Milky Way Density
up vote
2
down vote
favorite
It seems to be a simple question, but I wasn't really able to find an appropriate answer: How dense is the Milky Way? I am certain that there are reliable statistic, maybe even new ones from the GAIA catalogue?
I am very aware of the fact that the tremendously varies between the core, the bulge, the spiral arms and the inter-arm regions, but I'd like to have a single number for the whole galaxy, something like "a solar system per pc$^3$". Is there anything around?
Thank you very much in advance!
cosmology astrophysics astronomy density milky-way
asked Nov 26 at 10:48
kalle
16311
add a comment |
up vote
2
down vote
favorite
It seems to be a simple question, but I wasn't really able to find an appropriate answer: How dense is the Milky Way? I am certain that there are reliable statistic, maybe even new ones from the GAIA catalogue?
I am very aware of the fact that the tremendously varies between the core, the bulge, the spiral arms and the inter-arm regions, but I'd like to have a single number for the whole galaxy, something like "a solar system per pc$^3$". Is there anything around?
Thank you very much in advance!
cosmology astrophysics astronomy density milky-way
asked Nov 26 at 10:48
kalle
16311
You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
– Run like hell
Nov 26 at 10:57
Someone asked about the density profile a while ago, but it's been left unanswered :(
– Kyle Kanos
Nov 26 at 11:02
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
It seems to be a simple question, but I wasn't really able to find an appropriate answer: How dense is the Milky Way? I am certain that there are reliable statistic, maybe even new ones from the GAIA catalogue?
I am very aware of the fact that the tremendously varies between the core, the bulge, the spiral arms and the inter-arm regions, but I'd like to have a single number for the whole galaxy, something like "a solar system per pc$^3$". Is there anything around?
Thank you very much in advance!
cosmology astrophysics astronomy density milky-way
asked Nov 26 at 10:48
kalle
16311
It seems to be a simple question, but I wasn't really able to find an appropriate answer: How dense is the Milky Way? I am certain that there are reliable statistic, maybe even new ones from the GAIA catalogue?
I am very aware of the fact that the tremendously varies between the core, the bulge, the spiral arms and the inter-arm regions, but I'd like to have a single number for the whole galaxy, something like "a solar system per pc$^3$". Is there anything around?
Thank you very much in advance!
cosmology astrophysics astronomy density milky-way
cosmology astrophysics astronomy density milky-way
asked Nov 26 at 10:48
kalle
16311
asked Nov 26 at 10:48
kalle
16311
asked Nov 26 at 10:48
kalle
16311
asked Nov 26 at 10:48
kalle
16311
asked Nov 26 at 10:48
kalle
16311
16311
You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
– Run like hell
Nov 26 at 10:57
Someone asked about the density profile a while ago, but it's been left unanswered :(
– Kyle Kanos
Nov 26 at 11:02
add a comment |
You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
– Run like hell
Nov 26 at 10:57
Someone asked about the density profile a while ago, but it's been left unanswered :(
– Kyle Kanos
Nov 26 at 11:02
You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
– Run like hell
Nov 26 at 10:57
You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
– Run like hell
Nov 26 at 10:57
Someone asked about the density profile a while ago, but it's been left unanswered :(
– Kyle Kanos
Nov 26 at 11:02
Someone asked about the density profile a while ago, but it's been left unanswered :(
– Kyle Kanos
Nov 26 at 11:02
add a comment |
1 Answer
1
active
oldest
votes
up vote
3
down vote
accepted
It's possible to give a rough estimate with the data on Wikipedia:
- Diameter: 46–61 kpc
- Thickness of thin stellar disk: 0.6 kpc
- Number of stars: 1–4 × 1011
If we take the average of the range, the volume of the disc is $0.6 times frac{pi}4 53.5^2=1348.8 ,text{kpc}^3$ (the volume of the core is negligible, given the inaccuracy of the number of stars). So the average number of stars per $text{pc}^3$ is $frac{2.5 cdot 10^{11}}{1348.8 cdot 10^9} ≈ 0.2$, but given the inaccuracies in the estimates it could be three times higher or lower.
(Also, not every star has its own solar system.)
answered Nov 26 at 11:05
Glorfindel
2421310
New contributor
Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
– kalle
Nov 26 at 11:32
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
It's possible to give a rough estimate with the data on Wikipedia:
- Diameter: 46–61 kpc
- Thickness of thin stellar disk: 0.6 kpc
- Number of stars: 1–4 × 1011
If we take the average of the range, the volume of the disc is $0.6 times frac{pi}4 53.5^2=1348.8 ,text{kpc}^3$ (the volume of the core is negligible, given the inaccuracy of the number of stars). So the average number of stars per $text{pc}^3$ is $frac{2.5 cdot 10^{11}}{1348.8 cdot 10^9} ≈ 0.2$, but given the inaccuracies in the estimates it could be three times higher or lower.
(Also, not every star has its own solar system.)
answered Nov 26 at 11:05
Glorfindel
2421310
New contributor
Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
– kalle
Nov 26 at 11:32
add a comment |
up vote
3
down vote
accepted
It's possible to give a rough estimate with the data on Wikipedia:
- Diameter: 46–61 kpc
- Thickness of thin stellar disk: 0.6 kpc
- Number of stars: 1–4 × 1011
If we take the average of the range, the volume of the disc is $0.6 times frac{pi}4 53.5^2=1348.8 ,text{kpc}^3$ (the volume of the core is negligible, given the inaccuracy of the number of stars). So the average number of stars per $text{pc}^3$ is $frac{2.5 cdot 10^{11}}{1348.8 cdot 10^9} ≈ 0.2$, but given the inaccuracies in the estimates it could be three times higher or lower.
(Also, not every star has its own solar system.)
answered Nov 26 at 11:05
Glorfindel
2421310
New contributor
Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
– kalle
Nov 26 at 11:32
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
It's possible to give a rough estimate with the data on Wikipedia:
- Diameter: 46–61 kpc
- Thickness of thin stellar disk: 0.6 kpc
- Number of stars: 1–4 × 1011
If we take the average of the range, the volume of the disc is $0.6 times frac{pi}4 53.5^2=1348.8 ,text{kpc}^3$ (the volume of the core is negligible, given the inaccuracy of the number of stars). So the average number of stars per $text{pc}^3$ is $frac{2.5 cdot 10^{11}}{1348.8 cdot 10^9} ≈ 0.2$, but given the inaccuracies in the estimates it could be three times higher or lower.
(Also, not every star has its own solar system.)
answered Nov 26 at 11:05
Glorfindel
2421310
New contributor
Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
It's possible to give a rough estimate with the data on Wikipedia:
- Diameter: 46–61 kpc
- Thickness of thin stellar disk: 0.6 kpc
- Number of stars: 1–4 × 1011
If we take the average of the range, the volume of the disc is $0.6 times frac{pi}4 53.5^2=1348.8 ,text{kpc}^3$ (the volume of the core is negligible, given the inaccuracy of the number of stars). So the average number of stars per $text{pc}^3$ is $frac{2.5 cdot 10^{11}}{1348.8 cdot 10^9} ≈ 0.2$, but given the inaccuracies in the estimates it could be three times higher or lower.
(Also, not every star has its own solar system.)
answered Nov 26 at 11:05
Glorfindel
2421310
New contributor
Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Nov 26 at 11:05
Glorfindel
2421310
New contributor
Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Nov 26 at 11:05
Glorfindel
2421310
answered Nov 26 at 11:05
Glorfindel
2421310
2421310
New contributor
Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
– kalle
Nov 26 at 11:32
add a comment |
Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
– kalle
Nov 26 at 11:32
Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
– kalle
Nov 26 at 11:32
Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
– kalle
Nov 26 at 11:32
add a comment |
Thanks for contributing an answer to Physics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f443377%2fmilky-way-density%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
– Run like hell
Nov 26 at 10:57
Someone asked about the density profile a while ago, but it's been left unanswered :(
– Kyle Kanos
Nov 26 at 11:02