How do I use concepts in if-constexpr?












24















How does one use concepts in if constexpr?



Given the example below, what would one give to if constexpr to return 1 in case T meets the requirements of integral and else 0?



template<typename T>
concept integral = std::is_integral_v<T>;

struct X{};

template<typename T>
constexpr auto a () {
if constexpr (/* T is integral */) {
return 1;
}
else {
return 0;
}
}

int main () {
return a<X>();
}









share|improve this question





























    24















    How does one use concepts in if constexpr?



    Given the example below, what would one give to if constexpr to return 1 in case T meets the requirements of integral and else 0?



    template<typename T>
    concept integral = std::is_integral_v<T>;

    struct X{};

    template<typename T>
    constexpr auto a () {
    if constexpr (/* T is integral */) {
    return 1;
    }
    else {
    return 0;
    }
    }

    int main () {
    return a<X>();
    }









    share|improve this question



























      24












      24








      24


      1






      How does one use concepts in if constexpr?



      Given the example below, what would one give to if constexpr to return 1 in case T meets the requirements of integral and else 0?



      template<typename T>
      concept integral = std::is_integral_v<T>;

      struct X{};

      template<typename T>
      constexpr auto a () {
      if constexpr (/* T is integral */) {
      return 1;
      }
      else {
      return 0;
      }
      }

      int main () {
      return a<X>();
      }









      share|improve this question
















      How does one use concepts in if constexpr?



      Given the example below, what would one give to if constexpr to return 1 in case T meets the requirements of integral and else 0?



      template<typename T>
      concept integral = std::is_integral_v<T>;

      struct X{};

      template<typename T>
      constexpr auto a () {
      if constexpr (/* T is integral */) {
      return 1;
      }
      else {
      return 0;
      }
      }

      int main () {
      return a<X>();
      }






      c++ c++-concepts c++20 if-constexpr






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      edited Feb 11 at 13:37









      Peter Mortensen

      13.6k1986111




      13.6k1986111










      asked Feb 7 at 12:32









      kawillzockenkawillzocken

      480315




      480315
























          2 Answers
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          18














          Concepts are named boolean predicates on template parameters, evaluated at compile time.



          In a constexpr if statement, the value of the condition must be a contextually converted constant expression of type bool.



          So in this case, usage is simple:



          if constexpr ( integral<T> )





          share|improve this answer

































            13














            It is sufficient to do:



            if constexpr ( integral<T> )





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              2 Answers
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              2 Answers
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              18














              Concepts are named boolean predicates on template parameters, evaluated at compile time.



              In a constexpr if statement, the value of the condition must be a contextually converted constant expression of type bool.



              So in this case, usage is simple:



              if constexpr ( integral<T> )





              share|improve this answer






























                18














                Concepts are named boolean predicates on template parameters, evaluated at compile time.



                In a constexpr if statement, the value of the condition must be a contextually converted constant expression of type bool.



                So in this case, usage is simple:



                if constexpr ( integral<T> )





                share|improve this answer




























                  18












                  18








                  18







                  Concepts are named boolean predicates on template parameters, evaluated at compile time.



                  In a constexpr if statement, the value of the condition must be a contextually converted constant expression of type bool.



                  So in this case, usage is simple:



                  if constexpr ( integral<T> )





                  share|improve this answer















                  Concepts are named boolean predicates on template parameters, evaluated at compile time.



                  In a constexpr if statement, the value of the condition must be a contextually converted constant expression of type bool.



                  So in this case, usage is simple:



                  if constexpr ( integral<T> )






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Feb 11 at 13:38









                  Peter Mortensen

                  13.6k1986111




                  13.6k1986111










                  answered Feb 7 at 13:10









                  P.WP.W

                  14.1k31248




                  14.1k31248

























                      13














                      It is sufficient to do:



                      if constexpr ( integral<T> )





                      share|improve this answer






























                        13














                        It is sufficient to do:



                        if constexpr ( integral<T> )





                        share|improve this answer




























                          13












                          13








                          13







                          It is sufficient to do:



                          if constexpr ( integral<T> )





                          share|improve this answer















                          It is sufficient to do:



                          if constexpr ( integral<T> )






                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Feb 7 at 14:52









                          Barry

                          182k20316580




                          182k20316580










                          answered Feb 7 at 12:36









                          kawillzockenkawillzocken

                          480315




                          480315






























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