in a table. For eg, one line of the csv file is like: name, date1, date2



You can see the code below (a RHM class has also been created):



List<RHM> data1 = new List<RHM>();

List<string> lines = File.ReadAllLines(filePath).ToList();
lines.RemoveAt(0);
foreach (var line in lines)
{
string entries = line.Split(',');
RHM nRHM = new RMH
{
Name = entries[0],
Date1 = entries[1],
Date2 = entries[2]
};

data1.Add(nRMH);

}


Now that I've imported it successfully, I just want to display e.g. the 5 line in the Name list. So far, I've only managed to display all the names using a foreach loop:



foreach (var RMH in data1)
{
Console.WriteLine(RMH.Name);
}


I've tried using .skip but that will only remove one element from the list. I need a way to show for eg, lines 23, 34, 15.










share|improve this question




















  • 4





    You can use your variable data1 as it was an array data1[4] is the fifth element (an RHM) added to that list, and thus data1[4].Name

    – Steve
    Nov 20 '18 at 14:42
















0












0








0








I'm quite new to c# and I've been trying to search for an answer/solution online but couldn't.



Basically, I've read a csv file in C#, separated the lines by a comma (',') and stored the three sets of data in a table. For eg, one line of the csv file is like: name, date1, date2



You can see the code below (a RHM class has also been created):



List<RHM> data1 = new List<RHM>();

List<string> lines = File.ReadAllLines(filePath).ToList();
lines.RemoveAt(0);
foreach (var line in lines)
{
string entries = line.Split(',');
RHM nRHM = new RMH
{
Name = entries[0],
Date1 = entries[1],
Date2 = entries[2]
};

data1.Add(nRMH);

}


Now that I've imported it successfully, I just want to display e.g. the 5 line in the Name list. So far, I've only managed to display all the names using a foreach loop:



foreach (var RMH in data1)
{
Console.WriteLine(RMH.Name);
}


I've tried using .skip but that will only remove one element from the list. I need a way to show for eg, lines 23, 34, 15.










share|improve this question
















I'm quite new to c# and I've been trying to search for an answer/solution online but couldn't.



Basically, I've read a csv file in C#, separated the lines by a comma (',') and stored the three sets of data in a table. For eg, one line of the csv file is like: name, date1, date2



You can see the code below (a RHM class has also been created):



List<RHM> data1 = new List<RHM>();

List<string> lines = File.ReadAllLines(filePath).ToList();
lines.RemoveAt(0);
foreach (var line in lines)
{
string entries = line.Split(',');
RHM nRHM = new RMH
{
Name = entries[0],
Date1 = entries[1],
Date2 = entries[2]
};

data1.Add(nRMH);

}


Now that I've imported it successfully, I just want to display e.g. the 5 line in the Name list. So far, I've only managed to display all the names using a foreach loop:



foreach (var RMH in data1)
{
Console.WriteLine(RMH.Name);
}


I've tried using .skip but that will only remove one element from the list. I need a way to show for eg, lines 23, 34, 15.







c#






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 '18 at 14:52









Rand Random

2,97573163




2,97573163










asked Nov 20 '18 at 14:39









RefreshRefresh

31




31








  • 4





    You can use your variable data1 as it was an array data1[4] is the fifth element (an RHM) added to that list, and thus data1[4].Name

    – Steve
    Nov 20 '18 at 14:42
















  • 4





    You can use your variable data1 as it was an array data1[4] is the fifth element (an RHM) added to that list, and thus data1[4].Name

    – Steve
    Nov 20 '18 at 14:42










4




4





You can use your variable data1 as it was an array data1[4] is the fifth element (an RHM) added to that list, and thus data1[4].Name

– Steve
Nov 20 '18 at 14:42







You can use your variable data1 as it was an array data1[4] is the fifth element (an RHM) added to that list, and thus data1[4].Name

– Steve
Nov 20 '18 at 14:42














2 Answers
2






active

oldest

votes


















2














You can access object in the list by index. So if you want the 23rd element you simply do list[22]. Index is 0 based that means list[0] will be the first element in the list. Here is an example how to access and use your object in list:



RHM 23rdItemInList = data1[22];
Console.WriteLine($"Name of item in list on index 22 is: {23rdItemInList.Name}");




Note if you remove an item from the list, the index will not correspond to actual line in the file. If it matters I would suggest to store line number in your object.



List<RHM> data1 = new List<RHM>();

List<string> lines = File.ReadAllLines(filePath).ToList();
lines.RemoveAt(0);
int lineNumber = 1; //Here probably should be 2 because you skipping the first line in file with lines.RemoveAt(0);
foreach (var line in lines)
{
string entries = line.Split(',');
RHM nRHM = new RMH
{
Line = lineNumber,
Name = entries[0],
Date1 = entries[1],
Date2 = entries[2]
};

data1.Add(nRMH);
lineNumber++;
}


Now you can get object by line number like so:



var 23rdLineData = data1.FirstOrDefault(x=>x.Line == 23);


FirstOrDefault will return object of null if there is no record in the list with Line == 23.
Check if object is found before using it



if(23rdLineData != null)
Console.WriteLine($"Name on line 23 is {23rdLineData.Name}");
else
Console.WriteLine("There is no data on line 23");





share|improve this answer


























  • I've tried that before but for some reason it outputs the namespace name. I've also tried doing that in the foreach loop but that outputs the first character

    – Refresh
    Nov 20 '18 at 14:53











  • I updated my answer with example and added some notes

    – Reniuz
    Nov 20 '18 at 15:04











  • He should check if the item index exists to avoid an exception

    – crawletas
    Nov 20 '18 at 15:35



















0














There are multiple ways to achive your goal.



You could for example filter your list by any of your object fields by using LINQ like this:



List<RMH> results = data1.Where(d => d.Name == "HPBaxxter");


To filter by linenumber you can use TryGetValue for example:



RMH niceRMH;
int index = 23;
data1.TryGetValue(index, out niceRMH);





share|improve this answer
























  • TryGetValue is method of Dictionary not a List

    – Reniuz
    Nov 20 '18 at 15:05











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2 Answers
2






active

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2 Answers
2






active

oldest

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active

oldest

votes






active

oldest

votes









2














You can access object in the list by index. So if you want the 23rd element you simply do list[22]. Index is 0 based that means list[0] will be the first element in the list. Here is an example how to access and use your object in list:



RHM 23rdItemInList = data1[22];
Console.WriteLine($"Name of item in list on index 22 is: {23rdItemInList.Name}");




Note if you remove an item from the list, the index will not correspond to actual line in the file. If it matters I would suggest to store line number in your object.



List<RHM> data1 = new List<RHM>();

List<string> lines = File.ReadAllLines(filePath).ToList();
lines.RemoveAt(0);
int lineNumber = 1; //Here probably should be 2 because you skipping the first line in file with lines.RemoveAt(0);
foreach (var line in lines)
{
string entries = line.Split(',');
RHM nRHM = new RMH
{
Line = lineNumber,
Name = entries[0],
Date1 = entries[1],
Date2 = entries[2]
};

data1.Add(nRMH);
lineNumber++;
}


Now you can get object by line number like so:



var 23rdLineData = data1.FirstOrDefault(x=>x.Line == 23);


FirstOrDefault will return object of null if there is no record in the list with Line == 23.
Check if object is found before using it



if(23rdLineData != null)
Console.WriteLine($"Name on line 23 is {23rdLineData.Name}");
else
Console.WriteLine("There is no data on line 23");





share|improve this answer


























  • I've tried that before but for some reason it outputs the namespace name. I've also tried doing that in the foreach loop but that outputs the first character

    – Refresh
    Nov 20 '18 at 14:53











  • I updated my answer with example and added some notes

    – Reniuz
    Nov 20 '18 at 15:04











  • He should check if the item index exists to avoid an exception

    – crawletas
    Nov 20 '18 at 15:35
















2














You can access object in the list by index. So if you want the 23rd element you simply do list[22]. Index is 0 based that means list[0] will be the first element in the list. Here is an example how to access and use your object in list:



RHM 23rdItemInList = data1[22];
Console.WriteLine($"Name of item in list on index 22 is: {23rdItemInList.Name}");




Note if you remove an item from the list, the index will not correspond to actual line in the file. If it matters I would suggest to store line number in your object.



List<RHM> data1 = new List<RHM>();

List<string> lines = File.ReadAllLines(filePath).ToList();
lines.RemoveAt(0);
int lineNumber = 1; //Here probably should be 2 because you skipping the first line in file with lines.RemoveAt(0);
foreach (var line in lines)
{
string entries = line.Split(',');
RHM nRHM = new RMH
{
Line = lineNumber,
Name = entries[0],
Date1 = entries[1],
Date2 = entries[2]
};

data1.Add(nRMH);
lineNumber++;
}


Now you can get object by line number like so:



var 23rdLineData = data1.FirstOrDefault(x=>x.Line == 23);


FirstOrDefault will return object of null if there is no record in the list with Line == 23.
Check if object is found before using it



if(23rdLineData != null)
Console.WriteLine($"Name on line 23 is {23rdLineData.Name}");
else
Console.WriteLine("There is no data on line 23");





share|improve this answer


























  • I've tried that before but for some reason it outputs the namespace name. I've also tried doing that in the foreach loop but that outputs the first character

    – Refresh
    Nov 20 '18 at 14:53











  • I updated my answer with example and added some notes

    – Reniuz
    Nov 20 '18 at 15:04











  • He should check if the item index exists to avoid an exception

    – crawletas
    Nov 20 '18 at 15:35














2












2








2







You can access object in the list by index. So if you want the 23rd element you simply do list[22]. Index is 0 based that means list[0] will be the first element in the list. Here is an example how to access and use your object in list:



RHM 23rdItemInList = data1[22];
Console.WriteLine($"Name of item in list on index 22 is: {23rdItemInList.Name}");




Note if you remove an item from the list, the index will not correspond to actual line in the file. If it matters I would suggest to store line number in your object.



List<RHM> data1 = new List<RHM>();

List<string> lines = File.ReadAllLines(filePath).ToList();
lines.RemoveAt(0);
int lineNumber = 1; //Here probably should be 2 because you skipping the first line in file with lines.RemoveAt(0);
foreach (var line in lines)
{
string entries = line.Split(',');
RHM nRHM = new RMH
{
Line = lineNumber,
Name = entries[0],
Date1 = entries[1],
Date2 = entries[2]
};

data1.Add(nRMH);
lineNumber++;
}


Now you can get object by line number like so:



var 23rdLineData = data1.FirstOrDefault(x=>x.Line == 23);


FirstOrDefault will return object of null if there is no record in the list with Line == 23.
Check if object is found before using it



if(23rdLineData != null)
Console.WriteLine($"Name on line 23 is {23rdLineData.Name}");
else
Console.WriteLine("There is no data on line 23");





share|improve this answer















You can access object in the list by index. So if you want the 23rd element you simply do list[22]. Index is 0 based that means list[0] will be the first element in the list. Here is an example how to access and use your object in list:



RHM 23rdItemInList = data1[22];
Console.WriteLine($"Name of item in list on index 22 is: {23rdItemInList.Name}");




Note if you remove an item from the list, the index will not correspond to actual line in the file. If it matters I would suggest to store line number in your object.



List<RHM> data1 = new List<RHM>();

List<string> lines = File.ReadAllLines(filePath).ToList();
lines.RemoveAt(0);
int lineNumber = 1; //Here probably should be 2 because you skipping the first line in file with lines.RemoveAt(0);
foreach (var line in lines)
{
string entries = line.Split(',');
RHM nRHM = new RMH
{
Line = lineNumber,
Name = entries[0],
Date1 = entries[1],
Date2 = entries[2]
};

data1.Add(nRMH);
lineNumber++;
}


Now you can get object by line number like so:



var 23rdLineData = data1.FirstOrDefault(x=>x.Line == 23);


FirstOrDefault will return object of null if there is no record in the list with Line == 23.
Check if object is found before using it



if(23rdLineData != null)
Console.WriteLine($"Name on line 23 is {23rdLineData.Name}");
else
Console.WriteLine("There is no data on line 23");






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 20 '18 at 15:00

























answered Nov 20 '18 at 14:45









ReniuzReniuz

10.2k13555




10.2k13555













  • I've tried that before but for some reason it outputs the namespace name. I've also tried doing that in the foreach loop but that outputs the first character

    – Refresh
    Nov 20 '18 at 14:53











  • I updated my answer with example and added some notes

    – Reniuz
    Nov 20 '18 at 15:04











  • He should check if the item index exists to avoid an exception

    – crawletas
    Nov 20 '18 at 15:35



















  • I've tried that before but for some reason it outputs the namespace name. I've also tried doing that in the foreach loop but that outputs the first character

    – Refresh
    Nov 20 '18 at 14:53











  • I updated my answer with example and added some notes

    – Reniuz
    Nov 20 '18 at 15:04











  • He should check if the item index exists to avoid an exception

    – crawletas
    Nov 20 '18 at 15:35

















I've tried that before but for some reason it outputs the namespace name. I've also tried doing that in the foreach loop but that outputs the first character

– Refresh
Nov 20 '18 at 14:53





I've tried that before but for some reason it outputs the namespace name. I've also tried doing that in the foreach loop but that outputs the first character

– Refresh
Nov 20 '18 at 14:53













I updated my answer with example and added some notes

– Reniuz
Nov 20 '18 at 15:04





I updated my answer with example and added some notes

– Reniuz
Nov 20 '18 at 15:04













He should check if the item index exists to avoid an exception

– crawletas
Nov 20 '18 at 15:35





He should check if the item index exists to avoid an exception

– crawletas
Nov 20 '18 at 15:35













0














There are multiple ways to achive your goal.



You could for example filter your list by any of your object fields by using LINQ like this:



List<RMH> results = data1.Where(d => d.Name == "HPBaxxter");


To filter by linenumber you can use TryGetValue for example:



RMH niceRMH;
int index = 23;
data1.TryGetValue(index, out niceRMH);





share|improve this answer
























  • TryGetValue is method of Dictionary not a List

    – Reniuz
    Nov 20 '18 at 15:05
















0














There are multiple ways to achive your goal.



You could for example filter your list by any of your object fields by using LINQ like this:



List<RMH> results = data1.Where(d => d.Name == "HPBaxxter");


To filter by linenumber you can use TryGetValue for example:



RMH niceRMH;
int index = 23;
data1.TryGetValue(index, out niceRMH);





share|improve this answer
























  • TryGetValue is method of Dictionary not a List

    – Reniuz
    Nov 20 '18 at 15:05














0












0








0







There are multiple ways to achive your goal.



You could for example filter your list by any of your object fields by using LINQ like this:



List<RMH> results = data1.Where(d => d.Name == "HPBaxxter");


To filter by linenumber you can use TryGetValue for example:



RMH niceRMH;
int index = 23;
data1.TryGetValue(index, out niceRMH);





share|improve this answer













There are multiple ways to achive your goal.



You could for example filter your list by any of your object fields by using LINQ like this:



List<RMH> results = data1.Where(d => d.Name == "HPBaxxter");


To filter by linenumber you can use TryGetValue for example:



RMH niceRMH;
int index = 23;
data1.TryGetValue(index, out niceRMH);






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 20 '18 at 14:51









epanalepsisepanalepsis

1069




1069













  • TryGetValue is method of Dictionary not a List

    – Reniuz
    Nov 20 '18 at 15:05



















  • TryGetValue is method of Dictionary not a List

    – Reniuz
    Nov 20 '18 at 15:05

















TryGetValue is method of Dictionary not a List

– Reniuz
Nov 20 '18 at 15:05





TryGetValue is method of Dictionary not a List

– Reniuz
Nov 20 '18 at 15:05


















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