fill area between two lines with different x-values











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I have a data frame with two columns xs and ys. Each row represents a line and in each cell is a list with 51 consecutive observations (so 2 lists in each row for x and y!).



I want to fill the space between the lines in the data frame.



the problem is that there's a randomness in x and y, so I can't just take the ymin and ymax for each data point on x.



this would create similarly shaped data (with only 2 lines with 10 observations):



genData <- function() {
set.seed(42)
genOneLine <- function(m_x, m_y) {
xs = seq(0,1,by=0.1)
x_ran <- rnorm(8, m_x, 0.1)
xs[2:9] = xs[2:9] + x_ran
ys = seq(0,1,by=0.1)
y_ran <- rnorm(8, m_y, 0.1)
ys[2:9] = ys[2:9] + y_ran
return (data.table(x = list(xs), y = list(ys)))
}
return (rbind(genOneLine(-0.1, -0.1), genOneLine(0.1, 0.1)))
}









share|improve this question




















  • 5




    You may not be able to share your real data, but surely you can throw together some example data? Say, ~10 rows with similar structure and properties as your real data to demonstrate the problem? See here for advice on creating reproducible examples. Use set.seed to make any randomness reproducible.
    – Gregor
    Nov 13 at 20:22












  • What do you mean "fill the space between the lines in the data frame"? Do you mean something about plotting the data or interpolating?
    – G5W
    Nov 13 at 20:26












  • sure, I can throw together some example data! I thought it was more or less clear, but it probalby helps. I'll update the question in a few minutes
    – Leander
    Nov 13 at 20:44










  • I have updated the question
    – Leander
    Nov 13 at 21:05

















up vote
0
down vote

favorite












I have a data frame with two columns xs and ys. Each row represents a line and in each cell is a list with 51 consecutive observations (so 2 lists in each row for x and y!).



I want to fill the space between the lines in the data frame.



the problem is that there's a randomness in x and y, so I can't just take the ymin and ymax for each data point on x.



this would create similarly shaped data (with only 2 lines with 10 observations):



genData <- function() {
set.seed(42)
genOneLine <- function(m_x, m_y) {
xs = seq(0,1,by=0.1)
x_ran <- rnorm(8, m_x, 0.1)
xs[2:9] = xs[2:9] + x_ran
ys = seq(0,1,by=0.1)
y_ran <- rnorm(8, m_y, 0.1)
ys[2:9] = ys[2:9] + y_ran
return (data.table(x = list(xs), y = list(ys)))
}
return (rbind(genOneLine(-0.1, -0.1), genOneLine(0.1, 0.1)))
}









share|improve this question




















  • 5




    You may not be able to share your real data, but surely you can throw together some example data? Say, ~10 rows with similar structure and properties as your real data to demonstrate the problem? See here for advice on creating reproducible examples. Use set.seed to make any randomness reproducible.
    – Gregor
    Nov 13 at 20:22












  • What do you mean "fill the space between the lines in the data frame"? Do you mean something about plotting the data or interpolating?
    – G5W
    Nov 13 at 20:26












  • sure, I can throw together some example data! I thought it was more or less clear, but it probalby helps. I'll update the question in a few minutes
    – Leander
    Nov 13 at 20:44










  • I have updated the question
    – Leander
    Nov 13 at 21:05















up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a data frame with two columns xs and ys. Each row represents a line and in each cell is a list with 51 consecutive observations (so 2 lists in each row for x and y!).



I want to fill the space between the lines in the data frame.



the problem is that there's a randomness in x and y, so I can't just take the ymin and ymax for each data point on x.



this would create similarly shaped data (with only 2 lines with 10 observations):



genData <- function() {
set.seed(42)
genOneLine <- function(m_x, m_y) {
xs = seq(0,1,by=0.1)
x_ran <- rnorm(8, m_x, 0.1)
xs[2:9] = xs[2:9] + x_ran
ys = seq(0,1,by=0.1)
y_ran <- rnorm(8, m_y, 0.1)
ys[2:9] = ys[2:9] + y_ran
return (data.table(x = list(xs), y = list(ys)))
}
return (rbind(genOneLine(-0.1, -0.1), genOneLine(0.1, 0.1)))
}









share|improve this question















I have a data frame with two columns xs and ys. Each row represents a line and in each cell is a list with 51 consecutive observations (so 2 lists in each row for x and y!).



I want to fill the space between the lines in the data frame.



the problem is that there's a randomness in x and y, so I can't just take the ymin and ymax for each data point on x.



this would create similarly shaped data (with only 2 lines with 10 observations):



genData <- function() {
set.seed(42)
genOneLine <- function(m_x, m_y) {
xs = seq(0,1,by=0.1)
x_ran <- rnorm(8, m_x, 0.1)
xs[2:9] = xs[2:9] + x_ran
ys = seq(0,1,by=0.1)
y_ran <- rnorm(8, m_y, 0.1)
ys[2:9] = ys[2:9] + y_ran
return (data.table(x = list(xs), y = list(ys)))
}
return (rbind(genOneLine(-0.1, -0.1), genOneLine(0.1, 0.1)))
}






r ggplot2 plot






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share|improve this question








edited Nov 13 at 21:05

























asked Nov 13 at 20:18









Leander

553719




553719








  • 5




    You may not be able to share your real data, but surely you can throw together some example data? Say, ~10 rows with similar structure and properties as your real data to demonstrate the problem? See here for advice on creating reproducible examples. Use set.seed to make any randomness reproducible.
    – Gregor
    Nov 13 at 20:22












  • What do you mean "fill the space between the lines in the data frame"? Do you mean something about plotting the data or interpolating?
    – G5W
    Nov 13 at 20:26












  • sure, I can throw together some example data! I thought it was more or less clear, but it probalby helps. I'll update the question in a few minutes
    – Leander
    Nov 13 at 20:44










  • I have updated the question
    – Leander
    Nov 13 at 21:05
















  • 5




    You may not be able to share your real data, but surely you can throw together some example data? Say, ~10 rows with similar structure and properties as your real data to demonstrate the problem? See here for advice on creating reproducible examples. Use set.seed to make any randomness reproducible.
    – Gregor
    Nov 13 at 20:22












  • What do you mean "fill the space between the lines in the data frame"? Do you mean something about plotting the data or interpolating?
    – G5W
    Nov 13 at 20:26












  • sure, I can throw together some example data! I thought it was more or less clear, but it probalby helps. I'll update the question in a few minutes
    – Leander
    Nov 13 at 20:44










  • I have updated the question
    – Leander
    Nov 13 at 21:05










5




5




You may not be able to share your real data, but surely you can throw together some example data? Say, ~10 rows with similar structure and properties as your real data to demonstrate the problem? See here for advice on creating reproducible examples. Use set.seed to make any randomness reproducible.
– Gregor
Nov 13 at 20:22






You may not be able to share your real data, but surely you can throw together some example data? Say, ~10 rows with similar structure and properties as your real data to demonstrate the problem? See here for advice on creating reproducible examples. Use set.seed to make any randomness reproducible.
– Gregor
Nov 13 at 20:22














What do you mean "fill the space between the lines in the data frame"? Do you mean something about plotting the data or interpolating?
– G5W
Nov 13 at 20:26






What do you mean "fill the space between the lines in the data frame"? Do you mean something about plotting the data or interpolating?
– G5W
Nov 13 at 20:26














sure, I can throw together some example data! I thought it was more or less clear, but it probalby helps. I'll update the question in a few minutes
– Leander
Nov 13 at 20:44




sure, I can throw together some example data! I thought it was more or less clear, but it probalby helps. I'll update the question in a few minutes
– Leander
Nov 13 at 20:44












I have updated the question
– Leander
Nov 13 at 21:05






I have updated the question
– Leander
Nov 13 at 21:05



















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