define a method with a vector of templates as an argument












-4















I have a method in my C++11 code that accepts a template as an argument



template<typename type> uint64_t insert(type item) {
//code
return id;
}


and I want to create a similar in order to insert many items. My attempt was to pass these items as a vector. However the compilation failed with error "error: template argument 1 is invalid"



template<typename type> std::vector<uint64_t> insert_many(std::vector<type insta> items) {

std::vector<uint64_t> v;
//v.push_back(...)
//code
return v;
}


What is wrong with the above method signature?










share|improve this question




















  • 2





    What is type insta ?

    – Rhathin
    Nov 19 '18 at 11:58











  • insert_many(const std::vector<type>& items), don't copy your vector.

    – Matthieu Brucher
    Nov 19 '18 at 11:58








  • 2





    std::vector<type insta> is a syntax error, did you mean std::vector<type> ?

    – M.M
    Nov 19 '18 at 11:59






  • 2





    There is no such thing as a vector of templates. There are function templates and class templates in C++, and neither can be an element of a vector.

    – n.m.
    Nov 19 '18 at 12:01






  • 1





    Your code compiles correctly since the edit, except that id is not defined. Please post a MCVE if you are still having trouble

    – M.M
    Nov 19 '18 at 12:10


















-4















I have a method in my C++11 code that accepts a template as an argument



template<typename type> uint64_t insert(type item) {
//code
return id;
}


and I want to create a similar in order to insert many items. My attempt was to pass these items as a vector. However the compilation failed with error "error: template argument 1 is invalid"



template<typename type> std::vector<uint64_t> insert_many(std::vector<type insta> items) {

std::vector<uint64_t> v;
//v.push_back(...)
//code
return v;
}


What is wrong with the above method signature?










share|improve this question




















  • 2





    What is type insta ?

    – Rhathin
    Nov 19 '18 at 11:58











  • insert_many(const std::vector<type>& items), don't copy your vector.

    – Matthieu Brucher
    Nov 19 '18 at 11:58








  • 2





    std::vector<type insta> is a syntax error, did you mean std::vector<type> ?

    – M.M
    Nov 19 '18 at 11:59






  • 2





    There is no such thing as a vector of templates. There are function templates and class templates in C++, and neither can be an element of a vector.

    – n.m.
    Nov 19 '18 at 12:01






  • 1





    Your code compiles correctly since the edit, except that id is not defined. Please post a MCVE if you are still having trouble

    – M.M
    Nov 19 '18 at 12:10
















-4












-4








-4








I have a method in my C++11 code that accepts a template as an argument



template<typename type> uint64_t insert(type item) {
//code
return id;
}


and I want to create a similar in order to insert many items. My attempt was to pass these items as a vector. However the compilation failed with error "error: template argument 1 is invalid"



template<typename type> std::vector<uint64_t> insert_many(std::vector<type insta> items) {

std::vector<uint64_t> v;
//v.push_back(...)
//code
return v;
}


What is wrong with the above method signature?










share|improve this question
















I have a method in my C++11 code that accepts a template as an argument



template<typename type> uint64_t insert(type item) {
//code
return id;
}


and I want to create a similar in order to insert many items. My attempt was to pass these items as a vector. However the compilation failed with error "error: template argument 1 is invalid"



template<typename type> std::vector<uint64_t> insert_many(std::vector<type insta> items) {

std::vector<uint64_t> v;
//v.push_back(...)
//code
return v;
}


What is wrong with the above method signature?







c++ c++11






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 '18 at 12:13







Captain Nemo

















asked Nov 19 '18 at 11:54









Captain NemoCaptain Nemo

246




246








  • 2





    What is type insta ?

    – Rhathin
    Nov 19 '18 at 11:58











  • insert_many(const std::vector<type>& items), don't copy your vector.

    – Matthieu Brucher
    Nov 19 '18 at 11:58








  • 2





    std::vector<type insta> is a syntax error, did you mean std::vector<type> ?

    – M.M
    Nov 19 '18 at 11:59






  • 2





    There is no such thing as a vector of templates. There are function templates and class templates in C++, and neither can be an element of a vector.

    – n.m.
    Nov 19 '18 at 12:01






  • 1





    Your code compiles correctly since the edit, except that id is not defined. Please post a MCVE if you are still having trouble

    – M.M
    Nov 19 '18 at 12:10
















  • 2





    What is type insta ?

    – Rhathin
    Nov 19 '18 at 11:58











  • insert_many(const std::vector<type>& items), don't copy your vector.

    – Matthieu Brucher
    Nov 19 '18 at 11:58








  • 2





    std::vector<type insta> is a syntax error, did you mean std::vector<type> ?

    – M.M
    Nov 19 '18 at 11:59






  • 2





    There is no such thing as a vector of templates. There are function templates and class templates in C++, and neither can be an element of a vector.

    – n.m.
    Nov 19 '18 at 12:01






  • 1





    Your code compiles correctly since the edit, except that id is not defined. Please post a MCVE if you are still having trouble

    – M.M
    Nov 19 '18 at 12:10










2




2





What is type insta ?

– Rhathin
Nov 19 '18 at 11:58





What is type insta ?

– Rhathin
Nov 19 '18 at 11:58













insert_many(const std::vector<type>& items), don't copy your vector.

– Matthieu Brucher
Nov 19 '18 at 11:58







insert_many(const std::vector<type>& items), don't copy your vector.

– Matthieu Brucher
Nov 19 '18 at 11:58






2




2





std::vector<type insta> is a syntax error, did you mean std::vector<type> ?

– M.M
Nov 19 '18 at 11:59





std::vector<type insta> is a syntax error, did you mean std::vector<type> ?

– M.M
Nov 19 '18 at 11:59




2




2





There is no such thing as a vector of templates. There are function templates and class templates in C++, and neither can be an element of a vector.

– n.m.
Nov 19 '18 at 12:01





There is no such thing as a vector of templates. There are function templates and class templates in C++, and neither can be an element of a vector.

– n.m.
Nov 19 '18 at 12:01




1




1





Your code compiles correctly since the edit, except that id is not defined. Please post a MCVE if you are still having trouble

– M.M
Nov 19 '18 at 12:10







Your code compiles correctly since the edit, except that id is not defined. Please post a MCVE if you are still having trouble

– M.M
Nov 19 '18 at 12:10














1 Answer
1






active

oldest

votes


















2














Assuming that type is the type of the objects you store in your vector.



#include <iostream>
#include <vector>

template<typename type>
typename std::vector<type>::iterator insert(std::vector<type>& v, const std::vector<type>& add) {
return v.insert(v.end(), add.begin(), add.end());
}


int main() {
std::vector<int> a{0,1,2,3,4};
std::vector<int> b{5,6};
insert(a, b);
for(const auto val : a) {
std::cout << val << "n";
}
}


Output



0
1
2
3
4
5
6





share|improve this answer























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    2














    Assuming that type is the type of the objects you store in your vector.



    #include <iostream>
    #include <vector>

    template<typename type>
    typename std::vector<type>::iterator insert(std::vector<type>& v, const std::vector<type>& add) {
    return v.insert(v.end(), add.begin(), add.end());
    }


    int main() {
    std::vector<int> a{0,1,2,3,4};
    std::vector<int> b{5,6};
    insert(a, b);
    for(const auto val : a) {
    std::cout << val << "n";
    }
    }


    Output



    0
    1
    2
    3
    4
    5
    6





    share|improve this answer




























      2














      Assuming that type is the type of the objects you store in your vector.



      #include <iostream>
      #include <vector>

      template<typename type>
      typename std::vector<type>::iterator insert(std::vector<type>& v, const std::vector<type>& add) {
      return v.insert(v.end(), add.begin(), add.end());
      }


      int main() {
      std::vector<int> a{0,1,2,3,4};
      std::vector<int> b{5,6};
      insert(a, b);
      for(const auto val : a) {
      std::cout << val << "n";
      }
      }


      Output



      0
      1
      2
      3
      4
      5
      6





      share|improve this answer


























        2












        2








        2







        Assuming that type is the type of the objects you store in your vector.



        #include <iostream>
        #include <vector>

        template<typename type>
        typename std::vector<type>::iterator insert(std::vector<type>& v, const std::vector<type>& add) {
        return v.insert(v.end(), add.begin(), add.end());
        }


        int main() {
        std::vector<int> a{0,1,2,3,4};
        std::vector<int> b{5,6};
        insert(a, b);
        for(const auto val : a) {
        std::cout << val << "n";
        }
        }


        Output



        0
        1
        2
        3
        4
        5
        6





        share|improve this answer













        Assuming that type is the type of the objects you store in your vector.



        #include <iostream>
        #include <vector>

        template<typename type>
        typename std::vector<type>::iterator insert(std::vector<type>& v, const std::vector<type>& add) {
        return v.insert(v.end(), add.begin(), add.end());
        }


        int main() {
        std::vector<int> a{0,1,2,3,4};
        std::vector<int> b{5,6};
        insert(a, b);
        for(const auto val : a) {
        std::cout << val << "n";
        }
        }


        Output



        0
        1
        2
        3
        4
        5
        6






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 19 '18 at 12:09









        Ted LyngmoTed Lyngmo

        2,1961317




        2,1961317






























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