Cell Structure and Computing Homology Groups
$begingroup$
I am computing homology group of space $X=S^{2}cup T^{2}/sim$ such that $S^{2}$ and $T^{2}$ gluing by there points on 2-sphere $s_{1}, s_{2}, s_{3}$ and three points on 2-torus $t_{1}, t_{2}, t_{3}$ where $s_{i}sim t_{i}$. How can i found cell structure of this space and homology groups?
It looks like $S^{2}lor S^{1}lor S^{1}lor S^{1}lor S^{1}$ but I am not sure, maybe I should add one more $S^{2}$, I couldn't imagine it! I totally confused.
Thank you for your help!
algebraic-topology
$endgroup$
add a comment |
$begingroup$
I am computing homology group of space $X=S^{2}cup T^{2}/sim$ such that $S^{2}$ and $T^{2}$ gluing by there points on 2-sphere $s_{1}, s_{2}, s_{3}$ and three points on 2-torus $t_{1}, t_{2}, t_{3}$ where $s_{i}sim t_{i}$. How can i found cell structure of this space and homology groups?
It looks like $S^{2}lor S^{1}lor S^{1}lor S^{1}lor S^{1}$ but I am not sure, maybe I should add one more $S^{2}$, I couldn't imagine it! I totally confused.
Thank you for your help!
algebraic-topology
$endgroup$
add a comment |
$begingroup$
I am computing homology group of space $X=S^{2}cup T^{2}/sim$ such that $S^{2}$ and $T^{2}$ gluing by there points on 2-sphere $s_{1}, s_{2}, s_{3}$ and three points on 2-torus $t_{1}, t_{2}, t_{3}$ where $s_{i}sim t_{i}$. How can i found cell structure of this space and homology groups?
It looks like $S^{2}lor S^{1}lor S^{1}lor S^{1}lor S^{1}$ but I am not sure, maybe I should add one more $S^{2}$, I couldn't imagine it! I totally confused.
Thank you for your help!
algebraic-topology
$endgroup$
I am computing homology group of space $X=S^{2}cup T^{2}/sim$ such that $S^{2}$ and $T^{2}$ gluing by there points on 2-sphere $s_{1}, s_{2}, s_{3}$ and three points on 2-torus $t_{1}, t_{2}, t_{3}$ where $s_{i}sim t_{i}$. How can i found cell structure of this space and homology groups?
It looks like $S^{2}lor S^{1}lor S^{1}lor S^{1}lor S^{1}$ but I am not sure, maybe I should add one more $S^{2}$, I couldn't imagine it! I totally confused.
Thank you for your help!
algebraic-topology
algebraic-topology
edited Nov 25 '18 at 17:59
amWhy
1
1
asked Nov 25 '18 at 17:49
user619499user619499
214
214
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You can use the Mayer Vietoris sequence with $X_1 = S^2$, $X_2 = T^2$, $X_1 cap X_2 = {a, b, c}$ and $X = X_1 cup X_2$.
$endgroup$
$begingroup$
What about cell structure, how can I found it?
$endgroup$
– user619499
Nov 25 '18 at 18:04
1
$begingroup$
Try to find a way of realizing $S^2$ and $T^2$ with $3$ $0$-simplices each. With the torus you can start from the familiar square with sides identified, adding extra simplices on the edges.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:09
$begingroup$
I am really sorry I couldn't do it. Can you explain more? Thank you.
$endgroup$
– user619499
Nov 25 '18 at 18:18
1
$begingroup$
For $S^2$ you can take a triangle with $2$ $2$-simplexes; a top and a bottom one. For the torus you could take a square with additional vertex in the middle of each edge: after identifying edges, you will be left with $3$ vertices.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:26
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3013147%2fcell-structure-and-computing-homology-groups%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can use the Mayer Vietoris sequence with $X_1 = S^2$, $X_2 = T^2$, $X_1 cap X_2 = {a, b, c}$ and $X = X_1 cup X_2$.
$endgroup$
$begingroup$
What about cell structure, how can I found it?
$endgroup$
– user619499
Nov 25 '18 at 18:04
1
$begingroup$
Try to find a way of realizing $S^2$ and $T^2$ with $3$ $0$-simplices each. With the torus you can start from the familiar square with sides identified, adding extra simplices on the edges.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:09
$begingroup$
I am really sorry I couldn't do it. Can you explain more? Thank you.
$endgroup$
– user619499
Nov 25 '18 at 18:18
1
$begingroup$
For $S^2$ you can take a triangle with $2$ $2$-simplexes; a top and a bottom one. For the torus you could take a square with additional vertex in the middle of each edge: after identifying edges, you will be left with $3$ vertices.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:26
add a comment |
$begingroup$
You can use the Mayer Vietoris sequence with $X_1 = S^2$, $X_2 = T^2$, $X_1 cap X_2 = {a, b, c}$ and $X = X_1 cup X_2$.
$endgroup$
$begingroup$
What about cell structure, how can I found it?
$endgroup$
– user619499
Nov 25 '18 at 18:04
1
$begingroup$
Try to find a way of realizing $S^2$ and $T^2$ with $3$ $0$-simplices each. With the torus you can start from the familiar square with sides identified, adding extra simplices on the edges.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:09
$begingroup$
I am really sorry I couldn't do it. Can you explain more? Thank you.
$endgroup$
– user619499
Nov 25 '18 at 18:18
1
$begingroup$
For $S^2$ you can take a triangle with $2$ $2$-simplexes; a top and a bottom one. For the torus you could take a square with additional vertex in the middle of each edge: after identifying edges, you will be left with $3$ vertices.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:26
add a comment |
$begingroup$
You can use the Mayer Vietoris sequence with $X_1 = S^2$, $X_2 = T^2$, $X_1 cap X_2 = {a, b, c}$ and $X = X_1 cup X_2$.
$endgroup$
You can use the Mayer Vietoris sequence with $X_1 = S^2$, $X_2 = T^2$, $X_1 cap X_2 = {a, b, c}$ and $X = X_1 cup X_2$.
answered Nov 25 '18 at 17:57
Lukas KoflerLukas Kofler
1,2632519
1,2632519
$begingroup$
What about cell structure, how can I found it?
$endgroup$
– user619499
Nov 25 '18 at 18:04
1
$begingroup$
Try to find a way of realizing $S^2$ and $T^2$ with $3$ $0$-simplices each. With the torus you can start from the familiar square with sides identified, adding extra simplices on the edges.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:09
$begingroup$
I am really sorry I couldn't do it. Can you explain more? Thank you.
$endgroup$
– user619499
Nov 25 '18 at 18:18
1
$begingroup$
For $S^2$ you can take a triangle with $2$ $2$-simplexes; a top and a bottom one. For the torus you could take a square with additional vertex in the middle of each edge: after identifying edges, you will be left with $3$ vertices.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:26
add a comment |
$begingroup$
What about cell structure, how can I found it?
$endgroup$
– user619499
Nov 25 '18 at 18:04
1
$begingroup$
Try to find a way of realizing $S^2$ and $T^2$ with $3$ $0$-simplices each. With the torus you can start from the familiar square with sides identified, adding extra simplices on the edges.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:09
$begingroup$
I am really sorry I couldn't do it. Can you explain more? Thank you.
$endgroup$
– user619499
Nov 25 '18 at 18:18
1
$begingroup$
For $S^2$ you can take a triangle with $2$ $2$-simplexes; a top and a bottom one. For the torus you could take a square with additional vertex in the middle of each edge: after identifying edges, you will be left with $3$ vertices.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:26
$begingroup$
What about cell structure, how can I found it?
$endgroup$
– user619499
Nov 25 '18 at 18:04
$begingroup$
What about cell structure, how can I found it?
$endgroup$
– user619499
Nov 25 '18 at 18:04
1
1
$begingroup$
Try to find a way of realizing $S^2$ and $T^2$ with $3$ $0$-simplices each. With the torus you can start from the familiar square with sides identified, adding extra simplices on the edges.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:09
$begingroup$
Try to find a way of realizing $S^2$ and $T^2$ with $3$ $0$-simplices each. With the torus you can start from the familiar square with sides identified, adding extra simplices on the edges.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:09
$begingroup$
I am really sorry I couldn't do it. Can you explain more? Thank you.
$endgroup$
– user619499
Nov 25 '18 at 18:18
$begingroup$
I am really sorry I couldn't do it. Can you explain more? Thank you.
$endgroup$
– user619499
Nov 25 '18 at 18:18
1
1
$begingroup$
For $S^2$ you can take a triangle with $2$ $2$-simplexes; a top and a bottom one. For the torus you could take a square with additional vertex in the middle of each edge: after identifying edges, you will be left with $3$ vertices.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:26
$begingroup$
For $S^2$ you can take a triangle with $2$ $2$-simplexes; a top and a bottom one. For the torus you could take a square with additional vertex in the middle of each edge: after identifying edges, you will be left with $3$ vertices.
$endgroup$
– Lukas Kofler
Nov 25 '18 at 18:26
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3013147%2fcell-structure-and-computing-homology-groups%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown